Higher Tier - Set A, Paper 3

Exam Structure Set A: Higher Paper 3

An 80-mark, 90-minute calculator paper using the Edexcel 1MA1 paper structure as its reference.

25 questions - 80 marks - calculator allowed

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Questions

Question 1 [1 marks]

Indices and Standard Form

Write the number 45000 in standard form.

Question 2 [3 marks]

Quadratics

Factorise fully 3x^2 + 6x - 45

Question 3 [5 marks]

Graphs and Coordinates

The graph of y = x^3 is to be drawn for -2 <= x <= 2.

Complete the table of values for y = x^3. x : -2 , -1 , 0 , 1 , 2 y : -8 , _ , 0 , _ , 8

On the grid, plot the points from your table and join them with a smooth curve.

Write down the coordinates of the point where the curve crosses the y-axis.

Question 4 [1 marks]

Number and Calculation

Two offcuts of skirting board have lengths a = 14 cm and b = 9 cm, each measured correct to the nearest cm. Find the upper bound of a + b.

Question 5 [2 marks]

Statistics and Probability

24 pupils were asked how many siblings they have. One frequency, a, is missing from the table. Number of siblings (x): 0, 1, 2, 3 Frequency (f): 5, a, 6, 2 Total number of pupils = 24 Find the value of a.

Question 6 [2 marks]

Angles and Geometrical Reasoning

Fatima is making a scale drawing of a triangular field using a scale of 1 cm to 20 m. One side of the field is 130 m long.

Question 7 [2 marks]

Sequences

Work out an expression for the nth term of the sequence 1, 6, 15, 28.

Question 8 [2 marks]

Number and Calculation

Ffion uses her calculator to work out 4.5 x 3.2. She then uses the ANS key to subtract 2.6 from this answer. Work out her final result.

Question 9 [2 marks]

Angles and Geometrical Reasoning

A quadrilateral ABCD has angle A = 72 degrees, angle B = 99 degrees, angle C = 107 degrees and angle D = y.

Work out the size of angle y.

Give a reason for your answer to part (a).

Question 10 [3 marks]

Number and Calculation

A recipe for 8 people uses 3.85 kg of flour. By rounding suitable values to 1 significant figure, estimate the amount of flour needed for 31 people.

Question 11 [3 marks]

Area, Volume and Measures

A model car is made using a scale of 1 : 24. The real car has a length of 4.8 m.

Question 12 [3 marks]

Linear Algebra

n is an integer such that -2 <= n < 5.

List all the possible values of n.

Write down the smallest possible value of n.

Question 13 [3 marks]

Ratio and Proportion

A recipe uses flour and sugar in the ratio 5:2. Anna wants to make a batch using 800 g of flour. Work out how much sugar she must use.

Question 14 [3 marks]

Pythagoras and Trigonometry

Point A has coordinates (2, 3) and point B has coordinates (7, 11). Work out the distance AB. Give your answer correct to 3 significant figures.

Question 15 [3 marks]

Angles and Geometrical Reasoning

The plan of a solid, drawn on a centimetre grid, is an L-shape made from 5 unit squares, as shown. Every position in the plan has a stack of cubes exactly 3 cubes tall.

How many unit squares make up the plan?

Work out the total number of cubes in the solid.

Question 16 [3 marks]

Ratio and Proportion

A shop sells a jacket at 35% off the original price. The sale price is £78. Work out the original price of the jacket. Give your answer to the nearest 10p.

Question 17 [3 marks]

Angles and Geometrical Reasoning

OABC is a parallelogram, with vertices in order. OA = a and OC = c.

Find OB in terms of a and c.

Find CA in terms of a and c.

Question 18 [4 marks]

Fractions, Decimals and Percentages

A phone was sold for £306 after a 15% discount was applied. Lorraine says the original price was £360. Is she correct? Show your working.

Question 19 [4 marks]

Indices and Standard Form

Solve each of the following equations.

6^x = 216

7^(2x-1) = 343

Question 20 [7 marks]

Quadratics

The graph of y = x^2 + 2x - 3 is to be drawn for -4 <= x <= 2.

Complete the table of values for y = x^2 + 2x - 3. x : -4 , -3 , -2 , -1 , 0 , 1 , 2 y : _ , _ , _ , _ , _ , _ , _

Draw the graph of y = x^2 + 2x - 3 for -4 <= x <= 2.

Use the graph to write down the solutions of x^2 + 2x - 3 = 0.

Write down the coordinates of the minimum point of the graph.

Question 21 [4 marks]

Graphs and Coordinates

Find the equation of the straight line that is perpendicular to y = (1/2)x + 4 and passes through the point (3, -1). Give your answer in the form y = mx + c.

Question 22 [2 marks]

Angles and Geometrical Reasoning

Point S has coordinates (2, 2) and maps to the image point S'(-2, -2) under an enlargement with scale factor -1. Find the coordinates of the centre of enlargement.

Question 23 [4 marks]

Graphs and Coordinates

A curve y = r(x) passes through the point (8, 3).

After the transformation y = r(x) + c, the image of this point is (8, -5). Find the value of c.

The curve y = r(kx) has an image point (2, 3) that corresponds to (8, 3) on y = r(x). Find the value of k.

Question 24 [5 marks]

Indices and Standard Form

A student writes down the statement sqrt(16) + sqrt(9) = sqrt(16 + 9).

Show, by evaluating both sides, that the statement above is not correct.

By simplifying sqrt(20) + sqrt(5) and sqrt(20 + 5) separately, show that sqrt(a) + sqrt(b) is not equal to sqrt(a + b) in general.

Question 25 [6 marks]

Sequences

Here are the first four terms of a quadratic sequence. 23, 18, 11, 2

Show that the second difference of the sequence is -2.

Find an expression, in terms of n, for the nth term of the sequence.

Work out the 8th term of the sequence.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
4.5 x 10^4B1oe
Mark scheme for Question 2 [3 marks]
Question 2[3 marks]
Answer or workingMarks
takes out common factor of 3: 3(x^2 + 2x - 15)M1
identifies a pair of numbers with sum 2 and product -15 (5 and -3)M1
3(x + 5)(x - 3) cao, fully factorisedA1
Final answer: 3(x + 5)(x - 3)
Mark scheme for Question 3 [5 marks]
Question 3[5 marks]
Answer or workingMarks
y = -1 at x = -1B1
y = 1 at x = 1B1
all 5 points plotted correctly ft from tableB1
smooth s-shaped curve drawn through all points, not a series of straight linesB1
(0, 0)B1cao
Final answer: x=-1: -1, x=1: 1 | Smooth increasing s-shaped curve through the 5 points | (0, 0)
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
24 (cm)B1cao
Final answer: 24 cm
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
5 + 6 + 2 (= 13) oe, or 24 - 13M1
11A1cao
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
130 / 20M1oe
6.5 cmA1cao
Mark scheme for Question 7 [2 marks]
Question 7[2 marks]
Answer or workingMarks
second differences 5, 9, 13 so second difference = 4 and a = 2 (2a = 4)M1oe
nth term = 2n^2 - nA1cao
Final answer: 2n^2 - n
Mark scheme for Question 8 [2 marks]
Question 8[2 marks]
Answer or workingMarks
4.5 x 3.2 = 14.4 seen (or correct use of ANS shown)M1
11.8A1cao
Mark scheme for Question 9 [2 marks]
Question 9[2 marks]
Answer or workingMarks
82 degreesB1cao
angles in a quadrilateral sum to 360 degreesB1oe
Final answer: 82 degrees | Angles in a quadrilateral add up to 360 degrees.
Mark scheme for Question 10 [3 marks]
Question 10[3 marks]
Answer or workingMarks
rounding 3.85 to 4 and 31 to 30M1
dep, 4 x (30 / 8)M1
15 (kg), awrt 15A1
Final answer: 15 kg
Mark scheme for Question 11 [3 marks]
Question 11[3 marks]
Answer or workingMarks
4.8 m converted to 480 cmM1oe
480 / 24M1
20 (cm)A1cao
Final answer: 20 cm
Mark scheme for Question 12 [3 marks]
Question 12[3 marks]
Answer or workingMarks
-2 correctly included and 5 correctly excluded, at least 5 correct values shownM1
-2, -1, 0, 1, 2, 3, 4 oe cao, no extra or missing valuesA1
-2 cao, ft from their list in part (a)B1
Final answer: -2, -1, 0, 1, 2, 3, 4 | -2
Mark scheme for Question 13 [3 marks]
Question 13[3 marks]
Answer or workingMarks
find one part: 800 divided by 5 = 160 g (method shown)M1
multiply one part by 2 to find sugar: 160 * 2M1
320 gA1cao
Mark scheme for Question 14 [3 marks]
Question 14[3 marks]
Answer or workingMarks
(7-2)^2 + (11-3)^2 oe (= 89)M1
sqrt(their 89)M1
awrt 9.43A1
Final answer: 9.43 (3 s.f.)
Mark scheme for Question 15 [3 marks]
Question 15[3 marks]
Answer or workingMarks
5B1cao
5 x 3M1
15A1cao
Final answer: 5 | 15
Mark scheme for Question 16 [3 marks]
Question 16[3 marks]
Answer or workingMarks
use 65% = 78, method: 78 / 0.65 or equivalentM1
original price £120.00A1cao
answer given to nearest 10p (£120.00) or shown explicitlyB1
Final answer: £120.00 (£120.00). The original price is £120.00. (78 / 0.65 = 120.0). Working check: 35% of 120 = 42; 120 - 42 = 78.
Mark scheme for Question 17 [3 marks]
Question 17[3 marks]
Answer or workingMarks
recognises AB = OC = c (opposite sides of a parallelogram) and OB = OA + ABM1
a + cA1cao
a - cB1cao
Final answer: OB = a + c | CA = a - c
Mark scheme for Question 18 [4 marks]
Question 18[4 marks]
Answer or workingMarks
calculate original as 306/0.85 or apply reverse percentM1
360A1cao
state whether Lorraine is correct with calculation or counterexampleM1
conclusion: Lorraine is correct (or equivalent statement)A1cao
Final answer: £360. Lorraine is correct.
Mark scheme for Question 19 [4 marks]
Question 19[4 marks]
Answer or workingMarks
x = 3B1cao
343 = 7^3 oe seenM1
2x - 1 = 3M1oe
x = 2A1cao
Final answer: x = 3 | x = 2
Mark scheme for Question 20 [7 marks]
Question 20[7 marks]
Answer or workingMarks
at least 5 of the 7 y-values correctB1
all 7 y-values correctB1
all points plotted correctly ft from tableB1
smooth u-shaped curve drawn through all pointsB1
x = -3B1
x = 1B1
(-1, -4)B1
Final answer: 5, 0, -3, -4, -3, 0, 5 | Smooth u-shaped parabola, minimum point at (-1,-4) | x = -3 and x = 1 | (-1, -4)
Mark scheme for Question 21 [4 marks]
Question 21[4 marks]
Answer or workingMarks
uses m1 x m2 = -1 to find the perpendicular gradientM1
gradient = -2A1cao
substitutes (3, -1) and m = -2 into y = mx + c to find cM1dep
y = -2x + 5 oeA1cao
Final answer: y = -2x + 5
Mark scheme for Question 22 [2 marks]
Question 22[2 marks]
Answer or workingMarks
recognises that the centre is the midpoint of S and S' when k = -1M1oe
(0, 0)A1cao
Mark scheme for Question 23 [4 marks]
Question 23[4 marks]
Answer or workingMarks
3 + c = -5M1oe
c = -8A1cao
8 / k = 2M1oe
k = 4A1cao
Final answer: c = -8; k = 4
Mark scheme for Question 24 [5 marks]
Question 24[5 marks]
Answer or workingMarks
left-hand side evaluated: sqrt(16) + sqrt(9) = 4 + 3 = 7B1
right-hand side evaluated: sqrt(16 + 9) = sqrt(25) = 5, and 7 is not equal to 5 so the statement is incorrectB1
sqrt(20) = 2sqrt(5), so sqrt(20) + sqrt(5) = 3sqrt(5)M1
sqrt(20 + 5) = sqrt(25) = 5 evaluatedA1
cso - since 3sqrt(5) is not equal to 5, confirms sqrt(a) + sqrt(b) is not equal to sqrt(a + b) in generalA1
Final answer: (a) 7 is not equal to 5 (b) 3sqrt(5) is not equal to 5
Mark scheme for Question 25 [6 marks]
Question 25[6 marks]
Answer or workingMarks
first differences -5, -7, -9 shown, giving a second difference of -2B1cso
coefficient of n^2 = half the second difference = -1 identifiedM1
forms and solves simultaneous equations (or equivalent) for the remaining termsM1
-n^2 - 2n + 26 oeA1cao
substitutes n=8 into their expression, e.g. -(8)^2 - 2(8) + 26M1
-54 caoA1ft
Final answer: -2 (shown) | -n^2 - 2n + 26 | -54