Edexcel-Style Year 10 Higher Paper 2
An Edexcel-style Year 10 Higher Paper 2: 80 marks, 90 minutes, calculator, matching Edexcel 1MA1's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.
Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [1 marks]
Linear Algebra
Solve 5x = 35
Question 2 [1 marks]
Indices and Standard Form
Write 9.1 x 10^4 as an ordinary number.
Question 3 [1 marks]
Angles and Geometrical Reasoning
P, Q and R lie on a straight line. Angle a and an angle of 118 degrees lie on the same side of the line at Q.
Question 4 [2 marks]
Sequences
Here are the first four terms of a sequence. 3, 7, 11, 15
Write down the next term of the sequence.
Describe, in words, the term-to-term rule for the sequence.
Question 5 [2 marks]
Number and Calculation
The population of a town is 24 000, correct to 2 significant figures. Write down the error interval for the population, P.
Question 6 [3 marks]
Ratio and Proportion
Ayesha and Ben share £360 in the ratio 4:5. Work out how much money Ben receives.
Question 7 [1 marks]
Fractions, Decimals and Percentages
A number is decreased by 40% to give 54. Which calculation gives the original number?
Question 8 [2 marks]
Graphs and Coordinates
Explain why there is no point that can satisfy both y > 2x + 1 and y < 2x - 1. Give a short algebraic justification.
Question 9 [2 marks]
Area, Volume and Measures
Work out the circumference of a circle with radius 7 cm. Give your answer in terms of pi.
Question 10 [2 marks]
Fractions, Decimals and Percentages
The number of members of a gym increased by 12% this year. There are now 504 members. Work out the number of members last year.
Question 11 [5 marks]
Area, Volume and Measures
Cone G and cone H are mathematically similar. The base radius of cone G is 5 cm and the base radius of cone H is 8 cm. The surface area of cone G is 130 cm^2 and the volume of cone G is 150 cm^3.
Work out the surface area of cone H.
Work out the volume of cone H.
Question 12 [2 marks]
Linear Algebra
Show that x = 5, y = -2 satisfies both of the simultaneous equations: 3x + 2y = 11 2x - y = 12
Question 13 [2 marks]
Area, Volume and Measures
Work out the volume of a sphere with radius 5 cm. Give your answer in terms of pi.
Question 14 [2 marks]
Linear Algebra
Solve 6x - 5 = 19 Show your working.
Question 15 [3 marks]
Ratio and Proportion
Using 3 identical pumps, it takes 100 minutes to fill a swimming pool. The time taken, T minutes, is inversely proportional to the number of pumps used, n. Work out the minimum number of pumps needed to fill the pool in no more than 40 minutes.
Question 16 [3 marks]
Area, Volume and Measures
A cylinder has height 30 cm. The volume of the cylinder is 15000 cm^3. Diagram: cylinder labelled height 30 cm, radius r unknown. Work out the radius of the cylinder. Give your answer correct to 1 decimal place.
Question 17 [3 marks]
Angles and Geometrical Reasoning
A plane flies from airport A on a bearing of 060 for 100 km to reach point B. It then flies on a bearing of 150 for 100 km to reach point C. Diagram: Airport A, point B and point C are shown. AB = 100 km on a bearing of 060. BC = 100 km on a bearing of 150. North arrows are shown at A and B.
Question 18 [2 marks]
Area, Volume and Measures
Find the arc length of a sector with radius 10 m and central angle 72 degrees. Give your answer in metres, correct to 3 significant figures.
Question 19 [3 marks]
Fractions, Decimals and Percentages
Show that investing £800 at a compound interest rate of 5% per year gives a value of £882 after 2 years.
Question 20 [3 marks]
Graphs and Coordinates
Consider a vehicle with velocity described by: from t = 0 s to 3 s velocity increases uniformly from 0 to 6 m/s; from t = 3 s to 8 s velocity is constant at 6 m/s; from t = 8 s to 10 s velocity decreases uniformly from 6 to 0 m/s. State (a) the time interval when the vehicle is speeding up, (b) the interval when the vehicle moves at constant speed, and (c) the interval when the vehicle is slowing down.
State the time interval when the vehicle is speeding up.
State the time interval when the vehicle moves at constant speed.
State the time interval when the vehicle is slowing down.
Question 21 [4 marks]
Area, Volume and Measures
Two solid bronze statues are mathematically similar. The height of the smaller statue is 30 cm and its mass is 12 kg. The height of the larger statue is 45 cm. The statues are made from the same bronze, so mass is proportional to volume.
Question 22 [4 marks]
Fractions, Decimals and Percentages
A school fundraiser collected £840. The organisers decide to give 12% to charity, use 35% for equipment, and split the remainder equally between two sports teams. Work out how much each sports team receives. Show your working.
Question 23 [2 marks]
Angles and Geometrical Reasoning
v is the column vector (9, 12). Calculate the magnitude of v, |v|.
Question 24 [5 marks]
Area, Volume and Measures
The minute hand of a clock is 8 cm long. Calculate the area swept out by the minute hand in 25 minutes, giving your answer correct to 3 significant figures.
Question 25 [2 marks]
Linear Algebra
Prove algebraically that the product of any two even numbers is always a multiple of 4.
Question 26 [3 marks]
Area, Volume and Measures
Funnel P and funnel Q are mathematically similar. The volumes of funnel P and funnel Q are in the ratio 27:1000. The slant height of funnel P is 9 cm. Work out the slant height of funnel Q.
Question 27 [3 marks]
Linear Algebra
Solve x^2 - 5x - 14 = 0 by factorising. Show your working.
Question 28 [3 marks]
Sequences
The nth term of a sequence is 6n - 1. Prove algebraically that the sum of any three consecutive terms of this sequence is always a multiple of 3.
Question 29 [4 marks]
Fractions, Decimals and Percentages
A shop increases the price of a coffee machine by 30%, then reduces this new price by 30% in a clearance sale. The final sale price is £109.20. Work out the original price of the coffee machine, and state whether the final sale price is greater than, less than, or equal to the original price.
Question 30 [5 marks]
Linear Algebra
The time, T seconds, taken for a ball dropped from height h metres to hit the ground is given by the formula T = sqrt(2h/g), where g is the gravitational field strength.
Make h the subject of the formula.
A ball is dropped from a window and takes exactly 2 seconds to hit the ground. Use g = 9.8 m/s^2 and your formula from part (a) to work out the height of the window above the ground.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| x = 7 | B1cao |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| 91000 | B1cao |
| Question 3[1 mark] | |
|---|---|
| Answer or working | Marks |
| a = 62 | B1cao |
| Final answer: a = 62 degrees | |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| 19 | B1cao |
| start at 3 and add 4 each time | B1oe |
| Final answer: 19 | Start at 3 and add 4 each time (oe) | |
| Question 5[2 marks] | |
|---|---|
| Answer or working | Marks |
| one correct bound identified, 23500 or 24500 | M1oe |
| 23500 <= P < 24500 | A1cao |
| Question 6[3 marks] | |
|---|---|
| Answer or working | Marks |
| 360 / 9 = 40 oe (one share found) | M1 |
| 40 x 5 (dep on first M1) | M1 |
| £200 | A1cao |
| Question 7[1 mark] | |
|---|---|
| Answer or working | Marks |
| A | B1 |
| Final answer: A (original number 90) | |
| Question 8[2 marks] | |
|---|---|
| Answer or working | Marks |
| recognise and state that y must be greater than 2x+1 and simultaneously less than 2x-1, giving inequality 2x+1 < y < 2x-1 or equivalent | M1 |
| conclude this is impossible because 2x+1 > 2x-1 for all x so there is no y satisfying both; therefore no solution | A1cao |
| Final answer: No solution. Algebraic explanation: the two inequalities require 2x + 1 < y < 2x - 1. But 2x + 1 > 2x - 1 for all x (since 1 > -1), so there is no value of y between these two conflicting bounds. | |
| Question 9[2 marks] | |
|---|---|
| Answer or working | Marks |
| use circumference = 2 pi r or pi d | M1 |
| 14 pi cm | A1cao |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| 504 / 1.12 | M1oe |
| 450 | A1cao |
| Question 11[5 marks] | |
|---|---|
| Answer or working | Marks |
| linear scale factor = 8/5 (=1.6) | M1 |
| area scale factor = 1.6^2 (=2.56); 130 x 2.56 | M1 |
| 332.8 cao (cm^2), awrt 333 | A1 |
| volume scale factor = 1.6^3 (=4.096); 150 x 4.096 | M1 |
| 614.4 cao (cm^3), awrt 614 | A1 |
| Final answer: 332.8 cm^2 | 614.4 cm^3 | |
| Question 12[2 marks] | |
|---|---|
| Answer or working | Marks |
| substitutes into 3x + 2y and shows 3(5) + 2(-2) = 15 - 4 = 11 | B1 |
| cso, substitutes into 2x - y and shows 2(5) - (-2) = 10 + 2 = 12 | B1 |
| Final answer: Both equations are satisfied (shown) | |
| Question 13[2 marks] | |
|---|---|
| Answer or working | Marks |
| substitute into V = 4/3 pi r^3, showing 4/3 * pi * 5^3 or equivalent method | M1 |
| 500/3 pi cm^3 | A1cao |
| Final answer: 500/3 pi cm^3 (approx 523.6 cm^3) | |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| 6x = 24 | M1oe |
| x = 4 | A1cao |
| Question 15[3 marks] | |
|---|---|
| Answer or working | Marks |
| finds the constant of proportionality k = nT = 3 x 100 (=300) | M1 |
| n = 300/40 (=7.5) | M1 |
| 8 pumps, with reasoning that the number of pumps must be a whole number and 7 pumps would take longer than 40 minutes | A1 |
| Final answer: 8 pumps | |
| Question 16[3 marks] | |
|---|---|
| Answer or working | Marks |
| r^2 = V / (pi x h) oe rearrangement | M1 |
| 15000 / (pi x 30) oe substitution, then square root | M1 |
| awrt 12.6 (units cm) | A1 |
| Final answer: 12.6 cm (1 d.p.) | |
| Question 17[3 marks] | |
|---|---|
| Answer or working | Marks |
| bearing of A from B = 060 + 180 = 240 | M1oe |
| (dep) 240 - 150 | M1oe |
| angle ABC = 90, so triangle ABC is right-angled at B | A1cso |
| Final answer: Angle ABC = 90 degrees, so triangle ABC is right-angled at B | |
| Question 18[2 marks] | |
|---|---|
| Answer or working | Marks |
| use arc length = 2 pi r * angle/360 or r * theta in radians | M1 |
| 4 pi m = 12.566... so 12.6 m | A1awrt |
| Final answer: 12.6 m | |
| Question 19[3 marks] | |
|---|---|
| Answer or working | Marks |
| 1.05^2 (= 1.1025), or 1.05 x 1.05 | M1 |
| 800 x their 1.1025 (dependent on correct multiplier) | M1 |
| 882 cso (answer given, full working shown) | A1 |
| Final answer: £882 (as given) | |
| Question 20[3 marks] | |
|---|---|
| Answer or working | Marks |
| 0 to 3 s | B1oe |
| 3 to 8 s | B1oe |
| 8 to 10 s | B1oe |
| Final answer: 0 to 3 s | 3 to 8 s | 8 to 10 s | |
| Question 21[4 marks] | |
|---|---|
| Answer or working | Marks |
| linear scale factor = 45/30 (=1.5) | M1 |
| volume (mass) scale factor = 1.5^3 (=3.375) | M1 |
| 12 x 3.375 | M1 |
| 40.5 (kg) | A1cao |
| Final answer: 40.5 kg | |
| Question 22[4 marks] | |
|---|---|
| Answer or working | Marks |
| calculate amounts for charity and equipment: 840 x 0.12 = 100.8 and 840 x 0.35 = 294 | M1 |
| subtract from total to get remainder: 840 - 100.8 - 294 = 445.2 | M1 |
| divide remainder by 2: 445.2 / 2 = 222.6 | M1 |
| 222.60 | A1cao |
| Question 23[2 marks] | |
|---|---|
| Answer or working | Marks |
| sqrt(9^2 + 12^2) | M1oe |
| 15 | A1cao |
| Question 24[5 marks] | |
|---|---|
| Answer or working | Marks |
| 25 minutes is 25/60 of a full turn | M1oe |
| angle = 150 degrees | A1 |
| (150/360) x pi x 8^2 | M1oe |
| 83.7... seen (awrt 83.8) | A1 |
| 83.8 cm^2 awrt | A1cao |
| Final answer: 83.8 cm^2 (3 s.f.) | |
| Question 25[2 marks] | |
|---|---|
| Answer or working | Marks |
| Even numbers written as 2n and 2m, product formed as 2n x 2m = 4nm | M1oe |
| Conclusion that 4nm is a multiple of 4 for integers n and m | A1cso |
| Final answer: 2n x 2m = 4nm, which is a multiple of 4 for all integers n and m. | |
| Question 26[3 marks] | |
|---|---|
| Answer or working | Marks |
| linear scale factor = cbrt(1000/27) (=10/3, awrt 3.33) | M1 |
| 9 x 10/3 | M1 |
| 30 cao, units cm | A1 |
| Final answer: 30 cm | |
| Question 27[3 marks] | |
|---|---|
| Answer or working | Marks |
| finds two numbers with sum -5 and product -14, namely -7 and 2 | M1 |
| (x - 7)(x + 2) [= 0] | A1cao |
| x = 7 and x = -2 both | A1cao |
| Final answer: x = 7 or x = -2 | |
| Question 28[3 marks] | |
|---|---|
| Answer or working | Marks |
| correct expressions for three consecutive terms, e.g. 6n - 1, 6n + 5, 6n + 11 | M1oe |
| correctly sums and simplifies to 18n + 15 | M1oe |
| factorises as 3(6n + 5) and concludes this is always a multiple of 3, since 6n + 5 is an integer | A1cso |
| Final answer: Proven: the sum is 3(6n + 5), which is always a multiple of 3. | |
| Question 29[4 marks] | |
|---|---|
| Answer or working | Marks |
| combined multiplier 1.3 x 0.7 = 0.91 oe (or an equivalent stepwise method) | M1 |
| complete method 109.20 / 0.91 | M1 |
| £120 | A1cao |
| ft states less than, since the combined multiplier 0.91 is less than 1 | B1 |
| Final answer: £120; the final sale price is less than the original price. | |
| Question 30[5 marks] | |
|---|---|
| Answer or working | Marks |
| squares both sides, e.g. T^2 = 2h/g | M1 |
| multiplies both sides by g, e.g. gT^2 = 2h | M1 |
| h = gT^2/2 oe | A1cao |
| substitutes g = 9.8 and T = 2 into the formula from part (a), ft, e.g. h = 9.8 x 2^2/2 | M1 |
| h = 19.6 (m) | A1cao |
| Final answer: h = gT^2/2 | h = 19.6 m | |