Foundation Tier - Set A, Paper 1

Exam Structure Set A: Foundation Paper 1

An 80-mark, 90-minute non-calculator paper using the Edexcel 1MA1 paper structure as its reference.

33 questions - 80 marks

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Questions

Question 1 [1 marks]

Area, Volume and Measures

A cube has edge length 4 cm. Which of the following is the total surface area of the cube?

Question 2 [1 marks]

Pythagoras and Trigonometry

Write down the trigonometric ratio that links opposite and hypotenuse. Use the word "sine" in your answer.

Question 3 [2 marks]

Indices and Standard Form

Write each of these numbers as an ordinary number.

3.6 x 10^5

4.02 x 10^-3

Question 4 [2 marks]

Angles and Geometrical Reasoning

Lines l and m are parallel and are crossed by a straight transversal. Angle y is in the corresponding position to the 118 degree angle marked above line l.

Question 5 [2 marks]

Sequences

Here are the first four terms of a sequence. 2, 6, 10, 14

Write down the next two terms of the sequence.

Describe, in words, the term-to-term rule for the sequence.

Question 6 [3 marks]

Fractions, Decimals and Percentages

(Non-calculator)

Write 45% as a decimal.

Write 3/4 as a percentage.

Write 0.2 as a percentage.

Question 7 [1 marks]

Statistics and Probability

Using the diagram in Question 10, write down n(F).

Question 8 [1 marks]

Number and Calculation

Calculate 125 x 8.

Question 9 [1 marks]

Statistics and Probability

A school recorded the time, t minutes, spent on homework by 30 pupils in one evening. The table shows the results. Time, t (minutes): 0 < t <= 20, 20 < t <= 40, 40 < t <= 60, 60 < t <= 80, 80 < t <= 100 Frequency (f): 4, 9, 11, 4, 2 Total number of pupils = 30 Write down the modal class.

Question 10 [2 marks]

Linear Algebra

Solve 5 - 2x = 1 Show your working.

Question 11 [1 marks]

Number and Calculation

Work out 7 x 8.

Question 12 [1 marks]

Statistics and Probability

Priya says that 8 is a member of set A (using the sets in Question 1). Is she correct? Give a reason for your answer.

Question 13 [2 marks]

Number and Calculation

Work out the least common multiple of 14, 21 and 35.

Question 14 [2 marks]

Statistics and Probability

Grace kept a record of the number of books read last month by 20 pupils in her form. The table shows the results. Books read (x): 0, 1, 2, 3, 4 Frequency (f): 3, 7, 6, 3, 1 Total number of pupils = 20 Find the median number of books read.

Question 15 [1 marks]

Number and Calculation

Work out 8 x 6.

Question 16 [2 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (-1, 6) and (3, -2).

Question 17 [2 marks]

Indices and Standard Form

Simplify 20y^9 / 5y^3.

Question 18 [2 marks]

Graphs and Coordinates

Rearrange 2y = 8x - 6 into the form y = mx + c and state the gradient.

Question 19 [2 marks]

Number and Calculation

Show that 123456 is divisible by 3.

Question 20 [2 marks]

Ratio and Proportion

Given that a : b = 5 : 2 and a = 25, work out the value of b.

Question 21 [2 marks]

Area, Volume and Measures

Convert 4.5 km into metres.

Question 22 [2 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (2, 5) and (8, 1).

Question 23 [2 marks]

Linear Algebra

Expand and simplify (4x - 3)(2x + 5)

Question 24 [2 marks]

Quadratics

Solve x^2 + 9x = 0

Question 25 [2 marks]

Number and Calculation

Show that 108 = 2^2 x 3^3.

Question 26 [4 marks]

Ratio and Proportion

Priya mixes squash and water in the ratio 1:6 (squash : water). Let s be the amount of squash in litres and w the amount of water. Write w as a linear function of s in the form w = ks and give k.

Question 27 [3 marks]

Quadratics

A rectangular lawn has width x metres and length (x + 5) metres. The area of the lawn, A m^2, is given by A = x(x + 5).

Complete the table of values for A = x(x + 5), for 1 <= x <= 3. x : 1 , 2 , 3 A : _ , _ , _

Explain why, in this context, x cannot take a negative value.

Question 28 [3 marks]

Graphs and Coordinates

Priya walks from home to the bus stop, waits for the bus, then travels quickly by bus to college. Sketch a distance-time graph to show Priya's journey. Label your axes Time and Distance from home.

Question 29 [5 marks]

Linear Algebra

A triangle has angles of (2x + 10) degrees, (3x - 5) degrees and (x + 25) degrees.

Show that 6x + 30 = 180

Hence find the size of the smallest angle in the triangle.

Question 30 [3 marks]

Quadratics

For each equation, state whether its graph is u-shaped or n-shaped.

y = 4 - 7x^2

y = 6x^2 - x - 1

y = -x^2 + 3x - 2

Question 31 [6 marks]

Linear Algebra

The diagram shows a rectangular photo frame. The perimeter of the frame is 50 cm.

Show that 8x + 2 = 50

Solve the equation to find the value of x.

Work out the length and the width of the frame, and state whether the frame is in landscape or portrait orientation.

Question 32 [6 marks]

Sequences

Here are the first four terms of an arithmetic sequence. 15, 11.5, 8, 4.5

Find the common difference of the sequence.

Find an expression, in terms of n, for the nth term of the sequence.

Find the first term in the sequence that is negative.

Question 33 [7 marks]

Graphs and Coordinates

The time, t hours, taken to fill a water tank is inversely proportional to the number of pumps, n, used. When n = 4, t = 3.

Find a formula for t in terms of n.

Complete the table of values for t = 12/n. n : 1 , 2 , 3 , 4 , 6 t : _ , _ , _ , 3 , _

State one feature of the graph of t against n, for n > 0.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
C (96 cm^2)B1
Final answer: C) 96 cm^2
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
sine = opposite/hypotenuse or sine(theta) = opposite/hypotenuseB1cao
Final answer: sine = opposite/hypotenuse (sine(theta) = opposite/hypotenuse)
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
360000B1cao
0.00402B1cao
Final answer: 360000 | 0.00402
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
y = 118B1cao
correct reason: corresponding angles are equal (l parallel to m)B1
Final answer: y = 118 degrees
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
18 and 22 both correctB1oe
start at 2 and add 4 each timeB1oe
Final answer: 18, 22 | Start at 2 and add 4 each time (oe).
Mark scheme for Question 6 [3 marks]
Question 6[3 marks]
Answer or workingMarks
0.45B1
75%B1
20%B1
Final answer: 0.45 | 75% | 20%
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
10B1cao
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
1000B1cao
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
40 < t <= 60B1cao
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
-2x = -4 or 2x = 4M1oe
x = 2A1cao
Mark scheme for Question 11 [1 mark]
Question 11[1 mark]
Answer or workingMarks
56B1cao
Mark scheme for Question 12 [1 mark]
Question 12[1 mark]
Answer or workingMarks
No, with correct reason, e.g. A = {1,2,3,4,5} does not contain 8, so 8 is not a member of AB1
Final answer: No; 8 is not a member of A
Mark scheme for Question 13 [2 marks]
Question 13[2 marks]
Answer or workingMarks
Correct method: prime factors (14 = 2*7, 21 = 3*7, 35 = 5*7) and combineM1
210A1cao
Mark scheme for Question 14 [2 marks]
Question 14[2 marks]
Answer or workingMarks
correct use of cumulative frequencies to identify the 10th and 11th values (3, 10, 16, 19, 20)M1oe
1.5A1cao
Mark scheme for Question 15 [1 mark]
Question 15[1 mark]
Answer or workingMarks
48B1cao
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
(-2 - 6)/(3 - (-1)), oe substitution into the gradient formula with correct signsM1
-2A1cao
Mark scheme for Question 17 [2 marks]
Question 17[2 marks]
Answer or workingMarks
coefficient 4 or index y^6 seenM1
4y^6A1cao
Mark scheme for Question 18 [2 marks]
Question 18[2 marks]
Answer or workingMarks
divides every term by 2M1oe
4 cao (accept full statement y = 4x - 3)A1
Final answer: 4
Mark scheme for Question 19 [2 marks]
Question 19[2 marks]
Answer or workingMarks
Use digit sum method: 1+2+3+4+5+6 = 21M1
Therefore 123456 is divisible by 3A1cso
Final answer: Digits sum to 21 and 21 is divisible by 3, so 123456 is divisible by 3.
Mark scheme for Question 20 [2 marks]
Question 20[2 marks]
Answer or workingMarks
find one part: 25/5 = 5 or equivalent methodM1
10A1cao
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
method shown, 4.5 x 1000 or move decimalM1
4500 mA1cao
Mark scheme for Question 22 [2 marks]
Question 22[2 marks]
Answer or workingMarks
(1 - 5)/(8 - 2), oe substitution into the gradient formulaM1
-2/3 oeA1cao
Final answer: -2/3
Mark scheme for Question 23 [2 marks]
Question 23[2 marks]
Answer or workingMarks
8x^2 + 20x - 6x - 15, or at least 3 of the 4 terms correctM1oe
8x^2 + 14x - 15A1cao
Mark scheme for Question 24 [2 marks]
Question 24[2 marks]
Answer or workingMarks
x(x + 9) = 0M1oe
x = 0 and x = -9A1cao
Final answer: x = 0 or x = -9
Mark scheme for Question 25 [2 marks]
Question 25[2 marks]
Answer or workingMarks
Correct factor tree or repeated division shown (e.g. 108 / 2 = 54, 54 / 2 = 27, 27 / 3 = 9, 9 / 3 = 3)M1
2^2 x 3^3 = 4 x 27 = 108, so shownA1cso
Final answer: Shown: 108 = 2^2 x 3^3, since 2^2 x 3^3 = 4 x 27 = 108.
Mark scheme for Question 26 [4 marks]
Question 26[4 marks]
Answer or workingMarks
uses ratio w/s = 6/1 or writes w = 6sM1
w = 6sA1cao
states k = 6B1
units or variable consistent (litres) or equivalent statementB1
Final answer: w = 6s, k = 6
Mark scheme for Question 27 [3 marks]
Question 27[3 marks]
Answer or workingMarks
at least 2 of the 3 A-values correctB1
all 3 A-values correctB1
x represents a width/length, and a physical length cannot be negativeB1oe
Final answer: 6, 14, 24 | x is a width (a length), and a length cannot be negative
Mark scheme for Question 28 [3 marks]
Question 28[3 marks]
Answer or workingMarks
straight line with positive gradient from the origin (walking)B1
horizontal section following the first line (waiting for the bus)B1
straight line with a steeper positive gradient than the first section, following the horizontal section (bus, faster than walking)B1
Final answer: Line rises from the origin (walking to the bus stop), then a horizontal section (waiting), then a steeper rising line (travelling by bus, faster than walking).
Mark scheme for Question 29 [5 marks]
Question 29[5 marks]
Answer or workingMarks
correct collection of the three angle expressions, (2x+10) + (3x-5) + (x+25)M1oe
cso, correctly simplified to 6x + 30 = 180, using angles in a triangle sum to 180 degrees, with all steps shownA1
6x = 150 oe (ft from part a)M1
x = 25 (ft), substituted into all three angle expressionsM1
50 degrees cao, correctly identified as the smallest angle (angles are 60, 70 and 50 degrees)A1
Final answer: 6x + 30 = 180 (shown) | 50 degrees
Mark scheme for Question 30 [3 marks]
Question 30[3 marks]
Answer or workingMarks
n-shapedB1
u-shapedB1
n-shapedB1
Final answer: n-shaped | u-shaped | n-shaped
Mark scheme for Question 31 [6 marks]
Question 31[6 marks]
Answer or workingMarks
2[(x + 2) + (3x - 1)] = 50 oe (correct perimeter expression set equal to 50)M1
correctly expands and simplifies to 8x + 2 = 50A1dep
8x = 48M1oe
x = 6A1cao
substitutes x = 6 into both expressions (ft their x)M1
length = 17 cm and width = 8 cm (both required, cao), and correctly identifies landscape orientation since the length is greater than the widthA1
Final answer: 8x + 2 = 50 (shown) | x = 6 | length = 17 cm, width = 8 cm; landscape orientation
Mark scheme for Question 32 [6 marks]
Question 32[6 marks]
Answer or workingMarks
-3.5B1cao
common difference of -3.5 used correctly, e.g. -3.5n + cM1oe
18.5 - 3.5n oeA1cao
18.5 - 3.5n < 0 oe (ft their expression)M1
n > 5.28... (37/7) found, leading to n = 6M1
6th term, -2.5A1cao
Final answer: -3.5 | 18.5 - 3.5n | The 6th term, which is -2.5
Mark scheme for Question 33 [7 marks]
Question 33[7 marks]
Answer or workingMarks
sets up t = k/n and substitutes n=4, t=3 to find k=12M1
t = 12/nA1oe
t = 12 at n = 1B1
t = 6 at n = 2B1
t = 4 at n = 3B1
t = 2 at n = 6B1
any correct feature, e.g. as n increases t decreases; or the curve gets closer to the n-axis but never touches it; or the graph only exists for n > 0 in this contextB1
Final answer: t = 12/n | n=1: t=12; n=2: t=6; n=3: t=4; n=6: t=2 | As the number of pumps increases, the time taken decreases (the curve approaches but never touches the n-axis)