Exam Structure Set B: Higher Paper 1
An 80-mark, 90-minute non-calculator paper using the Edexcel 1MA1 paper structure as its reference.
Questions
Question 1 [1 marks]
Ratio and Proportion
Simplify the ratio 35:14.
Question 2 [1 marks]
Linear Algebra
Solve 8 + x = 15
Question 3 [2 marks]
Sequences
Here are the first four terms of a sequence. 2, 6, 10, 14
Write down the next two terms of the sequence.
Describe, in words, the term-to-term rule for the sequence.
Question 4 [2 marks]
Graphs and Coordinates
A line has equation y = -2x + 7.
Write down the gradient of the line.
Write down the coordinates of the point where the line crosses the y-axis.
Question 5 [1 marks]
Angles and Geometrical Reasoning
Point U has coordinates (-3, 5). Write down the coordinates of the image of U after a rotation of 180 degrees about the origin.
Question 6 [1 marks]
Indices and Standard Form
Simplify sqrt(50) fully.
Question 7 [2 marks]
Number and Calculation
Without using a calculator, estimate the value of sqrt(146). Show working to support your answer.
Question 8 [2 marks]
Indices and Standard Form
Simplify 20y^9 / 5y^3.
Question 9 [2 marks]
Area, Volume and Measures
Two similar triangles have corresponding sides in the ratio 5:8. A side of the smaller triangle is 15 cm. Work out the length of the corresponding side in the larger triangle.
Question 10 [2 marks]
Graphs and Coordinates
A line has equation 2y = 6x - 4.
Rearrange the equation into the form y = mx + c.
State the gradient of the line.
Question 11 [2 marks]
Statistics and Probability
A scatter graph shows the number of gym sessions attended per month (x) and the kilograms of weight lost that month (y), for data collected between 1 and 12 sessions per month. Aisha uses the line of best fit to estimate the weight lost by someone who attends 40 sessions in a month. Explain why this estimate would not be reliable.
Question 12 [3 marks]
Pythagoras and Trigonometry
Show that in any right-angled triangle the tangent of an acute angle is equal to the sine of that angle divided by the cosine of that angle. Give a short explanation using side lengths. This is a 'show that' question; all marks are for method and explanation.
Show that tan theta = sin theta / cos theta using opposite, adjacent and hypotenuse labels.
Question 13 [3 marks]
Angles and Geometrical Reasoning
Work out the value of x, then find the size of each angle.
Question 14 [3 marks]
Quadratics
Find the vertex (turning point) and minimum value of y = 2x^2 - 8x + 5.
Question 15 [3 marks]
Fractions, Decimals and Percentages
A class completed 5/8 of a test. Later, 3/10 of the pupils who had not completed it finished the test. What fraction of the class have now completed the test?
Question 16 [4 marks]
Quadratics
Write 6x^2 - 24x + 11 in the form a(x + p)^2 + q, stating the values of a, p and q.
Question 17 [4 marks]
Fractions, Decimals and Percentages
Show that increasing a number by 20% and then decreasing the result by 20% does not return to the original number. Use an algebraic approach with n as the original number and give the final expression in terms of n.
Question 18 [5 marks]
Angles and Geometrical Reasoning
On a diagram, A, B and C are points with position vectors relative to origin O: OA = (2, 1), OB = ( -1, 3), OC = (5, 4). (a) Find the vector AB. (b) Show that the three points are not collinear by using vectors.
Show that A, B and C are not collinear by using vectors.
Question 19 [5 marks]
Linear Algebra
A car park charges according to the formula C = 2.50 + 1.20h, where C is the total cost in £ and h is the number of hours parked.
Make h the subject of the formula.
Sasha pays £8.50 to park her car. Work out how many hours she parked for.
Question 20 [6 marks]
Statistics and Probability
A holiday company surveyed 120 travellers. 70 of the travellers were adults and the rest were children. 45 of the adults travelled by plane and the rest of the adults travelled by coach. Of the children, 28 travelled by coach and the rest travelled by plane.
Use this information to draw and complete a two-way table showing adults and children against plane and coach.
One traveller is picked at random from all 120 travellers. Find the probability that the traveller is a child who travelled by plane.
Question 21 [2 marks]
Indices and Standard Form
(4 x 10^n) x (2 x 10^3) = 8 x 10^8 Find the value of n.
Question 22 [2 marks]
Statistics and Probability
In a capture-recapture study, some of the marks put on animals in the first sample fall off before the second sample is taken.
Question 23 [3 marks]
Angles and Geometrical Reasoning
TA is a tangent to a circle at the point A. AB and AC are chords of the circle. The angle between the tangent and the chord AB is (3x + 8) degrees. The angle in the alternate segment, angle ACB, is (5x - 32) degrees. Diagram: circle, tangent TA at A, chords AB and AC drawn, tangent-chord angle (3x + 8) degrees marked at A, angle ACB = (5x - 32) degrees marked at C in the alternate segment.
Use the alternate segment theorem to form an equation in x, and solve it to find the value of x.
Work out the size of angle ACB.
Question 24 [3 marks]
Linear Algebra
Solve (5x - 3) / 4 = (3x + 1) / 2 Show your working.
Question 25 [4 marks]
Statistics and Probability
The Venn diagram shows solar panels (S) and heat pumps (H) for the 48 houses on a street in Manchester. S only = 3y, H only = y, both S and H = 2y, and 12 houses have neither.
Form an equation in y and solve it.
A house is selected at random. Find P(S).
Question 26 [3 marks]
Graphs and Coordinates
The graph of y = cos(x - 90) is a transformation of y = cos x.
Describe fully the transformation from y = cos x to y = cos(x - 90).
By considering this transformation, or otherwise, write cos(x - 90) in terms of sin x.
Question 27 [4 marks]
Statistics and Probability
A cafe recorded the time, m minutes, that 26 + b customers spent queuing at the counter. One frequency, b, is unknown. Time, m (minutes): 0 < m <= 5, 5 < m <= 10, 10 < m <= 15, 15 < m <= 20 Frequency (f): 8, 12, b, 6 Given that the estimated mean queuing time is 10 minutes, find the value of b. You must show your working.
Question 28 [5 marks]
Angles and Geometrical Reasoning
Show that for three parallel lines cut by a single transversal, the angle between the transversal and the top line plus the angle between the transversal and the bottom line equals twice the angle between the transversal and the middle line. Give a short proof using algebra: let the acute angle at the middle intersection be a degrees, and express the other two in terms of a.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 5:2 | B1cao |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| x = 7 | B1cao |
| Question 3[2 marks] | |
|---|---|
| Answer or working | Marks |
| 18 and 22 both correct | B1oe |
| start at 2 and add 4 each time | B1oe |
| Final answer: 18, 22 | Start at 2 and add 4 each time (oe). | |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| -2 | B1cao |
| (0, 7) | B1cao |
| Final answer: -2 | (0, 7) | |
| Question 5[1 mark] | |
|---|---|
| Answer or working | Marks |
| (3, -5) | B1cao |
| Question 6[1 mark] | |
|---|---|
| Answer or working | Marks |
| 5sqrt(2) oe | B1cao |
| Final answer: 5sqrt(2) | |
| Question 7[2 marks] | |
|---|---|
| Answer or working | Marks |
| identifying 144 = 12^2 (or 144 < 146 < 169) as the nearest square number | M1 |
| 12 (accept 12.0 to 12.2 | A1oe |
| Final answer: 12 | |
| Question 8[2 marks] | |
|---|---|
| Answer or working | Marks |
| coefficient 4 or index y^6 seen | M1 |
| 4y^6 | A1cao |
| Question 9[2 marks] | |
|---|---|
| Answer or working | Marks |
| multiply 15 by scale factor 8/5 or show equivalent method | M1 |
| 24 cm | A1cao |
| Final answer: 24 cm, because 15 x (8/5) = 24 (scale factor 8/5). | |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| y = 3x - 2 | B1oe |
| 3 ft from part (a) | B1 |
| Final answer: y = 3x - 2 | 3 | |
| Question 11[2 marks] | |
|---|---|
| Answer or working | Marks |
| 40 sessions is outside the range of data collected (1 to 12), so this is extrapolation | B1 |
| the same trend/rate of weight loss may not continue that far beyond the data, e.g. there could be a natural limit to how much weight can be lost, or attending 40 sessions a month may not be realistic | B1oe |
| Final answer: The estimate is unreliable because 40 sessions is far outside the data collected (1 to 12 sessions), so it involves extrapolation and the same trend may not continue. | |
| Question 12[3 marks] | |
|---|---|
| Answer or working | Marks |
| state sin theta = opposite/hypotenuse and cos theta = adjacent/hypotenuse | M1 |
| divide sin theta by cos theta to get (opposite/hypotenuse)/(adjacent/hypotenuse) = opposite/adjacent | M1 |
| conclude tan theta = opposite/adjacent = sin theta / cos theta | A1cso |
| Final answer: tan theta = sin theta / cos theta | |
| Question 13[3 marks] | |
|---|---|
| Answer or working | Marks |
| 4x - 8 = 2x + 30 oe (alternate angles are equal) | M1 |
| x = 19 | A1cao |
| each angle = 68 degrees, ft from their x | A1 |
| Final answer: x = 19; each angle = 68 degrees | |
| Question 14[3 marks] | |
|---|---|
| Answer or working | Marks |
| complete the square: 2(x^2 - 4x) + 5 = 2[(x - 2)^2 - 4] + 5 or equivalent | M1 |
| simplify to 2(x - 2)^2 - 3 | M1 |
| vertex (2, -3) and minimum value -3 | A1cao |
| Final answer: Turning point at (2, -3); minimum value -3 | |
| Question 15[3 marks] | |
|---|---|
| Answer or working | Marks |
| find fraction remaining 1 - 5/8 = 3/8 and find 3/10 of that, 3/10 × 3/8 | M1 |
| add new completions to original, e.g. 5/8 + 9/80 | M1 |
| 59/80 | A1cao |
| Question 16[4 marks] | |
|---|---|
| Answer or working | Marks |
| 6(x^2 - 4x) + 11 seen, factor of 6 taken out correctly | M1 |
| (x - 2)^2 seen within the bracket | M1 |
| 6(x - 2)^2 - 24 + 11 correctly simplified (dep. on both M marks) | A1 |
| a = 6, p = -2, q = -13 all correct, fully simplified 6(x - 2)^2 - 13 | A1cao |
| Final answer: 6(x - 2)^2 - 13 (a = 6, p = -2, q = -13) | |
| Question 17[4 marks] | |
|---|---|
| Answer or working | Marks |
| state after increase: n x 1.20 or 6/5 n | M1 |
| state after decrease: (n x 1.20) x 0.80 or (6/5 n) x 4/5 | M1 |
| simplify to give (6/5 x 4/5) n = 24/25 n | M1 |
| conclude 24/25 n, not equal to n, therefore does not return to original | A1cso |
| Final answer: 24/25 n | |
| Question 18[5 marks] | |
|---|---|
| Answer or working | Marks |
| Use AB = OB - OA | M1 |
| AB = ( -3, 2) | A1cao |
| Compute AC = OC - OA = (3, 3) and note AB = ( -3, 2) | M1 |
| Attempt to find scalar t with AB = t*AC or AC = t*AB and show no single t fits both components | M1 |
| Conclude not collinear since components would need same ratio but -3/3 != 2/3 | A1 |
| Final answer: (-3, 2) | AC = (3, 3), AB = ( -3, 2); no scalar t satisfies AB = t AC since -3/3 != 2/3, so points are not collinear. | |
| Question 19[5 marks] | |
|---|---|
| Answer or working | Marks |
| subtracts 2.50 from both sides, e.g. C - 2.50 = 1.20h | M1 |
| h = (C - 2.50)/1.20 oe | A1cao |
| substitutes C = 8.50 into the formula from part (a), ft, e.g. h = (8.50 - 2.50)/1.20 | M1 |
| simplifies to h = 6/1.20 | M1oe |
| 5 (hours) | A1cao |
| Final answer: h = (C - 2.50)/1.20 | 5 hours | |
| Question 20[6 marks] | |
|---|---|
| Answer or working | Marks |
| number of children = 50 | B1 |
| adults who travelled by coach = 25 | B1 |
| children who travelled by plane = 22 | B1 |
| correct row and column totals throughout: coach total 53, plane total 67, grand total 120 | B1 |
| 22/120 oe, ft their (a) | M1 |
| 11/60 cao | A1ft |
| Final answer: Adults: plane 45, coach 25 (total 70). Children: plane 22, coach 28 (total 50). Totals: plane 67, coach 53 (grand total 120). | 11/60 | |
| Question 21[2 marks] | |
|---|---|
| Answer or working | Marks |
| multiplies coefficients, 4 x 2 = 8, matching the given coefficient, so equates powers of 10, giving n + 3 = 8 | M1 |
| n = 5 | A1cao |
| Question 22[2 marks] | |
|---|---|
| Answer or working | Marks |
| fewer marked animals will be found/recaptured in the second sample, so m will be smaller than it should be | B1 |
| since N = n1 x n2 / m, a smaller value of m gives a larger value of N, so the population will be overestimated | B1 |
| Final answer: The population would be overestimated, because m is too small. | |
| Question 23[3 marks] | |
|---|---|
| Answer or working | Marks |
| 3x + 8 = 5x - 32 oe (equating tangent-chord angle to angle in alternate segment) | M1 |
| x = 20 | A1cao |
| 68 degrees cao (ft their x) | B1 |
| Final answer: x = 20 | 68 degrees | |
| Question 24[3 marks] | |
|---|---|
| Answer or working | Marks |
| cross multiplies correctly, 2(5x - 3) = 4(3x + 1) | M1oe |
| expands both sides and collects terms, 10x - 6 = 12x + 4 leading to -2x = 10 | dM1dep |
| x = -5 | A1cao |
| Question 25[4 marks] | |
|---|---|
| Answer or working | Marks |
| 3y + y + 2y + 12 = 48 oe (correct equation formed) | M1 |
| 6y = 36 (oe, correct simplification) | M1 |
| y = 6 | A1cao |
| 30/48 oe (= 5/8), ft from part (a) | B1 |
| Final answer: y = 6 | 30/48 = 5/8 | |
| Question 26[3 marks] | |
|---|---|
| Answer or working | Marks |
| translation by vector (90, 0) (oe: 90 degrees to the right) | B1 |
| recognises shifted cosine graph matches the sine graph | M1 |
| sin x | A1oe |
| Final answer: Translation by vector (90, 0) | cos(x - 90) = sin x | |
| Question 27[4 marks] | |
|---|---|
| Answer or working | Marks |
| correct midpoints identified: 2.5, 7.5, 12.5, 17.5 | M1 |
| sum(fx) = 20 + 90 + 12.5b + 105 (= 215 + 12.5b) oe, and sum(f) = 26 + b | M1oe |
| (215 + 12.5b) / (26 + b) = 10 leading to 215 + 12.5b = 260 + 10b, dependent on both previous M marks | dM1 |
| 18 | A1cao |
| Final answer: b = 18 | |
| Question 28[5 marks] | |
|---|---|
| Answer or working | Marks |
| recognise the top and middle lines are parallel and cut by the same transversal | M1 |
| state top acute angle = a, since corresponding angles between the top and middle lines are equal | A1 |
| recognise the middle and bottom lines are parallel and cut by the same transversal | M1 |
| state bottom acute angle = a, since corresponding angles between the middle and bottom lines are equal | A1 |
| conclude top + bottom = a + a = 2a = 2 x middle angle, as required | A1cao |
| Final answer: Top + bottom = 2 x middle angle, since the single transversal makes equal corresponding angles (each = a) with all three parallel lines | |