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Introduction to Factorising Quadratics - Worksheets, Questions and Revision

29 original exam-style questions - 6 pages of questions with a full mark scheme - free printable PDF.

This topic is chapter 1 of KS3 Maths: Algebra Practice Book 2.

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KS3 · Algebra

2.14 Introduction to Factorising Quadratics

AQA KS3.M-A14 · Calculators not allowed · about 90 minutes
Name: _______________________________    Date: ____ / ____ / ______
Answer ALL questions. Show all your working.
1
Factorise x2 + 6x + 5 and use the factorised form to solve x2 + 6x + 5 = 0
(3)
2
Factorise fully and solve x2 - 5x - 24 = 0
(3)
3
Factorise x2 + 13x + 36 fully and state the roots of the quadratic equation x2 + 13x + 36 = 0.
(4)
4
The product of two consecutive integers is 56. Let the smaller integer be x. (a) Write an equation in x. (b) Solve the equation to find the positive integer.
(5)
5
Factorise fully: 9x2 - 25
(3)
6
Show that x2 + 6x + 9 can be written as (x + 3)2. Use this to explain why x2 + 6x + 9 is never negative for any real x. Give the value(s) of x for which the expression equals 0.
(6)
7
Factorise: x2 + 2x - 8
(1)
8
Factorise: x2 - 7x + 12
(1)
9
Factorise fully: x2 + 9x + 20
(2)
10
Factorise fully: x2 - x - 6
(2)
11
Given that (x + 3)(x + 4) = x2 + bx + c, state the values of b and c.
(2)
12
Multiply out (x + 5)(x - 2) and then factorise your answer to show you get back the original factors.
(2)
13
Factorise the difference of two squares: x2 - 9
(2)
14
Factorise fully: 4x2 - 36
(2)
15
Factorise the quadratic expression fully: x2 + 7x + 10
(1)
16
Factorise x2 + 14x + 45 and hence find the values of x for which the expression equals zero.
(3)
17
Factorise fully: 25x2 - 64
(1)
18
Expand (x + 6)(x - 2) to form a quadratic. Then find all values of x such that this quadratic equals 9.
(3)
19
Factorise x2 + 17x + 72 fully and state the roots of the quadratic equation x2 + 17x + 72 = 0.
(3)
20
Given that f(x) = x2 + 19x + 90:
(a) factorise f(x) fully
(b) find f(-12).
(3)
21
Show that x2 + 10x + 25 can be written as (x + 5)2. Use this to explain why x2 + 10x + 25 is never negative for any real x. Give the value(s) of x for which the expression equals 0.
(3)
22
Factorise fully: 4x2 - 49. Hence solve 4x2 - 49 = 0.
(3)
23
Factorise: x2 + 3x - 10
(1)
24
Factorise: x2 - 9x + 18
(1)
25
Factorise fully: x2 + 11x + 24
(2)
26
Factorise fully: x2 - 2x - 15
(2)
27
Factorise the difference of two squares: x2 - 16
(1)
28
Factorise fully: 9x2 - 100
(2)
29
Factorise x2 + 8x + 7 and use the factorised form to solve x2 + 8x + 7 = 0
(3)
Mark scheme · 2.14 Introduction to Factorising Quadratics

Question 1

  • M1 Correct factorisation (x + 1)(x + 5) or equivalent
  • A1 Set each factor to zero: x + 1 = 0, x + 5 = 0
  • A1 Correct solutions x = -1 and x = -5 cao
  • Answer: x = -1, x = -5

Question 2

  • M1 Factorise correctly to (x - 8)(x + 3) or equivalent
  • A1 Set factors to zero shown (x - 8 = 0, x + 3 = 0)
  • A1 Correct solutions x = 8 and x = -3 cao
  • Answer: x = 8, x = -3

Question 3

  • M1 Identify two numbers multiply to 36 and add to 13
  • M1 Correct factorisation (x + 4)(x + 9)
  • A1 Set factors to zero method shown
  • A1 Correct roots x = -4 and x = -9 cao
  • Answer: x = -4, x = -9

Question 4

  • M1 Correct equation x(x + 1) = 56 or equivalent shown
  • M1 Rearrange to x2 + x - 56 = 0
  • M1 Correct factorisation (x + 8)(x - 7) or equivalent
  • A1 Correct solutions x = 7 and x = -8
  • A1 State positive integer is 7 cao
  • Answer: 7

Question 5

  • M1 Recognise as difference of squares 9x2 - 25 = (3x)2 - 52
  • A1 Correct factorisation (3x - 5)(3x + 5) cao
  • B1 Both linear factors given in correct order or equivalent
  • Answer: (3x - 5)(3x + 5)

Question 6

  • M1 Complete the square or expand (x + 3)2 showing x2 + 6x + 9
  • M1 State the identity x2 + 6x + 9 = (x + 3)2 explicitly
  • A1 Explain that a square is always ≥ 0, so (x + 3)2 ≥ 0 for all real x
  • M1 Conclude that x2 + 6x + 9 is never negative by following from the square property
  • A1 State that the minimum value is 0 and it occurs when x + 3 = 0
  • A1 Give the value x = -3 for which the expression equals 0 cao
  • Answer: x = -3

Question 7

  • B1 Correct factorisation (x + 4)(x - 2) cao
  • Answer: (x + 4)(x - 2)

Question 8

  • B1 Correct factorisation (x - 3)(x - 4) cao
  • Answer: (x - 3)(x - 4)

Question 9

  • M1 Identify two numbers multiply to 20 and add to 9
  • A1 Correct factorisation (x + 4)(x + 5) cao
  • Answer: (x + 4)(x + 5)

Question 10

  • M1 Find two numbers multiply to -6 and add to -1
  • A1 Correct factorisation (x - 3)(x + 2) cao
  • Answer: (x - 3)(x + 2)

Question 11

  • M1 Multiply out to get x2 + 7x + 12 or equivalent
  • A1 b = 7 and c = 12 cao
  • Answer: b = 7, c = 12

Question 12

  • M1 Correct expansion x2 + 3x - 10
  • A1 Correct factorisation back to (x + 5)(x - 2) cao
  • Answer: Expansion: x2 + 3x - 10; Factorised: (x + 5)(x - 2)

Question 13

  • M1 Recognise 9 = 32 and use difference of squares method
  • A1 Correct factorisation (x - 3)(x + 3) cao
  • Answer: (x - 3)(x + 3)

Question 14

  • M1 Factor out common factor 4 to get 4(x2 - 9)
  • A1 Complete factorisation 4(x - 3)(x + 3) cao
  • Answer: 4(x - 3)(x + 3)

Question 15

  • B1 (x + 2)(x + 5) cao
  • Answer: (x + 2)(x + 5)

Question 16

  • M1 correct pair of factors of 45 that sum to 14 identified
  • A1 (x + 5)(x + 9) cao
  • B1 x = -5 and x = -9
  • Answer: (x + 5)(x + 9); x = -5 or x = -9

Question 17

  • B1 (5x - 8)(5x + 8) cao
  • Answer: (5x - 8)(5x + 8)

Question 18

  • M1 expands to x2 + 4x - 12
  • M1 sets up and factorises x2 + 4x - 21 = 0 as (x + 7)(x - 3) = 0
  • A1 x = -7 and x = 3
  • Answer: x2 + 4x - 12; x = -7 or x = 3

Question 19

  • M1 correct pair of factors of 72 that sum to 17 identified
  • A1 (x + 8)(x + 9) cao
  • B1 x = -8 and x = -9
  • Answer: (x + 8)(x + 9); x = -8 or x = -9

Question 20

  • M1 correct pair of factors of 90 that sum to 19 identified
  • A1 (x + 9)(x + 10) cao
  • B1 f(-12) = 6 cao (ft their factorised form or by direct substitution)
  • Answer: (x + 9)(x + 10); f(-12) = 6

Question 21

  • M1 expands (x + 5)2 to confirm x2 + 10x + 25
  • A1 explains a square is never negative, so the expression is never negative
  • B1 x = -5
  • Answer: x2 + 10x + 25 = (x + 5)2, never negative since a square cannot be negative; equals 0 only when x = -5

Question 22

  • M1 identifies 4x2 = (2x)2 and 49 = 72
  • A1 (2x - 7)(2x + 7) cao
  • B1 x = 3.5 and x = -3.5
  • Answer: (2x - 7)(2x + 7); x = 3.5 or x = -3.5

Question 23

  • B1 (x - 2)(x + 5) cao
  • Answer: (x - 2)(x + 5)

Question 24

  • B1 (x - 6)(x - 3) cao
  • Answer: (x - 6)(x - 3)

Question 25

  • M1 correct pair of factors of 24 that sum to 11 identified
  • A1 (x + 3)(x + 8) cao
  • Answer: (x + 3)(x + 8)

Question 26

  • M1 correct pair of factors of -15 that sum to -2 identified
  • A1 (x - 5)(x + 3) cao
  • Answer: (x - 5)(x + 3)

Question 27

  • B1 (x - 4)(x + 4) cao
  • Answer: (x - 4)(x + 4)

Question 28

  • M1 identifies 9x2 = (3x)2 and 100 = 102
  • A1 (3x - 10)(3x + 10) cao
  • Answer: (3x - 10)(3x + 10)

Question 29

  • M1 correct pair of factors of 7 that sum to 8 identified
  • A1 (x + 1)(x + 7) cao
  • B1 x = -1 and x = -7
  • Answer: (x + 1)(x + 7); x = -1 or x = -7

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Question 9

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Question 22

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