Higher Tier - Set B, Paper 1

Exam Structure Set B: Higher Paper 1

An 80-mark, 90-minute non-calculator paper using the Edexcel 1MA1 paper structure as its reference.

28 questions - 80 marks

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Questions

Question 1 [1 marks]

Ratio and Proportion

Simplify the ratio 35:14.

Question 2 [1 marks]

Linear Algebra

Solve 8 + x = 15

Question 3 [2 marks]

Sequences

Here are the first four terms of a sequence. 2, 6, 10, 14

Write down the next two terms of the sequence.

Describe, in words, the term-to-term rule for the sequence.

Question 4 [2 marks]

Graphs and Coordinates

A line has equation y = -2x + 7.

Write down the gradient of the line.

Write down the coordinates of the point where the line crosses the y-axis.

Question 5 [1 marks]

Angles and Geometrical Reasoning

Point U has coordinates (-3, 5). Write down the coordinates of the image of U after a rotation of 180 degrees about the origin.

Question 6 [1 marks]

Indices and Standard Form

Simplify sqrt(50) fully.

Question 7 [2 marks]

Number and Calculation

Without using a calculator, estimate the value of sqrt(146). Show working to support your answer.

Question 8 [2 marks]

Indices and Standard Form

Simplify 20y^9 / 5y^3.

Question 9 [2 marks]

Area, Volume and Measures

Two similar triangles have corresponding sides in the ratio 5:8. A side of the smaller triangle is 15 cm. Work out the length of the corresponding side in the larger triangle.

Question 10 [2 marks]

Graphs and Coordinates

A line has equation 2y = 6x - 4.

Rearrange the equation into the form y = mx + c.

State the gradient of the line.

Question 11 [2 marks]

Statistics and Probability

A scatter graph shows the number of gym sessions attended per month (x) and the kilograms of weight lost that month (y), for data collected between 1 and 12 sessions per month. Aisha uses the line of best fit to estimate the weight lost by someone who attends 40 sessions in a month. Explain why this estimate would not be reliable.

Question 12 [3 marks]

Pythagoras and Trigonometry

Show that in any right-angled triangle the tangent of an acute angle is equal to the sine of that angle divided by the cosine of that angle. Give a short explanation using side lengths. This is a 'show that' question; all marks are for method and explanation.

Show that tan theta = sin theta / cos theta using opposite, adjacent and hypotenuse labels.

Question 13 [3 marks]

Angles and Geometrical Reasoning

Work out the value of x, then find the size of each angle.

Question 14 [3 marks]

Quadratics

Find the vertex (turning point) and minimum value of y = 2x^2 - 8x + 5.

Question 15 [3 marks]

Fractions, Decimals and Percentages

A class completed 5/8 of a test. Later, 3/10 of the pupils who had not completed it finished the test. What fraction of the class have now completed the test?

Question 16 [4 marks]

Quadratics

Write 6x^2 - 24x + 11 in the form a(x + p)^2 + q, stating the values of a, p and q.

Question 17 [4 marks]

Fractions, Decimals and Percentages

Show that increasing a number by 20% and then decreasing the result by 20% does not return to the original number. Use an algebraic approach with n as the original number and give the final expression in terms of n.

Question 18 [5 marks]

Angles and Geometrical Reasoning

On a diagram, A, B and C are points with position vectors relative to origin O: OA = (2, 1), OB = ( -1, 3), OC = (5, 4). (a) Find the vector AB. (b) Show that the three points are not collinear by using vectors.

Show that A, B and C are not collinear by using vectors.

Question 19 [5 marks]

Linear Algebra

A car park charges according to the formula C = 2.50 + 1.20h, where C is the total cost in £ and h is the number of hours parked.

Make h the subject of the formula.

Sasha pays £8.50 to park her car. Work out how many hours she parked for.

Question 20 [6 marks]

Statistics and Probability

A holiday company surveyed 120 travellers. 70 of the travellers were adults and the rest were children. 45 of the adults travelled by plane and the rest of the adults travelled by coach. Of the children, 28 travelled by coach and the rest travelled by plane.

Use this information to draw and complete a two-way table showing adults and children against plane and coach.

One traveller is picked at random from all 120 travellers. Find the probability that the traveller is a child who travelled by plane.

Question 21 [2 marks]

Indices and Standard Form

(4 x 10^n) x (2 x 10^3) = 8 x 10^8 Find the value of n.

Question 22 [2 marks]

Statistics and Probability

In a capture-recapture study, some of the marks put on animals in the first sample fall off before the second sample is taken.

Question 23 [3 marks]

Angles and Geometrical Reasoning

TA is a tangent to a circle at the point A. AB and AC are chords of the circle. The angle between the tangent and the chord AB is (3x + 8) degrees. The angle in the alternate segment, angle ACB, is (5x - 32) degrees. Diagram: circle, tangent TA at A, chords AB and AC drawn, tangent-chord angle (3x + 8) degrees marked at A, angle ACB = (5x - 32) degrees marked at C in the alternate segment.

Use the alternate segment theorem to form an equation in x, and solve it to find the value of x.

Work out the size of angle ACB.

Question 24 [3 marks]

Linear Algebra

Solve (5x - 3) / 4 = (3x + 1) / 2 Show your working.

Question 25 [4 marks]

Statistics and Probability

The Venn diagram shows solar panels (S) and heat pumps (H) for the 48 houses on a street in Manchester. S only = 3y, H only = y, both S and H = 2y, and 12 houses have neither.

Form an equation in y and solve it.

A house is selected at random. Find P(S).

Question 26 [3 marks]

Graphs and Coordinates

The graph of y = cos(x - 90) is a transformation of y = cos x.

Describe fully the transformation from y = cos x to y = cos(x - 90).

By considering this transformation, or otherwise, write cos(x - 90) in terms of sin x.

Question 27 [4 marks]

Statistics and Probability

A cafe recorded the time, m minutes, that 26 + b customers spent queuing at the counter. One frequency, b, is unknown. Time, m (minutes): 0 < m <= 5, 5 < m <= 10, 10 < m <= 15, 15 < m <= 20 Frequency (f): 8, 12, b, 6 Given that the estimated mean queuing time is 10 minutes, find the value of b. You must show your working.

Question 28 [5 marks]

Angles and Geometrical Reasoning

Show that for three parallel lines cut by a single transversal, the angle between the transversal and the top line plus the angle between the transversal and the bottom line equals twice the angle between the transversal and the middle line. Give a short proof using algebra: let the acute angle at the middle intersection be a degrees, and express the other two in terms of a.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
5:2B1cao
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
x = 7B1cao
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
18 and 22 both correctB1oe
start at 2 and add 4 each timeB1oe
Final answer: 18, 22 | Start at 2 and add 4 each time (oe).
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
-2B1cao
(0, 7)B1cao
Final answer: -2 | (0, 7)
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
(3, -5)B1cao
Mark scheme for Question 6 [1 mark]
Question 6[1 mark]
Answer or workingMarks
5sqrt(2) oeB1cao
Final answer: 5sqrt(2)
Mark scheme for Question 7 [2 marks]
Question 7[2 marks]
Answer or workingMarks
identifying 144 = 12^2 (or 144 < 146 < 169) as the nearest square numberM1
12 (accept 12.0 to 12.2A1oe
Final answer: 12
Mark scheme for Question 8 [2 marks]
Question 8[2 marks]
Answer or workingMarks
coefficient 4 or index y^6 seenM1
4y^6A1cao
Mark scheme for Question 9 [2 marks]
Question 9[2 marks]
Answer or workingMarks
multiply 15 by scale factor 8/5 or show equivalent methodM1
24 cmA1cao
Final answer: 24 cm, because 15 x (8/5) = 24 (scale factor 8/5).
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
y = 3x - 2B1oe
3 ft from part (a)B1
Final answer: y = 3x - 2 | 3
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
40 sessions is outside the range of data collected (1 to 12), so this is extrapolationB1
the same trend/rate of weight loss may not continue that far beyond the data, e.g. there could be a natural limit to how much weight can be lost, or attending 40 sessions a month may not be realisticB1oe
Final answer: The estimate is unreliable because 40 sessions is far outside the data collected (1 to 12 sessions), so it involves extrapolation and the same trend may not continue.
Mark scheme for Question 12 [3 marks]
Question 12[3 marks]
Answer or workingMarks
state sin theta = opposite/hypotenuse and cos theta = adjacent/hypotenuseM1
divide sin theta by cos theta to get (opposite/hypotenuse)/(adjacent/hypotenuse) = opposite/adjacentM1
conclude tan theta = opposite/adjacent = sin theta / cos thetaA1cso
Final answer: tan theta = sin theta / cos theta
Mark scheme for Question 13 [3 marks]
Question 13[3 marks]
Answer or workingMarks
4x - 8 = 2x + 30 oe (alternate angles are equal)M1
x = 19A1cao
each angle = 68 degrees, ft from their xA1
Final answer: x = 19; each angle = 68 degrees
Mark scheme for Question 14 [3 marks]
Question 14[3 marks]
Answer or workingMarks
complete the square: 2(x^2 - 4x) + 5 = 2[(x - 2)^2 - 4] + 5 or equivalentM1
simplify to 2(x - 2)^2 - 3M1
vertex (2, -3) and minimum value -3A1cao
Final answer: Turning point at (2, -3); minimum value -3
Mark scheme for Question 15 [3 marks]
Question 15[3 marks]
Answer or workingMarks
find fraction remaining 1 - 5/8 = 3/8 and find 3/10 of that, 3/10 × 3/8M1
add new completions to original, e.g. 5/8 + 9/80M1
59/80A1cao
Mark scheme for Question 16 [4 marks]
Question 16[4 marks]
Answer or workingMarks
6(x^2 - 4x) + 11 seen, factor of 6 taken out correctlyM1
(x - 2)^2 seen within the bracketM1
6(x - 2)^2 - 24 + 11 correctly simplified (dep. on both M marks)A1
a = 6, p = -2, q = -13 all correct, fully simplified 6(x - 2)^2 - 13A1cao
Final answer: 6(x - 2)^2 - 13 (a = 6, p = -2, q = -13)
Mark scheme for Question 17 [4 marks]
Question 17[4 marks]
Answer or workingMarks
state after increase: n x 1.20 or 6/5 nM1
state after decrease: (n x 1.20) x 0.80 or (6/5 n) x 4/5M1
simplify to give (6/5 x 4/5) n = 24/25 nM1
conclude 24/25 n, not equal to n, therefore does not return to originalA1cso
Final answer: 24/25 n
Mark scheme for Question 18 [5 marks]
Question 18[5 marks]
Answer or workingMarks
Use AB = OB - OAM1
AB = ( -3, 2)A1cao
Compute AC = OC - OA = (3, 3) and note AB = ( -3, 2)M1
Attempt to find scalar t with AB = t*AC or AC = t*AB and show no single t fits both componentsM1
Conclude not collinear since components would need same ratio but -3/3 != 2/3A1
Final answer: (-3, 2) | AC = (3, 3), AB = ( -3, 2); no scalar t satisfies AB = t AC since -3/3 != 2/3, so points are not collinear.
Mark scheme for Question 19 [5 marks]
Question 19[5 marks]
Answer or workingMarks
subtracts 2.50 from both sides, e.g. C - 2.50 = 1.20hM1
h = (C - 2.50)/1.20 oeA1cao
substitutes C = 8.50 into the formula from part (a), ft, e.g. h = (8.50 - 2.50)/1.20M1
simplifies to h = 6/1.20M1oe
5 (hours)A1cao
Final answer: h = (C - 2.50)/1.20 | 5 hours
Mark scheme for Question 20 [6 marks]
Question 20[6 marks]
Answer or workingMarks
number of children = 50B1
adults who travelled by coach = 25B1
children who travelled by plane = 22B1
correct row and column totals throughout: coach total 53, plane total 67, grand total 120B1
22/120 oe, ft their (a)M1
11/60 caoA1ft
Final answer: Adults: plane 45, coach 25 (total 70). Children: plane 22, coach 28 (total 50). Totals: plane 67, coach 53 (grand total 120). | 11/60
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
multiplies coefficients, 4 x 2 = 8, matching the given coefficient, so equates powers of 10, giving n + 3 = 8M1
n = 5A1cao
Mark scheme for Question 22 [2 marks]
Question 22[2 marks]
Answer or workingMarks
fewer marked animals will be found/recaptured in the second sample, so m will be smaller than it should beB1
since N = n1 x n2 / m, a smaller value of m gives a larger value of N, so the population will be overestimatedB1
Final answer: The population would be overestimated, because m is too small.
Mark scheme for Question 23 [3 marks]
Question 23[3 marks]
Answer or workingMarks
3x + 8 = 5x - 32 oe (equating tangent-chord angle to angle in alternate segment)M1
x = 20A1cao
68 degrees cao (ft their x)B1
Final answer: x = 20 | 68 degrees
Mark scheme for Question 24 [3 marks]
Question 24[3 marks]
Answer or workingMarks
cross multiplies correctly, 2(5x - 3) = 4(3x + 1)M1oe
expands both sides and collects terms, 10x - 6 = 12x + 4 leading to -2x = 10dM1dep
x = -5A1cao
Mark scheme for Question 25 [4 marks]
Question 25[4 marks]
Answer or workingMarks
3y + y + 2y + 12 = 48 oe (correct equation formed)M1
6y = 36 (oe, correct simplification)M1
y = 6A1cao
30/48 oe (= 5/8), ft from part (a)B1
Final answer: y = 6 | 30/48 = 5/8
Mark scheme for Question 26 [3 marks]
Question 26[3 marks]
Answer or workingMarks
translation by vector (90, 0) (oe: 90 degrees to the right)B1
recognises shifted cosine graph matches the sine graphM1
sin xA1oe
Final answer: Translation by vector (90, 0) | cos(x - 90) = sin x
Mark scheme for Question 27 [4 marks]
Question 27[4 marks]
Answer or workingMarks
correct midpoints identified: 2.5, 7.5, 12.5, 17.5M1
sum(fx) = 20 + 90 + 12.5b + 105 (= 215 + 12.5b) oe, and sum(f) = 26 + bM1oe
(215 + 12.5b) / (26 + b) = 10 leading to 215 + 12.5b = 260 + 10b, dependent on both previous M marksdM1
18A1cao
Final answer: b = 18
Mark scheme for Question 28 [5 marks]
Question 28[5 marks]
Answer or workingMarks
recognise the top and middle lines are parallel and cut by the same transversalM1
state top acute angle = a, since corresponding angles between the top and middle lines are equalA1
recognise the middle and bottom lines are parallel and cut by the same transversalM1
state bottom acute angle = a, since corresponding angles between the middle and bottom lines are equalA1
conclude top + bottom = a + a = 2a = 2 x middle angle, as requiredA1cao
Final answer: Top + bottom = 2 x middle angle, since the single transversal makes equal corresponding angles (each = a) with all three parallel lines