OCR-Style Year 10 Higher Paper 2
An OCR-style Year 10 Higher Paper 2: 100 marks, 90 minutes, non-calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures. OCR's non-calculator paper is the middle paper of a sitting rather than the first, verified against OCR's own published question papers.
Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [1 marks]
Indices and Standard Form
Work out the value of 3^4.
Question 2 [1 marks]
Fractions, Decimals and Percentages
Write 0.4444... (4 recurring) as a fraction. You do not need to simplify or show any working.
Question 3 [1 marks]
Ratio and Proportion
The ratio of boys to girls in a class is 5:7. Write the number of boys as a fraction of the total number of pupils in the class.
Question 4 [1 marks]
Angles and Geometrical Reasoning
Point Q has coordinates (-2, 4). Write down the coordinates of the image of Q after a reflection in the y-axis.
Question 5 [1 marks]
Linear Algebra
Solve x + 7 = 15
Question 6 [3 marks]
Graphs and Coordinates
Complete the table of values for y = x^3 - 1. x : -2 , -1 , 0 , 1 , 2 y : -9 , _ , _ , _ , 7
Question 7 [1 marks]
Indices and Standard Form
Simplify p^5 * p^3.
Question 8 [1 marks]
Number and Calculation
Sam rolls two ordinary six-sided dice, one red and one blue. Work out the number of different outcomes possible.
Question 9 [1 marks]
Indices and Standard Form
Write 3.15 x 10^6 as an ordinary number.
Question 10 [2 marks]
Area, Volume and Measures
Two similar triangles have corresponding sides in the ratio 5:8. A side of the smaller triangle is 15 cm. Work out the length of the corresponding side in the larger triangle.
Question 11 [1 marks]
Indices and Standard Form
Simplify sqrt(75) fully.
Question 12 [1 marks]
Ratio and Proportion
A fruit drink is made from concentrate and water in the ratio 1:4. Write down what fraction of the drink is concentrate.
Question 13 [1 marks]
Indices and Standard Form
Write 2.06 x 10^-3 as an ordinary number.
Question 14 [2 marks]
Number and Calculation
Find the LCM of 9 and 15.
Question 15 [2 marks]
Linear Algebra
Solve 3(2x - 5) = 21
Question 16 [2 marks]
Number and Calculation
A PE kit is made from one shirt (4 colours available), one pair of shorts (3 colours available) and one pair of socks (2 colours available). Work out the number of different PE kits possible.
Question 17 [2 marks]
Angles and Geometrical Reasoning
Triangle A has vertices A(1, 2), B(4, 2) and C(1, 5). Describe fully the single transformation that maps triangle A to triangle A' with vertices A'(1, -2), B'(4, -2) and C'(1, -5).
Question 18 [2 marks]
Linear Algebra
a = 6 and c = 2. Work out the value of a^2 - c^2.
Question 19 [2 marks]
Graphs and Coordinates
Rearrange 3x + y = 11 into the form y = mx + c and state the gradient and the y-intercept.
Question 20 [2 marks]
Linear Algebra
Make x the subject of the formula: y = (x - 5)/3
Question 21 [2 marks]
Graphs and Coordinates
Find the gradient of the straight line joining the points (1, 1) and (4, 7).
Question 22 [4 marks]
Number and Calculation
a = 2^3 x 5 and b = 2^2 x 5^2.
Find the HCF of a and b.
Find the LCM of a and b.
Question 23 [2 marks]
Linear Algebra
p = -4 and q = 5. Work out the value of (p + q)^2.
Question 24 [2 marks]
Angles and Geometrical Reasoning
The point P has coordinates (2, 3). P is enlarged by scale factor -1, centre the origin O, to give the image P'. Find the coordinates of P'.
Question 25 [3 marks]
Ratio and Proportion
A bag contains only red counters and blue counters. The ratio of red counters to blue counters is 3:5. There are 40 counters in the bag altogether.
Write the number of red counters as a fraction of the total number of counters.
Work out the number of red counters in the bag.
Question 26 [3 marks]
Linear Algebra
P = 2x^2 - 3x + 1. Work out the value of P when x = -4, showing your working.
Question 27 [3 marks]
Angles and Geometrical Reasoning
v is the column vector (k, 4), where k > 0, and |v| = 5. Find the value of k.
Question 28 [3 marks]
Graphs and Coordinates
Show that the inverse of f(x) = 5x - 8 is f^{-1}(x) = (x + 8)/5. Give full working.
Question 29 [5 marks]
Sequences
Here are the first four terms of a geometric sequence. 5, 15, 45, 135
Find the common ratio of the sequence.
Find the 6th term of the sequence.
Explain whether 3000 is a term of the sequence.
Question 30 [2 marks]
Linear Algebra
Solve 4x + 3 = 23 Show your working.
Question 31 [7 marks]
Sequences
Arjun is training for a marathon. In week 1, he runs 8 km. Each week after that, he runs 3 km more than the week before.
Work out how far Arjun runs in week 6.
Find an expression, in terms of n, for the distance, in km, Arjun runs in week n.
Arjun wants to know the first week in which he will run at least 50 km. Find this week number.
Question 32 [3 marks]
Linear Algebra
Make x the subject of the formula: y = 5 - 2x^2
Question 33 [2 marks]
Graphs and Coordinates
A line has gradient -3/5. Find the gradient of a line perpendicular to it.
Question 34 [3 marks]
Linear Algebra
Simplify fully (x^2 + 3x - 10) / (x^2 - 4)
Question 35 [3 marks]
Graphs and Coordinates
A quadrilateral has vertices at A(0, 0), B(4, 2), C(6, -2) and D(2, -4). Show that AB is parallel to DC.
Question 36 [4 marks]
Number and Calculation
Find the smallest positive integer n such that n is a multiple of both 18 and 24, and n is also a perfect square.
Question 37 [3 marks]
Linear Algebra
Two resistors, with resistances a ohms and b ohms, are connected in parallel. Their combined resistance, x ohms, satisfies the formula 1/x = 1/a + 1/b. Make x the subject of the formula.
Question 38 [4 marks]
Angles and Geometrical Reasoning
A, B and C are points on the circumference of a circle with centre O. B lies on the minor arc AC. The reflex angle AOC = 264 degrees. Diagram: circle, centre O, points A, B and C on the circumference, B on the minor arc AC, the reflex angle AOC = 264 degrees marked at the centre going the long way round, angle ABC marked at B.
Work out the size of the non-reflex angle AOC.
Work out the size of angle ABC.
Question 39 [3 marks]
Linear Algebra
Expand and simplify (x + 3)(x - 3)(x + 2)
Question 40 [4 marks]
Angles and Geometrical Reasoning
In triangle OAB, O is the origin. OA = a and OB = b. F is the point on OA such that OF = (2/5)a. G is the point on AB such that AG : GB = 3 : 1.
Question 41 [5 marks]
Number and Calculation
A charity club has 8 members. Three different roles, chair, vice-chair and treasurer, are each given to a different member.
Work out the number of different ways the three roles can be given out.
The treasurer role must go to either Kwame or Sophie. Work out the number of different ways the three roles can now be given out.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 81 | B1cao |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| 4/9 | B1cao |
| Question 3[1 mark] | |
|---|---|
| Answer or working | Marks |
| 5/12 | B1oe |
| Question 4[1 mark] | |
|---|---|
| Answer or working | Marks |
| (2, 4) | B1cao |
| Question 5[1 mark] | |
|---|---|
| Answer or working | Marks |
| x = 8 | B1cao |
| Question 6[3 marks] | |
|---|---|
| Answer or working | Marks |
| y = -2 at x = -1 | B1 |
| y = -1 at x = 0 | B1 |
| y = 0 at x = 1 | B1 |
| Final answer: x = -1: y = -2; x = 0: y = -1; x = 1: y = 0 | |
| Question 7[1 mark] | |
|---|---|
| Answer or working | Marks |
| p^8 | B1cao |
| Question 8[1 mark] | |
|---|---|
| Answer or working | Marks |
| 36 | B1cao |
| Question 9[1 mark] | |
|---|---|
| Answer or working | Marks |
| 3150000 | B1cao |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| multiply 15 by scale factor 8/5 or show equivalent method | M1 |
| 24 cm | A1cao |
| Final answer: 24 cm, because 15 x (8/5) = 24 (scale factor 8/5). | |
| Question 11[1 mark] | |
|---|---|
| Answer or working | Marks |
| 5sqrt(3) oe | B1cao |
| Final answer: 5sqrt(3) | |
| Question 12[1 mark] | |
|---|---|
| Answer or working | Marks |
| 1/5 | B1oe |
| Question 13[1 mark] | |
|---|---|
| Answer or working | Marks |
| 0.00206 | B1cao |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| 9 = 3^2 and 15 = 3 x 5, or a correct list of multiples of each number | M1 |
| 45 | A1cao |
| Question 15[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct method, e.g. expand to 6x - 15 = 21 oe, or divide first to 2x - 5 = 7 | M1oe |
| x = 6 | A1cao |
| Question 16[2 marks] | |
|---|---|
| Answer or working | Marks |
| 4 * 3 * 2 oe seen | M1 |
| 24 | A1cao |
| Question 17[2 marks] | |
|---|---|
| Answer or working | Marks |
| state reflection in the x-axis | B1oe |
| fully described mapping (x, y) -> (x, -y) or equivalent | B1cao |
| Final answer: Reflection in the x-axis. (x, y) -> (x, -y). | |
| Question 18[2 marks] | |
|---|---|
| Answer or working | Marks |
| a^2 = 36 and c^2 = 4 both evaluated | M1oe |
| 32 | A1cao |
| Question 19[2 marks] | |
|---|---|
| Answer or working | Marks |
| subtracts 3x from both sides | M1oe |
| gradient -3 and y-intercept 11 both stated correctly | A1cao |
| Final answer: Gradient = -3, y-intercept = 11 | |
| Question 20[2 marks] | |
|---|---|
| Answer or working | Marks |
| multiplies both sides by 3, e.g. 3y = x - 5 | M1 |
| x = 3y + 5 oe | A1cao |
| Final answer: x = 3y + 5 | |
| Question 21[2 marks] | |
|---|---|
| Answer or working | Marks |
| (7 - 1)/(4 - 1), oe substitution into the gradient formula | M1 |
| 2 | A1cao |
| Question 22[4 marks] | |
|---|---|
| Answer or working | Marks |
| correct lowest power of each common prime identified, 2^2 and 5^1 | M1 |
| 20 | A1cao |
| correct highest power of each prime identified, 2^3 and 5^2 | M1 |
| 200 | A1cao |
| Final answer: 20 | 200 | |
| Question 23[2 marks] | |
|---|---|
| Answer or working | Marks |
| p + q = 1 seen | M1oe |
| 1 | A1cao |
| Question 24[2 marks] | |
|---|---|
| Answer or working | Marks |
| P' = -1 * (2, 3) oe, or correct use of the enlargement formula | M1 |
| (-2, -3) | A1cao |
| Question 25[3 marks] | |
|---|---|
| Answer or working | Marks |
| 3/8 | B1oe |
| 40 / 8 (= 5), ft their fraction from (a) | M1 |
| 15 | A1cao |
| Final answer: 3/8 | 15 | |
| Question 26[3 marks] | |
|---|---|
| Answer or working | Marks |
| 2 x (-4)^2 (= 32) seen | M1oe |
| -3 x (-4) (= 12) seen, correctly signed | dM1 |
| 45 | A1cao |
| Question 27[3 marks] | |
|---|---|
| Answer or working | Marks |
| k^2 + 4^2 = 5^2 | M1oe |
| dep: k^2 = 9 | M1 |
| k = 3 cao (rejects k = -3 since k > 0) | A1 |
| Final answer: k = 3 | |
| Question 28[3 marks] | |
|---|---|
| Answer or working | Marks |
| set y = 5x - 8 and swap x and y or equivalent | M1 |
| rearrange to get x = 5y - 8 then solve y = (x + 8)/5 | M1 |
| f^{-1}(x) = (x + 8)/5 | A1cso |
| Question 29[5 marks] | |
|---|---|
| Answer or working | Marks |
| 3 | B1cao |
| 5 x 3^5 oe, or lists terms up to the 6th | M1 |
| 1215 | A1cao |
| identifies the two terms either side of 3000 (1215 and 3645), or sets up 5 x 3^(n-1) = 3000 | M1oe |
| correct conclusion: no, 3000 is not a term, e.g. it lies strictly between 1215 and 3645 | A1oe |
| Final answer: 3 | 1215 | No, 3000 is not a term of the sequence | |
| Question 30[2 marks] | |
|---|---|
| Answer or working | Marks |
| 4x = 20 | M1oe |
| x = 5 | A1cao |
| Question 31[7 marks] | |
|---|---|
| Answer or working | Marks |
| 8 + 5 x 3 oe, or lists terms up to week 6 | M1 |
| 23 km | A1cao |
| common difference of 3 used correctly, e.g. 3n + c | M1oe |
| 3n + 5 oe | A1cao |
| 3n + 5 >= 50 oe (ft their expression) | M1 |
| 3n >= 45 oe, leading to n >= 15 | M1 |
| week 15 | A1cao |
| Final answer: 23 km | 3n + 5 | Week 15 | |
| Question 32[3 marks] | |
|---|---|
| Answer or working | Marks |
| rearranges to isolate the term in x^2, e.g. 2x^2 = 5 - y | M1 |
| divides by 2 and square roots, e.g. x^2 = (5 - y)/2 | M1 |
| x = sqrt((5 - y)/2) oe, cao (allow +/-) | A1 |
| Final answer: x = sqrt((5 - y)/2) | |
| Question 33[2 marks] | |
|---|---|
| Answer or working | Marks |
| uses (gradient) x (perpendicular gradient) = -1, oe, taking the negative reciprocal of -3/5 | M1 |
| 5/3 oe | A1cao |
| Final answer: 5/3 | |
| Question 34[3 marks] | |
|---|---|
| Answer or working | Marks |
| factorises the numerator to (x + 5)(x - 2) | M1oe |
| factorises the denominator to (x - 2)(x + 2) | M1oe |
| (x + 5)/(x + 2) cao, with (x - 2) cancelled | A1 |
| Final answer: (x + 5)/(x + 2) | |
| Question 35[3 marks] | |
|---|---|
| Answer or working | Marks |
| gradient of AB = (2 - 0)/(4 - 0) = 1/2 | M1 |
| gradient of DC = (-2 - (-4))/(6 - 2) = 1/2 | M1 |
| correct conclusion with reason: gradients are equal (both 1/2), so AB is parallel to DC | A1cso |
| Final answer: Gradient of AB = gradient of DC = 1/2, so AB is parallel to DC | |
| Question 36[4 marks] | |
|---|---|
| Answer or working | Marks |
| 18 = 2 x 3^2 and 24 = 2^3 x 3 used to find LCM(18,24) = 2^3 x 3^2 = 72 | M1 |
| recognising that for n to be a perfect square, every prime in its factorisation must have an even power | M1 |
| identifying that the power of 2 (currently 2^3) is the only odd power, so 72 must be multiplied by a further 2 | M1 |
| 144 | A1cao |
| Question 37[3 marks] | |
|---|---|
| Answer or working | Marks |
| combines the right-hand side over a common denominator, e.g. 1/x = (b + a)/(ab) | M1 |
| takes the reciprocal of both sides, dependent on the previous method mark | dM1 |
| x = ab/(a + b) oe | A1cao |
| Final answer: x = ab/(a + b) | |
| Question 38[4 marks] | |
|---|---|
| Answer or working | Marks |
| 96 degrees | B1cao |
| identify that the angle at the centre theorem applies to the reflex angle AOC | M1 |
| 132 degrees | A1cao |
| reason: the angle at the centre is twice the angle at the circumference, subtended by the same (major) arc AC | B1oe |
| Final answer: 96 degrees | 132 degrees | |
| Question 39[3 marks] | |
|---|---|
| Answer or working | Marks |
| (x + 3)(x - 3) = x^2 - 9, or expands two of the three brackets correctly | M1oe |
| multiplies their quadratic by the remaining bracket, (x^2 - 9)(x + 2), with at least 3 correct terms | dM1oe |
| x^3 + 2x^2 - 9x - 18 | A1cao |
| Question 40[4 marks] | |
|---|---|
| Answer or working | Marks |
| OF = (2/5)a | M1 |
| AG = (3/4)(b - a), leading to OG = OA + AG = (1/4)a + (3/4)b | M1 |
| FG = OG - OF | M1 |
| -(3/20)a + (3/4)b oe, e.g. (3/4)b - (3/20)a | A1 |
| Final answer: FG = (3/4)b - (3/20)a | |
| Question 41[5 marks] | |
|---|---|
| Answer or working | Marks |
| 8 * 7 * 6 oe seen | M1 |
| 336 | A1cao |
| identifies 2 choices for treasurer (Kwame or Sophie) | M1 |
| (dep) 2 * 7 * 6 oe for the remaining two roles | M1 |
| 84 | A1cao |
| Final answer: 336 | 84 | |