OCR-Style Year 10 Higher Paper 3
An OCR-style Year 10 Higher Paper 3: 100 marks, 90 minutes, calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.
Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [1 marks]
Indices and Standard Form
Write the number 0.0032 in standard form.
Question 2 [1 marks]
Graphs and Coordinates
Find the gradient of the straight line joining the points (0, 7) and (4, -1).
Question 3 [2 marks]
Ratio and Proportion
A car travels 150 km in 3 hours, travelling at a constant average speed. Calculate the average speed of the car in km/h.
Question 4 [2 marks]
Fractions, Decimals and Percentages
Write 0.3333... (3 recurring) as a fraction in its simplest form.
Question 5 [2 marks]
Sequences
Here are the first four terms of a sequence. 2, 6, 10, 14
Write down the next two terms of the sequence.
Describe, in words, the term-to-term rule for the sequence.
Question 6 [4 marks]
Area, Volume and Measures
Priya's living room is L-shaped. It is made from a rectangle 5 m by 4 m with an alcove that adds a rectangle 2 m by 1.5 m.
Work out the total floor area of the living room.
Carpet for the room costs £18.50 per m^2. Work out the total cost of the carpet.
Question 7 [1 marks]
Fractions, Decimals and Percentages
Write 7/20 as a decimal.
Question 8 [1 marks]
Angles and Geometrical Reasoning
State a simple compass-and-straightedge construction to find the midpoint of segment AB.
Question 9 [1 marks]
Linear Algebra
A function machine multiplies the input by 7 then subtracts 2. Write an expression in terms of x for the output.
Question 10 [1 marks]
Angles and Geometrical Reasoning
Two straight roads cross at a roundabout. One of the four angles formed between the roads is 63 degrees. Work out the size of the angle that is vertically opposite this 63 degree angle.
Question 11 [2 marks]
Linear Algebra
Solve 5x + 2 = 2x + 14 Show your working.
Question 12 [2 marks]
Number and Calculation
Write 84 as a product of its prime factors, giving your answer in index form.
Question 13 [2 marks]
Linear Algebra
Expand and simplify (x - 5)(x + 9)
Question 14 [2 marks]
Indices and Standard Form
Simplify sqrt(8) + sqrt(2) fully.
Question 15 [2 marks]
Linear Algebra
The formula v = u + at connects speeds u and v, acceleration a and time t. Make t the subject of the formula.
Question 16 [2 marks]
Angles and Geometrical Reasoning
A shape is enlarged by scale factor -1. Sunita says, 'The image will have the same area as the original shape.' Is Sunita correct? Justify your answer.
Question 17 [2 marks]
Number and Calculation
Work out sqrt(225) + cube root(64).
Question 18 [2 marks]
Area, Volume and Measures
A trapezium-shaped tabletop has parallel sides of length 12 cm and 18 cm and a height of 9 cm. Calculate the area of the tabletop.
Question 19 [2 marks]
Angles and Geometrical Reasoning
Point W has coordinates (5, 3). Find the coordinates of the image of W after a rotation of 180 degrees about the point (2, 2).
Question 20 [2 marks]
Fractions, Decimals and Percentages
Simplify 45/60 to lowest terms.
Question 21 [2 marks]
Area, Volume and Measures
The linear scale factor between two mathematically similar shapes is 0.4. Work out the area scale factor.
Question 22 [3 marks]
Fractions, Decimals and Percentages
Show that 0.363636... (36 recurring) = 4/11.
Question 23 [3 marks]
Angles and Geometrical Reasoning
A model car is similar to the real car. The scale factor of similarity (model : real) for linear dimensions is 1:18. (a) Work out the area scale factor (model : real). (b) The model has a painted roof area of 12 cm^2. Work out the area of the real car roof in square metres. Give your answer in standard form to 2 significant figures.
The model roof area is 12 cm^2. Work out the real roof area in m^2, give answer in standard form to 2 s.f.
Question 24 [3 marks]
Fractions, Decimals and Percentages
Chloe buys a sofa on a deferred payment plan. She pays a deposit equal to 15% of the cash price of the sofa. The remaining amount is then increased by 8%, to cover a credit charge, before being split into equal monthly instalments. The remaining amount, after the 8% credit charge has been added, is £642.60. Work out the cash price of the sofa.
Question 25 [3 marks]
Graphs and Coordinates
A school marks out a square flower bed on a coordinate grid, where 1 unit represents 1 metre. Three of its corners are at A(-3, -3), B(2, -3) and C(2, 2). Find the coordinates of the fourth corner D, and work out the perimeter of the flower bed.
Question 26 [3 marks]
Indices and Standard Form
Show that x^(2/3) / x^(1/6) = x^(1/2). State any restriction on x.
Question 27 [4 marks]
Linear Algebra
An old recipe book gives a formula for converting a temperature C degrees Celsius into F degrees Fahrenheit: F = 9C/5 + 32
Make C the subject of the formula.
Use your formula to work out the value of C when F = 68. Give your answer in degrees Celsius.
Question 28 [4 marks]
Area, Volume and Measures
A rectangular garden measures 15 m by 8 m. A uniform path of width x m is laid around the inside so that the lawn that remains has area 66 m^2 less than the original garden. Work out x, giving your answer correct to 2 decimal places.
Question 29 [4 marks]
Linear Algebra
Given g(x) = 5x^2 - 2x + 3,
Simplify g(x) - (2x^2 - 3x + 1).
The table below shows two values of x. Use your answer to part (a) to complete the table, giving each value of 3x^2 + x + 2. x | -2 | 3 3x^2 + x + 2 | ___ | ___
Question 30 [4 marks]
Ratio and Proportion
Aaliyah needs at least 2 kg of sugar for a school bake sale. A shop sells sugar in bags of 750 g for 90p each, and bags of 1 kg for £1.10 each. She can only buy whole bags.
Question 31 [5 marks]
Graphs and Coordinates
Work out the intersection point of the lines y = 2x + 1 and y = -x + 7. Give full working and the final coordinates.
Question 32 [3 marks]
Indices and Standard Form
A rectangular garden bed has length (6 + sqrt(11)) m and width (6 - sqrt(11)) m. Find the area of the garden bed, giving your answer as an integer.
Question 33 [3 marks]
Number and Calculation
A rectangular photo has length 15 cm and width 10 cm, each measured correct to the nearest cm. A framer claims the area of the photo could be as large as 160 cm^2. Using bounds, show whether the framer's claim is correct. You must show your working.
Question 34 [3 marks]
Graphs and Coordinates
The graph of y = 3^x is an exponential curve.
Write down the coordinates of the point where the graph crosses the y-axis.
Write down the equation of the horizontal asymptote of the graph.
State whether y = 3^x is increasing or decreasing as x increases.
Question 35 [3 marks]
Area, Volume and Measures
Two spheres are mathematically similar. Their radii are in the ratio 2:3. The volume of the smaller sphere is 96 cm^3. Work out the volume of the larger sphere.
Question 36 [4 marks]
Graphs and Coordinates
The graph of y = 2cos x - 1 is a transformation of y = cos x.
Write down the maximum and minimum values of y = 2cos x - 1.
Write down the coordinates of the y-intercept of the graph.
State the period of the graph.
Question 37 [5 marks]
Fractions, Decimals and Percentages
Priya has 10 1/2 metres of ribbon. She cuts off 1/4 of it. From the remaining ribbon she uses 3/5 for making bows. How much ribbon remains unused? Give your answer as a mixed number in simplest form.
Question 38 [5 marks]
Area, Volume and Measures
Triangle ABC has AB = 15 cm, AC = 10 cm and area 36 cm^2. Work out angle A and then calculate the length BC. Give the final length BC to the nearest whole number.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 3.2 x 10^-3 | B1oe |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| -2 | B1cao |
| Question 3[2 marks] | |
|---|---|
| Answer or working | Marks |
| speed = distance / time i.e. 150 / 3 | M1oe |
| 50 (km/h) | A1cao |
| Final answer: 50 km/h | |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| 3/9 seen or equivalent unsimplified fraction with denominator 9 | M1 |
| 1/3 | A1cao |
| Question 5[2 marks] | |
|---|---|
| Answer or working | Marks |
| 18 and 22 both correct | B1oe |
| start at 2 and add 4 each time | B1oe |
| Final answer: 18, 22 | Start at 2 and add 4 each time (oe). | |
| Question 6[4 marks] | |
|---|---|
| Answer or working | Marks |
| 5 x 4 + 2 x 1.5 | M1 |
| 23 (m^2) | A1cao |
| their (a) x 18.50 | M1ft |
| 425.50 (pounds) cao, ft from (a) | A1 |
| Final answer: (a) 23 m^2 (b) GBP 425.50 | |
| Question 7[1 mark] | |
|---|---|
| Answer or working | Marks |
| 0.35 | B1cao |
| Question 8[1 mark] | |
|---|---|
| Answer or working | Marks |
| draw equal-radius arcs from A and B to make two intersection points; join intersections; intersection with AB is midpoint | B1cao |
| Final answer: With compass draw equal-radius arcs from A and B to make two intersections; join those intersections with a straight line; where that line meets AB is the midpoint. | |
| Question 9[1 mark] | |
|---|---|
| Answer or working | Marks |
| 7x - 2 | B1cao |
| Final answer: 7x - 2. | |
| Question 10[1 mark] | |
|---|---|
| Answer or working | Marks |
| 63 degrees | B1cao |
| Question 11[2 marks] | |
|---|---|
| Answer or working | Marks |
| 3x + 2 = 14 or 3x = 12 oe (collect x terms correctly) | M1 |
| x = 4 | A1cao |
| Question 12[2 marks] | |
|---|---|
| Answer or working | Marks |
| at least two correct prime factors identified, e.g. 2, 2, 3, 7 from a factor tree or repeated division | M1 |
| 2^2 x 3 x 7 oe, fully correct in index form | A1 |
| Final answer: 2^2 x 3 x 7 | |
| Question 13[2 marks] | |
|---|---|
| Answer or working | Marks |
| x^2 + 9x - 5x - 45, or at least 3 of the 4 terms correct | M1oe |
| x^2 + 4x - 45 | A1cao |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| sqrt(8) = 2sqrt(2) identified | M1 |
| 3sqrt(2) oe | A1cao |
| Final answer: 3sqrt(2) | |
| Question 15[2 marks] | |
|---|---|
| Answer or working | Marks |
| subtracts u from both sides, e.g. v - u = at | M1 |
| t = (v - u)/a oe | A1cao |
| Final answer: t = (v - u)/a | |
| Question 16[2 marks] | |
|---|---|
| Answer or working | Marks |
| yes, Sunita is correct | B1 |
| reason: area scale factor = (-1)^2 = 1, so the area is unchanged | B1oe |
| Final answer: Yes, Sunita is correct. | |
| Question 17[2 marks] | |
|---|---|
| Answer or working | Marks |
| sqrt(225) = 15, or cube root(64) = 4, seen | M1 |
| 19 | A1cao |
| Question 18[2 marks] | |
|---|---|
| Answer or working | Marks |
| Use area = 1/2 x (sum of parallel sides) x height = 1/2 x (12 + 18) x 9 | M1 |
| 135 cm^2 | A1cao |
| Question 19[2 marks] | |
|---|---|
| Answer or working | Marks |
| uses image = (2 x 2 - 5, 2 x 2 - 3) oe, or a correct diagram/vector method | M1 |
| (-1, 1) | A1cao |
| Question 20[2 marks] | |
|---|---|
| Answer or working | Marks |
| divide numerator and denominator by a common factor, e.g. 15 | M1oe |
| 3/4 | A1cao |
| Question 21[2 marks] | |
|---|---|
| Answer or working | Marks |
| 0.4^2 set up | M1 |
| 0.16 | A1cao |
| Question 22[3 marks] | |
|---|---|
| Answer or working | Marks |
| x = 0.363636... and 100x = 36.363636... written | M1 |
| subtracts to get 99x = 36, dependent on M1 | dM1 |
| cso, x = 4/11 with full algebraic method shown (36/99 simplified) | A1 |
| Final answer: 4/11 (shown) | |
| Question 23[3 marks] | |
|---|---|
| Answer or working | Marks |
| 1 : 324 | B1cao |
| scale up area by factor 324: real area = 12 * 324 = 3888 cm^2 | M1 |
| 3.9 x 10^-1 m^2 cao (3888 cm^2 = 0.3888 m^2 -> 3.9 x 10^-1 to 2 s.f.) | A1 |
| Final answer: 1 : 324 | 3.9 x 10^-1 m^2 | |
| Question 24[3 marks] | |
|---|---|
| Answer or working | Marks |
| 642.60 / 1.08 (= 595) | M1oe |
| 595 / 0.85 used, dependent on the first M1 | M1 |
| £700 | A1cao |
| Question 25[3 marks] | |
|---|---|
| Answer or working | Marks |
| recognise D has x-coordinate -3 (same as A) and y-coordinate 2 (same as C), or use vector method | M1 |
| D = (-3, 2) | A1cao |
| perimeter = 4 x 5 = 20 m ft their side length | B1 |
| Final answer: D = (-3, 2); perimeter = 20 m | |
| Question 26[3 marks] | |
|---|---|
| Answer or working | Marks |
| subtract exponents: 2/3 - 1/6 = 4/6 - 1/6 = 3/6 | M1 |
| 3/6 simplifies to 1/2 | M1 |
| x^(1/2) cao; state x > 0 for real principal roots (division by x^(1/6) requires x != 0) | A1 |
| Final answer: x^(1/2) (Valid for x > 0 when interpreting fractional powers as principal real roots, since x^(1/6) in the denominator cannot be zero.) | |
| Question 27[4 marks] | |
|---|---|
| Answer or working | Marks |
| subtracts 32 from both sides, e.g. F - 32 = 9C/5 | M1 |
| multiplies both sides by 5 (or by 5/9), e.g. 5(F - 32) = 9C | M1 |
| C = 5(F - 32)/9 oe, e.g. C = (5F - 160)/9 | A1cao |
| C = 20 (deg C), ft from part a | B1 |
| Final answer: C = 5(F - 32)/9 | C = 20 deg C | |
| Question 28[4 marks] | |
|---|---|
| Answer or working | Marks |
| Write inner area = (15 - 2x)(8 - 2x) and set equal to 120 - 66 = 54 | M1 |
| Expand to form quadratic: 4x^2 - 46x + 66 = 0 (or equivalent) | M1 |
| Use quadratic formula to find positive solution for x | M1 |
| x = 1.68 m awrt (1.6803...) | A1 |
| Final answer: 1.68 m | |
| Question 29[4 marks] | |
|---|---|
| Answer or working | Marks |
| subtracts like terms: 5x^2 - 2x^2 and -2x - (-3x) and 3 - 1 | M1 |
| 3x^2 + x + 2 | A1cao |
| 12 cao (when x = -2) | B1 |
| 32 cao (when x = 3) | B1 |
| Final answer: 3x^2 + x + 2 (cao) | 12 and 32 (cao) | |
| Question 30[4 marks] | |
|---|---|
| Answer or working | Marks |
| at least two valid combinations of whole bags totalling at least 2 kg identified, e.g. 3 x 750 g and 2 x 1 kg | P1 |
| 3 x 90 (= 2.70) oe and 2 x 1.10 (= 2.20) | M1oe |
| £2.70 and £2.20 both correct | A1cao |
| correct conclusion that 2 x 1 kg bags for £2.20 is the cheapest way to buy at least 2 kg | C1 |
| Final answer: Buy 2 bags of 1 kg sugar for £2.20 (this gives exactly 2 kg for the least cost) | |
| Question 31[5 marks] | |
|---|---|
| Answer or working | Marks |
| equate 2x + 1 = -x + 7 to form an equation in x | M1 |
| collect terms and solve for x giving x = 2 | M1 |
| x = 2 | A1cao |
| substitute x = 2 into one of the equations to find y | M1 |
| y = 5 | A1cao |
| Final answer: (2, 5) | |
| Question 32[3 marks] | |
|---|---|
| Answer or working | Marks |
| sets up area = (6 + sqrt(11))(6 - sqrt(11)) | M1 |
| 36 - 11 evaluated (from 36 - 6sqrt(11) + 6sqrt(11) - 11 or difference of two squares) | M1 |
| 25 m^2 | A1cao |
| Question 33[3 marks] | |
|---|---|
| Answer or working | Marks |
| upper bound of length = 15.5 and upper bound of width = 10.5 | M1oe |
| dep calculates upper bound of area = 15.5 x 10.5 (= 162.75) | M1oe |
| correct conclusion with supporting figures, e.g. Yes, the claim is correct, since the maximum possible area is 162.75 cm^2, which is greater than 160 cm^2 | A1cso |
| Final answer: Yes - the framer is correct, since the maximum possible area (162.75 cm^2) is greater than 160 cm^2. | |
| Question 34[3 marks] | |
|---|---|
| Answer or working | Marks |
| (0, 1) | B1 |
| y = 0 | B1 |
| increasing (since base 3 > 1) | B1 |
| Final answer: (0, 1) | y = 0 | Increasing | |
| Question 35[3 marks] | |
|---|---|
| Answer or working | Marks |
| volume scale factor = (3/2)^3 (oe, from linear scale factor 3/2) | M1 |
| volume scale factor = 27/8 (= 3.375) | M1oe |
| 324 cm^3 | A1cao |
| Question 36[4 marks] | |
|---|---|
| Answer or working | Marks |
| maximum = 1 | B1 |
| minimum = -3 | B1 |
| (0, 1) | B1 |
| 360 | B1 |
| Final answer: Maximum = 1, minimum = -3 | (0, 1) | 360 degrees | |
| Question 37[5 marks] | |
|---|---|
| Answer or working | Marks |
| convert 10 1/2 to improper fraction 21/2 | M1 |
| find amount removed: 1/4 × 21/2 = 21/8 and find remainder 21/2 - 21/8 = 63/8 | M1 |
| find amount used for bows: 3/5 × 63/8 = 189/40 | M1 |
| subtract used from remainder: 63/8 - 189/40 = 63/20 | M1 |
| 3 3/20 | A1cao |
| Question 38[5 marks] | |
|---|---|
| Answer or working | Marks |
| use 1/2 * 15 * 10 * sin A = 36 so sin A = 72/150 = 0.48 | M1 |
| take inverse sine to find A = arcsin(0.48) | M1oe |
| use law of cosines: BC^2 = 15^2 + 10^2 - 2*15*10*cos A | M1 |
| substitute cos A and evaluate BC | M1 |
| 8 cm | A1cao |