Higher Grades 6-7 Mini Test
A 45-minute, 40-mark test using only authored grades 6-7 questions, focused on the full topic bank.
Questions
Question 1 [2 marks]
Ratio and Proportion
P is directly proportional to Q. When Q = 5, P = 30. Find the value of P when Q = 9.
Question 2 [2 marks]
Pythagoras and Trigonometry
Fatima is fencing a triangular flower bed in her garden. Two of the sides measure 1.5 m and 2.3 m, with an angle of 48 degrees between them. Calculate the length of the third side. Give your answer correct to 3 significant figures.
Question 3 [2 marks]
Indices and Standard Form
Evaluate 27^(2/3).
Question 4 [2 marks]
Quadratics
Factorise 3x^2 + 10x + 3
Question 5 [2 marks]
Angles and Geometrical Reasoning
TA is a tangent to a circle at the point A. AB is a chord of the circle, and C is a point on the circle in the alternate segment. The angle between the tangent TA and the chord AB is 63 degrees. Diagram: circle, tangent TA drawn touching at A, chord AB drawn, angle between TA and AB marked 63 degrees at A, point C marked on the circle in the alternate segment, angle ACB marked at C. Write down the size of angle ACB, giving a reason for your answer.
Question 6 [2 marks]
Graphs and Coordinates
A line has gradient 6. Find the gradient of a line perpendicular to it.
Question 7 [3 marks]
Linear Algebra
Solve (x + 3)/4 + (x - 2)/6 = 5/2
Question 8 [3 marks]
Sequences
A quadratic sequence has constant second difference 8. Its 3rd term is 24 and its 5th term is 60. Find an expression for the nth term.
Question 9 [4 marks]
Number and Calculation
The number A = 2^4 x 3^2 x 5 and the number B = 2^2 x 3^3 x 7. (a) Find HCF(A, B). (b) Find LCM(A, B).
Question 10 [6 marks]
Area, Volume and Measures
A gardener makes a raised flower bed in the shape of a rectangle 6 m by 3 m. At each end she places a semicircular planting area whose diameters are the short side of the rectangle, so the semicircles extend beyond the rectangle. She covers the combined area with turf costing £4.50 per square metre. Work out the total cost of turf to the nearest pound. Show your working.
Question 11 [4 marks]
Fractions, Decimals and Percentages
Which of the following mixed numbers are equal? Explain fully. 1 3/5, 1 9/15, 1 6/10, 1 11/15
Question 12 [3 marks]
Statistics and Probability
A nature reserve covers 5 hectares. To estimate its hare population, 45 hares are caught and tagged in a first sample. In a second sample of 60 hares, 9 are found to be tagged.
Estimate the total number of hares in the reserve.
Work out the population density of hares, in hares per hectare.
Question 13 [3 marks]
Graphs and Coordinates
A has coordinates (-2, 1) and B has coordinates (4, 5). Find the length of AB, giving your answer correct to 3 significant figures.
Question 14 [2 marks]
Statistics and Probability
A researcher estimates there are 420 mice in a barn. She marked 35 mice in the first sample. She wants her second sample to contain exactly 5 marked mice.
Model solutions
| Question 1[2 marks] | |
|---|---|
| Answer or working | Marks |
| finds the constant of proportionality k = 30/5 (=6), or uses a valid scale factor method | M1 |
| P = 54 | A1cao |
| Question 2[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct substitution, e.g. third side^2 = 1.5^2 + 2.3^2 - 2*1.5*2.3*cos(48) | M1oe |
| 1.71 m (awrt 1.71) | A1cao |
| Final answer: Third side = 1.71 m (3 s.f.) | |
| Question 3[2 marks] | |
|---|---|
| Answer or working | Marks |
| interpret 27^(2/3) = (cube root of 27)^2 or (27^2)^(1/3) | M1 |
| 9 | A1cao |
| Final answer: 9 (since cube root of 27 is 3, 3^2 = 9) | |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| identifies a pair of numbers with product 9 and sum 10 (9 and 1), or one correct bracket seen | M1 |
| (3x + 1)(x + 3) | A1cao |
| Question 5[2 marks] | |
|---|---|
| Answer or working | Marks |
| 63 degrees | B1cao |
| reason: alternate segment theorem, the angle between a tangent and a chord equals the angle in the alternate segment | B1oe |
| Final answer: 63 degrees, by the alternate segment theorem. | |
| Question 6[2 marks] | |
|---|---|
| Answer or working | Marks |
| uses (gradient) x (perpendicular gradient) = -1 | M1oe |
| -1/6 oe | A1cao |
| Final answer: -1/6 | |
| Question 7[3 marks] | |
|---|---|
| Answer or working | Marks |
| multiplies every term by the common denominator 12: 3(x + 3) + 2(x - 2) = 30 | M1 |
| expands and collects: 5x + 5 = 30 | M1 |
| x = 5 | A1cao |
| Question 8[3 marks] | |
|---|---|
| Answer or working | Marks |
| second difference = 8 so a = 4 (2a = 8) | M1oe |
| use T3 and T5 to form two linear equations and solve for b and c (eg 36 + 3b + c = 24 and 100 + 5b + c = 60) | M1oe |
| nth term = 4n^2 - 14n + 30 | A1cao |
| Final answer: 4n^2 - 14n + 30 | |
| Question 9[4 marks] | |
|---|---|
| Answer or working | Marks |
| choose minimum powers: 2^2 x 3^2 | M1oe |
| HCF = 4 x 9 = 36 | A1cao |
| take highest powers: 2^4 x 3^3 x 5 x 7 | M1oe |
| LCM = 16 x 27 x 5 x 7 = 15120 | A1cao |
| Final answer: 36 | 15120 | |
| Question 10[6 marks] | |
|---|---|
| Answer or working | Marks |
| area rectangle = 6*3 = 18 m^2 | M1 |
| diameter of each semicircle = 3 so radius = 1.5; area semicircle = 1/2*pi*1.5^2 = 1.125pi each | M1 |
| two semicircles combined = 2*1.125pi = 2.25pi | M1 |
| total area = 18 + 2.25pi | M1 |
| numeric area = 18 + 2.25pi = 18 + 7.068583... = 25.0686... m^2 | A1 |
| cost = 25.0686... * 4.5 = 112.8089... -> £113 to nearest pound | A1 |
| Final answer: £113 (nearest pound). Working check: total area 18 + 2.25pi = 25.0686..., cost 25.0686...*4.5 = 112.8089... -> 113. | |
| Question 11[4 marks] | |
|---|---|
| Answer or working | Marks |
| convert 3/5 to 9/15 | M1oe |
| convert 3/5 to 6/10 oe (or convert others to common denominator) | M1oe |
| identify that 1 3/5 = 1 9/15 = 1 6/10 | M1oe |
| state that 1 3/5, 1 9/15 and 1 6/10 are equal and 1 11/15 is different | A1cao |
| Final answer: 1 3/5, 1 9/15 and 1 6/10 are equal because 3/5 = 9/15 = 6/10; 1 11/15 is not equal to them. | |
| Question 12[3 marks] | |
|---|---|
| Answer or working | Marks |
| 45 x 60 / 9 | M1oe |
| 300 | A1cao |
| 60 (ft their part (a) answer / 5) | B1 |
| Final answer: (a) 300 hares (b) 60 hares per hectare | |
| Question 13[3 marks] | |
|---|---|
| Answer or working | Marks |
| correct substitution into sqrt((x2-x1)^2 + (y2-y1)^2) | M1 |
| sqrt(52) oe (e.g. sqrt(36 + 16)) seen | A1 |
| awrt 7.21 | A1 |
| Final answer: 7.21 | |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct rearrangement n2 = N x m / n1 | M1oe |
| 60 | A1cao |
| Final answer: 60 mice | |