AQA-Style Year 10 Higher Paper 1
An AQA-style Year 10 Higher Paper 1: 80 marks, 90 minutes, non-calculator, matching AQA 8300's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.
Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [1 marks]
Graphs and Coordinates
The speed-time graph below shows a car's journey. Speed (m/s) is on the vertical axis, 0 to 20, and Time (seconds) is on the horizontal axis, 0 to 40. The graph rises in a straight line from (0,0) to (10,20), is horizontal from (10,20) to (25,20), then falls in a straight line from (25,20) to (40,0). Which section of the graph shows the car travelling at a constant speed?
Question 2 [2 marks]
Area, Volume and Measures
Rectangle A measures 5 cm by 8 cm.
Which of these rectangles is mathematically similar to rectangle A?
Write down the scale factor of enlargement from rectangle A to the rectangle you chose in part (a).
Question 3 [3 marks]
Sequences
Three sequences are shown below. Sequence A: 7, 11, 15, 19 Sequence B: 4, 12, 36, 108 Sequence C: 3, 6, 11, 18
State whether Sequence A is arithmetic, geometric, or neither of these. Give a reason for your answer.
State whether Sequence B is arithmetic, geometric, or neither of these. Give a reason for your answer.
State whether Sequence C is arithmetic, geometric, or neither of these. Give a reason for your answer.
Question 4 [1 marks]
Indices and Standard Form
Simplify 3sqrt(2) + 5sqrt(2).
Question 5 [1 marks]
Number and Calculation
Sam rolls two ordinary six-sided dice, one red and one blue. Work out the number of different outcomes possible.
Question 6 [1 marks]
Angles and Geometrical Reasoning
Point R has coordinates (6, -1). Write down the coordinates of the image of R after a reflection in the line y = x.
Question 7 [1 marks]
Indices and Standard Form
Simplify p^5 * p^3.
Question 8 [1 marks]
Graphs and Coordinates
Plot the point with coordinates (3, -2) on a pair of axes.
Question 9 [1 marks]
Indices and Standard Form
Simplify sqrt(80) fully.
Question 10 [2 marks]
Linear Algebra
p = -4 and q = 5. Work out the value of (p + q)^2.
Question 11 [2 marks]
Fractions, Decimals and Percentages
Work out 2 2/5 + 1 4/5. Give your answer as a mixed number.
Question 12 [2 marks]
Graphs and Coordinates
The graphs of y = x - 1 and y = -2x - 7 are drawn on the grid. Write down the solution of the simultaneous equations y = x - 1 and y = -2x - 7.
Question 13 [2 marks]
Number and Calculation
Find the LCM of 6, 8 and 10.
Question 14 [2 marks]
Graphs and Coordinates
Find the gradient of the straight line joining the points (1, 1) and (4, 7).
Question 15 [2 marks]
Indices and Standard Form
Show that (6 + sqrt(7))(6 - sqrt(7)) = 29.
Question 16 [2 marks]
Sequences
Work out an expression for the nth term of the sequence 1, 6, 15, 28.
Question 17 [2 marks]
Angles and Geometrical Reasoning
A, B, C and D are points on the circumference of a circle. C and D are on the same side of the chord AB, so angle ACB and angle ADB are angles in the same segment. Angle ADB = 37 degrees. Diagram: circle with chord AB drawn, points C and D on the circumference on the same side of AB, angle ADB = 37 degrees marked at D, angle ACB marked at C. Write down the size of angle ACB, giving a reason for your answer.
Question 18 [3 marks]
Ratio and Proportion
The cost, C pounds, of a length of ribbon is directly proportional to its length, L metres. 5 metres of ribbon costs £6.50.
Find the value of k in the formula C = kL.
Work out the cost of 12 metres of the same ribbon.
Question 19 [3 marks]
Angles and Geometrical Reasoning
Enlarge triangle T with vertices (2, 1), (4, 1) and (2, 3) by a scale factor of -2 centre (1, 1). Find the coordinates of the image vertices.
Question 20 [3 marks]
Graphs and Coordinates
The circle x^2 + y^2 = 50 meets the vertical line x = 5 at two points. Take the point with positive y-coordinate. Work out the equation of the tangent to the circle at this point.
Question 21 [3 marks]
Sequences
The quadratic sequence begins 3, 8, 15, 24, 35. Find an expression for the nth term in the form an^2 + bn + c.
Question 22 [4 marks]
Linear Algebra
A carpenter charges a fixed call-out fee of £45 plus £35 per hour worked. Let C pounds be the total cost of a job that takes h hours.
Write an expression for C in terms of h.
One job costs Sanjay £220 in total. Form an equation and solve it to find how many hours the job took.
Question 23 [3 marks]
Indices and Standard Form
A bacterium has a diameter of 4 x 10^-6 m. A dust mite has a diameter of 2 x 10^-4 m. Work out how many times bigger the diameter of the dust mite is than the diameter of the bacterium.
Question 24 [6 marks]
Linear Algebra
These formulae involve a square or a square root.
The area of a circle of radius r is A = pi * r^2. Make r the subject of the formula.
v^2 = u^2 + 2as. Make u the subject of the formula.
Question 25 [4 marks]
Angles and Geometrical Reasoning
AB is a diameter of a circle with centre O. C is a point on the circumference, and OC is drawn. Angle OCB = 33 degrees. Diagram: circle, centre O, AB drawn as a diameter, C on the circumference, radius OC drawn, angle OCB = 33 degrees marked at C. Work out the size of angle BAC, giving reasons at each stage of your working.
Question 26 [3 marks]
Indices and Standard Form
The volume of a cube is 64x^12 cm^3. Find an expression, in terms of x, for the length of one edge of the cube. Give your answer in its simplest form.
Question 27 [5 marks]
Angles and Geometrical Reasoning
Triangle A has vertices (1, 1), (1, 3) and (4, 1). Triangle A is rotated 90 degrees clockwise about the point (p, q) to form triangle B, with vertices (3, -3), (5, -3) and (3, -6). Find the values of p and q.
Question 28 [5 marks]
Number and Calculation
A charity club has 8 members. Three different roles, chair, vice-chair and treasurer, are each given to a different member.
Work out the number of different ways the three roles can be given out.
The treasurer role must go to either Kwame or Sophie. Work out the number of different ways the three roles can now be given out.
Question 29 [5 marks]
Angles and Geometrical Reasoning
Triangle P has vertices (1, 1), (1, 3) and (3, 1). Triangle P is rotated 90 degrees clockwise about the origin, and the image is then translated by the vector (2, -1), to form triangle Q.
Find the coordinates of the vertices of triangle Q.
A student says: 'The single transformation that maps triangle Q back onto triangle P is a rotation of 90 degrees anticlockwise about the origin.' Show, using at least one vertex, that the student is incorrect.
Question 30 [5 marks]
Angles and Geometrical Reasoning
Show that for three parallel lines cut by a single transversal, the angle between the transversal and the top line plus the angle between the transversal and the bottom line equals twice the angle between the transversal and the middle line. Give a short proof using algebra: let the acute angle at the middle intersection be a degrees, and express the other two in terms of a.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| B | B1cao |
| Final answer: B) 10 to 25 seconds | |
| Question 2[2 marks] | |
|---|---|
| Answer or working | Marks |
| B) 15 cm by 24 cm | B1 |
| 3 cao ft their (a) | B1 |
| Final answer: a) B b) 3 | |
| Question 3[3 marks] | |
|---|---|
| Answer or working | Marks |
| arithmetic, since the terms have a common difference of 4 | B1oe |
| geometric, since the terms have a common ratio of 3 | B1oe |
| neither, since the differences (3, 5, 7) are not constant and the ratios are not constant | B1oe |
| Final answer: Arithmetic (common difference of 4) | Geometric (common ratio of 3) | Neither (it is a quadratic sequence) | |
| Question 4[1 mark] | |
|---|---|
| Answer or working | Marks |
| 8sqrt(2) oe | B1cao |
| Final answer: 8sqrt(2) | |
| Question 5[1 mark] | |
|---|---|
| Answer or working | Marks |
| 36 | B1cao |
| Question 6[1 mark] | |
|---|---|
| Answer or working | Marks |
| (-1, 6) | B1cao |
| Question 7[1 mark] | |
|---|---|
| Answer or working | Marks |
| p^8 | B1cao |
| Question 8[1 mark] | |
|---|---|
| Answer or working | Marks |
| point plotted at (3, -2) within tolerance (correct quadrant and position) | B1oe |
| Final answer: (3, -2) | |
| Question 9[1 mark] | |
|---|---|
| Answer or working | Marks |
| 4sqrt(5) oe | B1cao |
| Final answer: 4sqrt(5) | |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| p + q = 1 seen | M1oe |
| 1 | A1cao |
| Question 11[2 marks] | |
|---|---|
| Answer or working | Marks |
| convert or add whole and fractions correctly, e.g. 2 + 1 and 2/5 + 4/5 = 6/5 shown | M1 |
| 4 1/5 | A1cao |
| Question 12[2 marks] | |
|---|---|
| Answer or working | Marks |
| x = -2 | B1 |
| y = -3 (oe as a coordinate pair) | B1 |
| Final answer: x = -2, y = -3 | |
| Question 13[2 marks] | |
|---|---|
| Answer or working | Marks |
| 6 = 2 x 3, 8 = 2^3 and 10 = 2 x 5 all shown | M1 |
| 120 | A1cao |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| (7 - 1)/(4 - 1), oe substitution into the gradient formula | M1 |
| 2 | A1cao |
| Question 15[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct expansion 36 - 6sqrt(7) + 6sqrt(7) - 7 (or 36 - 7) | M1 |
| cso - 36 - 7 = 29 shown | A1 |
| Final answer: 29 (given) | |
| Question 16[2 marks] | |
|---|---|
| Answer or working | Marks |
| second differences 5, 9, 13 so second difference = 4 and a = 2 (2a = 4) | M1oe |
| nth term = 2n^2 - n | A1cao |
| Final answer: 2n^2 - n | |
| Question 17[2 marks] | |
|---|---|
| Answer or working | Marks |
| 37 degrees | B1cao |
| reason: angles in the same segment (subtended by the same arc) are equal | B1oe |
| Final answer: 37 degrees, because angles in the same segment are equal. | |
| Question 18[3 marks] | |
|---|---|
| Answer or working | Marks |
| k = 1.3 | B1oe |
| substitutes L = 12 into C = 1.3L (ft their k) | M1 |
| £15.60 | A1cao |
| Final answer: k = 1.3 | £15.60 | |
| Question 19[3 marks] | |
|---|---|
| Answer or working | Marks |
| subtract centre (1,1) then multiply by -2 for each coordinate (method shown) | M1oe |
| image of (2,1) is (-1,1) | A1cao |
| images of other vertices: (4,1) -> (-5,1) and (2,3) -> (-1,-3) | A1cao |
| Final answer: Images: (2,1) -> (-1,1); (4,1) -> (-5,1); (2,3) -> (-1,-3). | |
| Question 20[3 marks] | |
|---|---|
| Answer or working | Marks |
| find y: y^2 = 50 - 25 so y = 5 (positive) | M1oe |
| find tangent gradient -x/y = -5/5 = -1 | M1oe |
| y = -x + 10 | A1cao |
| Question 21[3 marks] | |
|---|---|
| Answer or working | Marks |
| second difference = 2 so a = 1 (2a = 2) | M1oe |
| use n = 1 and n = 2 to form linear equations and solve for b and c (eg 1 + b + c = 3 and 4 + 2b + c = 8) | M1oe |
| nth term = n^2 + 2n | A1cao |
| Final answer: n^2 + 2n | |
| Question 22[4 marks] | |
|---|---|
| Answer or working | Marks |
| C = 45 + 35h | B1oe |
| 45 + 35h = 220 oe (ft from part a) | M1 |
| 35h = 175 | M1oe |
| h = 5 (hours) | A1cao |
| Final answer: C = 45 + 35h | h = 5 hours | |
| Question 23[3 marks] | |
|---|---|
| Answer or working | Marks |
| sets up (2 x 10^-4) / (4 x 10^-6) | M1 |
| 2 / 4 = 0.5 and 10^-4 / 10^-6 = 10^2 seen, or 0.5 x 10^2 oe unsimplified | M1 |
| 50 | A1cao |
| Final answer: 50 (times bigger) | |
| Question 24[6 marks] | |
|---|---|
| Answer or working | Marks |
| divides both sides by pi, e.g. r^2 = A/pi | M1 |
| square roots both sides, dependent on the previous method mark | dM1 |
| r = sqrt(A/pi) oe, cao (positive root only, since r is a length) | A1 |
| subtracts 2as from both sides, e.g. u^2 = v^2 - 2as | M1 |
| square roots both sides, dependent on the previous method mark | dM1 |
| u = sqrt(v^2 - 2as) oe | A1cao |
| Final answer: r = sqrt(A/pi) | u = sqrt(v^2 - 2as) | |
| Question 25[4 marks] | |
|---|---|
| Answer or working | Marks |
| angle ACB = 90 degrees, since AB is a diameter (angle in a semicircle) | B1 |
| angle OCA = 90 - 33 = 57 degrees | M1 |
| OA = OC (radii), so triangle OAC is isosceles, angle OAC = angle OCA | M1 |
| angle BAC = 57 degrees | A1cao |
| Final answer: 57 degrees | |
| Question 26[3 marks] | |
|---|---|
| Answer or working | Marks |
| cube root of 64 = 4 seen | M1 |
| cube root of x^12 = x^4 seen (12 / 3) | M1 |
| 4x^4 oe | A1cao |
| Final answer: 4x^4 cm | |
| Question 27[5 marks] | |
|---|---|
| Answer or working | Marks |
| sets up the general image of a 90 degree clockwise rotation about (p,q): (x,y) -> (y-q+p, p-x+q) | M1 |
| forms two equations in p and q using a vertex and its image, e.g. from (1,1) -> (3,-3): 1-q+p=3 and p-1+q=-3 | M1 |
| solves the equations simultaneously (or uses an equivalent method, e.g. locating the centre as the intersection of the perpendicular bisectors of two vertex-image pairs) | M1 |
| p = 0 | A1 |
| q = -2 | A1 |
| Final answer: p = 0, q = -2 | |
| Question 28[5 marks] | |
|---|---|
| Answer or working | Marks |
| 8 * 7 * 6 oe seen | M1 |
| 336 | A1cao |
| identifies 2 choices for treasurer (Kwame or Sophie) | M1 |
| (dep) 2 * 7 * 6 oe for the remaining two roles | M1 |
| 84 | A1cao |
| Final answer: 336 | 84 | |
| Question 29[5 marks] | |
|---|---|
| Answer or working | Marks |
| rotates at least one vertex of P by 90 degrees clockwise about the origin using (x,y) -> (y,-x) | M1 |
| dep translates the rotated vertices by the vector (2,-1) | M1 |
| all three vertices correct: (3,-2), (5,-2), (3,-4) | A1cao |
| applies a 90 degree anticlockwise rotation about the origin to a vertex of Q, e.g. (3,-2) -> (2,3) | M1 |
| correct conclusion that this does not give the corresponding vertex of P (e.g. (2,3) is not equal to (1,1)), so the student is incorrect, because triangle P and Q are related by a rotation combined with a translation, not by a rotation alone | A1 |
| Final answer: (3, -2), (5, -2), (3, -4) | Incorrect: rotating (3,-2) by 90 degrees anticlockwise about the origin gives (2,3), not (1,1), so a single rotation about the origin cannot map Q back onto P (a translation was also applied) | |
| Question 30[5 marks] | |
|---|---|
| Answer or working | Marks |
| recognise the top and middle lines are parallel and cut by the same transversal | M1 |
| state top acute angle = a, since corresponding angles between the top and middle lines are equal | A1 |
| recognise the middle and bottom lines are parallel and cut by the same transversal | M1 |
| state bottom acute angle = a, since corresponding angles between the middle and bottom lines are equal | A1 |
| conclude top + bottom = a + a = 2a = 2 x middle angle, as required | A1cao |
| Final answer: Top + bottom = 2 x middle angle, since the single transversal makes equal corresponding angles (each = a) with all three parallel lines | |