GCSE Maths · Topic guide

Changing the Subject of a Formula

Changing the subject of a formula means rearranging an equation so that a different letter is isolated on one side, using the same inverse operations as solving an equation. It is a core GCSE algebra skill used whenever a formula, such as speed = distance / time, needs to be rewritten to make a different variable the subject.

Grade 5-6 (Higher)AlgebraEdexcelAQAOCR

Before you start

Make sure you're comfortable with these topics first:

Method

  1. Identify the letter that needs to become the new subject and treat every other letter as if it were a number.
  2. Undo the operations applied to the subject in reverse order (the opposite of BIDMAS), using inverse operations: addition undoes subtraction, multiplication undoes division, and so on.
  3. If the subject appears inside a bracket, first undo anything outside the bracket, then expand or divide to release it.
  4. If the subject appears more than once, expand any brackets, collect all terms containing the subject on one side, then factorise it out before dividing.
  5. If the formula involves a square or square root, square or square-root both sides as the very last step, once the subject's term is isolated.
  6. Check your rearranged formula by substituting numbers into both the original and new versions to confirm they give the same result.

Worked example

Make x the subject of the formula y = 5x - 7.

  1. Add 7 to both sides to isolate the term in x: y + 7 = 5x.
  2. Divide both sides by 5: (y + 7) / 5 = x.
  3. Rewrite with x as the subject: x = (y + 7) / 5.
  4. State the final answer: x = (y + 7) / 5.

Practice questions

Try each question, then tap to reveal the answer.

Exam-style questions

Written in the style of a GCSE Maths exam paper, with a full mark scheme.

Q1[2 marks]

Make x the subject of the formula y = 7x + 2.

Q2[4 marks]

The formula for the volume of a cylinder is V = pi x r^2 x h. (a) Make h the subject of the formula. (2) (b) Find h when V = 400, r = 5 and pi = 3.14, giving your answer correct to 1 decimal place. (2)

Q3[5 marks]

Make x the subject of the formula: y = (4x + 3)/(x - 2)

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