Foundation Tier - Grade 5 A

Foundation Grade 5 Mini Test A

A 45-minute, 40-mark test using only authored grade 5 questions, focused on ratio, indices, algebra, graphs and quadratics.

12 questions - 40 marks - calculator allowed

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Questions

Question 1 [1 marks]

Indices and Standard Form

Work out the value of 5^-1. Give your answer as a fraction.

Question 2 [1 marks]

Graphs and Coordinates

Write down the equation of the straight line that is parallel to the y-axis and passes through the point (5, 2).

Question 3 [2 marks]

Ratio and Proportion

Simplify the ratio 6x:15x fully (x is not zero), and hence write the first quantity as a fraction of the second quantity.

Question 4 [2 marks]

Linear Algebra

Make m the subject of the formula: k = 3m + 2n

Question 5 [2 marks]

Graphs and Coordinates

Show that the line with equation 3y = 6x + 9 is parallel to the line with equation y = 2x - 1.

Question 6 [3 marks]

Linear Algebra

Solve the simultaneous equations: 1.5x + y = 9 0.5x + y = 5

Question 7 [3 marks]

Quadratics

Solve 9x^2 - 16 = 0

Question 8 [10 marks]

Graphs and Coordinates

A train leaves Uppington station at 09:00. It travels 120 km to Lowbridge station, arriving at 10:30. It waits at Lowbridge for 20 minutes, then travels back to Uppington, non-stop, arriving at 12:25.

Draw a distance-time graph to show the train's journey.

Calculate the average speed of the train on the outward journey, in km/h.

Calculate the average speed of the train on the return journey, in km/h. Give your answer correct to 1 decimal place.

Calculate the average speed of the train for the whole journey (Uppington to Lowbridge and back to Uppington), including the time spent waiting at Lowbridge. Give your answer correct to 3 significant figures.

Question 9 [5 marks]

Linear Algebra

Solve the compound inequality 1 <= 2x + 1 < 7. Show working and give the final range for x.

Question 10 [6 marks]

Ratio and Proportion

A liquid has mass 250 g and occupies 200 cm^3. Part (a): Calculate the density of the liquid in kg/m^3. Part (b): Give the density in g/cm^3. Part (c): What mass, in grams, of this liquid would fill 1.5 litres?

Calculate the density in kg/m^3.

Question 11 [3 marks]

Linear Algebra

The circumference of a circle of radius r is given by the formula C = 2 * pi * r

Rearrange the formula to make r the subject.

A circular pond has a circumference of 18.84 metres. Work out the radius of the pond. Give your answer correct to 1 decimal place.

Question 12 [2 marks]

Indices and Standard Form

A student's working to simplify 4^3 x 4^2 is shown below. 4^3 x 4^2 = 4^6 = 4096 Identify the error in the student's working, and write down the correct answer.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
1/5B1oe
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
x = 5B1cao
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
divides both parts by common factor 3x to get 2:5M1
2/5A1cao
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
subtracts 2n from both sides, e.g. k - 2n = 3mM1
m = (k - 2n)/3 oeA1cao
Final answer: m = (k - 2n)/3
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
rearranges 3y = 6x + 9 to y = 2x + 3M1oe
cso: states both lines have gradient 2, so they are parallelA1
Final answer: Both lines have gradient 2, so they are parallel.
Mark scheme for Question 6 [3 marks]
Question 6[3 marks]
Answer or workingMarks
subtracts the equations to eliminate yM1
x = 4A1cao
y = 3A1cao
Final answer: x = 4, y = 3
Mark scheme for Question 7 [3 marks]
Question 7[3 marks]
Answer or workingMarks
9x^2 = 16 oe, or correct factorisation (3x - 4)(3x + 4) = 0M1
x = 4/3A1oe
x = -4/3A1oe
Final answer: x = 4/3 or x = -4/3
Mark scheme for Question 8 [10 marks]
Question 8[10 marks]
Answer or workingMarks
correct straight line from (09:00, 0) to (10:30, 120)B1
correct horizontal line from (10:30, 120) to (10:50, 120)B1
correct straight line from (10:50, 120) to (12:25, 0)B1
120 divided by 1.5M1oe
80 (km/h)A1cao
120 divided by (95/60) oe, or 120 divided by 1.5833...M1
awrt 75.8 (km/h)A1
total distance = 240 (km)M1
total time = 205 minutes oe (3 h 25 min, or 205/60 hours, or 3.4167 hours)M1
awrt 70.2 (km/h)A1
Final answer: Straight line rising from (09:00, 0 km) to (10:30, 120 km); horizontal line from (10:30, 120 km) to (10:50, 120 km); straight line falling from (10:50, 120 km) to (12:25, 0 km). | 80 km/h | 75.8 km/h | 70.2 km/h
Mark scheme for Question 9 [5 marks]
Question 9[5 marks]
Answer or workingMarks
subtract 1 across: 0 <= 2x < 6M1
divide by 2 across: 0 <= x < 3M1
0 <= x < 3A1cao
states integer examples or checks, e.g. x = 0 and x = 2 satisfy the inequalityB1
notes that x = 3 is not allowed (shows strict inequality at upper end)B1
Mark scheme for Question 10 [6 marks]
Question 10[6 marks]
Answer or workingMarks
convert mass to kg and volume to m^3, 250 g = 0.25 kg, 200 cm^3 = 0.0002 m^3M1
use density = mass/volume, 0.25 / 0.0002M1
1250 kg/m^3A1cao
1.25 g/cm^3B1cao
convert 1.5 L to 1500 cm^3 and use mass = density x volume in g, 1.25 x 1500M1
1875 gA1cao
Final answer: 1250 kg/m^3 | 1.25 g/cm^3 | 1875 g
Mark scheme for Question 11 [3 marks]
Question 11[3 marks]
Answer or workingMarks
r = C/(2 * pi)B1oe
substitutes C = 18.84 into r = C/(2 * pi), ft from part aM1
awrt 3.0 (m)A1
Final answer: r = C/(2 * pi) | r = 3.0 m (1 dp)
Mark scheme for Question 12 [2 marks]
Question 12[2 marks]
Answer or workingMarks
identifies that the powers should be added, not multiplied (3 + 2 = 5, not 3 x 2 = 6)B1oe
correct answer 4^5 = 1024B1cao
Final answer: The student multiplied the powers (3 x 2 = 6) instead of adding them. The correct working is 4^3 x 4^2 = 4^(3+2) = 4^5 = 1024.