Foundation Tier - Year 10

Year 10 Paper 2: Graphs and Sequences

Covers linear algebra, graphs and coordinates, sequences, number and calculation, ratio and proportion, and angles and geometrical reasoning.

21 questions - 60 marks - calculator allowed

Year 10 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 10, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [2 marks]

Sequences

Here are the first five terms of a sequence. 2, 5, 7, 12, 19

Explain how each term of the sequence, after the first two, is found from the previous two terms.

Work out the next term in the sequence.

Question 2 [2 marks]

Angles and Geometrical Reasoning

Shape P has vertices at (1, 1), (1, 3) and (3, 1). Shape Q has vertices at (1, -1), (1, -3) and (3, -1).

Question 3 [2 marks]

Number and Calculation

Round 15.976 to 3 significant figures.

Question 4 [3 marks]

Linear Algebra

Each part below shows a different function machine with input n. Select the expression that represents the output.

input n --> [ x 2 ] --> [ +5 ] --> output. Which expression represents the output?

input n --> [ +3 ] --> [ x 4 ] --> output. Which expression represents the output?

input n --> [ x 5 ] --> [ -2 ] --> output. Which expression represents the output?

Question 5 [3 marks]

Ratio and Proportion

A football squad has 24 players. The ratio of forwards to midfielders to defenders is 3:5:4. Work out the percentage of the squad who are defenders.

Question 6 [3 marks]

Linear Algebra

x = -2 and y = 1/4. Work out the value of 1/x + 1/y.

Question 7 [4 marks]

Graphs and Coordinates

A sequence of points is generated on a grid. The first point is (1, -2). Each new point is formed by adding 3 to the x-coordinate and adding 2 to the y-coordinate of the previous point.

Write down the coordinates of the second point in the sequence.

Write down the coordinates of the third point in the sequence.

One of the points in the sequence has coordinates (16, y). Work out the value of y.

Question 8 [1 marks]

Number and Calculation

Work out 9^2 - 12.

Question 9 [2 marks]

Ratio and Proportion

Share £63 in the ratio 1:2. Work out how much the smaller share is.

Question 10 [2 marks]

Angles and Geometrical Reasoning

The exterior angle of a regular polygon is 15 degrees. Work out the number of sides of the polygon.

Question 11 [2 marks]

Sequences

The sequence is 5, 9, 13, 17, ... Find the value of n for the term 29.

Question 12 [2 marks]

Number and Calculation

Show that 41472 is divisible by 8.

Question 13 [2 marks]

Angles and Geometrical Reasoning

v is the column vector (9, 12). Calculate the magnitude of v, |v|.

Question 14 [3 marks]

Number and Calculation

A jacket normally costs £45. In a sale, the price is reduced by 1/5. Work out the sale price of the jacket.

Question 15 [3 marks]

Linear Algebra

The formula for the cost C (in pounds) of m apples and n bananas is C = 0.30m + 0.20n. Work out C when m = 4 and n = 6. Give your answer to the nearest penny.

Question 16 [3 marks]

Number and Calculation

Use long division to work out 9876 ÷ 12.

Question 17 [4 marks]

Ratio and Proportion

Sara walks 3.6 km in 45 minutes, at a constant speed. Calculate her average speed in m/s. Give your answer to 3 significant figures.

Question 18 [4 marks]

Linear Algebra

Form and solve an equation. "Sarah has £2.50. She buys a drink costing d pounds and has £1.10 left. How much did the drink cost?"

Form an equation in d to represent the situation.

Solve the equation and give the cost of the drink.

Question 19 [6 marks]

Number and Calculation

The integers a, b and c are given by a = -4, b = 7 and c = -3. This question has four parts.

Work out a + b - c.

Work out a x c.

Hence or otherwise, work out (a x c) / b, giving your answer as a decimal rounded to 1 decimal place.

Given that d is an integer such that b + d = a, work out the value of d.

Question 20 [5 marks]

Sequences

Here are the first four terms of a geometric sequence. 5, 15, 45, 135

Find the common ratio of the sequence.

Find the 6th term of the sequence.

Explain whether 3000 is a term of the sequence.

Question 21 [2 marks]

Number and Calculation

Work out (-8) + 15 - 6.

Model solutions

Mark scheme for Question 1 [2 marks]
Question 1[2 marks]
Answer or workingMarks
each term is the sum of the two previous termsB1oe
31 cao, ft from their rule in part (a)B1
Final answer: Each term is found by adding the two previous terms together. | 31
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
reflection (oe 'reflected')B1
mirror line x-axis, y = 0B1oe
Final answer: Reflection in the x-axis (y = 0)
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
identifies the first 3 significant figures as 1, 5, 9 and the next digit as 7M1oe
16.0A1cao
Mark scheme for Question 4 [3 marks]
Question 4[3 marks]
Answer or workingMarks
AB1cao
BB1cao
AB1cao
Final answer: A, B, A
Mark scheme for Question 5 [3 marks]
Question 5[3 marks]
Answer or workingMarks
24 / 12 = 2 oe (one share found)M1
defenders = 4 x 2 = 8 oe, then 8/24 x 100M1dep
awrt 33.3% (exact value 100/3%)A1
Final answer: 33.3% (1 dp); exact value 100/3%
Mark scheme for Question 6 [3 marks]
Question 6[3 marks]
Answer or workingMarks
1 / (-2) (= -0.5) seenM1oe
1 / (1/4) (= 4) seenM1oe
3.5 oe (7/2)A1
Final answer: 3.5 (or 7/2)
Mark scheme for Question 7 [4 marks]
Question 7[4 marks]
Answer or workingMarks
(4, 0)B1cao
(7, 2)B1cao
correct method to find which term has x = 16, e.g. 1 + 3n = 16 so n = 5M1oe
y = 8A1cao
Final answer: (4, 0) | (7, 2) | y = 8
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
69B1cao
Mark scheme for Question 9 [2 marks]
Question 9[2 marks]
Answer or workingMarks
divide 63 by 3 to find one part (63/3 = 21) or equivalent methodM1
£21A1cao
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
360 / 15M1
24A1cao
Final answer: 24 sides
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
use nth term formula 4n + 1 = 29 or show 5 + (n-1)4 = 29M1oe
7A1cao
Mark scheme for Question 12 [2 marks]
Question 12[2 marks]
Answer or workingMarks
Uses the divisibility test for 8: a number is divisible by 8 if its last three digits are divisible by 8, and identifies the last three digits as 472M1
472 = 8 x 59, so 41472 is divisible by 8A1cso
Final answer: 41472 is divisible by 8, since its last three digits (472) equal 8 x 59.
Mark scheme for Question 13 [2 marks]
Question 13[2 marks]
Answer or workingMarks
sqrt(9^2 + 12^2)M1oe
15A1cao
Mark scheme for Question 14 [3 marks]
Question 14[3 marks]
Answer or workingMarks
45 / 5 (= 9) seenM1
45 - their 9 (dependent method)M1
£36A1cao
Mark scheme for Question 15 [3 marks]
Question 15[3 marks]
Answer or workingMarks
substitute m = 4 and n = 6 into 0.30m + 0.20n and evaluateM1
add totals for apples and bananas correctlyM1
£2.40A1cao
Final answer: 2.40
Mark scheme for Question 16 [3 marks]
Question 16[3 marks]
Answer or workingMarks
correct stages of long division shown (e.g. subtract 9600 leaving 276 or equivalent)M1
correct subsequent division step shown (e.g. 276 ÷ 12 = 23)M1
823A1cao
Mark scheme for Question 17 [4 marks]
Question 17[4 marks]
Answer or workingMarks
3.6 km = 3600 mM1oe
45 minutes = 2700 secondsM1oe
3600 / 2700 oe (ft their distance in m and time in s)M1
1.33 (m/s)A1awrt
Final answer: 1.33 m/s (3 s.f.)
Mark scheme for Question 18 [4 marks]
Question 18[4 marks]
Answer or workingMarks
equation formed, e.g. 2.50 - d = 1.10M1oe
subtract 1.10 from both sides or rearrange (2.50 - 1.10 = d seen)M1
calculate correctly 2.50 - 1.10 = 1.40M1
d = 1.40A1cao
Final answer: 2.50 - d = 1.10, d = 1.40
Mark scheme for Question 19 [6 marks]
Question 19[6 marks]
Answer or workingMarks
6B1cao
12B1cao
12 / 7 seen, or correct division set upM1oe
1.7A1awrt
correct rearrangement: d = a - bM1oe
-11A1cao
Final answer: 6 | 12 | 1.7 (awrt) | -11
Mark scheme for Question 20 [5 marks]
Question 20[5 marks]
Answer or workingMarks
3B1cao
5 x 3^5 oe, or lists terms up to the 6thM1
1215A1cao
identifies the two terms either side of 3000 (1215 and 3645), or sets up 5 x 3^(n-1) = 3000M1oe
correct conclusion: no, 3000 is not a term, e.g. it lies strictly between 1215 and 3645A1oe
Final answer: 3 | 1215 | No, 3000 is not a term of the sequence
Mark scheme for Question 21 [2 marks]
Question 21[2 marks]
Answer or workingMarks
-8 + 15 (= 7) (oe), or equivalent complete methodM1
1A1cao