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Quadratic Inequalities: Solving and Graphing Regions - Worksheets, Questions and Revision

7 original exam-style questions - 2 pages of questions with a full mark scheme - free printable PDF.

This topic is chapter 1 of IGCSE Maths Practice Book 2.

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2.9 Quadratic Inequalities: Solving and Graphing Regions

EDEXCEL 4MA1 · Calculator allowed · about 25 minutes
Total Marks
Name: _______________________________    Date: ____ / ____ / ______
Answer ALL questions. Show all your working.
1
In the context of basic factorisation, solve the inequality x2 - 5x + 6 > 0 for x on the real number line.
(Total for Question 1 is 1 mark)
2
For the parabola context y = x2 - x - 6, find where y ≤ 0. Give your answer in inequality form for x.
(Total for Question 2 is 1 mark)
3
On the real number line, solve 2x2 - 8x < 0 by factorising and state the solution set.
(Total for Question 3 is 2 marks)
4
Consider the quadratic expression q(x) = -x2 + 6x - 5. Solve q(x) ≥ 0 and give the solution for x.
(Total for Question 4 is 2 marks)
5
Sketch and shade the region on the xy-plane for the inequality y > x2 - 4x + 3. Indicate clearly which side of the parabola is shaded and mark the critical points on the x-axis.
(Total for Question 5 is 3 marks)
6
A quadratic region problem: solve x2 + x - 12 ≤ 0 and then sketch the x-axis interval to show the solution set clearly on a number line.
(Total for Question 6 is 3 marks)
7
Solve the inequality 3x2 - 18x + 23 > 0. The roots are not integers. Show your working including the critical values found using the quadratic formula, and give the final solution in inequality notation.
(Total for Question 7 is 4 marks)
Mark scheme · 2.9 Quadratic Inequalities: Solving and Graphing Regions

Question 1

  • B1 correct solution x < 2 or x > 3, in correct inequality notation
  • Answer: x < 2 or x > 3

Question 2

  • B1 -2 ≤ x ≤ 3 cao
  • Answer: -2 ≤ x ≤ 3

Question 3

  • M1 factorises to 2x(x - 4) and identifies roots x = 0 and x = 4
  • A1 0 < x < 4, correct inequality notation
  • Answer: 0 < x < 4

Question 4

  • M1 rearranges or factorises, noting -x2 + 6x - 5 = -(x2 - 6x + 5) and finds roots x = 1 and x = 5
  • A1 1 ≤ x ≤ 5 cao
  • Answer: 1 ≤ x ≤ 5

Question 5

  • M1 identifies and plots the roots of x2 - 4x + 3 = 0 as x = 1 and x = 3 or marks points (1,0) and (3,0)
  • M1 sketches a correct upward-opening parabola passing through the roots
  • A1 shades the region above the parabola (y > x2 - 4x + 3) clearly
  • Answer: Region above the parabola y = x2 - 4x + 3, excluding the curve itself, with the curve crossing the x-axis at x = 1 and x = 3

Question 6

  • M1 factorises to (x + 4)(x - 3) and finds roots x = -4 and x = 3
  • A1 -4 ≤ x ≤ 3, correct inequality notation
  • B1 number line or small sketch showing closed dots at -4 and 3 and shading between them
  • Answer: -4 ≤ x ≤ 3

Question 7

  • M1 uses quadratic formula correctly and computes discriminant: b2 - 4ac = 324 - 276 = 48
  • M1 finds critical values x = (18 ± √48)/6 and simplifies exactly to x = (9 ± 2sqrt(3))/3, oe
  • A1 gives final solution in correct form: x < (9 - 2sqrt(3))/3 or x > (9 + 2sqrt(3))/3, cao
  • A1 states approximate critical values, for example x approximately 1.845 and x approximately 4.155, supporting the correct inequality notation
  • Answer: x < (9 - 2sqrt(3))/3 or x > (9 + 2sqrt(3))/3

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Question 4

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Question 5

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Question 6

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Question 7

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