Foundation Tier - Year 10

OCR-Style Year 10 Foundation Paper 1

An OCR-style Year 10 Foundation Paper 1: 100 marks, 90 minutes, calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.

45 questions - 100 marks - calculator allowed

Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [1 marks]

Area, Volume and Measures

Convert 2 days to hours.

Question 2 [1 marks]

Angles and Geometrical Reasoning

A scale drawing is to be made of a school hall that is 30 m long in real life. Explain why a scale of 1 : 1 would not be sensible to use for this drawing.

Question 3 [1 marks]

Number and Calculation

Work out the missing number. 12 + ___ = 20

Question 4 [2 marks]

Linear Algebra

Solve 6x = -0.9

Question 5 [2 marks]

Sequences

Here are the first five terms of a sequence. 2, 5, 7, 12, 19

Explain how each term of the sequence, after the first two, is found from the previous two terms.

Work out the next term in the sequence.

Question 6 [2 marks]

Graphs and Coordinates

A student, Erin, says: 'If you translate a point 5 units up and then 5 units down, you always end up back at the point you started with, whatever point you start at.' Decide whether Erin is correct. Justify your answer with an example.

Question 7 [2 marks]

Ratio and Proportion

Given that 5:x = 15:24, work out the value of x.

Question 8 [2 marks]

Indices and Standard Form

Work out each cube root.

cbrt(-27)

cbrt(-1000)

Question 9 [3 marks]

Angles and Geometrical Reasoning

Quadrilateral WXYZ has angle W = 80 degrees, angle X = 95 degrees, angle Y = 110 degrees and angle Z = k. Work out the size of angle k.

Question 10 [6 marks]

Number and Calculation

m = -4, n = 3, k = -5

Work out m + nk

Work out (m - k)^2

Sam says: 'mk is definitely greater than m + k.' Determine, with working, whether Sam is correct.

Question 11 [4 marks]

Fractions, Decimals and Percentages

Simplify each fraction fully.

36/48

28/70

32/40

63/81

Question 12 [6 marks]

Number and Calculation

Priya and Tomasz are comparing scores in a quiz. A wrong answer scores negative points. Priya's scores in four rounds: -3, 5, -2, 6 Tomasz's scores in four rounds: 2, -1, 4, -3

Work out Priya's total score.

Work out Tomasz's total score.

Priya says: 'I scored more than double Tomasz's total.' Is Priya correct? Show working to justify your answer.

Question 13 [1 marks]

Area, Volume and Measures

Convert 74 millimetres to centimetres.

Question 14 [1 marks]

Number and Calculation

Work out 7 + 3 x 5.

Question 15 [1 marks]

Fractions, Decimals and Percentages

State an equivalent fraction to 7/8 that has numerator 21.

Question 16 [1 marks]

Angles and Geometrical Reasoning

On a scale drawing, 1 cm represents 40 m in real life. Write this scale as a ratio in the form 1:n.

Question 17 [1 marks]

Graphs and Coordinates

Write down the equation of the graph obtained by translating y = f(x) 2 units to the right.

Question 18 [1 marks]

Angles and Geometrical Reasoning

Reflect the point A(-1, 4) in the y-axis. Give the coordinates of the reflected point.

Question 19 [1 marks]

Sequences

Work out the 6th term of the sequence defined by nth term = 4n - 1.

Question 20 [1 marks]

Fractions, Decimals and Percentages

Write 125% as a decimal.

Question 21 [1 marks]

Angles and Geometrical Reasoning

Look at this description of a solid and its three elevations. - Plan (view from above): a 6 cm by 4 cm rectangle with a 2 cm by 2 cm square removed from one corner. - Front elevation: a rectangle 6 cm by 3 cm with a 2 cm square notch at the top right. - Side elevation: a rectangle 4 cm by 3 cm. Which of these statements must be true? Tick the correct answer. A. The solid has overall height 3 cm. B. The solid has a full 2 cm cube removed from its corner. C. The plan shows a hole all the way through the solid. D. The front elevation shows a triangular shape.

Question 22 [1 marks]

Area, Volume and Measures

A ferry leaves at 23:40. The next ferry leaves at 01:20. How long does a passenger wait for the next ferry?

Question 23 [1 marks]

Indices and Standard Form

Work out the value of 10^0.

Question 24 [1 marks]

Angles and Geometrical Reasoning

Translate point P(2, 3) by the vector (4, -1). Write down the coordinates of the image.

Question 25 [2 marks]

Number and Calculation

Complete a prime factor tree for 45 and write the prime factorisation.

Question 26 [2 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (-1, 6) and (3, -2).

Question 27 [2 marks]

Angles and Geometrical Reasoning

True or false? The locus of points equidistant from a fixed point F and a fixed line d is a parabola that can be constructed exactly using only compass and straightedge. Give a brief reason for your answer.

Question 28 [2 marks]

Fractions, Decimals and Percentages

Increase 160 by 35%.

Question 29 [2 marks]

Number and Calculation

Estimate 246 × 78 by rounding each number to 1 significant figure before multiplying.

Question 30 [2 marks]

Fractions, Decimals and Percentages

In a school raffle, 32 out of 72 tickets sold were bought by Year 11 students. Write the fraction of tickets bought by Year 11 students in its simplest form.

Question 31 [2 marks]

Indices and Standard Form

Simplify (4^2)^3 and give your answer as an ordinary number.

Question 32 [2 marks]

Angles and Geometrical Reasoning

A solid has a front elevation that is 8 cm wide and 6 cm high. The side elevation is 5 cm wide and 6 cm high. Work out the size of the plan (give length and width).

Question 33 [2 marks]

Indices and Standard Form

Simplify sqrt(180) giving your answer in simplest form.

Question 34 [3 marks]

Area, Volume and Measures

Small scented candles are cylinders with radius 2 cm and height 8 cm. A shop has a box with internal volume 5.0 litres. What is the maximum number of these candles that can fit in the box if only volume is considered? You may give an answer as a whole number.

Question 35 [3 marks]

Linear Algebra

A rectangle has length (x + 5) cm and width (x - 2) cm. The perimeter of the rectangle is 46 cm.

Question 36 [3 marks]

Number and Calculation

Aisha and Ben each go for a run. The table shows the distance each of them ran and the time each of them took. Runner | Distance (km) | Time (minutes) Aisha | 15 | 50 Ben | 21 | 60 Work out which runner had the greater average speed. You must show your working.

Question 37 [3 marks]

Fractions, Decimals and Percentages

A shop sets a selling price of £65 to make a 30% profit. Work out the cost price of the item to the shop.

Question 38 [3 marks]

Number and Calculation

Priya calculates (7 + 2) x 3^2 incorrectly as 7 + 2 x 3^2. Work out Priya's answer and the correct answer. Find the difference between the two answers.

Question 39 [3 marks]

Linear Algebra

Three angles lie on a straight line. The angles are x degrees, (2x + 8) degrees and (3x - 2) degrees.

Question 40 [3 marks]

Area, Volume and Measures

Triangle ABC is similar to triangle XYZ, with AB corresponding to XY and BC corresponding to YZ. AB = 8 cm, XY = 12 cm and BC = 10 cm.

Question 41 [3 marks]

Angles and Geometrical Reasoning

O is the origin. The position vectors of points A and B, relative to O, are a and b. M is the midpoint of AB.

Find the vector AB in terms of a and b.

Find the position vector of M in terms of a and b, giving your answer in its simplest form.

Question 42 [3 marks]

Area, Volume and Measures

Work out the circumference of a circle with radius 2.5 cm. Use pi = 3.14 and give your answer to 2 decimal places.

Question 43 [4 marks]

Linear Algebra

Three consecutive integers have a sum of 96. Let n be the smallest integer.

Form an equation in n and solve it.

Hence write down the three consecutive integers.

Question 44 [4 marks]

Ratio and Proportion

A gardener mixes fertiliser and water in the ratio 1 : 24 to make feed for tomato plants. He has 6 litres of fertiliser.

Work out the maximum volume of feed he can make using all 6 litres of fertiliser.

He decides to use only 250 ml of fertiliser at a time, mixed with water in the same ratio. Work out how many litres of water are needed for one 250 ml application.

Question 45 [3 marks]

Area, Volume and Measures

A hollow tube has outer radius 5 cm, inner radius 3 cm and height 10 cm. Work out the total curved surface area (sum of the inner and outer curved surfaces) of the tube. Give your answer in terms of pi.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
48 hoursB1cao
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
Correct reason, e.g. the drawing would have to be 30 m long (the same size as the real hall), which is too big to fit on a sheet of paperB1
Final answer: The drawing would be the same size as the real hall (30 m long), which is impractically large for a sheet of paper.
Mark scheme for Question 3 [1 mark]
Question 3[1 mark]
Answer or workingMarks
8B1cao
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
both sides divided by 6M1oe
x = -0.15 oeA1cao
Final answer: x = -0.15
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
each term is the sum of the two previous termsB1oe
31 cao, ft from their rule in part (a)B1
Final answer: Each term is found by adding the two previous terms together. | 31
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
correctB1cao
valid example showing the point returns to its start, e.g. starting at (2, 3): 5 up gives (2, 8), then 5 down gives (2, 3)B1
Final answer: Erin is correct. For example, starting at (2, 3): 5 up gives (2, 8), then 5 down from (2, 8) gives (2, 3), the original point.
Mark scheme for Question 7 [2 marks]
Question 7[2 marks]
Answer or workingMarks
sets up 5/15 = x/24 oe, or cross-multiplies 5 x 24 = 15xM1
x = 8A1cao
Mark scheme for Question 8 [2 marks]
Question 8[2 marks]
Answer or workingMarks
-3B1cao
-10B1cao
Final answer: -3 | -10
Mark scheme for Question 9 [3 marks]
Question 9[3 marks]
Answer or workingMarks
states angles in a quadrilateral sum to 360 (degrees)B1oe
360 - 80 - 95 - 110M1
k = 75A1cao
Final answer: k = 75 degrees
Mark scheme for Question 10 [6 marks]
Question 10[6 marks]
Answer or workingMarks
nk = 3 x (-5) = -15 seenM1
-19A1cao
m - k = -4 - (-5) = 1 seenM1
1A1cao
mk = (-4) x (-5) = 20 and m + k = -4 + (-5) = -9 both seenM1
correct conclusion with comparison shown, e.g. 'Yes, since 20 > -9'A1cso
Final answer: -19 | 1 | Yes, Sam is correct; mk = 20 and m + k = -9, and 20 is greater than -9.
Mark scheme for Question 11 [4 marks]
Question 11[4 marks]
Answer or workingMarks
3/4B1cao
2/5B1cao
4/5B1cao
7/9B1cao
Final answer: 3/4 | 2/5 | 4/5 | 7/9
Mark scheme for Question 12 [6 marks]
Question 12[6 marks]
Answer or workingMarks
-3 + 5 - 2 + 6 oe, or correct partial sum shownM1
6A1cao
2 - 1 + 4 - 3 oe, or correct partial sum shownM1
2A1cao
double of Tomasz's total found, 2 x 2 = 4, ft from (b)M1
correct conclusion with comparison shown, e.g. 'Yes, since 6 > 4' csoA1ft
Final answer: 6 | 2 | Yes, Priya is correct; double Tomasz's total is 4, and Priya's total of 6 is more than 4.
Mark scheme for Question 13 [1 mark]
Question 13[1 mark]
Answer or workingMarks
7.4 cmB1cao
Mark scheme for Question 14 [1 mark]
Question 14[1 mark]
Answer or workingMarks
22B1cao
Mark scheme for Question 15 [1 mark]
Question 15[1 mark]
Answer or workingMarks
21/24B1cao
Mark scheme for Question 16 [1 mark]
Question 16[1 mark]
Answer or workingMarks
1:4000B1cao
Mark scheme for Question 17 [1 mark]
Question 17[1 mark]
Answer or workingMarks
y = f(x - 2)B1cao
Mark scheme for Question 18 [1 mark]
Question 18[1 mark]
Answer or workingMarks
1, 4B1cao
Final answer: (1, 4)
Mark scheme for Question 19 [1 mark]
Question 19[1 mark]
Answer or workingMarks
23B1cao
Mark scheme for Question 20 [1 mark]
Question 20[1 mark]
Answer or workingMarks
1.25B1cao
Mark scheme for Question 21 [1 mark]
Question 21[1 mark]
Answer or workingMarks
AB1cao
Mark scheme for Question 22 [1 mark]
Question 22[1 mark]
Answer or workingMarks
1 hour 40 minutesB1cao
Mark scheme for Question 23 [1 mark]
Question 23[1 mark]
Answer or workingMarks
1 cao (any non-zero number to the power 0 is 1)B1
Final answer: 1
Mark scheme for Question 24 [1 mark]
Question 24[1 mark]
Answer or workingMarks
6, 2B1cao
Final answer: (6, 2)
Mark scheme for Question 25 [2 marks]
Question 25[2 marks]
Answer or workingMarks
correct factor tree or method shown, e.g. 45 = 9 * 5, 9 = 3 * 3M1
3^2 * 5A1cao
Mark scheme for Question 26 [2 marks]
Question 26[2 marks]
Answer or workingMarks
(-2 - 6)/(3 - (-1)), oe substitution into the gradient formula with correct signsM1
-2A1cao
Mark scheme for Question 27 [2 marks]
Question 27[2 marks]
Answer or workingMarks
false, because the parabola is a quadratic locus and cannot be constructed exactly with a finite sequence of compass-and-straightedge stepsB1oe
give reason: construction of a full parabola requires plotting many points or higher-order methods, not a single compass-and-straightedge procedureB1oe
Final answer: False. The parabola is a continuous quadratic locus and cannot be constructed exactly by a finite straightedge-and-compass procedure; it is usually drawn by plotting many points.
Mark scheme for Question 28 [2 marks]
Question 28[2 marks]
Answer or workingMarks
1.35 x 160 (oe: 35% of 160 = 56)M1
216A1
Mark scheme for Question 29 [2 marks]
Question 29[2 marks]
Answer or workingMarks
round 246->200 and 78->80 to 1 s.f. and multiplyM1oe
16000A1cao
Mark scheme for Question 30 [2 marks]
Question 30[2 marks]
Answer or workingMarks
divide numerator and denominator by a common factor, e.g. 8M1oe
4/9A1cao
Mark scheme for Question 31 [2 marks]
Question 31[2 marks]
Answer or workingMarks
use index law (a^m)^n = a^(mn) to get 4^(2x3) = 4^6M1
4096A1cao
Final answer: 4096 ((4^2)^3 = 4^6 = 4096).
Mark scheme for Question 32 [2 marks]
Question 32[2 marks]
Answer or workingMarks
identify plan shows the two horizontal dimensions: 8 cm and 5 cmM1oe
8 cm by 5 cmA1cao
Final answer: Plan dimensions are 8 cm by 5 cm (length 8 cm, width 5 cm).
Mark scheme for Question 33 [2 marks]
Question 33[2 marks]
Answer or workingMarks
factor 180 as 36 x 5 and take square root of square factorM1
6 sqrt(5)A1cao
Final answer: 6 sqrt(5) (sqrt(180) = sqrt(36 x 5) = 6 sqrt(5)).
Mark scheme for Question 34 [3 marks]
Question 34[3 marks]
Answer or workingMarks
calculate volume of one candle: V = pi * 2^2 * 8 = 32pi cm^3M1
convert box volume to cm^3: 5.0 litres = 5000 cm^3 and divide: 5000 / (32pi) = 49.75...M1
49 candles (whole number, floor of 49.75...)A1
Final answer: 49
Mark scheme for Question 35 [3 marks]
Question 35[3 marks]
Answer or workingMarks
correct equation formed, 2(x+5) + 2(x-2) = 46 oe, or 4x + 6 = 46M1
correct method to solve, 4x = 40M1oe
x = 10A1cao
Mark scheme for Question 36 [3 marks]
Question 36[3 marks]
Answer or workingMarks
finds Aisha's average speed: 15 / (50/60) = 18 km/hM1oe
finds Ben's average speed: 21 / (60/60) = 21 km/hM1oe
correct conclusion that Ben has the greater average speed (21 km/h > 18 km/h)A1cao
Final answer: Ben has the greater average speed (21 km/h compared with Aisha's 18 km/h). Working check: Aisha 15 / (50/60) = 18; Ben 21 / (60/60) = 21.
Mark scheme for Question 37 [3 marks]
Question 37[3 marks]
Answer or workingMarks
recognise selling price = cost * 1.30M1
divide 65 by 1.3 shownM1
50A1cao
Final answer: £50 cao
Mark scheme for Question 38 [3 marks]
Question 38[3 marks]
Answer or workingMarks
show Priya's method 7 + (2 x 3^2) and evaluate to 25M1
show correct method (7 + 2) x 3^2 and evaluate to 81M1
difference 56A1cao
Final answer: Priya's answer 25; correct answer 81; difference 56
Mark scheme for Question 39 [3 marks]
Question 39[3 marks]
Answer or workingMarks
correct equation formed, x + (2x+8) + (3x-2) = 180M1oe
correct simplification, 6x + 6 = 180M1oe
x = 29A1cao
Mark scheme for Question 40 [3 marks]
Question 40[3 marks]
Answer or workingMarks
scale factor = 12/8 oe (= 1.5 or 3/2)M1
10 x their scale factorM1
15 (cm)A1cao
Final answer: 15 cm
Mark scheme for Question 41 [3 marks]
Question 41[3 marks]
Answer or workingMarks
b - aB1cao
OM = a + (1/2)(b - a) or OM = (1/2)(a + b), correct methodM1
(1/2)(a + b) oe, e.g. (a+b)/2A1
Final answer: AB = b - a | OM = (a + b)/2
Mark scheme for Question 42 [3 marks]
Question 42[3 marks]
Answer or workingMarks
use C = 2 * pi * r, substitution: 2 * 3.14 * 2.5M1
15.7 cm cao (2 * 3.14 * 2.5 = 15.7)A1
answer to 2 dp 15.70 cmA1awrt
Final answer: 15.70 cm
Mark scheme for Question 43 [4 marks]
Question 43[4 marks]
Answer or workingMarks
correct equation, n + (n+1) + (n+2) = 96 oe, or 3n + 3 = 96B1
n = 31A1cao
correct method, n+1 and n+2 foundM1ft
31, 32 and 33 allA1cao
Final answer: n = 31 | 31, 32, 33
Mark scheme for Question 44 [4 marks]
Question 44[4 marks]
Answer or workingMarks
total parts = 1 + 24 = 25, so 6 x 25M1oe
150 litresA1cao
250 x 24M1oe
6 litres (cao, accept 6000 ml)A1
Final answer: 150 litres | 6 litres
Mark scheme for Question 45 [3 marks]
Question 45[3 marks]
Answer or workingMarks
use curved surface areas: 2pi * R * h + 2pi * r * h = 2pi * (R + r) * hM1
substitute R = 5, r = 3, h = 10 to get 2pi * (5 + 3) * 10 = 160piM1
160pi cm^2A1cao