Write 0.00072 in standard form (a x 10n where 1 ≤ a < 10).
(Total for Question 3 is 2 marks)
4
Solve 2x = 32.
(Total for Question 4 is 2 marks)
5
Simplify (x2 y-3)2 / (x-1 y). Give your answer with positive or negative powers as appropriate.
(Total for Question 5 is 3 marks)
6
Show that 2n * 5n = 10n for any integer n.
(Total for Question 6 is 1 mark)
7
Evaluate 272/3.
(Total for Question 7 is 2 marks)
8
Solve 4x-1 = 8. Give your answer as a fraction or mixed number if needed.
(Total for Question 8 is 3 marks)
9
Show that (x3)1/2 * (x2)1/3 = x13/6, stating any restriction on x if necessary.
(Total for Question 9 is 3 marks)
10
Simplify (16 x4)3/2. Give your answer with integer coefficients and powers.
(Total for Question 10 is 3 marks)
11
Solve (1/4) * 23x = 8. Give your answer as a fraction.
(Total for Question 11 is 3 marks)
12
Simplify (2 x-1/3)3 * (4 x2/3)2. Give your answer simplified as a single term.
(Total for Question 12 is 3 marks)
13
Show that x2/3 / x1/6 = x1/2. State any restriction on x.
(Total for Question 13 is 3 marks)
14
A culture contains 500 bacteria. The population doubles every 3 hours. Write an expression for the number of bacteria after t hours, then work out how many after 18 hours.
(Total for Question 14 is 3 marks)
Mark scheme · 4.2H Indices: Higher Tier Practice
Question 1
B1 3 cao
Answer:3 (32 * 3-1 = 32-1 = 31 = 3 )
Question 2
M1 subtract exponents: 3 - 5 = -2
A1 x-2 cao
Answer: x-2
Question 3
M1 move decimal point 4 places to the right to get 7.2
A1 7.2 x 10-4 cao
Answer: 7.2 x 10-4
Question 4
M1 recognise 32 = 25 or take logs
A1 x = 5 cao
Answer: 5
Question 5
M1 apply power of a product: (x2 y-3)2 = x4 y-6
M1 divide by x-1 y gives x4-(-1) y-6-1 or equivalent
A1 x5 y-7 cao
Answer: x5 y-7
Question 6
C1 2n * 5n = (2*5)n = 10n cso
Answer:10n (Because 2n * 5n = (2*5)n = 10n.)
Question 7
M1 interpret 272/3 = (cube root of 27)2 or (272)1/3
A1 9 cao
Answer:9 (since cube root of 27 is 3, 32 = 9)
Question 8
M1 write 4 and 8 as powers of 2: 4x-1 = (22)x-1 = 22x-2, 8 = 23
M1 equate exponents: 2x - 2 = 3
A1 x = 5/2 cao
Answer: 5/2
Question 9
M1 apply power rule: (x3)1/2 = x3/2 and (x2)1/3 = x2/3
M1 add exponents: 3/2 + 2/3 = (9+4)/6 = 13/6
A1 x13/6 cao; state x ≥ 0 or work in real principal values
Answer:x13/6 (Valid for x ≥ 0 if working with real principal fractional powers.)