Higher Tier - Year 10

AQA-Style Year 10 Higher Paper 1

An AQA-style Year 10 Higher Paper 1: 80 marks, 90 minutes, non-calculator, matching AQA 8300's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.

30 questions - 80 marks

Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

Download printable PDF

Questions

Question 1 [1 marks]

Graphs and Coordinates

The speed-time graph below shows a car's journey. Speed (m/s) is on the vertical axis, 0 to 20, and Time (seconds) is on the horizontal axis, 0 to 40. The graph rises in a straight line from (0,0) to (10,20), is horizontal from (10,20) to (25,20), then falls in a straight line from (25,20) to (40,0). Which section of the graph shows the car travelling at a constant speed?

Question 2 [2 marks]

Area, Volume and Measures

Rectangle A measures 5 cm by 8 cm.

Which of these rectangles is mathematically similar to rectangle A?

Write down the scale factor of enlargement from rectangle A to the rectangle you chose in part (a).

Question 3 [3 marks]

Sequences

Three sequences are shown below. Sequence A: 7, 11, 15, 19 Sequence B: 4, 12, 36, 108 Sequence C: 3, 6, 11, 18

State whether Sequence A is arithmetic, geometric, or neither of these. Give a reason for your answer.

State whether Sequence B is arithmetic, geometric, or neither of these. Give a reason for your answer.

State whether Sequence C is arithmetic, geometric, or neither of these. Give a reason for your answer.

Question 4 [1 marks]

Indices and Standard Form

Simplify 3sqrt(2) + 5sqrt(2).

Question 5 [1 marks]

Number and Calculation

Sam rolls two ordinary six-sided dice, one red and one blue. Work out the number of different outcomes possible.

Question 6 [1 marks]

Angles and Geometrical Reasoning

Point R has coordinates (6, -1). Write down the coordinates of the image of R after a reflection in the line y = x.

Question 7 [1 marks]

Indices and Standard Form

Simplify p^5 * p^3.

Question 8 [1 marks]

Graphs and Coordinates

Plot the point with coordinates (3, -2) on a pair of axes.

Question 9 [1 marks]

Indices and Standard Form

Simplify sqrt(80) fully.

Question 10 [2 marks]

Linear Algebra

p = -4 and q = 5. Work out the value of (p + q)^2.

Question 11 [2 marks]

Fractions, Decimals and Percentages

Work out 2 2/5 + 1 4/5. Give your answer as a mixed number.

Question 12 [2 marks]

Graphs and Coordinates

The graphs of y = x - 1 and y = -2x - 7 are drawn on the grid. Write down the solution of the simultaneous equations y = x - 1 and y = -2x - 7.

Question 13 [2 marks]

Number and Calculation

Find the LCM of 6, 8 and 10.

Question 14 [2 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (1, 1) and (4, 7).

Question 15 [2 marks]

Indices and Standard Form

Show that (6 + sqrt(7))(6 - sqrt(7)) = 29.

Question 16 [2 marks]

Sequences

Work out an expression for the nth term of the sequence 1, 6, 15, 28.

Question 17 [2 marks]

Angles and Geometrical Reasoning

A, B, C and D are points on the circumference of a circle. C and D are on the same side of the chord AB, so angle ACB and angle ADB are angles in the same segment. Angle ADB = 37 degrees. Diagram: circle with chord AB drawn, points C and D on the circumference on the same side of AB, angle ADB = 37 degrees marked at D, angle ACB marked at C. Write down the size of angle ACB, giving a reason for your answer.

Question 18 [3 marks]

Ratio and Proportion

The cost, C pounds, of a length of ribbon is directly proportional to its length, L metres. 5 metres of ribbon costs £6.50.

Find the value of k in the formula C = kL.

Work out the cost of 12 metres of the same ribbon.

Question 19 [3 marks]

Angles and Geometrical Reasoning

Enlarge triangle T with vertices (2, 1), (4, 1) and (2, 3) by a scale factor of -2 centre (1, 1). Find the coordinates of the image vertices.

Question 20 [3 marks]

Graphs and Coordinates

The circle x^2 + y^2 = 50 meets the vertical line x = 5 at two points. Take the point with positive y-coordinate. Work out the equation of the tangent to the circle at this point.

Question 21 [3 marks]

Sequences

The quadratic sequence begins 3, 8, 15, 24, 35. Find an expression for the nth term in the form an^2 + bn + c.

Question 22 [4 marks]

Linear Algebra

A carpenter charges a fixed call-out fee of £45 plus £35 per hour worked. Let C pounds be the total cost of a job that takes h hours.

Write an expression for C in terms of h.

One job costs Sanjay £220 in total. Form an equation and solve it to find how many hours the job took.

Question 23 [3 marks]

Indices and Standard Form

A bacterium has a diameter of 4 x 10^-6 m. A dust mite has a diameter of 2 x 10^-4 m. Work out how many times bigger the diameter of the dust mite is than the diameter of the bacterium.

Question 24 [6 marks]

Linear Algebra

These formulae involve a square or a square root.

The area of a circle of radius r is A = pi * r^2. Make r the subject of the formula.

v^2 = u^2 + 2as. Make u the subject of the formula.

Question 25 [4 marks]

Angles and Geometrical Reasoning

AB is a diameter of a circle with centre O. C is a point on the circumference, and OC is drawn. Angle OCB = 33 degrees. Diagram: circle, centre O, AB drawn as a diameter, C on the circumference, radius OC drawn, angle OCB = 33 degrees marked at C. Work out the size of angle BAC, giving reasons at each stage of your working.

Question 26 [3 marks]

Indices and Standard Form

The volume of a cube is 64x^12 cm^3. Find an expression, in terms of x, for the length of one edge of the cube. Give your answer in its simplest form.

Question 27 [5 marks]

Angles and Geometrical Reasoning

Triangle A has vertices (1, 1), (1, 3) and (4, 1). Triangle A is rotated 90 degrees clockwise about the point (p, q) to form triangle B, with vertices (3, -3), (5, -3) and (3, -6). Find the values of p and q.

Question 28 [5 marks]

Number and Calculation

A charity club has 8 members. Three different roles, chair, vice-chair and treasurer, are each given to a different member.

Work out the number of different ways the three roles can be given out.

The treasurer role must go to either Kwame or Sophie. Work out the number of different ways the three roles can now be given out.

Question 29 [5 marks]

Angles and Geometrical Reasoning

Triangle P has vertices (1, 1), (1, 3) and (3, 1). Triangle P is rotated 90 degrees clockwise about the origin, and the image is then translated by the vector (2, -1), to form triangle Q.

Find the coordinates of the vertices of triangle Q.

A student says: 'The single transformation that maps triangle Q back onto triangle P is a rotation of 90 degrees anticlockwise about the origin.' Show, using at least one vertex, that the student is incorrect.

Question 30 [5 marks]

Angles and Geometrical Reasoning

Show that for three parallel lines cut by a single transversal, the angle between the transversal and the top line plus the angle between the transversal and the bottom line equals twice the angle between the transversal and the middle line. Give a short proof using algebra: let the acute angle at the middle intersection be a degrees, and express the other two in terms of a.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
BB1cao
Final answer: B) 10 to 25 seconds
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
B) 15 cm by 24 cmB1
3 cao ft their (a)B1
Final answer: a) B b) 3
Mark scheme for Question 3 [3 marks]
Question 3[3 marks]
Answer or workingMarks
arithmetic, since the terms have a common difference of 4B1oe
geometric, since the terms have a common ratio of 3B1oe
neither, since the differences (3, 5, 7) are not constant and the ratios are not constantB1oe
Final answer: Arithmetic (common difference of 4) | Geometric (common ratio of 3) | Neither (it is a quadratic sequence)
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
8sqrt(2) oeB1cao
Final answer: 8sqrt(2)
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
36B1cao
Mark scheme for Question 6 [1 mark]
Question 6[1 mark]
Answer or workingMarks
(-1, 6)B1cao
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
p^8B1cao
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
point plotted at (3, -2) within tolerance (correct quadrant and position)B1oe
Final answer: (3, -2)
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
4sqrt(5) oeB1cao
Final answer: 4sqrt(5)
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
p + q = 1 seenM1oe
1A1cao
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
convert or add whole and fractions correctly, e.g. 2 + 1 and 2/5 + 4/5 = 6/5 shownM1
4 1/5A1cao
Mark scheme for Question 12 [2 marks]
Question 12[2 marks]
Answer or workingMarks
x = -2B1
y = -3 (oe as a coordinate pair)B1
Final answer: x = -2, y = -3
Mark scheme for Question 13 [2 marks]
Question 13[2 marks]
Answer or workingMarks
6 = 2 x 3, 8 = 2^3 and 10 = 2 x 5 all shownM1
120A1cao
Mark scheme for Question 14 [2 marks]
Question 14[2 marks]
Answer or workingMarks
(7 - 1)/(4 - 1), oe substitution into the gradient formulaM1
2A1cao
Mark scheme for Question 15 [2 marks]
Question 15[2 marks]
Answer or workingMarks
correct expansion 36 - 6sqrt(7) + 6sqrt(7) - 7 (or 36 - 7)M1
cso - 36 - 7 = 29 shownA1
Final answer: 29 (given)
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
second differences 5, 9, 13 so second difference = 4 and a = 2 (2a = 4)M1oe
nth term = 2n^2 - nA1cao
Final answer: 2n^2 - n
Mark scheme for Question 17 [2 marks]
Question 17[2 marks]
Answer or workingMarks
37 degreesB1cao
reason: angles in the same segment (subtended by the same arc) are equalB1oe
Final answer: 37 degrees, because angles in the same segment are equal.
Mark scheme for Question 18 [3 marks]
Question 18[3 marks]
Answer or workingMarks
k = 1.3B1oe
substitutes L = 12 into C = 1.3L (ft their k)M1
£15.60A1cao
Final answer: k = 1.3 | £15.60
Mark scheme for Question 19 [3 marks]
Question 19[3 marks]
Answer or workingMarks
subtract centre (1,1) then multiply by -2 for each coordinate (method shown)M1oe
image of (2,1) is (-1,1)A1cao
images of other vertices: (4,1) -> (-5,1) and (2,3) -> (-1,-3)A1cao
Final answer: Images: (2,1) -> (-1,1); (4,1) -> (-5,1); (2,3) -> (-1,-3).
Mark scheme for Question 20 [3 marks]
Question 20[3 marks]
Answer or workingMarks
find y: y^2 = 50 - 25 so y = 5 (positive)M1oe
find tangent gradient -x/y = -5/5 = -1M1oe
y = -x + 10A1cao
Mark scheme for Question 21 [3 marks]
Question 21[3 marks]
Answer or workingMarks
second difference = 2 so a = 1 (2a = 2)M1oe
use n = 1 and n = 2 to form linear equations and solve for b and c (eg 1 + b + c = 3 and 4 + 2b + c = 8)M1oe
nth term = n^2 + 2nA1cao
Final answer: n^2 + 2n
Mark scheme for Question 22 [4 marks]
Question 22[4 marks]
Answer or workingMarks
C = 45 + 35hB1oe
45 + 35h = 220 oe (ft from part a)M1
35h = 175M1oe
h = 5 (hours)A1cao
Final answer: C = 45 + 35h | h = 5 hours
Mark scheme for Question 23 [3 marks]
Question 23[3 marks]
Answer or workingMarks
sets up (2 x 10^-4) / (4 x 10^-6)M1
2 / 4 = 0.5 and 10^-4 / 10^-6 = 10^2 seen, or 0.5 x 10^2 oe unsimplifiedM1
50A1cao
Final answer: 50 (times bigger)
Mark scheme for Question 24 [6 marks]
Question 24[6 marks]
Answer or workingMarks
divides both sides by pi, e.g. r^2 = A/piM1
square roots both sides, dependent on the previous method markdM1
r = sqrt(A/pi) oe, cao (positive root only, since r is a length)A1
subtracts 2as from both sides, e.g. u^2 = v^2 - 2asM1
square roots both sides, dependent on the previous method markdM1
u = sqrt(v^2 - 2as) oeA1cao
Final answer: r = sqrt(A/pi) | u = sqrt(v^2 - 2as)
Mark scheme for Question 25 [4 marks]
Question 25[4 marks]
Answer or workingMarks
angle ACB = 90 degrees, since AB is a diameter (angle in a semicircle)B1
angle OCA = 90 - 33 = 57 degreesM1
OA = OC (radii), so triangle OAC is isosceles, angle OAC = angle OCAM1
angle BAC = 57 degreesA1cao
Final answer: 57 degrees
Mark scheme for Question 26 [3 marks]
Question 26[3 marks]
Answer or workingMarks
cube root of 64 = 4 seenM1
cube root of x^12 = x^4 seen (12 / 3)M1
4x^4 oeA1cao
Final answer: 4x^4 cm
Mark scheme for Question 27 [5 marks]
Question 27[5 marks]
Answer or workingMarks
sets up the general image of a 90 degree clockwise rotation about (p,q): (x,y) -> (y-q+p, p-x+q)M1
forms two equations in p and q using a vertex and its image, e.g. from (1,1) -> (3,-3): 1-q+p=3 and p-1+q=-3M1
solves the equations simultaneously (or uses an equivalent method, e.g. locating the centre as the intersection of the perpendicular bisectors of two vertex-image pairs)M1
p = 0A1
q = -2A1
Final answer: p = 0, q = -2
Mark scheme for Question 28 [5 marks]
Question 28[5 marks]
Answer or workingMarks
8 * 7 * 6 oe seenM1
336A1cao
identifies 2 choices for treasurer (Kwame or Sophie)M1
(dep) 2 * 7 * 6 oe for the remaining two rolesM1
84A1cao
Final answer: 336 | 84
Mark scheme for Question 29 [5 marks]
Question 29[5 marks]
Answer or workingMarks
rotates at least one vertex of P by 90 degrees clockwise about the origin using (x,y) -> (y,-x)M1
dep translates the rotated vertices by the vector (2,-1)M1
all three vertices correct: (3,-2), (5,-2), (3,-4)A1cao
applies a 90 degree anticlockwise rotation about the origin to a vertex of Q, e.g. (3,-2) -> (2,3)M1
correct conclusion that this does not give the corresponding vertex of P (e.g. (2,3) is not equal to (1,1)), so the student is incorrect, because triangle P and Q are related by a rotation combined with a translation, not by a rotation aloneA1
Final answer: (3, -2), (5, -2), (3, -4) | Incorrect: rotating (3,-2) by 90 degrees anticlockwise about the origin gives (2,3), not (1,1), so a single rotation about the origin cannot map Q back onto P (a translation was also applied)
Mark scheme for Question 30 [5 marks]
Question 30[5 marks]
Answer or workingMarks
recognise the top and middle lines are parallel and cut by the same transversalM1
state top acute angle = a, since corresponding angles between the top and middle lines are equalA1
recognise the middle and bottom lines are parallel and cut by the same transversalM1
state bottom acute angle = a, since corresponding angles between the middle and bottom lines are equalA1
conclude top + bottom = a + a = 2a = 2 x middle angle, as requiredA1cao
Final answer: Top + bottom = 2 x middle angle, since the single transversal makes equal corresponding angles (each = a) with all three parallel lines