Higher Tier - Grades 6-7

Higher Grades 6-7 Mini Test

A 45-minute, 40-mark test using only authored grades 6-7 questions, focused on the full topic bank.

14 questions - 40 marks - calculator allowed

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Questions

Question 1 [2 marks]

Ratio and Proportion

P is directly proportional to Q. When Q = 5, P = 30. Find the value of P when Q = 9.

Question 2 [2 marks]

Pythagoras and Trigonometry

Fatima is fencing a triangular flower bed in her garden. Two of the sides measure 1.5 m and 2.3 m, with an angle of 48 degrees between them. Calculate the length of the third side. Give your answer correct to 3 significant figures.

Question 3 [2 marks]

Indices and Standard Form

Evaluate 27^(2/3).

Question 4 [2 marks]

Quadratics

Factorise 3x^2 + 10x + 3

Question 5 [2 marks]

Angles and Geometrical Reasoning

TA is a tangent to a circle at the point A. AB is a chord of the circle, and C is a point on the circle in the alternate segment. The angle between the tangent TA and the chord AB is 63 degrees. Diagram: circle, tangent TA drawn touching at A, chord AB drawn, angle between TA and AB marked 63 degrees at A, point C marked on the circle in the alternate segment, angle ACB marked at C. Write down the size of angle ACB, giving a reason for your answer.

Question 6 [2 marks]

Graphs and Coordinates

A line has gradient 6. Find the gradient of a line perpendicular to it.

Question 7 [3 marks]

Linear Algebra

Solve (x + 3)/4 + (x - 2)/6 = 5/2

Question 8 [3 marks]

Sequences

A quadratic sequence has constant second difference 8. Its 3rd term is 24 and its 5th term is 60. Find an expression for the nth term.

Question 9 [4 marks]

Number and Calculation

The number A = 2^4 x 3^2 x 5 and the number B = 2^2 x 3^3 x 7. (a) Find HCF(A, B). (b) Find LCM(A, B).

Question 10 [6 marks]

Area, Volume and Measures

A gardener makes a raised flower bed in the shape of a rectangle 6 m by 3 m. At each end she places a semicircular planting area whose diameters are the short side of the rectangle, so the semicircles extend beyond the rectangle. She covers the combined area with turf costing £4.50 per square metre. Work out the total cost of turf to the nearest pound. Show your working.

Question 11 [4 marks]

Fractions, Decimals and Percentages

Which of the following mixed numbers are equal? Explain fully. 1 3/5, 1 9/15, 1 6/10, 1 11/15

Question 12 [3 marks]

Statistics and Probability

A nature reserve covers 5 hectares. To estimate its hare population, 45 hares are caught and tagged in a first sample. In a second sample of 60 hares, 9 are found to be tagged.

Estimate the total number of hares in the reserve.

Work out the population density of hares, in hares per hectare.

Question 13 [3 marks]

Graphs and Coordinates

A has coordinates (-2, 1) and B has coordinates (4, 5). Find the length of AB, giving your answer correct to 3 significant figures.

Question 14 [2 marks]

Statistics and Probability

A researcher estimates there are 420 mice in a barn. She marked 35 mice in the first sample. She wants her second sample to contain exactly 5 marked mice.

Model solutions

Mark scheme for Question 1 [2 marks]
Question 1[2 marks]
Answer or workingMarks
finds the constant of proportionality k = 30/5 (=6), or uses a valid scale factor methodM1
P = 54A1cao
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
correct substitution, e.g. third side^2 = 1.5^2 + 2.3^2 - 2*1.5*2.3*cos(48)M1oe
1.71 m (awrt 1.71)A1cao
Final answer: Third side = 1.71 m (3 s.f.)
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
interpret 27^(2/3) = (cube root of 27)^2 or (27^2)^(1/3)M1
9A1cao
Final answer: 9 (since cube root of 27 is 3, 3^2 = 9)
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
identifies a pair of numbers with product 9 and sum 10 (9 and 1), or one correct bracket seenM1
(3x + 1)(x + 3)A1cao
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
63 degreesB1cao
reason: alternate segment theorem, the angle between a tangent and a chord equals the angle in the alternate segmentB1oe
Final answer: 63 degrees, by the alternate segment theorem.
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
uses (gradient) x (perpendicular gradient) = -1M1oe
-1/6 oeA1cao
Final answer: -1/6
Mark scheme for Question 7 [3 marks]
Question 7[3 marks]
Answer or workingMarks
multiplies every term by the common denominator 12: 3(x + 3) + 2(x - 2) = 30M1
expands and collects: 5x + 5 = 30M1
x = 5A1cao
Mark scheme for Question 8 [3 marks]
Question 8[3 marks]
Answer or workingMarks
second difference = 8 so a = 4 (2a = 8)M1oe
use T3 and T5 to form two linear equations and solve for b and c (eg 36 + 3b + c = 24 and 100 + 5b + c = 60)M1oe
nth term = 4n^2 - 14n + 30A1cao
Final answer: 4n^2 - 14n + 30
Mark scheme for Question 9 [4 marks]
Question 9[4 marks]
Answer or workingMarks
choose minimum powers: 2^2 x 3^2M1oe
HCF = 4 x 9 = 36A1cao
take highest powers: 2^4 x 3^3 x 5 x 7M1oe
LCM = 16 x 27 x 5 x 7 = 15120A1cao
Final answer: 36 | 15120
Mark scheme for Question 10 [6 marks]
Question 10[6 marks]
Answer or workingMarks
area rectangle = 6*3 = 18 m^2M1
diameter of each semicircle = 3 so radius = 1.5; area semicircle = 1/2*pi*1.5^2 = 1.125pi eachM1
two semicircles combined = 2*1.125pi = 2.25piM1
total area = 18 + 2.25piM1
numeric area = 18 + 2.25pi = 18 + 7.068583... = 25.0686... m^2A1
cost = 25.0686... * 4.5 = 112.8089... -> £113 to nearest poundA1
Final answer: £113 (nearest pound). Working check: total area 18 + 2.25pi = 25.0686..., cost 25.0686...*4.5 = 112.8089... -> 113.
Mark scheme for Question 11 [4 marks]
Question 11[4 marks]
Answer or workingMarks
convert 3/5 to 9/15M1oe
convert 3/5 to 6/10 oe (or convert others to common denominator)M1oe
identify that 1 3/5 = 1 9/15 = 1 6/10M1oe
state that 1 3/5, 1 9/15 and 1 6/10 are equal and 1 11/15 is differentA1cao
Final answer: 1 3/5, 1 9/15 and 1 6/10 are equal because 3/5 = 9/15 = 6/10; 1 11/15 is not equal to them.
Mark scheme for Question 12 [3 marks]
Question 12[3 marks]
Answer or workingMarks
45 x 60 / 9M1oe
300A1cao
60 (ft their part (a) answer / 5)B1
Final answer: (a) 300 hares (b) 60 hares per hectare
Mark scheme for Question 13 [3 marks]
Question 13[3 marks]
Answer or workingMarks
correct substitution into sqrt((x2-x1)^2 + (y2-y1)^2)M1
sqrt(52) oe (e.g. sqrt(36 + 16)) seenA1
awrt 7.21A1
Final answer: 7.21
Mark scheme for Question 14 [2 marks]
Question 14[2 marks]
Answer or workingMarks
correct rearrangement n2 = N x m / n1M1oe
60A1cao
Final answer: 60 mice