OCR-Style Year 10 Higher Paper 1
An OCR-style Year 10 Higher Paper 1: 100 marks, 90 minutes, calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.
Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [1 marks]
Indices and Standard Form
Write the number 0.0032 in standard form.
Question 2 [1 marks]
Angles and Geometrical Reasoning
State, in degrees, the sum of the interior angles of a triangle.
Question 3 [1 marks]
Linear Algebra
Solve 8 + x = 15
Question 4 [2 marks]
Ratio and Proportion
A rectangular garden bed has length 24 m and width 18 m. Write the ratio of length to width in its simplest form.
Question 5 [2 marks]
Area, Volume and Measures
A cuboid has length 9 cm, width 6 cm and height 4 cm. Work out the volume of the cuboid.
Question 6 [2 marks]
Sequences
Here are the first four terms of a sequence. 2, 6, 10, 14
Write down the next two terms of the sequence.
Describe, in words, the term-to-term rule for the sequence.
Question 7 [3 marks]
Fractions, Decimals and Percentages
(Non-calculator)
Write 45% as a decimal.
Write 3/4 as a percentage.
Write 0.2 as a percentage.
Question 8 [1 marks]
Number and Calculation
Write down the bounds for a number given as 5, correct to 1 significant figure, using inequality notation.
Question 9 [1 marks]
Fractions, Decimals and Percentages
Work out 1/6 of 42.
Question 10 [1 marks]
Graphs and Coordinates
Find the gradient of the straight line joining the points (5, -2) and (5, 6).
Question 11 [1 marks]
Area, Volume and Measures
Work out the area of a square with side length 7 cm.
Question 12 [1 marks]
Indices and Standard Form
Work out 9^(1/2).
Question 13 [1 marks]
Fractions, Decimals and Percentages
A price is increased by 12%. State the single decimal multiplier used to find the new price directly from the original price.
Question 14 [1 marks]
Graphs and Coordinates
Plot the point with coordinates (3, -2) on a pair of axes.
Question 15 [1 marks]
Angles and Geometrical Reasoning
Work out the missing angle. On a straight line the two adjacent angles are 46 degrees and x. Find x.
Question 16 [2 marks]
Linear Algebra
Make x the subject of the formula: y = (x - 5)/3
Question 17 [2 marks]
Graphs and Coordinates
P has coordinates (-2, 3) and Q has coordinates (6, -9). Find the coordinates of the midpoint of PQ.
Question 18 [2 marks]
Linear Algebra
Simplify (6x^3) / (3x).
Question 19 [3 marks]
Number and Calculation
A cyclist travels 45 km, correct to the nearest km, in a time of 2 hours, correct to the nearest 0.5 hours. Work out the lower bound for the average speed of the cyclist. Give your answer correct to 3 significant figures.
Question 20 [2 marks]
Graphs and Coordinates
Find the gradient of the straight line joining the points (1, 1) and (4, 7).
Question 21 [2 marks]
Linear Algebra
Solve 5 - 2x = 1 Show your working.
Question 22 [2 marks]
Fractions, Decimals and Percentages
A car is worth £12,000. It depreciates by 10% each year. Find its value after 2 years.
Question 23 [2 marks]
Graphs and Coordinates
The graph of y = x^3 - 7x passes through the point (2, -6).
Show that (2, -6) lies on the curve.
Use the symmetry of the graph to write down another point on the curve.
Question 24 [3 marks]
Number and Calculation
Calculate 46.8 x 3.25. Give your answer rounded to 2 decimal places. Then estimate the product by rounding each number to 1 significant figure and say whether your rounded answer is reasonable.
Question 25 [2 marks]
Graphs and Coordinates
Plot the three points from the table on graph paper and draw the straight line joining them. x: 0, 1, 2 y: 0, 3, 6
Question 26 [3 marks]
Fractions, Decimals and Percentages
A car service costs £96, including VAT at 20%. Work out the cost of the service before VAT was added.
Question 27 [3 marks]
Ratio and Proportion
An alloy is made from copper and tin in the ratio 7 : 3 by mass. A sample of the alloy has a mass of 450 g. Work out the mass of copper in the sample.
Question 28 [4 marks]
Linear Algebra
Make t the subject of s = vt + 0.5 a t^2. Give your answer in terms of s, v and a.
Question 29 [4 marks]
Ratio and Proportion
A map uses a scale of 1 cm to 7.5 km. A cyclist plans a route that is proportional to the straight-line distance. On the map the route would be 28 cm. Calculate the real distance and then the time taken if the cyclist rides at an average speed of 18 km/h. Give the time in hours and minutes, correct to the nearest minute.
Question 30 [4 marks]
Angles and Geometrical Reasoning
Triangle ABC has vertices A(3,4), B(5,4) and C(3,6). Triangle ABC is enlarged by scale factor -3, centre (1,2), to give triangle A'B'C'. Find the coordinates of A', B' and C'.
Question 31 [4 marks]
Area, Volume and Measures
A pipe is a hollow cylinder with outer radius 8 cm and inner radius 6 cm. The pipe is 50 cm long. Diagram: hollow cylindrical pipe, outer radius 8 cm, inner radius 6 cm, length 50 cm. Work out the volume of material used to make the pipe. Give your answer correct to 3 significant figures.
Question 32 [5 marks]
Graphs and Coordinates
Find the equation of the perpendicular bisector of the line segment joining (1, 1) and (5, 3). Give your answer in the form y = mx + c.
Question 33 [5 marks]
Area, Volume and Measures
Freya drives a distance of 175 miles. You are given that 5 miles is approximately 8 km. The journey takes 2 hours 30 minutes.
Work out the distance in kilometres.
Work out Freya's average speed for the journey in km/h.
Question 34 [1 marks]
Graphs and Coordinates
The graph of y = f(x) is transformed to give the graph of y = f(x) + 4. Which of the following correctly describes this transformation?
Question 35 [2 marks]
Linear Algebra
Simplify fully (x^2 - 9)/(x + 3)
Question 36 [4 marks]
Area, Volume and Measures
Vase P and vase Q are mathematically similar. The volume of vase P is 250 cm^3 and the volume of vase Q is 500 cm^3. The height of vase P is 18 cm.
Question 37 [4 marks]
Linear Algebra
Prove algebraically that the sum of any four consecutive integers is always even, but is never a multiple of 4.
Question 38 [4 marks]
Graphs and Coordinates
Line L1 passes through the points A(2, 5) and B(8, k). Line L2 has equation 3x + y = 12 and is perpendicular to L1. Find the value of k.
Question 39 [5 marks]
Angles and Geometrical Reasoning
Let sum(n) = (n - 2) * 180 be the sum of the interior angles of a polygon with n sides.
Prove algebraically that sum(n + 1) - sum(n) = 180 for every whole number n, showing that increasing the number of sides of a polygon by 1 always increases the sum of its interior angles by exactly 180 degrees.
A polygon with 22 sides has an interior angle sum of 3600 degrees. Using the result from part (a), write down the sum of the interior angles of a polygon with 23 sides.
Question 40 [6 marks]
Graphs and Coordinates
Priya and Tom start cycling from the same point at the same time and travel along the same straight road for 20 seconds. Priya accelerates uniformly from rest to a velocity of 10 m/s in the first 5 seconds, then travels at this constant velocity for the remaining 15 seconds. Tom cycles at a constant velocity of 8 m/s for the whole 20 seconds.
Calculate the distance Priya has travelled after 20 seconds.
Calculate the distance Tom has travelled after 20 seconds.
Determine which cyclist is further along the road after 20 seconds, and by how much.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 3.2 x 10^-3 | B1oe |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| 180 (degrees) | B1cao |
| Final answer: 180 degrees | |
| Question 3[1 mark] | |
|---|---|
| Answer or working | Marks |
| x = 7 | B1cao |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| identify a common factor of 24 and 18 (e.g. 6) | M1oe |
| 4:3 | A1cao |
| Question 5[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct substitution into V = l x w x h, e.g. 9 x 6 x 4 | M1oe |
| 216 cm^3 | A1cao |
| Question 6[2 marks] | |
|---|---|
| Answer or working | Marks |
| 18 and 22 both correct | B1oe |
| start at 2 and add 4 each time | B1oe |
| Final answer: 18, 22 | Start at 2 and add 4 each time (oe). | |
| Question 7[3 marks] | |
|---|---|
| Answer or working | Marks |
| 0.45 | B1 |
| 75% | B1 |
| 20% | B1 |
| Final answer: 0.45 | 75% | 20% | |
| Question 8[1 mark] | |
|---|---|
| Answer or working | Marks |
| 4.5 <= x < 5.5 | B1cao |
| Question 9[1 mark] | |
|---|---|
| Answer or working | Marks |
| 7 | B1cao |
| Question 10[1 mark] | |
|---|---|
| Answer or working | Marks |
| undefined (the line is vertical) | B1oe |
| Final answer: Undefined (vertical line) | |
| Question 11[1 mark] | |
|---|---|
| Answer or working | Marks |
| 49 cm^2 | B1cao |
| Final answer: 49 cm^2 (or 49) | |
| Question 12[1 mark] | |
|---|---|
| Answer or working | Marks |
| 3 | B1cao |
| Question 13[1 mark] | |
|---|---|
| Answer or working | Marks |
| 1.12 | B1oe |
| Question 14[1 mark] | |
|---|---|
| Answer or working | Marks |
| point plotted at (3, -2) within tolerance (correct quadrant and position) | B1oe |
| Final answer: (3, -2) | |
| Question 15[1 mark] | |
|---|---|
| Answer or working | Marks |
| 134 degrees | B1cao |
| Question 16[2 marks] | |
|---|---|
| Answer or working | Marks |
| multiplies both sides by 3, e.g. 3y = x - 5 | M1 |
| x = 3y + 5 oe | A1cao |
| Final answer: x = 3y + 5 | |
| Question 17[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct use of the midpoint formula ((x1+x2)/2, (y1+y2)/2) | M1 |
| (2, -3) | A1cao |
| Question 18[2 marks] | |
|---|---|
| Answer or working | Marks |
| divide coefficients 6/3 and subtract indices 3 - 1 | M1 |
| 2x^2 | A1cao |
| Final answer: 2x^2 (cao) | |
| Question 19[3 marks] | |
|---|---|
| Answer or working | Marks |
| lower bound of distance = 44.5 and upper bound of time = 2.25 | M1oe |
| dep 44.5 / 2.25 | M1oe |
| 19.8 (km/h) awrt, ft from correct bounds | A1 |
| Final answer: 19.8 km/h (awrt) | |
| Question 20[2 marks] | |
|---|---|
| Answer or working | Marks |
| (7 - 1)/(4 - 1), oe substitution into the gradient formula | M1 |
| 2 | A1cao |
| Question 21[2 marks] | |
|---|---|
| Answer or working | Marks |
| -2x = -4 or 2x = 4 | M1oe |
| x = 2 | A1cao |
| Question 22[2 marks] | |
|---|---|
| Answer or working | Marks |
| 12000 * 0.9^2 | M1oe |
| 9720 | A1cao |
| Final answer: £9,720 | |
| Question 23[2 marks] | |
|---|---|
| Answer or working | Marks |
| substitutes x=2 to get y = 8-14 = -6, confirming the point lies on the curve | B1 |
| (-2, 6), by the rotational symmetry of a cubic of this form about the origin | B1oe |
| Final answer: 2^3 - 7(2) = 8 - 14 = -6, so (2,-6) lies on the curve | (-2, 6) | |
| Question 24[3 marks] | |
|---|---|
| Answer or working | Marks |
| correct calculation of product, e.g. 46.8 x 3.25 = 152.1 or method shown | M1 |
| 152.10 | A1cao |
| estimation: 50 x 3 = 150 and conclusion that 152.10 is reasonable | B1oe |
| Question 25[2 marks] | |
|---|---|
| Answer or working | Marks |
| at least two points plotted correctly and a straight line drawn through them | M1oe |
| all three points plotted accurately and correct straight line | A1cao |
| Final answer: Line with equation y = 3x, passing through (0,0), (1,3), (2,6). | |
| Question 26[3 marks] | |
|---|---|
| Answer or working | Marks |
| correct multiplier 1.20 | M1oe |
| complete method 96 / 1.2 | M1 |
| £80 | A1cao |
| Question 27[3 marks] | |
|---|---|
| Answer or working | Marks |
| total parts = 7 + 3 = 10 | M1 |
| 450 / 10 = 45 (value of one part) | M1 |
| 315 g | A1cao |
| Question 28[4 marks] | |
|---|---|
| Answer or working | Marks |
| rearrange to quadratic form 0.5 a t^2 + v t - s = 0 (or multiply by 2 to a t^2 + 2v t - 2s = 0) | M1 |
| identify coefficients and use quadratic formula | M1 |
| substitute and simplify the discriminant to v^2 + 2as | M1 |
| t = [ -v +/- sqrt(v^2 + 2as) ] / a | A1cao |
| Question 29[4 marks] | |
|---|---|
| Answer or working | Marks |
| convert map length to real distance: distance = 28 * 7.5 km | M1 |
| 210 km | A1cao |
| use time = distance / speed: 210 / 18 hours | M1 |
| 11 hours 40 minutes | A1cao |
| Final answer: 210 km and 11 hours 40 minutes. Working: distance = 28 * 7.5 = 210 km. Time = 210 / 18 = 11.666... hours = 11 hours + 0.666...*60 = 11 hours 40 minutes. Check: 18 * 11.666... = 210. | |
| Question 30[4 marks] | |
|---|---|
| Answer or working | Marks |
| correct vector method used for at least one vertex, e.g. (A - centre) x -3, then + centre | M1 |
| A'(-5,-4) | A1 |
| B'(-11,-4) | A1 |
| C'(-5,-10) | A1cao |
| Final answer: A'(-5,-4), B'(-11,-4), C'(-5,-10) | |
| Question 31[4 marks] | |
|---|---|
| Answer or working | Marks |
| 8^2 - 6^2 (= 28), area of cross-section of the material | M1oe |
| pi x 28 oe (= 28pi) | M1 |
| their area x 50 oe (= 1400pi) | M1 |
| awrt 4400 (units cm^3) | A1 |
| Final answer: 4400 cm^3 (3 s.f.) | |
| Question 32[5 marks] | |
|---|---|
| Answer or working | Marks |
| find midpoint ( (1+5)/2, (1+3)/2 ) = (3, 2 ) | M1 |
| find gradient of segment = (3 - 1)/(5 - 1) = 2/4 = 1/2 | M1 |
| perpendicular gradient = -2 | M1 |
| form equation y - 2 = -2(x - 3) | M1 |
| y = -2x + 8 | A1cao |
| Question 33[5 marks] | |
|---|---|
| Answer or working | Marks |
| 175 / 5 x 8, or equivalent scaling | M1 |
| 280 (km) | A1cao |
| converts 2 hours 30 minutes to 2.5 hours | M1 |
| their (a) / 2.5 | M1dep |
| 112 (km/h) | A1cao |
| Final answer: 280 km; 112 km/h | |
| Question 34[1 mark] | |
|---|---|
| Answer or working | Marks |
| B | B1 |
| Question 35[2 marks] | |
|---|---|
| Answer or working | Marks |
| factorises the numerator, (x - 3)(x + 3) | M1 |
| x - 3 oe cao, (x + 3) cancelled correctly | A1 |
| Final answer: x - 3 | |
| Question 36[4 marks] | |
|---|---|
| Answer or working | Marks |
| volume ratio = 500/250 (=2) | M1 |
| linear scale factor = cbrt(2) | M1 |
| 18 x cbrt(2) | M1 |
| 22.7 (cm) | A1awrt |
| Final answer: 22.7 cm (awrt) | |
| Question 37[4 marks] | |
|---|---|
| Answer or working | Marks |
| Four consecutive integers n, n+1, n+2, n+3 summed and simplified to 4n + 6 | M1 |
| Factorised to 2(2n + 3), showing the sum is even (has factor 2) | A1 |
| 2n + 3 identified as odd (2n is even, plus 3 is odd) | M1 |
| Conclusion: 2(2n+3) is even but, since 2n+3 is odd, it cannot be a multiple of 4 | A1cso |
| Final answer: n + (n+1) + (n+2) + (n+3) = 4n + 6 = 2(2n+3). This is even, but since 2n+3 is odd, the sum is never a multiple of 4. | |
| Question 38[4 marks] | |
|---|---|
| Answer or working | Marks |
| rearranges 3x + y = 12 to find the gradient of L2 as -3 | M1 |
| uses the perpendicular condition to find the gradient of L1 as 1/3, ft their gradient of L2 | M1 |
| sets up (k - 5)/(8 - 2) = 1/3, oe, ft their gradient of L1 | M1 |
| k = 7 | A1cao |
| Question 39[5 marks] | |
|---|---|
| Answer or working | Marks |
| sum(n + 1) = (n + 1 - 2) * 180 = (n - 1) * 180 stated or used | M1 |
| sum(n + 1) - sum(n) = (n - 1) * 180 - (n - 2) * 180 expanded correctly | M1 |
| = 180 * [(n - 1) - (n - 2)] = 180 * 1 = 180 (cso, answer given, all algebra must be shown) | A1 |
| 3600 + 180 (ft use of the 180 degree increase per extra side from part (a)) | M1 |
| 3780 (degrees) | A1cao |
| Final answer: sum(n + 1) - sum(n) = 180 (proven) | 3780 degrees | |
| Question 40[6 marks] | |
|---|---|
| Answer or working | Marks |
| 0.5 x 5 x 10 (= 25) | M1 |
| 10 x 15 (= 150), and adds to the triangle area | M1 |
| 175 (m) | A1cao |
| 160 (m) | B1 |
| 175 - 160 (ft from (a) and (b)) | M1 |
| Priya, by 15 (m) | A1cao |
| Final answer: 175 m | 160 m | Priya, by 15 m | |