Higher Tier - Year 10

OCR-Style Year 10 Higher Paper 1

An OCR-style Year 10 Higher Paper 1: 100 marks, 90 minutes, calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.

40 questions - 100 marks - calculator allowed

Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [1 marks]

Indices and Standard Form

Write the number 0.0032 in standard form.

Question 2 [1 marks]

Angles and Geometrical Reasoning

State, in degrees, the sum of the interior angles of a triangle.

Question 3 [1 marks]

Linear Algebra

Solve 8 + x = 15

Question 4 [2 marks]

Ratio and Proportion

A rectangular garden bed has length 24 m and width 18 m. Write the ratio of length to width in its simplest form.

Question 5 [2 marks]

Area, Volume and Measures

A cuboid has length 9 cm, width 6 cm and height 4 cm. Work out the volume of the cuboid.

Question 6 [2 marks]

Sequences

Here are the first four terms of a sequence. 2, 6, 10, 14

Write down the next two terms of the sequence.

Describe, in words, the term-to-term rule for the sequence.

Question 7 [3 marks]

Fractions, Decimals and Percentages

(Non-calculator)

Write 45% as a decimal.

Write 3/4 as a percentage.

Write 0.2 as a percentage.

Question 8 [1 marks]

Number and Calculation

Write down the bounds for a number given as 5, correct to 1 significant figure, using inequality notation.

Question 9 [1 marks]

Fractions, Decimals and Percentages

Work out 1/6 of 42.

Question 10 [1 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (5, -2) and (5, 6).

Question 11 [1 marks]

Area, Volume and Measures

Work out the area of a square with side length 7 cm.

Question 12 [1 marks]

Indices and Standard Form

Work out 9^(1/2).

Question 13 [1 marks]

Fractions, Decimals and Percentages

A price is increased by 12%. State the single decimal multiplier used to find the new price directly from the original price.

Question 14 [1 marks]

Graphs and Coordinates

Plot the point with coordinates (3, -2) on a pair of axes.

Question 15 [1 marks]

Angles and Geometrical Reasoning

Work out the missing angle. On a straight line the two adjacent angles are 46 degrees and x. Find x.

Question 16 [2 marks]

Linear Algebra

Make x the subject of the formula: y = (x - 5)/3

Question 17 [2 marks]

Graphs and Coordinates

P has coordinates (-2, 3) and Q has coordinates (6, -9). Find the coordinates of the midpoint of PQ.

Question 18 [2 marks]

Linear Algebra

Simplify (6x^3) / (3x).

Question 19 [3 marks]

Number and Calculation

A cyclist travels 45 km, correct to the nearest km, in a time of 2 hours, correct to the nearest 0.5 hours. Work out the lower bound for the average speed of the cyclist. Give your answer correct to 3 significant figures.

Question 20 [2 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (1, 1) and (4, 7).

Question 21 [2 marks]

Linear Algebra

Solve 5 - 2x = 1 Show your working.

Question 22 [2 marks]

Fractions, Decimals and Percentages

A car is worth £12,000. It depreciates by 10% each year. Find its value after 2 years.

Question 23 [2 marks]

Graphs and Coordinates

The graph of y = x^3 - 7x passes through the point (2, -6).

Show that (2, -6) lies on the curve.

Use the symmetry of the graph to write down another point on the curve.

Question 24 [3 marks]

Number and Calculation

Calculate 46.8 x 3.25. Give your answer rounded to 2 decimal places. Then estimate the product by rounding each number to 1 significant figure and say whether your rounded answer is reasonable.

Question 25 [2 marks]

Graphs and Coordinates

Plot the three points from the table on graph paper and draw the straight line joining them. x: 0, 1, 2 y: 0, 3, 6

Question 26 [3 marks]

Fractions, Decimals and Percentages

A car service costs £96, including VAT at 20%. Work out the cost of the service before VAT was added.

Question 27 [3 marks]

Ratio and Proportion

An alloy is made from copper and tin in the ratio 7 : 3 by mass. A sample of the alloy has a mass of 450 g. Work out the mass of copper in the sample.

Question 28 [4 marks]

Linear Algebra

Make t the subject of s = vt + 0.5 a t^2. Give your answer in terms of s, v and a.

Question 29 [4 marks]

Ratio and Proportion

A map uses a scale of 1 cm to 7.5 km. A cyclist plans a route that is proportional to the straight-line distance. On the map the route would be 28 cm. Calculate the real distance and then the time taken if the cyclist rides at an average speed of 18 km/h. Give the time in hours and minutes, correct to the nearest minute.

Question 30 [4 marks]

Angles and Geometrical Reasoning

Triangle ABC has vertices A(3,4), B(5,4) and C(3,6). Triangle ABC is enlarged by scale factor -3, centre (1,2), to give triangle A'B'C'. Find the coordinates of A', B' and C'.

Question 31 [4 marks]

Area, Volume and Measures

A pipe is a hollow cylinder with outer radius 8 cm and inner radius 6 cm. The pipe is 50 cm long. Diagram: hollow cylindrical pipe, outer radius 8 cm, inner radius 6 cm, length 50 cm. Work out the volume of material used to make the pipe. Give your answer correct to 3 significant figures.

Question 32 [5 marks]

Graphs and Coordinates

Find the equation of the perpendicular bisector of the line segment joining (1, 1) and (5, 3). Give your answer in the form y = mx + c.

Question 33 [5 marks]

Area, Volume and Measures

Freya drives a distance of 175 miles. You are given that 5 miles is approximately 8 km. The journey takes 2 hours 30 minutes.

Work out the distance in kilometres.

Work out Freya's average speed for the journey in km/h.

Question 34 [1 marks]

Graphs and Coordinates

The graph of y = f(x) is transformed to give the graph of y = f(x) + 4. Which of the following correctly describes this transformation?

Question 35 [2 marks]

Linear Algebra

Simplify fully (x^2 - 9)/(x + 3)

Question 36 [4 marks]

Area, Volume and Measures

Vase P and vase Q are mathematically similar. The volume of vase P is 250 cm^3 and the volume of vase Q is 500 cm^3. The height of vase P is 18 cm.

Question 37 [4 marks]

Linear Algebra

Prove algebraically that the sum of any four consecutive integers is always even, but is never a multiple of 4.

Question 38 [4 marks]

Graphs and Coordinates

Line L1 passes through the points A(2, 5) and B(8, k). Line L2 has equation 3x + y = 12 and is perpendicular to L1. Find the value of k.

Question 39 [5 marks]

Angles and Geometrical Reasoning

Let sum(n) = (n - 2) * 180 be the sum of the interior angles of a polygon with n sides.

Prove algebraically that sum(n + 1) - sum(n) = 180 for every whole number n, showing that increasing the number of sides of a polygon by 1 always increases the sum of its interior angles by exactly 180 degrees.

A polygon with 22 sides has an interior angle sum of 3600 degrees. Using the result from part (a), write down the sum of the interior angles of a polygon with 23 sides.

Question 40 [6 marks]

Graphs and Coordinates

Priya and Tom start cycling from the same point at the same time and travel along the same straight road for 20 seconds. Priya accelerates uniformly from rest to a velocity of 10 m/s in the first 5 seconds, then travels at this constant velocity for the remaining 15 seconds. Tom cycles at a constant velocity of 8 m/s for the whole 20 seconds.

Calculate the distance Priya has travelled after 20 seconds.

Calculate the distance Tom has travelled after 20 seconds.

Determine which cyclist is further along the road after 20 seconds, and by how much.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
3.2 x 10^-3B1oe
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
180 (degrees)B1cao
Final answer: 180 degrees
Mark scheme for Question 3 [1 mark]
Question 3[1 mark]
Answer or workingMarks
x = 7B1cao
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
identify a common factor of 24 and 18 (e.g. 6)M1oe
4:3A1cao
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
correct substitution into V = l x w x h, e.g. 9 x 6 x 4M1oe
216 cm^3A1cao
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
18 and 22 both correctB1oe
start at 2 and add 4 each timeB1oe
Final answer: 18, 22 | Start at 2 and add 4 each time (oe).
Mark scheme for Question 7 [3 marks]
Question 7[3 marks]
Answer or workingMarks
0.45B1
75%B1
20%B1
Final answer: 0.45 | 75% | 20%
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
4.5 <= x < 5.5B1cao
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
7B1cao
Mark scheme for Question 10 [1 mark]
Question 10[1 mark]
Answer or workingMarks
undefined (the line is vertical)B1oe
Final answer: Undefined (vertical line)
Mark scheme for Question 11 [1 mark]
Question 11[1 mark]
Answer or workingMarks
49 cm^2B1cao
Final answer: 49 cm^2 (or 49)
Mark scheme for Question 12 [1 mark]
Question 12[1 mark]
Answer or workingMarks
3B1cao
Mark scheme for Question 13 [1 mark]
Question 13[1 mark]
Answer or workingMarks
1.12B1oe
Mark scheme for Question 14 [1 mark]
Question 14[1 mark]
Answer or workingMarks
point plotted at (3, -2) within tolerance (correct quadrant and position)B1oe
Final answer: (3, -2)
Mark scheme for Question 15 [1 mark]
Question 15[1 mark]
Answer or workingMarks
134 degreesB1cao
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
multiplies both sides by 3, e.g. 3y = x - 5M1
x = 3y + 5 oeA1cao
Final answer: x = 3y + 5
Mark scheme for Question 17 [2 marks]
Question 17[2 marks]
Answer or workingMarks
correct use of the midpoint formula ((x1+x2)/2, (y1+y2)/2)M1
(2, -3)A1cao
Mark scheme for Question 18 [2 marks]
Question 18[2 marks]
Answer or workingMarks
divide coefficients 6/3 and subtract indices 3 - 1M1
2x^2A1cao
Final answer: 2x^2 (cao)
Mark scheme for Question 19 [3 marks]
Question 19[3 marks]
Answer or workingMarks
lower bound of distance = 44.5 and upper bound of time = 2.25M1oe
dep 44.5 / 2.25M1oe
19.8 (km/h) awrt, ft from correct boundsA1
Final answer: 19.8 km/h (awrt)
Mark scheme for Question 20 [2 marks]
Question 20[2 marks]
Answer or workingMarks
(7 - 1)/(4 - 1), oe substitution into the gradient formulaM1
2A1cao
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
-2x = -4 or 2x = 4M1oe
x = 2A1cao
Mark scheme for Question 22 [2 marks]
Question 22[2 marks]
Answer or workingMarks
12000 * 0.9^2M1oe
9720A1cao
Final answer: £9,720
Mark scheme for Question 23 [2 marks]
Question 23[2 marks]
Answer or workingMarks
substitutes x=2 to get y = 8-14 = -6, confirming the point lies on the curveB1
(-2, 6), by the rotational symmetry of a cubic of this form about the originB1oe
Final answer: 2^3 - 7(2) = 8 - 14 = -6, so (2,-6) lies on the curve | (-2, 6)
Mark scheme for Question 24 [3 marks]
Question 24[3 marks]
Answer or workingMarks
correct calculation of product, e.g. 46.8 x 3.25 = 152.1 or method shownM1
152.10A1cao
estimation: 50 x 3 = 150 and conclusion that 152.10 is reasonableB1oe
Mark scheme for Question 25 [2 marks]
Question 25[2 marks]
Answer or workingMarks
at least two points plotted correctly and a straight line drawn through themM1oe
all three points plotted accurately and correct straight lineA1cao
Final answer: Line with equation y = 3x, passing through (0,0), (1,3), (2,6).
Mark scheme for Question 26 [3 marks]
Question 26[3 marks]
Answer or workingMarks
correct multiplier 1.20M1oe
complete method 96 / 1.2M1
£80A1cao
Mark scheme for Question 27 [3 marks]
Question 27[3 marks]
Answer or workingMarks
total parts = 7 + 3 = 10M1
450 / 10 = 45 (value of one part)M1
315 gA1cao
Mark scheme for Question 28 [4 marks]
Question 28[4 marks]
Answer or workingMarks
rearrange to quadratic form 0.5 a t^2 + v t - s = 0 (or multiply by 2 to a t^2 + 2v t - 2s = 0)M1
identify coefficients and use quadratic formulaM1
substitute and simplify the discriminant to v^2 + 2asM1
t = [ -v +/- sqrt(v^2 + 2as) ] / aA1cao
Mark scheme for Question 29 [4 marks]
Question 29[4 marks]
Answer or workingMarks
convert map length to real distance: distance = 28 * 7.5 kmM1
210 kmA1cao
use time = distance / speed: 210 / 18 hoursM1
11 hours 40 minutesA1cao
Final answer: 210 km and 11 hours 40 minutes. Working: distance = 28 * 7.5 = 210 km. Time = 210 / 18 = 11.666... hours = 11 hours + 0.666...*60 = 11 hours 40 minutes. Check: 18 * 11.666... = 210.
Mark scheme for Question 30 [4 marks]
Question 30[4 marks]
Answer or workingMarks
correct vector method used for at least one vertex, e.g. (A - centre) x -3, then + centreM1
A'(-5,-4)A1
B'(-11,-4)A1
C'(-5,-10)A1cao
Final answer: A'(-5,-4), B'(-11,-4), C'(-5,-10)
Mark scheme for Question 31 [4 marks]
Question 31[4 marks]
Answer or workingMarks
8^2 - 6^2 (= 28), area of cross-section of the materialM1oe
pi x 28 oe (= 28pi)M1
their area x 50 oe (= 1400pi)M1
awrt 4400 (units cm^3)A1
Final answer: 4400 cm^3 (3 s.f.)
Mark scheme for Question 32 [5 marks]
Question 32[5 marks]
Answer or workingMarks
find midpoint ( (1+5)/2, (1+3)/2 ) = (3, 2 )M1
find gradient of segment = (3 - 1)/(5 - 1) = 2/4 = 1/2M1
perpendicular gradient = -2M1
form equation y - 2 = -2(x - 3)M1
y = -2x + 8A1cao
Mark scheme for Question 33 [5 marks]
Question 33[5 marks]
Answer or workingMarks
175 / 5 x 8, or equivalent scalingM1
280 (km)A1cao
converts 2 hours 30 minutes to 2.5 hoursM1
their (a) / 2.5M1dep
112 (km/h)A1cao
Final answer: 280 km; 112 km/h
Mark scheme for Question 34 [1 mark]
Question 34[1 mark]
Answer or workingMarks
BB1
Mark scheme for Question 35 [2 marks]
Question 35[2 marks]
Answer or workingMarks
factorises the numerator, (x - 3)(x + 3)M1
x - 3 oe cao, (x + 3) cancelled correctlyA1
Final answer: x - 3
Mark scheme for Question 36 [4 marks]
Question 36[4 marks]
Answer or workingMarks
volume ratio = 500/250 (=2)M1
linear scale factor = cbrt(2)M1
18 x cbrt(2)M1
22.7 (cm)A1awrt
Final answer: 22.7 cm (awrt)
Mark scheme for Question 37 [4 marks]
Question 37[4 marks]
Answer or workingMarks
Four consecutive integers n, n+1, n+2, n+3 summed and simplified to 4n + 6M1
Factorised to 2(2n + 3), showing the sum is even (has factor 2)A1
2n + 3 identified as odd (2n is even, plus 3 is odd)M1
Conclusion: 2(2n+3) is even but, since 2n+3 is odd, it cannot be a multiple of 4A1cso
Final answer: n + (n+1) + (n+2) + (n+3) = 4n + 6 = 2(2n+3). This is even, but since 2n+3 is odd, the sum is never a multiple of 4.
Mark scheme for Question 38 [4 marks]
Question 38[4 marks]
Answer or workingMarks
rearranges 3x + y = 12 to find the gradient of L2 as -3M1
uses the perpendicular condition to find the gradient of L1 as 1/3, ft their gradient of L2M1
sets up (k - 5)/(8 - 2) = 1/3, oe, ft their gradient of L1M1
k = 7A1cao
Mark scheme for Question 39 [5 marks]
Question 39[5 marks]
Answer or workingMarks
sum(n + 1) = (n + 1 - 2) * 180 = (n - 1) * 180 stated or usedM1
sum(n + 1) - sum(n) = (n - 1) * 180 - (n - 2) * 180 expanded correctlyM1
= 180 * [(n - 1) - (n - 2)] = 180 * 1 = 180 (cso, answer given, all algebra must be shown)A1
3600 + 180 (ft use of the 180 degree increase per extra side from part (a))M1
3780 (degrees)A1cao
Final answer: sum(n + 1) - sum(n) = 180 (proven) | 3780 degrees
Mark scheme for Question 40 [6 marks]
Question 40[6 marks]
Answer or workingMarks
0.5 x 5 x 10 (= 25)M1
10 x 15 (= 150), and adds to the triangle areaM1
175 (m)A1cao
160 (m)B1
175 - 160 (ft from (a) and (b))M1
Priya, by 15 (m)A1cao
Final answer: 175 m | 160 m | Priya, by 15 m