Higher Tier - Grades 5-6

Higher Grades 5-6 Mini Test

A 45-minute, 40-mark test using only authored grades 5-6 questions, focused on the full topic bank.

15 questions - 40 marks - calculator allowed

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Questions

Question 1 [1 marks]

Quadratics

Factorise x^2 - 49

Question 2 [2 marks]

Number and Calculation

A cafe sells sandwiches with a choice of 4 types of bread and 3 types of filling. Each sandwich has exactly one type of bread and one filling. Work out the total number of different sandwiches possible.

Question 3 [1 marks]

Ratio and Proportion

Given that y = 3/5 x, write down the ratio x:y in its simplest form.

Question 4 [1 marks]

Angles and Geometrical Reasoning

Point R has coordinates (6, -1). Write down the coordinates of the image of R after a reflection in the line y = x.

Question 5 [2 marks]

Indices and Standard Form

Show that (6 + sqrt(7))(6 - sqrt(7)) = 29.

Question 6 [2 marks]

Pythagoras and Trigonometry

In triangle YZA, angle Y = 96 degrees, ZA = 15.2 cm (opposite angle Y), and YA = 8.6 cm (opposite angle Z). Calculate the size of angle Z. Give your answer correct to 1 decimal place.

Question 7 [2 marks]

Statistics and Probability

Using the same table as Question 7 (time, t minutes, spent on homework by 30 pupils): Time, t (minutes): 0 < t <= 20, 20 < t <= 40, 40 < t <= 60, 60 < t <= 80, 80 < t <= 100 Frequency (f): 4, 9, 11, 4, 2 Total number of pupils = 30 State the class that contains the median.

Question 8 [2 marks]

Linear Algebra

Factorise x^2 + 3x - 40

Question 9 [2 marks]

Fractions, Decimals and Percentages

£250 is invested for 3 years at a rate of 2% per year compound interest. Work out the value of the investment at the end of 3 years, giving your answer to the nearest penny.

Question 10 [3 marks]

Graphs and Coordinates

Without using a calculator, write down the exact value of each of the following.

sin 30 degrees

cos 60 degrees

tan 45 degrees

Question 11 [3 marks]

Linear Algebra

Solve the simultaneous equations: 4x + y = 5 2x - 3y = 13

Question 12 [3 marks]

Angles and Geometrical Reasoning

O is the origin. The position vectors of A and B, relative to O, are a and b. P lies on AB such that AP : PB = 2 : 3. Find the position vector of P, OP, in terms of a and b, giving your answer in its simplest form.

Question 13 [4 marks]

Area, Volume and Measures

A sector of a circle has radius 9 cm and angle 120 degrees. Work out the length of the arc of the sector. Give your answer in terms of pi.

Question 14 [5 marks]

Angles and Geometrical Reasoning

PA and PB are tangents to a circle with centre O, touching the circle at A and B respectively. Angle APB = 50 degrees. Diagram: circle, centre O, external point P, tangents PA and PB drawn touching the circle at A and B, radii OA and OB drawn, right angles marked at A and B, angle APB = 50 degrees marked at P.

Work out the size of angle AOB.

Work out the size of angle OAB.

Question 15 [7 marks]

Sequences

Arjun is training for a marathon. In week 1, he runs 8 km. Each week after that, he runs 3 km more than the week before.

Work out how far Arjun runs in week 6.

Find an expression, in terms of n, for the distance, in km, Arjun runs in week n.

Arjun wants to know the first week in which he will run at least 50 km. Find this week number.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
(x - 7)(x + 7)B1cao
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
4 x 3 oe seenM1
12A1cao
Mark scheme for Question 3 [1 mark]
Question 3[1 mark]
Answer or workingMarks
5:3B1cao
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
(-1, 6)B1cao
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
correct expansion 36 - 6sqrt(7) + 6sqrt(7) - 7 (or 36 - 7)M1
cso - 36 - 7 = 29 shownA1
Final answer: 29 (given)
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
sin(Z)/8.6 = sin(96)/15.2M1oe
awrt 34.2 (degrees)A1
Final answer: angle Z = 34.2 degrees (1 d.p.)
Mark scheme for Question 7 [2 marks]
Question 7[2 marks]
Answer or workingMarks
correct use of cumulative frequencies to locate the 15th and 16th values (4, 13, 24, 28, 30)M1oe
40 < t <= 60A1cao
Mark scheme for Question 8 [2 marks]
Question 8[2 marks]
Answer or workingMarks
two numbers with sum 3 and product -40 identified (8 and -5)M1oe
(x + 8)(x - 5)A1cao
Mark scheme for Question 9 [2 marks]
Question 9[2 marks]
Answer or workingMarks
250 x 1.02^3 oe, or a correct year-by-year methodM1
265.30 (pounds)A1awrt
Final answer: £265.30
Mark scheme for Question 10 [3 marks]
Question 10[3 marks]
Answer or workingMarks
1/2 oe (e.g. 0.5)B1
1/2 oe (e.g. 0.5)B1
1B1cao
Final answer: 1/2 | 1/2 | 1
Mark scheme for Question 11 [3 marks]
Question 11[3 marks]
Answer or workingMarks
rearranges y = 5 - 4x and substitutes into the second equation (or equivalent elimination)M1
x = 2A1cao
y = -3A1cao
Final answer: x = 2, y = -3
Mark scheme for Question 12 [3 marks]
Question 12[3 marks]
Answer or workingMarks
AB = b - aM1
OP = a + (2/5)(b - a), correct method for the ratioM1
(3a + 2b)/5 oe, e.g. (3/5)a + (2/5)bA1
Final answer: OP = (3a + 2b)/5
Mark scheme for Question 13 [4 marks]
Question 13[4 marks]
Answer or workingMarks
method: arc length = (angle/360) x circumference = (angle/360) x 2 pi rM1
substitute angle = 120, r = 9 to get (120/360) x 2 pi x 9M1
6 piA1cao
units: cmB1
Final answer: 6 pi cm
Mark scheme for Question 14 [5 marks]
Question 14[5 marks]
Answer or workingMarks
angle OAP = angle OBP = 90 degrees (tangent perpendicular to radius)M1
360 - 90 - 90 - 50 oe (angle sum of quadrilateral OAPB)M1
130 degreesA1cao
(180 - their AOB) / 2 oe, using triangle OAB isosceles since OA = OB (radii)M1
25 degreesA1cao
Final answer: 130 degrees | 25 degrees
Mark scheme for Question 15 [7 marks]
Question 15[7 marks]
Answer or workingMarks
8 + 5 x 3 oe, or lists terms up to week 6M1
23 kmA1cao
common difference of 3 used correctly, e.g. 3n + cM1oe
3n + 5 oeA1cao
3n + 5 >= 50 oe (ft their expression)M1
3n >= 45 oe, leading to n >= 15M1
week 15A1cao
Final answer: 23 km | 3n + 5 | Week 15