Higher Tier - Year 10

OCR-Style Year 10 Higher Paper 2

An OCR-style Year 10 Higher Paper 2: 100 marks, 90 minutes, non-calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures. OCR's non-calculator paper is the middle paper of a sitting rather than the first, verified against OCR's own published question papers.

41 questions - 100 marks

Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [1 marks]

Indices and Standard Form

Work out the value of 3^4.

Question 2 [1 marks]

Fractions, Decimals and Percentages

Write 0.4444... (4 recurring) as a fraction. You do not need to simplify or show any working.

Question 3 [1 marks]

Ratio and Proportion

The ratio of boys to girls in a class is 5:7. Write the number of boys as a fraction of the total number of pupils in the class.

Question 4 [1 marks]

Angles and Geometrical Reasoning

Point Q has coordinates (-2, 4). Write down the coordinates of the image of Q after a reflection in the y-axis.

Question 5 [1 marks]

Linear Algebra

Solve x + 7 = 15

Question 6 [3 marks]

Graphs and Coordinates

Complete the table of values for y = x^3 - 1. x : -2 , -1 , 0 , 1 , 2 y : -9 , _ , _ , _ , 7

Question 7 [1 marks]

Indices and Standard Form

Simplify p^5 * p^3.

Question 8 [1 marks]

Number and Calculation

Sam rolls two ordinary six-sided dice, one red and one blue. Work out the number of different outcomes possible.

Question 9 [1 marks]

Indices and Standard Form

Write 3.15 x 10^6 as an ordinary number.

Question 10 [2 marks]

Area, Volume and Measures

Two similar triangles have corresponding sides in the ratio 5:8. A side of the smaller triangle is 15 cm. Work out the length of the corresponding side in the larger triangle.

Question 11 [1 marks]

Indices and Standard Form

Simplify sqrt(75) fully.

Question 12 [1 marks]

Ratio and Proportion

A fruit drink is made from concentrate and water in the ratio 1:4. Write down what fraction of the drink is concentrate.

Question 13 [1 marks]

Indices and Standard Form

Write 2.06 x 10^-3 as an ordinary number.

Question 14 [2 marks]

Number and Calculation

Find the LCM of 9 and 15.

Question 15 [2 marks]

Linear Algebra

Solve 3(2x - 5) = 21

Question 16 [2 marks]

Number and Calculation

A PE kit is made from one shirt (4 colours available), one pair of shorts (3 colours available) and one pair of socks (2 colours available). Work out the number of different PE kits possible.

Question 17 [2 marks]

Angles and Geometrical Reasoning

Triangle A has vertices A(1, 2), B(4, 2) and C(1, 5). Describe fully the single transformation that maps triangle A to triangle A' with vertices A'(1, -2), B'(4, -2) and C'(1, -5).

Question 18 [2 marks]

Linear Algebra

a = 6 and c = 2. Work out the value of a^2 - c^2.

Question 19 [2 marks]

Graphs and Coordinates

Rearrange 3x + y = 11 into the form y = mx + c and state the gradient and the y-intercept.

Question 20 [2 marks]

Linear Algebra

Make x the subject of the formula: y = (x - 5)/3

Question 21 [2 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (1, 1) and (4, 7).

Question 22 [4 marks]

Number and Calculation

a = 2^3 x 5 and b = 2^2 x 5^2.

Find the HCF of a and b.

Find the LCM of a and b.

Question 23 [2 marks]

Linear Algebra

p = -4 and q = 5. Work out the value of (p + q)^2.

Question 24 [2 marks]

Angles and Geometrical Reasoning

The point P has coordinates (2, 3). P is enlarged by scale factor -1, centre the origin O, to give the image P'. Find the coordinates of P'.

Question 25 [3 marks]

Ratio and Proportion

A bag contains only red counters and blue counters. The ratio of red counters to blue counters is 3:5. There are 40 counters in the bag altogether.

Write the number of red counters as a fraction of the total number of counters.

Work out the number of red counters in the bag.

Question 26 [3 marks]

Linear Algebra

P = 2x^2 - 3x + 1. Work out the value of P when x = -4, showing your working.

Question 27 [3 marks]

Angles and Geometrical Reasoning

v is the column vector (k, 4), where k > 0, and |v| = 5. Find the value of k.

Question 28 [3 marks]

Graphs and Coordinates

Show that the inverse of f(x) = 5x - 8 is f^{-1}(x) = (x + 8)/5. Give full working.

Question 29 [5 marks]

Sequences

Here are the first four terms of a geometric sequence. 5, 15, 45, 135

Find the common ratio of the sequence.

Find the 6th term of the sequence.

Explain whether 3000 is a term of the sequence.

Question 30 [2 marks]

Linear Algebra

Solve 4x + 3 = 23 Show your working.

Question 31 [7 marks]

Sequences

Arjun is training for a marathon. In week 1, he runs 8 km. Each week after that, he runs 3 km more than the week before.

Work out how far Arjun runs in week 6.

Find an expression, in terms of n, for the distance, in km, Arjun runs in week n.

Arjun wants to know the first week in which he will run at least 50 km. Find this week number.

Question 32 [3 marks]

Linear Algebra

Make x the subject of the formula: y = 5 - 2x^2

Question 33 [2 marks]

Graphs and Coordinates

A line has gradient -3/5. Find the gradient of a line perpendicular to it.

Question 34 [3 marks]

Linear Algebra

Simplify fully (x^2 + 3x - 10) / (x^2 - 4)

Question 35 [3 marks]

Graphs and Coordinates

A quadrilateral has vertices at A(0, 0), B(4, 2), C(6, -2) and D(2, -4). Show that AB is parallel to DC.

Question 36 [4 marks]

Number and Calculation

Find the smallest positive integer n such that n is a multiple of both 18 and 24, and n is also a perfect square.

Question 37 [3 marks]

Linear Algebra

Two resistors, with resistances a ohms and b ohms, are connected in parallel. Their combined resistance, x ohms, satisfies the formula 1/x = 1/a + 1/b. Make x the subject of the formula.

Question 38 [4 marks]

Angles and Geometrical Reasoning

A, B and C are points on the circumference of a circle with centre O. B lies on the minor arc AC. The reflex angle AOC = 264 degrees. Diagram: circle, centre O, points A, B and C on the circumference, B on the minor arc AC, the reflex angle AOC = 264 degrees marked at the centre going the long way round, angle ABC marked at B.

Work out the size of the non-reflex angle AOC.

Work out the size of angle ABC.

Question 39 [3 marks]

Linear Algebra

Expand and simplify (x + 3)(x - 3)(x + 2)

Question 40 [4 marks]

Angles and Geometrical Reasoning

In triangle OAB, O is the origin. OA = a and OB = b. F is the point on OA such that OF = (2/5)a. G is the point on AB such that AG : GB = 3 : 1.

Question 41 [5 marks]

Number and Calculation

A charity club has 8 members. Three different roles, chair, vice-chair and treasurer, are each given to a different member.

Work out the number of different ways the three roles can be given out.

The treasurer role must go to either Kwame or Sophie. Work out the number of different ways the three roles can now be given out.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
81B1cao
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
4/9B1cao
Mark scheme for Question 3 [1 mark]
Question 3[1 mark]
Answer or workingMarks
5/12B1oe
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
(2, 4)B1cao
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
x = 8B1cao
Mark scheme for Question 6 [3 marks]
Question 6[3 marks]
Answer or workingMarks
y = -2 at x = -1B1
y = -1 at x = 0B1
y = 0 at x = 1B1
Final answer: x = -1: y = -2; x = 0: y = -1; x = 1: y = 0
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
p^8B1cao
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
36B1cao
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
3150000B1cao
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
multiply 15 by scale factor 8/5 or show equivalent methodM1
24 cmA1cao
Final answer: 24 cm, because 15 x (8/5) = 24 (scale factor 8/5).
Mark scheme for Question 11 [1 mark]
Question 11[1 mark]
Answer or workingMarks
5sqrt(3) oeB1cao
Final answer: 5sqrt(3)
Mark scheme for Question 12 [1 mark]
Question 12[1 mark]
Answer or workingMarks
1/5B1oe
Mark scheme for Question 13 [1 mark]
Question 13[1 mark]
Answer or workingMarks
0.00206B1cao
Mark scheme for Question 14 [2 marks]
Question 14[2 marks]
Answer or workingMarks
9 = 3^2 and 15 = 3 x 5, or a correct list of multiples of each numberM1
45A1cao
Mark scheme for Question 15 [2 marks]
Question 15[2 marks]
Answer or workingMarks
correct method, e.g. expand to 6x - 15 = 21 oe, or divide first to 2x - 5 = 7M1oe
x = 6A1cao
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
4 * 3 * 2 oe seenM1
24A1cao
Mark scheme for Question 17 [2 marks]
Question 17[2 marks]
Answer or workingMarks
state reflection in the x-axisB1oe
fully described mapping (x, y) -> (x, -y) or equivalentB1cao
Final answer: Reflection in the x-axis. (x, y) -> (x, -y).
Mark scheme for Question 18 [2 marks]
Question 18[2 marks]
Answer or workingMarks
a^2 = 36 and c^2 = 4 both evaluatedM1oe
32A1cao
Mark scheme for Question 19 [2 marks]
Question 19[2 marks]
Answer or workingMarks
subtracts 3x from both sidesM1oe
gradient -3 and y-intercept 11 both stated correctlyA1cao
Final answer: Gradient = -3, y-intercept = 11
Mark scheme for Question 20 [2 marks]
Question 20[2 marks]
Answer or workingMarks
multiplies both sides by 3, e.g. 3y = x - 5M1
x = 3y + 5 oeA1cao
Final answer: x = 3y + 5
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
(7 - 1)/(4 - 1), oe substitution into the gradient formulaM1
2A1cao
Mark scheme for Question 22 [4 marks]
Question 22[4 marks]
Answer or workingMarks
correct lowest power of each common prime identified, 2^2 and 5^1M1
20A1cao
correct highest power of each prime identified, 2^3 and 5^2M1
200A1cao
Final answer: 20 | 200
Mark scheme for Question 23 [2 marks]
Question 23[2 marks]
Answer or workingMarks
p + q = 1 seenM1oe
1A1cao
Mark scheme for Question 24 [2 marks]
Question 24[2 marks]
Answer or workingMarks
P' = -1 * (2, 3) oe, or correct use of the enlargement formulaM1
(-2, -3)A1cao
Mark scheme for Question 25 [3 marks]
Question 25[3 marks]
Answer or workingMarks
3/8B1oe
40 / 8 (= 5), ft their fraction from (a)M1
15A1cao
Final answer: 3/8 | 15
Mark scheme for Question 26 [3 marks]
Question 26[3 marks]
Answer or workingMarks
2 x (-4)^2 (= 32) seenM1oe
-3 x (-4) (= 12) seen, correctly signeddM1
45A1cao
Mark scheme for Question 27 [3 marks]
Question 27[3 marks]
Answer or workingMarks
k^2 + 4^2 = 5^2M1oe
dep: k^2 = 9M1
k = 3 cao (rejects k = -3 since k > 0)A1
Final answer: k = 3
Mark scheme for Question 28 [3 marks]
Question 28[3 marks]
Answer or workingMarks
set y = 5x - 8 and swap x and y or equivalentM1
rearrange to get x = 5y - 8 then solve y = (x + 8)/5M1
f^{-1}(x) = (x + 8)/5A1cso
Mark scheme for Question 29 [5 marks]
Question 29[5 marks]
Answer or workingMarks
3B1cao
5 x 3^5 oe, or lists terms up to the 6thM1
1215A1cao
identifies the two terms either side of 3000 (1215 and 3645), or sets up 5 x 3^(n-1) = 3000M1oe
correct conclusion: no, 3000 is not a term, e.g. it lies strictly between 1215 and 3645A1oe
Final answer: 3 | 1215 | No, 3000 is not a term of the sequence
Mark scheme for Question 30 [2 marks]
Question 30[2 marks]
Answer or workingMarks
4x = 20M1oe
x = 5A1cao
Mark scheme for Question 31 [7 marks]
Question 31[7 marks]
Answer or workingMarks
8 + 5 x 3 oe, or lists terms up to week 6M1
23 kmA1cao
common difference of 3 used correctly, e.g. 3n + cM1oe
3n + 5 oeA1cao
3n + 5 >= 50 oe (ft their expression)M1
3n >= 45 oe, leading to n >= 15M1
week 15A1cao
Final answer: 23 km | 3n + 5 | Week 15
Mark scheme for Question 32 [3 marks]
Question 32[3 marks]
Answer or workingMarks
rearranges to isolate the term in x^2, e.g. 2x^2 = 5 - yM1
divides by 2 and square roots, e.g. x^2 = (5 - y)/2M1
x = sqrt((5 - y)/2) oe, cao (allow +/-)A1
Final answer: x = sqrt((5 - y)/2)
Mark scheme for Question 33 [2 marks]
Question 33[2 marks]
Answer or workingMarks
uses (gradient) x (perpendicular gradient) = -1, oe, taking the negative reciprocal of -3/5M1
5/3 oeA1cao
Final answer: 5/3
Mark scheme for Question 34 [3 marks]
Question 34[3 marks]
Answer or workingMarks
factorises the numerator to (x + 5)(x - 2)M1oe
factorises the denominator to (x - 2)(x + 2)M1oe
(x + 5)/(x + 2) cao, with (x - 2) cancelledA1
Final answer: (x + 5)/(x + 2)
Mark scheme for Question 35 [3 marks]
Question 35[3 marks]
Answer or workingMarks
gradient of AB = (2 - 0)/(4 - 0) = 1/2M1
gradient of DC = (-2 - (-4))/(6 - 2) = 1/2M1
correct conclusion with reason: gradients are equal (both 1/2), so AB is parallel to DCA1cso
Final answer: Gradient of AB = gradient of DC = 1/2, so AB is parallel to DC
Mark scheme for Question 36 [4 marks]
Question 36[4 marks]
Answer or workingMarks
18 = 2 x 3^2 and 24 = 2^3 x 3 used to find LCM(18,24) = 2^3 x 3^2 = 72M1
recognising that for n to be a perfect square, every prime in its factorisation must have an even powerM1
identifying that the power of 2 (currently 2^3) is the only odd power, so 72 must be multiplied by a further 2M1
144A1cao
Mark scheme for Question 37 [3 marks]
Question 37[3 marks]
Answer or workingMarks
combines the right-hand side over a common denominator, e.g. 1/x = (b + a)/(ab)M1
takes the reciprocal of both sides, dependent on the previous method markdM1
x = ab/(a + b) oeA1cao
Final answer: x = ab/(a + b)
Mark scheme for Question 38 [4 marks]
Question 38[4 marks]
Answer or workingMarks
96 degreesB1cao
identify that the angle at the centre theorem applies to the reflex angle AOCM1
132 degreesA1cao
reason: the angle at the centre is twice the angle at the circumference, subtended by the same (major) arc ACB1oe
Final answer: 96 degrees | 132 degrees
Mark scheme for Question 39 [3 marks]
Question 39[3 marks]
Answer or workingMarks
(x + 3)(x - 3) = x^2 - 9, or expands two of the three brackets correctlyM1oe
multiplies their quadratic by the remaining bracket, (x^2 - 9)(x + 2), with at least 3 correct termsdM1oe
x^3 + 2x^2 - 9x - 18A1cao
Mark scheme for Question 40 [4 marks]
Question 40[4 marks]
Answer or workingMarks
OF = (2/5)aM1
AG = (3/4)(b - a), leading to OG = OA + AG = (1/4)a + (3/4)bM1
FG = OG - OFM1
-(3/20)a + (3/4)b oe, e.g. (3/4)b - (3/20)aA1
Final answer: FG = (3/4)b - (3/20)a
Mark scheme for Question 41 [5 marks]
Question 41[5 marks]
Answer or workingMarks
8 * 7 * 6 oe seenM1
336A1cao
identifies 2 choices for treasurer (Kwame or Sophie)M1
(dep) 2 * 7 * 6 oe for the remaining two rolesM1
84A1cao
Final answer: 336 | 84