Higher Tier - Set A, Paper 1

Exam Structure Set A: Higher Paper 1

An 80-mark, 90-minute non-calculator paper using the Edexcel 1MA1 paper structure as its reference.

36 questions - 80 marks

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Questions

Question 1 [1 marks]

Area, Volume and Measures

A cube has edge length 4 cm. Which of the following is the total surface area of the cube?

Question 2 [2 marks]

Graphs and Coordinates

A line has equation y = -2x + 7.

Write down the gradient of the line.

Write down the coordinates of the point where the line crosses the y-axis.

Question 3 [3 marks]

Angles and Geometrical Reasoning

Column vectors are written in the form (x, y), where x is the top (horizontal) number and y is the bottom (vertical) number. u = (4, 1) and v = (-2, 5).

Work out u + v as a column vector.

Work out u - v as a column vector.

Work out 3v as a column vector.

Question 4 [1 marks]

Pythagoras and Trigonometry

Write down the exact value of cos 45 degrees, giving your answer as a surd in its simplest form.

Question 5 [1 marks]

Statistics and Probability

Using the Venn diagram from Question 2, a student is chosen at random from the 30 students.

What is n(F union N)? A) 5 B) 13 C) 23 D) 30

Question 6 [1 marks]

Indices and Standard Form

Simplify sqrt(75) fully.

Question 7 [1 marks]

Ratio and Proportion

Given that m:n = 4:7, write n in terms of m as a linear function in the form n = km.

Question 8 [1 marks]

Sequences

Write down the second difference for the sequence 4, 9, 16, 25, 36.

Question 9 [1 marks]

Ratio and Proportion

A fruit drink is made from concentrate and water in the ratio 1:4. Write down what fraction of the drink is concentrate.

Question 10 [1 marks]

Statistics and Probability

Describe in words the region that represents A' and B'.

Question 11 [1 marks]

Linear Algebra

The diagram below shows a number line. There is an open circle at x = 3, with shading and an arrow extending to the left. Write down the inequality that is shown.

Question 12 [1 marks]

Graphs and Coordinates

Work out f(2) for f(x) = 3x + 1.

Question 13 [1 marks]

Number and Calculation

Ayesha has 4 different T-shirts and 3 different skirts. Work out the number of different outfits she can make by choosing one T-shirt and one skirt.

Question 14 [1 marks]

Graphs and Coordinates

Work out f(-2) for f(x) = 2x^2.

Question 15 [2 marks]

Number and Calculation

Write 18 as a product of its prime factors.

Question 16 [2 marks]

Quadratics

Consider the equation 3x^2 - 2x + 5 = 0.

Calculate the value of the discriminant, b^2 - 4ac.

Hence state, giving a reason, how many real solutions the equation has.

Question 17 [2 marks]

Linear Algebra

Solve 3(x - 2) < 15 Show your working.

Question 18 [2 marks]

Pythagoras and Trigonometry

Work out the exact value of sin 30 degrees + cos 60 degrees. Show your working.

Question 19 [2 marks]

Graphs and Coordinates

The graphs of y = 2x - 6 and y = -x + 6 are drawn on the grid. Write down the solution of the simultaneous equations y = 2x - 6 and y = -x + 6.

Question 20 [2 marks]

Indices and Standard Form

Three stars have these distances from Earth, in light-years. Star P: 3.6 x 10^2 Star Q: 9 x 10^1 Star R: 1.4 x 10^3 Put the stars in order of distance from Earth, starting with the nearest. Show how you have compared the distances.

Question 21 [2 marks]

Graphs and Coordinates

The graphs of y = 1 and y = 3x - 5 are drawn on the grid. Write down the solution of the simultaneous equations y = 1 and y = 3x - 5.

Question 22 [2 marks]

Linear Algebra

a = 6 and b = -3. Work out the value of 2a - b.

Question 23 [2 marks]

Indices and Standard Form

Simplify (3d^2)^3.

Question 24 [2 marks]

Graphs and Coordinates

The graphs of y = x - 1 and y = -2x - 7 are drawn on the grid. Write down the solution of the simultaneous equations y = x - 1 and y = -2x - 7.

Question 25 [2 marks]

Statistics and Probability

Priya, a gardener, recorded the height, in cm, of 15 tomato plants. The five-number summary is: Minimum = 30, Lower quartile = 45, Median = 55, Upper quartile = 68, Maximum = 140

Work out the interquartile range of the plant heights.

The maximum height of 140 cm is much larger than the rest of the data. Suggest one reason why this value might not be typical of the tomato plants.

Question 26 [3 marks]

Fractions, Decimals and Percentages

Convert 0.512512512... (512 recurring) to a fraction in its simplest form.

Question 27 [4 marks]

Ratio and Proportion

It takes 6 builders 15 days to build a wall, all working at the same constant rate. The number of days, D, needed is inversely proportional to the number of builders, n.

Find the value of k in the formula D = k/n.

Work out how many days it would take 9 builders, working at the same rate, to build the same wall.

Give one reason why this inverse proportion model might not give a realistic answer if a very large number of builders were used.

Question 28 [4 marks]

Quadratics

Solve x^2 + 14x + 9 = 0 by completing the square. Give your answers in surd form, simplified where possible.

Question 29 [4 marks]

Ratio and Proportion

y is directly proportional to sqrt(x). When x = 16, y = 12.

Find a formula for y in terms of x.

Work out the value of y when x = 25.

Question 30 [3 marks]

Angles and Geometrical Reasoning

For a certain regular polygon, the sum of its interior angles is 10 times the sum of its exterior angles. Work out the number of sides of the polygon.

Question 31 [3 marks]

Indices and Standard Form

Simplify sqrt(x^3) / x^(1/4). Give your answer as a single power of x.

Question 32 [3 marks]

Angles and Geometrical Reasoning

TA is a tangent to a circle at the point A. AB and AC are chords of the circle. The angle between the tangent and the chord AB is (3x + 8) degrees. The angle in the alternate segment, angle ACB, is (5x - 32) degrees. Diagram: circle, tangent TA at A, chords AB and AC drawn, tangent-chord angle (3x + 8) degrees marked at A, angle ACB = (5x - 32) degrees marked at C in the alternate segment.

Use the alternate segment theorem to form an equation in x, and solve it to find the value of x.

Work out the size of angle ACB.

Question 33 [4 marks]

Linear Algebra

The formula connecting m and n is m = (4n + 5)/(3 - n). Show that n = (3m - 5)/(m + 4)

Question 34 [4 marks]

Graphs and Coordinates

The graph of y = 2cos x - 1 is a transformation of y = cos x.

Write down the maximum and minimum values of y = 2cos x - 1.

Write down the coordinates of the y-intercept of the graph.

State the period of the graph.

Question 35 [4 marks]

Angles and Geometrical Reasoning

A, B and C are points on the circumference of a circle with centre O. B lies on the minor arc AC. The reflex angle AOC = 264 degrees. Diagram: circle, centre O, points A, B and C on the circumference, B on the minor arc AC, the reflex angle AOC = 264 degrees marked at the centre going the long way round, angle ABC marked at B.

Work out the size of the non-reflex angle AOC.

Work out the size of angle ABC.

Question 36 [5 marks]

Statistics and Probability

A gym in Glasgow, run by manager Callum, has 44 members in total. Of these, x members use the pool only, x^2 members use both the pool and the gym floor, and (2x + 1) members use the gym floor only. The remaining 3 members use neither facility.

Show that x^2 + 3x - 40 = 0.

Solve the equation to find the value of x, explaining why the other solution is not valid.

Hence find the probability that a randomly selected member uses the pool (including those who use both facilities).

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
C (96 cm^2)B1
Final answer: C) 96 cm^2
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
-2B1cao
(0, 7)B1cao
Final answer: -2 | (0, 7)
Mark scheme for Question 3 [3 marks]
Question 3[3 marks]
Answer or workingMarks
(2, 6)B1cao
(6, -4)B1cao
(-6, 15)B1cao
Final answer: (2, 6) | (6, -4) | (-6, 15)
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
sqrt(2)/2 oe, accept 1/sqrt(2)B1
Final answer: sqrt(2)/2
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
C (23)B1cao
Final answer: C) 23
Mark scheme for Question 6 [1 mark]
Question 6[1 mark]
Answer or workingMarks
5sqrt(3) oeB1cao
Final answer: 5sqrt(3)
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
n = 7/4 m oe (k = 7/4)B1
Final answer: n = 7/4 m
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
second difference = 2B1cao
Final answer: 2
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
1/5B1oe
Mark scheme for Question 10 [1 mark]
Question 10[1 mark]
Answer or workingMarks
correct description, e.g. the elements outside both circles, in neither A nor BB1
Final answer: The elements outside both circles, i.e. in neither A nor B.
Mark scheme for Question 11 [1 mark]
Question 11[1 mark]
Answer or workingMarks
x < 3 oeB1cao
Final answer: x < 3
Mark scheme for Question 12 [1 mark]
Question 12[1 mark]
Answer or workingMarks
7B1cao
Mark scheme for Question 13 [1 mark]
Question 13[1 mark]
Answer or workingMarks
12B1cao
Mark scheme for Question 14 [1 mark]
Question 14[1 mark]
Answer or workingMarks
8B1cao
Mark scheme for Question 15 [2 marks]
Question 15[2 marks]
Answer or workingMarks
correct first split of 18 shown, e.g. 2 x 9, or a factor tree with at least one prime factor correctM1
2 x 3^2 oe, fully correct in index formA1
Final answer: 2 x 3^2
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
-56B1cao
0 (no real solutions), since the discriminant is negative (ft from part a)B1
Final answer: -56 | No real solutions
Mark scheme for Question 17 [2 marks]
Question 17[2 marks]
Answer or workingMarks
3x - 6 < 15 oe (expand the bracket correctly)M1
x < 7A1cao
Mark scheme for Question 18 [2 marks]
Question 18[2 marks]
Answer or workingMarks
sin30 = 1/2 and cos60 = 1/2 both seen or usedM1
1A1cao
Mark scheme for Question 19 [2 marks]
Question 19[2 marks]
Answer or workingMarks
x = 4B1
y = 2 (oe as a coordinate pair)B1
Final answer: x = 4, y = 2
Mark scheme for Question 20 [2 marks]
Question 20[2 marks]
Answer or workingMarks
converts distances to a comparable form, e.g. as ordinary numbers 360, 90, 1400M1oe
Q, P, R cao, all three in correct order (nearest first)A1
Final answer: Star Q, Star P, Star R
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
x = 2B1
y = 1 (oe as a coordinate pair)B1
Final answer: x = 2, y = 1
Mark scheme for Question 22 [2 marks]
Question 22[2 marks]
Answer or workingMarks
2 x 6 (= 12) seenM1oe
15A1cao
Mark scheme for Question 23 [2 marks]
Question 23[2 marks]
Answer or workingMarks
3^3 = 27 seen, or index d^6 seenM1
27d^6A1cao
Mark scheme for Question 24 [2 marks]
Question 24[2 marks]
Answer or workingMarks
x = -2B1
y = -3 (oe as a coordinate pair)B1
Final answer: x = -2, y = -3
Mark scheme for Question 25 [2 marks]
Question 25[2 marks]
Answer or workingMarks
23 cmB1cao
oe: it could be an unusual/faster-growing variety, a measurement error, or an outlier that does not represent the typical plant in the groupB1
Final answer: 23 cm | It may be an unusually tall or fast-growing plant, a different variety, or a measurement error - a possible outlier.
Mark scheme for Question 26 [3 marks]
Question 26[3 marks]
Answer or workingMarks
x = 0.512512512... and 1000x = 512.512512... writtenM1
subtracts to get 999x = 512, dependent on M1dM1
512/999 cao (already in simplest form)A1
Final answer: 512/999
Mark scheme for Question 27 [4 marks]
Question 27[4 marks]
Answer or workingMarks
k = 90B1
substitutes n = 9 into D = 90/n (ft their k)M1
10 daysA1cao
any sensible practical limitation, e.g. there may not be enough space or tools for all the builders to work efficiently at the same time, so the time cannot keep decreasing indefinitelyB1oe
Final answer: k = 90 | 10 days | e.g. with very many builders there is not enough space or materials for them all to work efficiently, so productivity per builder falls and the model breaks down
Mark scheme for Question 28 [4 marks]
Question 28[4 marks]
Answer or workingMarks
(x + 7)^2 - 49 + 9 = 0 oe, correct completed square set to zeroM1
(x + 7)^2 = 40 (dep. on previous M1)M1
x + 7 = +/- sqrt(40), condone unsimplified surdM1
x = -7 + 2sqrt(10) or x = -7 - 2sqrt(10) oe, both fully simplifiedA1cao
Final answer: x = -7 + 2sqrt(10) or x = -7 - 2sqrt(10)
Mark scheme for Question 29 [4 marks]
Question 29[4 marks]
Answer or workingMarks
finds k = 12/sqrt(16) (= 12/4)M1oe
y = 3sqrt(x)A1oe
substitutes x = 25: y = 3sqrt(25)M1
y = 15A1cao
Final answer: y = 3sqrt(x) | y = 15
Mark scheme for Question 30 [3 marks]
Question 30[3 marks]
Answer or workingMarks
10 * 360 (= 3600), using sum of exterior angles = 360M1
(n - 2) * 180 = 3600 leading to n - 2 = 20M1
n = 22A1cao
Final answer: 22 sides
Mark scheme for Question 31 [3 marks]
Question 31[3 marks]
Answer or workingMarks
sqrt(x^3) written as x^(3/2)M1
indices subtracted: 3/2 - 1/4M1
x^(5/4) oe (accept x^1.25)A1
Final answer: x^(5/4)
Mark scheme for Question 32 [3 marks]
Question 32[3 marks]
Answer or workingMarks
3x + 8 = 5x - 32 oe (equating tangent-chord angle to angle in alternate segment)M1
x = 20A1cao
68 degrees cao (ft their x)B1
Final answer: x = 20 | 68 degrees
Mark scheme for Question 33 [4 marks]
Question 33[4 marks]
Answer or workingMarks
multiplies both sides by (3 - n), e.g. m(3 - n) = 4n + 5M1
expands the bracket, e.g. 3m - mn = 4n + 5M1
collects all terms in n on one side and factorises, e.g. 3m - 5 = n(4 + m), dependent on the previous method markdM1
correct rearrangement with all steps shown leading to n = (3m - 5)/(m + 4)A1cso
Final answer: n = (3m - 5)/(m + 4) (printed answer, shown)
Mark scheme for Question 34 [4 marks]
Question 34[4 marks]
Answer or workingMarks
maximum = 1B1
minimum = -3B1
(0, 1)B1
360B1
Final answer: Maximum = 1, minimum = -3 | (0, 1) | 360 degrees
Mark scheme for Question 35 [4 marks]
Question 35[4 marks]
Answer or workingMarks
96 degreesB1cao
identify that the angle at the centre theorem applies to the reflex angle AOCM1
132 degreesA1cao
reason: the angle at the centre is twice the angle at the circumference, subtended by the same (major) arc ACB1oe
Final answer: 96 degrees | 132 degrees
Mark scheme for Question 36 [5 marks]
Question 36[5 marks]
Answer or workingMarks
x + x^2 + (2x + 1) + 3 = 44 oe (correct sum set equal to 44)M1
cso, correctly rearranged to x^2 + 3x - 40 = 0A1
(x + 8)(x - 5) = 0 oe (correct factorisation, or correct use of the quadratic formula)M1
x = 5, rejecting x = -8 since a number of members cannot be negativeA1
30/44 oe (= 15/22), ft from part (b)B1
Final answer: x^2 + 3x - 40 = 0 (shown) | x = 5 | 30/44 = 15/22