Percentages: Fluency and Exam Drill - Worksheets, Questions and Revision

22 original exam-style questions - 6 pages of questions with a full mark scheme - free printable PDF.

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GCSE · EDEXCEL

3.7D Percentages: Fluency and Exam Drill

EDEXCEL 1MA1 · Calculator allowed · about 80 minutes

Total Marks

Name: _______________________________ Date: ____ / ____ / ______

Answer ALL questions. Show all your working.

Work out 12% of 450 pounds.

(Total for Question 1 is 2 marks)

Out of 40 tomato plants in Mrs Whitfield's greenhouse, 18 produce ripe fruit before the end of July. Write 18 out of 40 as a percentage.

(Total for Question 2 is 2 marks)

Increase 160 by 35%.

(Total for Question 3 is 2 marks)

Decrease 90 by 8%.

(Total for Question 4 is 2 marks)

A laptop has a price of 540 pounds before VAT. VAT is charged at 20%. Work out the total price of the laptop including VAT.

(Total for Question 5 is 2 marks)

Kwame puts 1200 pounds into a savings account that pays 2.5% simple interest per year. Work out the total interest he earns after 5 years.

(Total for Question 6 is 2 marks)

A denim jacket is normally priced at 64 pounds. In a clearance sale it is reduced to 48 pounds. Work out the percentage decrease in the price.

(Total for Question 7 is 3 marks)

After a price increase of 20%, a mountain bike now costs 252 pounds. Work out the original price of the bike, before the increase.

(Total for Question 8 is 3 marks)

Daniel buys a second-hand table for 85 pounds. He restores it and sells it for 102 pounds. Work out his percentage profit.

(Total for Question 9 is 3 marks)

A secondary school has 1200 students. 55% of the students are girls. Of the girls, 40% study French. Work out how many girls study French.

(Total for Question 10 is 3 marks)

Aisha invests 2500 pounds in an account paying 3% compound interest per year. Work out the value of her investment at the end of 4 years. Give your answer to the nearest penny.

(Total for Question 11 is 3 marks)

Sophie buys a car for 18000 pounds. The car depreciates in value by 12% each year. Work out the value of the car after 3 years. Give your answer to the nearest pound.

(Total for Question 12 is 3 marks)

In a sale, a shop reduces every price by 15%. The sale price of a jumper is 39.10 pounds. Work out the original price of the jumper, before the sale.

(Total for Question 13 is 3 marks)

Liam works out 30% of 150 by calculating 150 - 30 = 120. He says the answer is 120.

(a)Explain the mistake in Liam's method.(2)

(b)Work out the correct value of 150 reduced by 30%.(2)

(Total for Question 14 is 4 marks)

A shop increases the price of a television by 20%. In a later sale, it decreases the new price by 20%.

(a)Using p pounds for the original price, show that the final price is 0.96p pounds, and state the overall percentage change.(3)

(b)Explain why the overall change is not 0%, even though one percentage is an increase of 20% and the other is a decrease of 20%.(1)

(Total for Question 15 is 4 marks)

A furniture shop applies two successive discounts to the price of a sofa: first 10% off, then a further 15% off the reduced price. After both discounts, the sofa costs 91.80 pounds. Work out the original price of the sofa.

(Total for Question 16 is 4 marks)

A price of 270 pounds includes VAT at 20%. A shop removes the VAT to find the pre-VAT price, then applies a separate 10% loyalty-card discount to that pre-VAT price.

(a)Work out the price before VAT was added.(2)

(b)Work out the final price a loyalty-card customer pays, after the 10% discount is applied to the pre-VAT price.(2)

(Total for Question 17 is 4 marks)

A painting is currently worth 5000 pounds. Its value is expected to increase by 8% each year. Find the number of complete years it takes for the value of the painting to first be worth more than 7000 pounds.

(Total for Question 18 is 4 marks)

A bacteria population starts at 800 and increases by 25% every hour.

(a)Work out the population after 6 hours. Give your answer to 3 significant figures.(3)

(b)Work out the overall percentage increase in the population over the 6 hours. Give your answer to 3 significant figures.(2)

(Total for Question 19 is 5 marks)

Priya invests 4000 pounds on 01/09/2025. For the first year the account pays 2.5% compound interest. For the second year the rate rises to 3.2% compound interest.

(Total for Question 20 is 3 marks)

The price of an item is increased by x%. It is then decreased by x%. The final price is 4% less than the original price.

(Total for Question 21 is 4 marks)

A company's revenue increases by 15% in Year 1. In Year 2, the revenue decreases by r%. Over the two years, the overall change in revenue is a decrease of 6%.

(Total for Question 22 is 4 marks)

Mark scheme · 3.7D Percentages: Fluency and Exam Drill

Question 1

M1 0.12 x 450 (oe)
A1 54 (pounds)
Answer: 54 pounds

Question 2

M1 18/40 x 100 (oe)
A1 45%
Answer: 45%

Question 3

M1 1.35 x 160 (oe: 35% of 160 = 56)
A1 216
Answer: 216

Question 4

M1 0.92 x 90 (oe: 8% of 90 = 7.2)
A1 82.8
Answer: 82.8

Question 5

M1 1.2 x 540 (oe: 20% of 540 = 108)
A1 648 (pounds)
Answer: 648 pounds

Question 6

M1 2.5% of 1200 = 30 (interest for one year)
A1 150 (pounds), from 30 x 5
Answer: 150 pounds

Question 7

M1 decrease = 64 - 48 = 16
M1 16/64 x 100 (oe)
A1 25%
Answer: 25%

Question 8

M1 recognises 252 represents 120% (1.2) of the original price
M1 252 / 1.2 (oe)
A1 210 (pounds)
Answer: 210 pounds

Question 9

M1 profit = 102 - 85 = 17
M1 17/85 x 100 (oe)
A1 20%
Answer: 20%

Question 10

M1 number of girls = 0.55 x 1200 = 660
M1 0.40 x 660 (oe)
A1 264
Answer: 264

Question 11

M1 2500 x 1.03⁴ (oe, or repeated year-on-year multiplication by 1.03)
M1 correct evaluation of 1.03⁴ = 1.12550881 (oe intermediate values seen)
A1 2813.77 (pounds), awrt
Answer: 2813.77 pounds

Question 12

M1 18000 x 0.88³ (oe, or repeated year-on-year multiplication by 0.88)
M1 correct evaluation of 0.88³ = 0.681472 (oe intermediate values seen)
A1 12266 (pounds), awrt
Answer: 12266 pounds

Question 13

M1 recognises 39.10 represents 85% (0.85) of the original price
M1 39.10 / 0.85 (oe)
A1 46 (pounds)
Answer: 46 pounds

Question 14

(a) B1 identifies that Liam has subtracted the number 30, treating it as an amount, instead of finding 30% of 150
(a) B1 states that the correct method requires working out 30% of 150 (as an amount) and then subtracting that amount from 150
(a) Answer: Liam subtracted the number 30 instead of subtracting 30% of 150 (which is 45)
(b) M1 30% of 150 = 45 (oe: 0.3 x 150)
(b) A1 105
(b) Answer: 105

Question 15

(a) M1 price after increase = p x 1.2 (oe)
(a) M1 price after decrease = (1.2p) x 0.8 (oe)
(a) A1 = 0.96p, an overall decrease of 4%
(a) Answer: 0.96p pounds; a 4% decrease overall
(b) B1 the 20% decrease is taken from the larger, increased price, so the amount taken off (0.24p) is more than the amount added on (0.2p)
(b) Answer: The 20% decrease is applied to a larger amount than the original, so more is taken off than was added on

Question 16

M1 recognises the combined multiplier 0.9 x 0.85 = 0.765 (oe)
M1 sets up original price x 0.765 = 91.80 (oe)
M1 91.80 / 0.765 (oe)
A1 120 (pounds)
Answer: 120 pounds

Question 17

(a) M1 270 / 1.2 (oe)
(a) A1 225 (pounds)
(a) Answer: 225 pounds
(b) M1 0.9 x 225 (ft their part (a) answer)
(b) A1 202.50 (pounds)
(b) Answer: 202.50 pounds

Question 18

M1 a correct trial value calculated, e.g. value after 4 years = 5000 x 1.08⁴ = awrt 6802.44
M1 a second correct trial value calculated that brackets 7000, e.g. value after 5 years = 5000 x 1.08⁵ = awrt 7346.64
A1 correct comparison stated: value after 4 years (awrt 6802) is below 7000, value after 5 years (awrt 7347) is above 7000
A1 5 (complete years), cao
Answer: 5 complete years

Question 19

(a) M1 1.25⁶ evaluated (oe, or repeated multiplication by 1.25 six times)
(a) M1 800 x 1.25⁶ (oe)
(a) A1 3050, awrt 3sf
(a) Answer: 3050 (3sf)
(b) M1 (3051.7578... - 800) / 800 x 100 (oe, ft their unrounded part (a) value)
(b) A1 281%, awrt 3sf
(b) Answer: 281% (3sf)

Question 20

M1 value after year 1 = 4000 x 1.025 = 4100 (oe)
M1 value after year 2 = 4100 x 1.032 (oe)
A1 4231.20 (pounds)
Answer: 4231.20 pounds

Question 21

M1 sets up (1 + x/100)(1 - x/100) = 0.96 (oe)
M1 expands to 1 - (x/100)² = 0.96 (oe)
M1 (x/100)² = 0.04, so x/100 = 0.2 (oe, positive root taken)
A1 x = 20, cao
Answer: x = 20

Question 22

M1 sets up 1.15 x (1 - r/100) = 0.94 (oe)
M1 (1 - r/100) = 0.94 / 1.15 (oe)
M1 r/100 = 1 - 0.94/1.15 = 0.182608... (oe, evaluated)
A1 r = 18.3, awrt 1dp
Answer: r = 18.3 (1dp)

Question 22

4 marks

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Percentages: Fluency and Exam Drill - Worksheets, Questions and Revision

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