Year 11 Paper 2: Graphs and Shape
Covers indices and standard form, graphs and coordinates, sequences, area, volume and measures, angles and geometrical reasoning, and ratio and proportion.
Year 11 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 11, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [1 marks]
Area, Volume and Measures
Convert 2 kg to g
Question 2 [1 marks]
Angles and Geometrical Reasoning
An angle measures 265 degrees. Write down the mathematical name for this type of angle.
Question 3 [1 marks]
Area, Volume and Measures
The volume of a sphere of radius r is given by one of the formulae below.
Question 4 [2 marks]
Ratio and Proportion
Given that 5:x = 15:24, work out the value of x.
Question 5 [2 marks]
Graphs and Coordinates
On the grid provided, draw the following straight lines.
Draw the graph of x = -3.
Draw the graph of y = 2.
Question 6 [2 marks]
Indices and Standard Form
Show that 4^2 + 3^2 = 5^2
Question 7 [2 marks]
Angles and Geometrical Reasoning
Lines l and m are parallel and are crossed by a straight transversal. Angle y is in the corresponding position to the 118 degree angle marked above line l.
Question 8 [3 marks]
Sequences
Three sequences are shown below. Sequence A: 7, 11, 15, 19 Sequence B: 4, 12, 36, 108 Sequence C: 3, 6, 11, 18
State whether Sequence A is arithmetic, geometric, or neither of these. Give a reason for your answer.
State whether Sequence B is arithmetic, geometric, or neither of these. Give a reason for your answer.
State whether Sequence C is arithmetic, geometric, or neither of these. Give a reason for your answer.
Question 9 [3 marks]
Angles and Geometrical Reasoning
A ship sails from port A on a bearing of 065 degrees.
Write down why the bearing is given as 065 and not 65.
Work out the bearing needed to sail back to port A (the back bearing).
Question 10 [1 marks]
Area, Volume and Measures
Two squares are drawn, of any size.
Question 11 [1 marks]
Ratio and Proportion
Convert the ratio 2:7 into a fraction.
Question 12 [1 marks]
Indices and Standard Form
Work out the value of 5^-1. Give your answer as a fraction.
Question 13 [3 marks]
Angles and Geometrical Reasoning
Lines l and m are parallel. A transversal crosses l at P and m at Q, and the angle between the transversal and l is 118 degrees. At Q, three further angles going all the way around the point are marked 90 degrees, 150 degrees and w, in addition to the angle co-interior to the 118 degree angle.
Question 14 [1 marks]
Indices and Standard Form
Work out (-3)^3.
Question 15 [2 marks]
Angles and Geometrical Reasoning
Triangle PQR has vertex P at (-3, 2). Triangle PQR is translated by the vector (4, -5) to give triangle P'Q'R'.
Write down the coordinates of P'.
Write down the column vector that translates P' back to P.
Question 16 [2 marks]
Graphs and Coordinates
Complete the table for y = x^3. Give values for the missing entries.
x = -2, y = ____
x = 1, y = ____
Question 17 [1 marks]
Area, Volume and Measures
A parallelogram-shaped ceramic tile has a base of 13 cm and a perpendicular height of 7 cm. Calculate the area of the tile.
Question 18 [3 marks]
Angles and Geometrical Reasoning
Triangle ABC has a straight line DAE through vertex A, parallel to side BC (D on the same side as B, E on the same side as C). The angle between DAE and AB is 52 degrees; the angle between DAE and AC is 65 degrees. Work out the size of angle BAC. Show your reasoning.
Question 19 [3 marks]
Ratio and Proportion
Ravi has £3.60 and his sister has 90p. Write the ratio of Ravi's money to his sister's money in its simplest form.
Question 20 [4 marks]
Graphs and Coordinates
Use your table of values from Question 5 for y = 4/x.
Draw the graph of y = 4/x for -4 <= x <= 4, x not equal to 0, on the grid provided.
Explain why there is no point on the graph when x = 0.
Question 21 [4 marks]
Angles and Geometrical Reasoning
On a map with scale 1 : 50,000, the distance between town A and town B is 8.4 cm. The bearing of town B from town A is 072. Diagram: Point A is shown with a North arrow and a ray to B at a bearing of 072 degrees, with a parallel North arrow at B.
Calculate the real-life distance AB, giving your answer in km.
State the bearing of town A from town B.
Question 22 [5 marks]
Area, Volume and Measures
A circular garden has radius 14 m. A path is made that follows an arc of 120 degrees around the garden. The path is 2 m wide and runs along the outside edge of the garden (so the outer radius is 16 m). Work out the area of the path only. Give your answer to 1 decimal place. Use pi = 3.14159.
Question 23 [6 marks]
Graphs and Coordinates
The pressure, P pascals, of a fixed mass of gas is inversely proportional to its volume, V m^3, so that P = k/V for a constant k. When V = 2, P = 150.
Find the value of k.
Find the value of P when V = 5.
Describe the shape of the graph of P against V for V > 0.
State what happens to the pressure P if the volume V is doubled.
Question 24 [6 marks]
Area, Volume and Measures
A cone and a cylinder have the same radius 3 cm. The cone has height 8 cm and the cylinder has height 8 cm. Work out the total volume of the two solids. Give your answer in terms of pi.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 2000 g | B1cao |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| reflex | B1cao |
| Question 3[1 mark] | |
|---|---|
| Answer or working | Marks |
| B | B1cao |
| Final answer: B) 4/3 pi r^3 | |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| sets up 5/15 = x/24 oe, or cross-multiplies 5 x 24 = 15x | M1 |
| x = 8 | A1cao |
| Question 5[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct vertical line drawn through x = -3 | B1 |
| correct horizontal line drawn through y = 2 | B1 |
| Final answer: Vertical line through every point with x-coordinate -3. | Horizontal line through every point with y-coordinate 2. | |
| Question 6[2 marks] | |
|---|---|
| Answer or working | Marks |
| 4^2 + 3^2 = 16 + 9 = 25 shown | B1 |
| 5^2 = 25 stated, so both sides are equal | B1cso |
| Final answer: 25 = 25, so the statement is true | |
| Question 7[2 marks] | |
|---|---|
| Answer or working | Marks |
| y = 118 | B1cao |
| correct reason: corresponding angles are equal (l parallel to m) | B1 |
| Final answer: y = 118 degrees | |
| Question 8[3 marks] | |
|---|---|
| Answer or working | Marks |
| arithmetic, since the terms have a common difference of 4 | B1oe |
| geometric, since the terms have a common ratio of 3 | B1oe |
| neither, since the differences (3, 5, 7) are not constant and the ratios are not constant | B1oe |
| Final answer: Arithmetic (common difference of 4) | Geometric (common ratio of 3) | Neither (it is a quadratic sequence) | |
| Question 9[3 marks] | |
|---|---|
| Answer or working | Marks |
| bearings are always written using three figures (digits) | B1oe |
| 065 + 180 | M1 |
| 245 | A1cao |
| Final answer: Bearings are always written using three figures. | 245 degrees | |
| Question 10[1 mark] | |
|---|---|
| Answer or working | Marks |
| Yes, because all squares have four equal sides and four right angles, so the ratio of corresponding sides is always the same (equal to 1) | B1oe |
| Final answer: Yes, any two squares are mathematically similar. | |
| Question 11[1 mark] | |
|---|---|
| Answer or working | Marks |
| 2/7 | B1cao |
| Question 12[1 mark] | |
|---|---|
| Answer or working | Marks |
| 1/5 | B1oe |
| Question 13[3 marks] | |
|---|---|
| Answer or working | Marks |
| co-interior angle = 180 - 118 = 62 | M1 |
| 360 - 62 - 90 - 150 (angles around a point sum to 360) | M1 |
| w = 58 | A1cao |
| Final answer: w = 58 degrees | |
| Question 14[1 mark] | |
|---|---|
| Answer or working | Marks |
| -27 | B1cao |
| Question 15[2 marks] | |
|---|---|
| Answer or working | Marks |
| (1, -3) | B1cao |
| (-4, 5) ft from (a) | B1 |
| Final answer: (1, -3) | (-4, 5) | |
| Question 16[2 marks] | |
|---|---|
| Answer or working | Marks |
| -8 | B1cao |
| 1 | B1cao |
| Final answer: -8 | 1 | |
| Question 17[1 mark] | |
|---|---|
| Answer or working | Marks |
| Area = base x height = 13 x 7 = 91 cm^2 | B1cao |
| Final answer: 91 cm^2 | |
| Question 18[3 marks] | |
|---|---|
| Answer or working | Marks |
| angle ABC = 52 (alternate angles, DAE parallel to BC) | M1 |
| angle ACB = 65 (alternate angles, DAE parallel to BC) | M1 |
| angle BAC = 180 - 52 - 65 = 63 cao (angle sum of a triangle) | A1 |
| Final answer: angle BAC = 63 degrees | |
| Question 19[3 marks] | |
|---|---|
| Answer or working | Marks |
| convert £3.60 to 360p | M1oe |
| form the ratio 360:90 and begin to simplify | M1 |
| 4:1 | A1cao |
| Question 20[4 marks] | |
|---|---|
| Answer or working | Marks |
| branch in the region x<0 plotted correctly through (-4,-1), (-2,-2), (-1,-4), ft candidate's table | B1 |
| branch in the region x>0 plotted correctly through (1,4), (2,2), (4,1), ft candidate's table | B1 |
| two separate smooth curved branches drawn, correctly getting closer to both axes without touching or crossing them, and not joined across x=0 | B1 |
| correct explanation that division by zero is undefined, e.g. 4/0 has no value | B1oe |
| Final answer: Two branches: one through (-4,-1), (-2,-2), (-1,-4); one through (1,4), (2,2), (4,1) | x cannot equal 0 because 4/0 is undefined (division by zero has no value) | |
| Question 21[4 marks] | |
|---|---|
| Answer or working | Marks |
| 8.4 x 50000 (=420000) | M1oe |
| 4.2 km | A1cao |
| 072 + 180 | M1oe |
| 252 | A1cao |
| Final answer: 4.2 km | 252 | |
| Question 22[5 marks] | |
|---|---|
| Answer or working | Marks |
| area path = fraction (120/360) * (pi * R^2 - pi * r^2) | M1 |
| substitute R = 16, r = 14 so area = 1/3 * pi * (256 - 196) = 1/3 * pi * 60 | M1 |
| calculate 1/3 * 60 = 20 so area = 20 * pi | M1 |
| 62.8318... -> 62.8 m^2 (1 dp) | A1 |
| final answer given as 62.8 m^2 | B1cao |
| Final answer: 62.8 m^2 | |
| Question 23[6 marks] | |
|---|---|
| Answer or working | Marks |
| substitutes P=150 and V=2 into P=k/V, e.g. 150=k/2 | M1 |
| k = 300 | A1cao |
| substitutes k=300 and V=5 into P=k/V | M1 |
| P = 60 cao (units: pascals) | A1 |
| a curve that continually decreases as V increases, getting closer to but never touching either axis | B1oe |
| P is halved | B1oe |
| Final answer: k = 300 | P = 60 pascals | A decreasing reciprocal-shaped curve that never touches the axes | P is halved | |
| Question 24[6 marks] | |
|---|---|
| Answer or working | Marks |
| find r^2: 3^2 = 9 | M1 |
| cylinder volume method: V = pi r^2 h, so 9 * 8 = 72, cylinder = 72 pi | M1 |
| cone method: V = (1/3) pi r^2 h, so (1/3) * 9 * 8 = 24, cone = 24 pi | M1 |
| write cone volume = 24 pi and cylinder = 72 pi | M1 |
| add volumes: 72 pi + 24 pi = 96 pi | A1 |
| 96 pi cm^3 | A1cao |