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KS3 · Algebra
2.8 Expanding Single Brackets
AQA KS3.M-A8 · Calculators not allowed · about 65 minutes
Name: _______________________________ Date: ____ / ____ / ______
Answer ALL questions. Show all your working.
1
Expand the brackets and solve the linear equation 2(x + 3) + 5 = 3x + 1.
Solve 2(x + 3) + 5 = 3x + 1.
(2)
2
Expand the brackets and solve the linear equation -3(x - 2) + 4 = 2x.
Solve -3(x - 2) + 4 = 2x.
(2)
3
Expand and simplify, taking care with negative signs: -2(x + 3) - 3(x - 1).
Work out -2(x + 3) - 3(x - 1).
(2)
4
Expand the single bracket -2(x - 5), taking care with the negative sign.
Expand -2(x - 5).
(1)
5
Expand the single bracket 5(2x + 3).
Expand 5(2x + 3).
(1)
6
Expand and simplify the expression 2(x + 3) + x.
Work out 2(x + 3) + x.
(2)
7
Expand and simplify the expression 3(a + 2) + 2(a - 5).
Work out 3(a + 2) + 2(a - 5).
(2)
8
Expand and simplify the expression 3(x + 4) - 2(x - 1).
Work out 3(x + 4) - 2(x - 1).
(2)
9
Expand and simplify the expression 2(3x + 4) - 5x.
Work out 2(3x + 4) - 5x.
(2)
11
Expand and simplify 2(3x + 4) - 5.
(2)
12
Expand and simplify -3(x + 2) + 10.
(2)
13
Expand and simplify 4(x + 6) - 3(x - 2).
(2)
14
Expand and simplify 5(2x - 3) - 3(x + 4).
(3)
15
Expand the brackets and solve the equation 3(x + 4) = 2x + 19.
(3)
16
A rectangle has length (x + 5) cm and width 3 cm. The perimeter of the rectangle is 46 cm. Form and solve an equation to find x.
(3)
17
A gardener buys tomato seed packs costing (2x + 3) pounds each and pepper seed packs costing (x - 1) pounds each. He buys 3 tomato packs and 2 pepper packs.
(a)Write and simplify an expression, in terms of x, for the total cost in pounds.(2)
(b)Given that x = 5, work out the total cost in pounds.(2)
18
A triangle has perimeter 5(x + 2) cm. Two of its sides are (x + 3) cm and (x + 5) cm.
(a)Expand 5(x + 2) to write the perimeter without brackets.(1)
(b)Find and simplify an expression, in terms of x, for the length of the third side.(2)
(c)Given that x = 4, find the length of the third side.(2)
24
Expand and simplify 3(x + 5) + 2x.
(2)
25
Expand and simplify 4(x - 3) + 7.
(2)
Mark scheme · 2.8 Expanding Single Brackets
Question 1
- M1 expand and collect like terms: 2x + 6 + 5 = 3x + 1 or 2x + 11 = 3x + 1
- A1 x = 10 cao
- Answer: 10
Question 2
- M1 expand to -3x + 6 + 4 = 2x or -3x + 10 = 2x and collect terms
- A1 x = 2 cao
- Answer: 2
Question 3
- M1 expand both brackets: -2x - 6 and -3x + 3 or equivalent
- A1 -5x - 3 cao
- Answer: -5x - 3
Question 4
- B1 -2x + 10 cao
- Answer: -2x + 10
Question 5
- B1 10x + 15 cao
- Answer: 10x + 15
Question 6
- M1 expand 2(x+3) to 2x + 6 or equivalent method
- A1 3x + 6 cao
- Answer: 3x + 6
Question 7
- M1 expand both brackets: 3a + 6 and 2a - 10 shown
- A1 5a - 4 cao
- Answer: 5a - 4
Question 8
- M1 expand both brackets: 3x + 12 and -2x + 2 or equivalent method
- A1 x + 14 cao
- Answer: x + 14
Question 9
- M1 expand 2(3x+4) to 6x + 8 or equivalent method
- A1 x + 8 cao
- Answer: x + 8
Question 10
- B1 5x + 10 cao
- Answer: 5x + 10
Question 11
- M1 expand 2(3x+4) to 6x + 8 or equivalent method
- A1 6x + 3 cao
- Answer: 6x + 3
Question 12
- M1 expand -3(x+2) to -3x - 6 or equivalent method
- A1 -3x + 4 cao
- Answer: -3x + 4
Question 13
- M1 expand both brackets: 4x + 24 and -3x + 6 or equivalent
- A1 x + 30 cao
- Answer: x + 30
Question 14
- M1 expand 5(2x-3) to 10x - 15
- M1 expand -3(x+4) to -3x - 12
- A1 7x - 27 cao
- Answer: 7x - 27
Question 15
- M1 expand 3(x+4) to 3x + 12
- M1 collect terms correctly, e.g. 3x + 12 = 2x + 19 leading to x = 19 - 12
- A1 x = 7 cao
- Answer: 7
Question 16
- M1 form expression for perimeter, e.g. 2(x+5) + 2(3) or 2x + 16
- M1 set expression equal to 46 and rearrange, e.g. 2x = 30
- A1 x = 15 cao
- Answer: 15
Question 17
- (a) M1 expand both: 3(2x+3) = 6x + 9 and 2(x-1) = 2x - 2
- (a) A1 8x + 7 cao
- (a) Answer: 8x + 7
- (b) M1 substitute x = 5 into 8x + 7
- (b) A1 47 cao
- (b) Answer: 47
Question 18
- (a) B1 5x + 10 cao
- (a) Answer: 5x + 10
- (b) M1 subtract the two given sides from the perimeter, e.g. (5x+10) - (x+3) - (x+5)
- (b) A1 3x + 2 cao
- (b) Answer: 3x + 2
- (c) M1 substitute x = 4 into 3x + 2
- (c) A1 14 cm cao
- (c) Answer: 14 cm
Question 19
- B1 -4x - 12 cao
- Answer: -4x - 12
Question 20
- B1 -2x + 14 cao
- Answer: -2x + 14
Question 21
- B1 12x + 6 cao
- Answer: 12x + 6
Question 22
- B1 21x - 14 cao
- Answer: 21x - 14
Question 23
- B1 -12x - 15 cao
- Answer: -12x - 15
Question 24
- M1 expand 3(x+5) to 3x + 15 or equivalent method
- A1 5x + 15 cao
- Answer: 5x + 15
Question 25
- M1 expand 4(x-3) to 4x - 12 or equivalent method
- A1 4x - 5 cao
- Answer: 4x - 5
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