Foundation Tier - Year 11

Year 11 Paper 2: Graphs and Shape

Covers indices and standard form, graphs and coordinates, sequences, area, volume and measures, angles and geometrical reasoning, and ratio and proportion.

24 questions - 60 marks - calculator allowed

Year 11 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 11, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [1 marks]

Area, Volume and Measures

Convert 2 kg to g

Question 2 [1 marks]

Angles and Geometrical Reasoning

An angle measures 265 degrees. Write down the mathematical name for this type of angle.

Question 3 [1 marks]

Area, Volume and Measures

The volume of a sphere of radius r is given by one of the formulae below.

Question 4 [2 marks]

Ratio and Proportion

Given that 5:x = 15:24, work out the value of x.

Question 5 [2 marks]

Graphs and Coordinates

On the grid provided, draw the following straight lines.

Draw the graph of x = -3.

Draw the graph of y = 2.

Question 6 [2 marks]

Indices and Standard Form

Show that 4^2 + 3^2 = 5^2

Question 7 [2 marks]

Angles and Geometrical Reasoning

Lines l and m are parallel and are crossed by a straight transversal. Angle y is in the corresponding position to the 118 degree angle marked above line l.

Question 8 [3 marks]

Sequences

Three sequences are shown below. Sequence A: 7, 11, 15, 19 Sequence B: 4, 12, 36, 108 Sequence C: 3, 6, 11, 18

State whether Sequence A is arithmetic, geometric, or neither of these. Give a reason for your answer.

State whether Sequence B is arithmetic, geometric, or neither of these. Give a reason for your answer.

State whether Sequence C is arithmetic, geometric, or neither of these. Give a reason for your answer.

Question 9 [3 marks]

Angles and Geometrical Reasoning

A ship sails from port A on a bearing of 065 degrees.

Write down why the bearing is given as 065 and not 65.

Work out the bearing needed to sail back to port A (the back bearing).

Question 10 [1 marks]

Area, Volume and Measures

Two squares are drawn, of any size.

Question 11 [1 marks]

Ratio and Proportion

Convert the ratio 2:7 into a fraction.

Question 12 [1 marks]

Indices and Standard Form

Work out the value of 5^-1. Give your answer as a fraction.

Question 13 [3 marks]

Angles and Geometrical Reasoning

Lines l and m are parallel. A transversal crosses l at P and m at Q, and the angle between the transversal and l is 118 degrees. At Q, three further angles going all the way around the point are marked 90 degrees, 150 degrees and w, in addition to the angle co-interior to the 118 degree angle.

Question 14 [1 marks]

Indices and Standard Form

Work out (-3)^3.

Question 15 [2 marks]

Angles and Geometrical Reasoning

Triangle PQR has vertex P at (-3, 2). Triangle PQR is translated by the vector (4, -5) to give triangle P'Q'R'.

Write down the coordinates of P'.

Write down the column vector that translates P' back to P.

Question 16 [2 marks]

Graphs and Coordinates

Complete the table for y = x^3. Give values for the missing entries.

x = -2, y = ____

x = 1, y = ____

Question 17 [1 marks]

Area, Volume and Measures

A parallelogram-shaped ceramic tile has a base of 13 cm and a perpendicular height of 7 cm. Calculate the area of the tile.

Question 18 [3 marks]

Angles and Geometrical Reasoning

Triangle ABC has a straight line DAE through vertex A, parallel to side BC (D on the same side as B, E on the same side as C). The angle between DAE and AB is 52 degrees; the angle between DAE and AC is 65 degrees. Work out the size of angle BAC. Show your reasoning.

Question 19 [3 marks]

Ratio and Proportion

Ravi has £3.60 and his sister has 90p. Write the ratio of Ravi's money to his sister's money in its simplest form.

Question 20 [4 marks]

Graphs and Coordinates

Use your table of values from Question 5 for y = 4/x.

Draw the graph of y = 4/x for -4 <= x <= 4, x not equal to 0, on the grid provided.

Explain why there is no point on the graph when x = 0.

Question 21 [4 marks]

Angles and Geometrical Reasoning

On a map with scale 1 : 50,000, the distance between town A and town B is 8.4 cm. The bearing of town B from town A is 072. Diagram: Point A is shown with a North arrow and a ray to B at a bearing of 072 degrees, with a parallel North arrow at B.

Calculate the real-life distance AB, giving your answer in km.

State the bearing of town A from town B.

Question 22 [5 marks]

Area, Volume and Measures

A circular garden has radius 14 m. A path is made that follows an arc of 120 degrees around the garden. The path is 2 m wide and runs along the outside edge of the garden (so the outer radius is 16 m). Work out the area of the path only. Give your answer to 1 decimal place. Use pi = 3.14159.

Question 23 [6 marks]

Graphs and Coordinates

The pressure, P pascals, of a fixed mass of gas is inversely proportional to its volume, V m^3, so that P = k/V for a constant k. When V = 2, P = 150.

Find the value of k.

Find the value of P when V = 5.

Describe the shape of the graph of P against V for V > 0.

State what happens to the pressure P if the volume V is doubled.

Question 24 [6 marks]

Area, Volume and Measures

A cone and a cylinder have the same radius 3 cm. The cone has height 8 cm and the cylinder has height 8 cm. Work out the total volume of the two solids. Give your answer in terms of pi.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
2000 gB1cao
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
reflexB1cao
Mark scheme for Question 3 [1 mark]
Question 3[1 mark]
Answer or workingMarks
BB1cao
Final answer: B) 4/3 pi r^3
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
sets up 5/15 = x/24 oe, or cross-multiplies 5 x 24 = 15xM1
x = 8A1cao
Mark scheme for Question 5 [2 marks]
Question 5[2 marks]
Answer or workingMarks
correct vertical line drawn through x = -3B1
correct horizontal line drawn through y = 2B1
Final answer: Vertical line through every point with x-coordinate -3. | Horizontal line through every point with y-coordinate 2.
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
4^2 + 3^2 = 16 + 9 = 25 shownB1
5^2 = 25 stated, so both sides are equalB1cso
Final answer: 25 = 25, so the statement is true
Mark scheme for Question 7 [2 marks]
Question 7[2 marks]
Answer or workingMarks
y = 118B1cao
correct reason: corresponding angles are equal (l parallel to m)B1
Final answer: y = 118 degrees
Mark scheme for Question 8 [3 marks]
Question 8[3 marks]
Answer or workingMarks
arithmetic, since the terms have a common difference of 4B1oe
geometric, since the terms have a common ratio of 3B1oe
neither, since the differences (3, 5, 7) are not constant and the ratios are not constantB1oe
Final answer: Arithmetic (common difference of 4) | Geometric (common ratio of 3) | Neither (it is a quadratic sequence)
Mark scheme for Question 9 [3 marks]
Question 9[3 marks]
Answer or workingMarks
bearings are always written using three figures (digits)B1oe
065 + 180M1
245A1cao
Final answer: Bearings are always written using three figures. | 245 degrees
Mark scheme for Question 10 [1 mark]
Question 10[1 mark]
Answer or workingMarks
Yes, because all squares have four equal sides and four right angles, so the ratio of corresponding sides is always the same (equal to 1)B1oe
Final answer: Yes, any two squares are mathematically similar.
Mark scheme for Question 11 [1 mark]
Question 11[1 mark]
Answer or workingMarks
2/7B1cao
Mark scheme for Question 12 [1 mark]
Question 12[1 mark]
Answer or workingMarks
1/5B1oe
Mark scheme for Question 13 [3 marks]
Question 13[3 marks]
Answer or workingMarks
co-interior angle = 180 - 118 = 62M1
360 - 62 - 90 - 150 (angles around a point sum to 360)M1
w = 58A1cao
Final answer: w = 58 degrees
Mark scheme for Question 14 [1 mark]
Question 14[1 mark]
Answer or workingMarks
-27B1cao
Mark scheme for Question 15 [2 marks]
Question 15[2 marks]
Answer or workingMarks
(1, -3)B1cao
(-4, 5) ft from (a)B1
Final answer: (1, -3) | (-4, 5)
Mark scheme for Question 16 [2 marks]
Question 16[2 marks]
Answer or workingMarks
-8B1cao
1B1cao
Final answer: -8 | 1
Mark scheme for Question 17 [1 mark]
Question 17[1 mark]
Answer or workingMarks
Area = base x height = 13 x 7 = 91 cm^2B1cao
Final answer: 91 cm^2
Mark scheme for Question 18 [3 marks]
Question 18[3 marks]
Answer or workingMarks
angle ABC = 52 (alternate angles, DAE parallel to BC)M1
angle ACB = 65 (alternate angles, DAE parallel to BC)M1
angle BAC = 180 - 52 - 65 = 63 cao (angle sum of a triangle)A1
Final answer: angle BAC = 63 degrees
Mark scheme for Question 19 [3 marks]
Question 19[3 marks]
Answer or workingMarks
convert £3.60 to 360pM1oe
form the ratio 360:90 and begin to simplifyM1
4:1A1cao
Mark scheme for Question 20 [4 marks]
Question 20[4 marks]
Answer or workingMarks
branch in the region x<0 plotted correctly through (-4,-1), (-2,-2), (-1,-4), ft candidate's tableB1
branch in the region x>0 plotted correctly through (1,4), (2,2), (4,1), ft candidate's tableB1
two separate smooth curved branches drawn, correctly getting closer to both axes without touching or crossing them, and not joined across x=0B1
correct explanation that division by zero is undefined, e.g. 4/0 has no valueB1oe
Final answer: Two branches: one through (-4,-1), (-2,-2), (-1,-4); one through (1,4), (2,2), (4,1) | x cannot equal 0 because 4/0 is undefined (division by zero has no value)
Mark scheme for Question 21 [4 marks]
Question 21[4 marks]
Answer or workingMarks
8.4 x 50000 (=420000)M1oe
4.2 kmA1cao
072 + 180M1oe
252A1cao
Final answer: 4.2 km | 252
Mark scheme for Question 22 [5 marks]
Question 22[5 marks]
Answer or workingMarks
area path = fraction (120/360) * (pi * R^2 - pi * r^2)M1
substitute R = 16, r = 14 so area = 1/3 * pi * (256 - 196) = 1/3 * pi * 60M1
calculate 1/3 * 60 = 20 so area = 20 * piM1
62.8318... -> 62.8 m^2 (1 dp)A1
final answer given as 62.8 m^2B1cao
Final answer: 62.8 m^2
Mark scheme for Question 23 [6 marks]
Question 23[6 marks]
Answer or workingMarks
substitutes P=150 and V=2 into P=k/V, e.g. 150=k/2M1
k = 300A1cao
substitutes k=300 and V=5 into P=k/VM1
P = 60 cao (units: pascals)A1
a curve that continually decreases as V increases, getting closer to but never touching either axisB1oe
P is halvedB1oe
Final answer: k = 300 | P = 60 pascals | A decreasing reciprocal-shaped curve that never touches the axes | P is halved
Mark scheme for Question 24 [6 marks]
Question 24[6 marks]
Answer or workingMarks
find r^2: 3^2 = 9M1
cylinder volume method: V = pi r^2 h, so 9 * 8 = 72, cylinder = 72 piM1
cone method: V = (1/3) pi r^2 h, so (1/3) * 9 * 8 = 24, cone = 24 piM1
write cone volume = 24 pi and cylinder = 72 piM1
add volumes: 72 pi + 24 pi = 96 piA1
96 pi cm^3A1cao