GCSE Maths · Topic guide

Parallel and Perpendicular Lines

Parallel and perpendicular lines are straight lines whose gradients follow fixed rules: parallel lines have equal gradients, while perpendicular lines have gradients that multiply to give -1. This lets you find the equation of a new line, in the form y = mx + c, once you know it must be parallel or perpendicular to a given line through a stated point. It is a core Higher GCSE topic.

Grade 6-7 (Higher)AlgebraEdexcelAQAOCR

Before you start

Make sure you're comfortable with these topics first:

Method

  1. Find the gradient of the given line, rearranging its equation into the form y = mx + c if needed.
  2. For a parallel line, use exactly the same gradient (m stays the same).
  3. For a perpendicular line, find the negative reciprocal of the gradient (flip the fraction and change the sign, so the two gradients multiply to -1).
  4. Substitute the new gradient and the coordinates of the given point into y - y1 = m(x - x1).
  5. Rearrange your equation into the form y = mx + c, or ax + by = c if the question asks for integer coefficients.
  6. Check your answer by substituting the given point back into your final equation.

Worked example

Find the equation of the line that is perpendicular to y = 2x + 3 and passes through the point (4, 1). Give your answer in the form y = mx + c.

  1. The gradient of y = 2x + 3 is 2.
  2. The perpendicular gradient is the negative reciprocal of 2, which is -1/2.
  3. Substitute m = -1/2 and the point (4, 1) into y - y1 = m(x - x1): y - 1 = -1/2(x - 4).
  4. Expand the brackets: y - 1 = -1/2 x + 2.
  5. Rearrange to make y the subject: y = -1/2 x + 3.

Practice questions

Try each question, then tap to reveal the answer.

Exam-style questions

Written in the style of a GCSE Maths exam paper, with a full mark scheme.

Q1[3 marks]

A straight line passes through the points (-2, 5) and (4, -7). Find the equation of the line, giving your answer in the form y = mx + c.

Q2[3 marks]

Show that the line y = 3x - 2 is parallel to the line with equation 9x - 3y + 6 = 0.

Q3[4 marks]

Triangle DEF has vertices D(-3, 0), E(1, 2) and F(3, -2). Show that triangle DEF has a right angle at E.

See real past-paper questions on parallel and perpendicular lines, organised by topic with official mark schemes

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