Higher Tier - Year 10

OCR-Style Year 10 Higher Paper 3

An OCR-style Year 10 Higher Paper 3: 100 marks, 90 minutes, calculator, matching OCR J560's published paper format. Covers the same nine Year 10 topics as the board-agnostic set: number and calculation, fractions, decimals and percentages, ratio and proportion, indices and standard form, linear algebra, graphs and coordinates, sequences, angles and geometrical reasoning, and area, volume and measures.

38 questions - 100 marks - calculator allowed

Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [1 marks]

Indices and Standard Form

Write the number 0.0032 in standard form.

Question 2 [1 marks]

Graphs and Coordinates

Find the gradient of the straight line joining the points (0, 7) and (4, -1).

Question 3 [2 marks]

Ratio and Proportion

A car travels 150 km in 3 hours, travelling at a constant average speed. Calculate the average speed of the car in km/h.

Question 4 [2 marks]

Fractions, Decimals and Percentages

Write 0.3333... (3 recurring) as a fraction in its simplest form.

Question 5 [2 marks]

Sequences

Here are the first four terms of a sequence. 2, 6, 10, 14

Write down the next two terms of the sequence.

Describe, in words, the term-to-term rule for the sequence.

Question 6 [4 marks]

Area, Volume and Measures

Priya's living room is L-shaped. It is made from a rectangle 5 m by 4 m with an alcove that adds a rectangle 2 m by 1.5 m.

Work out the total floor area of the living room.

Carpet for the room costs £18.50 per m^2. Work out the total cost of the carpet.

Question 7 [1 marks]

Fractions, Decimals and Percentages

Write 7/20 as a decimal.

Question 8 [1 marks]

Angles and Geometrical Reasoning

State a simple compass-and-straightedge construction to find the midpoint of segment AB.

Question 9 [1 marks]

Linear Algebra

A function machine multiplies the input by 7 then subtracts 2. Write an expression in terms of x for the output.

Question 10 [1 marks]

Angles and Geometrical Reasoning

Two straight roads cross at a roundabout. One of the four angles formed between the roads is 63 degrees. Work out the size of the angle that is vertically opposite this 63 degree angle.

Question 11 [2 marks]

Linear Algebra

Solve 5x + 2 = 2x + 14 Show your working.

Question 12 [2 marks]

Number and Calculation

Write 84 as a product of its prime factors, giving your answer in index form.

Question 13 [2 marks]

Linear Algebra

Expand and simplify (x - 5)(x + 9)

Question 14 [2 marks]

Indices and Standard Form

Simplify sqrt(8) + sqrt(2) fully.

Question 15 [2 marks]

Linear Algebra

The formula v = u + at connects speeds u and v, acceleration a and time t. Make t the subject of the formula.

Question 16 [2 marks]

Angles and Geometrical Reasoning

A shape is enlarged by scale factor -1. Sunita says, 'The image will have the same area as the original shape.' Is Sunita correct? Justify your answer.

Question 17 [2 marks]

Number and Calculation

Work out sqrt(225) + cube root(64).

Question 18 [2 marks]

Area, Volume and Measures

A trapezium-shaped tabletop has parallel sides of length 12 cm and 18 cm and a height of 9 cm. Calculate the area of the tabletop.

Question 19 [2 marks]

Angles and Geometrical Reasoning

Point W has coordinates (5, 3). Find the coordinates of the image of W after a rotation of 180 degrees about the point (2, 2).

Question 20 [2 marks]

Fractions, Decimals and Percentages

Simplify 45/60 to lowest terms.

Question 21 [2 marks]

Area, Volume and Measures

The linear scale factor between two mathematically similar shapes is 0.4. Work out the area scale factor.

Question 22 [3 marks]

Fractions, Decimals and Percentages

Show that 0.363636... (36 recurring) = 4/11.

Question 23 [3 marks]

Angles and Geometrical Reasoning

A model car is similar to the real car. The scale factor of similarity (model : real) for linear dimensions is 1:18. (a) Work out the area scale factor (model : real). (b) The model has a painted roof area of 12 cm^2. Work out the area of the real car roof in square metres. Give your answer in standard form to 2 significant figures.

The model roof area is 12 cm^2. Work out the real roof area in m^2, give answer in standard form to 2 s.f.

Question 24 [3 marks]

Fractions, Decimals and Percentages

Chloe buys a sofa on a deferred payment plan. She pays a deposit equal to 15% of the cash price of the sofa. The remaining amount is then increased by 8%, to cover a credit charge, before being split into equal monthly instalments. The remaining amount, after the 8% credit charge has been added, is £642.60. Work out the cash price of the sofa.

Question 25 [3 marks]

Graphs and Coordinates

A school marks out a square flower bed on a coordinate grid, where 1 unit represents 1 metre. Three of its corners are at A(-3, -3), B(2, -3) and C(2, 2). Find the coordinates of the fourth corner D, and work out the perimeter of the flower bed.

Question 26 [3 marks]

Indices and Standard Form

Show that x^(2/3) / x^(1/6) = x^(1/2). State any restriction on x.

Question 27 [4 marks]

Linear Algebra

An old recipe book gives a formula for converting a temperature C degrees Celsius into F degrees Fahrenheit: F = 9C/5 + 32

Make C the subject of the formula.

Use your formula to work out the value of C when F = 68. Give your answer in degrees Celsius.

Question 28 [4 marks]

Area, Volume and Measures

A rectangular garden measures 15 m by 8 m. A uniform path of width x m is laid around the inside so that the lawn that remains has area 66 m^2 less than the original garden. Work out x, giving your answer correct to 2 decimal places.

Question 29 [4 marks]

Linear Algebra

Given g(x) = 5x^2 - 2x + 3,

Simplify g(x) - (2x^2 - 3x + 1).

The table below shows two values of x. Use your answer to part (a) to complete the table, giving each value of 3x^2 + x + 2. x | -2 | 3 3x^2 + x + 2 | ___ | ___

Question 30 [4 marks]

Ratio and Proportion

Aaliyah needs at least 2 kg of sugar for a school bake sale. A shop sells sugar in bags of 750 g for 90p each, and bags of 1 kg for £1.10 each. She can only buy whole bags.

Question 31 [5 marks]

Graphs and Coordinates

Work out the intersection point of the lines y = 2x + 1 and y = -x + 7. Give full working and the final coordinates.

Question 32 [3 marks]

Indices and Standard Form

A rectangular garden bed has length (6 + sqrt(11)) m and width (6 - sqrt(11)) m. Find the area of the garden bed, giving your answer as an integer.

Question 33 [3 marks]

Number and Calculation

A rectangular photo has length 15 cm and width 10 cm, each measured correct to the nearest cm. A framer claims the area of the photo could be as large as 160 cm^2. Using bounds, show whether the framer's claim is correct. You must show your working.

Question 34 [3 marks]

Graphs and Coordinates

The graph of y = 3^x is an exponential curve.

Write down the coordinates of the point where the graph crosses the y-axis.

Write down the equation of the horizontal asymptote of the graph.

State whether y = 3^x is increasing or decreasing as x increases.

Question 35 [3 marks]

Area, Volume and Measures

Two spheres are mathematically similar. Their radii are in the ratio 2:3. The volume of the smaller sphere is 96 cm^3. Work out the volume of the larger sphere.

Question 36 [4 marks]

Graphs and Coordinates

The graph of y = 2cos x - 1 is a transformation of y = cos x.

Write down the maximum and minimum values of y = 2cos x - 1.

Write down the coordinates of the y-intercept of the graph.

State the period of the graph.

Question 37 [5 marks]

Fractions, Decimals and Percentages

Priya has 10 1/2 metres of ribbon. She cuts off 1/4 of it. From the remaining ribbon she uses 3/5 for making bows. How much ribbon remains unused? Give your answer as a mixed number in simplest form.

Question 38 [5 marks]

Area, Volume and Measures

Triangle ABC has AB = 15 cm, AC = 10 cm and area 36 cm^2. Work out angle A and then calculate the length BC. Give the final length BC to the nearest whole number.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
3.2 x 10^-3B1oe
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
-2B1cao
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
speed = distance / time i.e. 150 / 3M1oe
50 (km/h)A1cao
Final answer: 50 km/h
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
3/9 seen or equivalent unsimplified fraction with denominator 9M1
1/3A1cao
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
18 and 22 both correctB1oe
start at 2 and add 4 each timeB1oe
Final answer: 18, 22 | Start at 2 and add 4 each time (oe).
Mark scheme for Question 6 [4 marks]
Question 6[4 marks]
Answer or workingMarks
5 x 4 + 2 x 1.5M1
23 (m^2)A1cao
their (a) x 18.50M1ft
425.50 (pounds) cao, ft from (a)A1
Final answer: (a) 23 m^2 (b) GBP 425.50
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
0.35B1cao
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
draw equal-radius arcs from A and B to make two intersection points; join intersections; intersection with AB is midpointB1cao
Final answer: With compass draw equal-radius arcs from A and B to make two intersections; join those intersections with a straight line; where that line meets AB is the midpoint.
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
7x - 2B1cao
Final answer: 7x - 2.
Mark scheme for Question 10 [1 mark]
Question 10[1 mark]
Answer or workingMarks
63 degreesB1cao
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
3x + 2 = 14 or 3x = 12 oe (collect x terms correctly)M1
x = 4A1cao
Mark scheme for Question 12 [2 marks]
Question 12[2 marks]
Answer or workingMarks
at least two correct prime factors identified, e.g. 2, 2, 3, 7 from a factor tree or repeated divisionM1
2^2 x 3 x 7 oe, fully correct in index formA1
Final answer: 2^2 x 3 x 7
Mark scheme for Question 13 [2 marks]
Question 13[2 marks]
Answer or workingMarks
x^2 + 9x - 5x - 45, or at least 3 of the 4 terms correctM1oe
x^2 + 4x - 45A1cao
Mark scheme for Question 14 [2 marks]
Question 14[2 marks]
Answer or workingMarks
sqrt(8) = 2sqrt(2) identifiedM1
3sqrt(2) oeA1cao
Final answer: 3sqrt(2)
Mark scheme for Question 15 [2 marks]
Question 15[2 marks]
Answer or workingMarks
subtracts u from both sides, e.g. v - u = atM1
t = (v - u)/a oeA1cao
Final answer: t = (v - u)/a
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
yes, Sunita is correctB1
reason: area scale factor = (-1)^2 = 1, so the area is unchangedB1oe
Final answer: Yes, Sunita is correct.
Mark scheme for Question 17 [2 marks]
Question 17[2 marks]
Answer or workingMarks
sqrt(225) = 15, or cube root(64) = 4, seenM1
19A1cao
Mark scheme for Question 18 [2 marks]
Question 18[2 marks]
Answer or workingMarks
Use area = 1/2 x (sum of parallel sides) x height = 1/2 x (12 + 18) x 9M1
135 cm^2A1cao
Mark scheme for Question 19 [2 marks]
Question 19[2 marks]
Answer or workingMarks
uses image = (2 x 2 - 5, 2 x 2 - 3) oe, or a correct diagram/vector methodM1
(-1, 1)A1cao
Mark scheme for Question 20 [2 marks]
Question 20[2 marks]
Answer or workingMarks
divide numerator and denominator by a common factor, e.g. 15M1oe
3/4A1cao
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
0.4^2 set upM1
0.16A1cao
Mark scheme for Question 22 [3 marks]
Question 22[3 marks]
Answer or workingMarks
x = 0.363636... and 100x = 36.363636... writtenM1
subtracts to get 99x = 36, dependent on M1dM1
cso, x = 4/11 with full algebraic method shown (36/99 simplified)A1
Final answer: 4/11 (shown)
Mark scheme for Question 23 [3 marks]
Question 23[3 marks]
Answer or workingMarks
1 : 324B1cao
scale up area by factor 324: real area = 12 * 324 = 3888 cm^2M1
3.9 x 10^-1 m^2 cao (3888 cm^2 = 0.3888 m^2 -> 3.9 x 10^-1 to 2 s.f.)A1
Final answer: 1 : 324 | 3.9 x 10^-1 m^2
Mark scheme for Question 24 [3 marks]
Question 24[3 marks]
Answer or workingMarks
642.60 / 1.08 (= 595)M1oe
595 / 0.85 used, dependent on the first M1M1
£700A1cao
Mark scheme for Question 25 [3 marks]
Question 25[3 marks]
Answer or workingMarks
recognise D has x-coordinate -3 (same as A) and y-coordinate 2 (same as C), or use vector methodM1
D = (-3, 2)A1cao
perimeter = 4 x 5 = 20 m ft their side lengthB1
Final answer: D = (-3, 2); perimeter = 20 m
Mark scheme for Question 26 [3 marks]
Question 26[3 marks]
Answer or workingMarks
subtract exponents: 2/3 - 1/6 = 4/6 - 1/6 = 3/6M1
3/6 simplifies to 1/2M1
x^(1/2) cao; state x > 0 for real principal roots (division by x^(1/6) requires x != 0)A1
Final answer: x^(1/2) (Valid for x > 0 when interpreting fractional powers as principal real roots, since x^(1/6) in the denominator cannot be zero.)
Mark scheme for Question 27 [4 marks]
Question 27[4 marks]
Answer or workingMarks
subtracts 32 from both sides, e.g. F - 32 = 9C/5M1
multiplies both sides by 5 (or by 5/9), e.g. 5(F - 32) = 9CM1
C = 5(F - 32)/9 oe, e.g. C = (5F - 160)/9A1cao
C = 20 (deg C), ft from part aB1
Final answer: C = 5(F - 32)/9 | C = 20 deg C
Mark scheme for Question 28 [4 marks]
Question 28[4 marks]
Answer or workingMarks
Write inner area = (15 - 2x)(8 - 2x) and set equal to 120 - 66 = 54M1
Expand to form quadratic: 4x^2 - 46x + 66 = 0 (or equivalent)M1
Use quadratic formula to find positive solution for xM1
x = 1.68 m awrt (1.6803...)A1
Final answer: 1.68 m
Mark scheme for Question 29 [4 marks]
Question 29[4 marks]
Answer or workingMarks
subtracts like terms: 5x^2 - 2x^2 and -2x - (-3x) and 3 - 1M1
3x^2 + x + 2A1cao
12 cao (when x = -2)B1
32 cao (when x = 3)B1
Final answer: 3x^2 + x + 2 (cao) | 12 and 32 (cao)
Mark scheme for Question 30 [4 marks]
Question 30[4 marks]
Answer or workingMarks
at least two valid combinations of whole bags totalling at least 2 kg identified, e.g. 3 x 750 g and 2 x 1 kgP1
3 x 90 (= 2.70) oe and 2 x 1.10 (= 2.20)M1oe
£2.70 and £2.20 both correctA1cao
correct conclusion that 2 x 1 kg bags for £2.20 is the cheapest way to buy at least 2 kgC1
Final answer: Buy 2 bags of 1 kg sugar for £2.20 (this gives exactly 2 kg for the least cost)
Mark scheme for Question 31 [5 marks]
Question 31[5 marks]
Answer or workingMarks
equate 2x + 1 = -x + 7 to form an equation in xM1
collect terms and solve for x giving x = 2M1
x = 2A1cao
substitute x = 2 into one of the equations to find yM1
y = 5A1cao
Final answer: (2, 5)
Mark scheme for Question 32 [3 marks]
Question 32[3 marks]
Answer or workingMarks
sets up area = (6 + sqrt(11))(6 - sqrt(11))M1
36 - 11 evaluated (from 36 - 6sqrt(11) + 6sqrt(11) - 11 or difference of two squares)M1
25 m^2A1cao
Mark scheme for Question 33 [3 marks]
Question 33[3 marks]
Answer or workingMarks
upper bound of length = 15.5 and upper bound of width = 10.5M1oe
dep calculates upper bound of area = 15.5 x 10.5 (= 162.75)M1oe
correct conclusion with supporting figures, e.g. Yes, the claim is correct, since the maximum possible area is 162.75 cm^2, which is greater than 160 cm^2A1cso
Final answer: Yes - the framer is correct, since the maximum possible area (162.75 cm^2) is greater than 160 cm^2.
Mark scheme for Question 34 [3 marks]
Question 34[3 marks]
Answer or workingMarks
(0, 1)B1
y = 0B1
increasing (since base 3 > 1)B1
Final answer: (0, 1) | y = 0 | Increasing
Mark scheme for Question 35 [3 marks]
Question 35[3 marks]
Answer or workingMarks
volume scale factor = (3/2)^3 (oe, from linear scale factor 3/2)M1
volume scale factor = 27/8 (= 3.375)M1oe
324 cm^3A1cao
Mark scheme for Question 36 [4 marks]
Question 36[4 marks]
Answer or workingMarks
maximum = 1B1
minimum = -3B1
(0, 1)B1
360B1
Final answer: Maximum = 1, minimum = -3 | (0, 1) | 360 degrees
Mark scheme for Question 37 [5 marks]
Question 37[5 marks]
Answer or workingMarks
convert 10 1/2 to improper fraction 21/2M1
find amount removed: 1/4 × 21/2 = 21/8 and find remainder 21/2 - 21/8 = 63/8M1
find amount used for bows: 3/5 × 63/8 = 189/40M1
subtract used from remainder: 63/8 - 189/40 = 63/20M1
3 3/20A1cao
Mark scheme for Question 38 [5 marks]
Question 38[5 marks]
Answer or workingMarks
use 1/2 * 15 * 10 * sin A = 36 so sin A = 72/150 = 0.48M1
take inverse sine to find A = arcsin(0.48)M1oe
use law of cosines: BC^2 = 15^2 + 10^2 - 2*15*10*cos AM1
substitute cos A and evaluate BCM1
8 cmA1cao