Higher Tier - Year 11

Year 11 Paper 5: Quadratics and Trigonometry

Covers number and calculation, ratio and proportion, indices and standard form, quadratics, angles and geometrical reasoning, area, volume and measures, and Pythagoras' theorem and trigonometry.

20 questions - 60 marks - calculator allowed

Year 11 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 11, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [1 marks]

Angles and Geometrical Reasoning

Point Q has coordinates (-2, 4). Write down the coordinates of the image of Q after a reflection in the y-axis.

Question 2 [1 marks]

Indices and Standard Form

Write the number 0.0032 in standard form.

Question 3 [1 marks]

Ratio and Proportion

The ratio of boys to girls in a class is 5:7. Write the number of boys as a fraction of the total number of pupils in the class.

Question 4 [1 marks]

Area, Volume and Measures

Rectangle A measures 6 cm by 9 cm.

Which of these rectangles is mathematically similar to rectangle A?

Question 5 [1 marks]

Pythagoras and Trigonometry

The diagram shows a right-angled triangle with the right angle marked. The sides are labelled p, q and r, where r is the side opposite the right angle. Diagram: right-angled triangle, right angle shown at the bottom-left corner, side p along the base, side q up the vertical side, side r as the slanted side joining the two ends.

Question 6 [2 marks]

Quadratics

Factorise 2x^2 - 7x + 3

Question 7 [1 marks]

Number and Calculation

Write down 5/6 - 1/4 as a single fraction.

Question 8 [2 marks]

Indices and Standard Form

Simplify sqrt(27) - sqrt(3) fully.

Question 9 [2 marks]

Area, Volume and Measures

Two mathematically similar shapes have areas of 20 cm^2 and 45 cm^2. Find the linear scale factor from the smaller shape to the larger shape.

Question 10 [3 marks]

Number and Calculation

A charity fun run raises £3,460, to be shared equally between 7 local charities. Work out the exact amount each charity receives, then round your answer to the nearest penny to state the amount that will actually be paid to each charity.

Question 11 [2 marks]

Pythagoras and Trigonometry

A right-angled triangle has hypotenuse length 10 cm and one acute angle 30 degrees. Work out the exact length of the side opposite the 30 degree angle.

Question 12 [3 marks]

Number and Calculation

Work out 4 1/3 - 1 3/4, giving your answer as a mixed number. You may use the fraction key on your calculator.

Question 13 [3 marks]

Ratio and Proportion

Ravi has £3.60 and his sister has 90p. Write the ratio of Ravi's money to his sister's money in its simplest form.

Question 14 [4 marks]

Number and Calculation

a = 2^3 x 5 and b = 2^2 x 5^2.

Find the HCF of a and b.

Find the LCM of a and b.

Question 15 [5 marks]

Ratio and Proportion

A cake recipe for 8 people uses 240 g of caster sugar and 200 g of butter. The amounts of each ingredient needed are directly proportional to the number of people.

Work out the mass of caster sugar needed to make the recipe for 6 people.

Nadia has 620 g of butter. Work out the maximum number of people she can make the recipe for.

Question 16 [5 marks]

Quadratics

Solve the quadratic equation by factorising: x^2 - x - 30 = 0. Give answers in exact form.

Question 17 [8 marks]

Ratio and Proportion

A town council divides its budget between parks and libraries in the ratio 5:(t + 3). The total budget is 1600 units. The council then changes the split so that the ratio of parks to libraries becomes 3:2, while keeping the total budget at 1600 units and keeping the actual amount allocated to parks exactly the same as before. Find t.

Question 18 [4 marks]

Angles and Geometrical Reasoning

ABCDEF is a regular hexagon with centre O; the vertices are labelled in order around the hexagon. OA = a and OB = b.

Find AB in terms of a and b.

D is the vertex opposite A. Find OD in terms of a.

E is the vertex opposite B. Find OE in terms of b.

Find EB in terms of b, giving your answer in its simplest form.

Question 19 [4 marks]

Area, Volume and Measures

A solid sphere has volume 500 cm^3. Calculate the surface area of the sphere. Give your answer correct to 3 significant figures.

Question 20 [7 marks]

Pythagoras and Trigonometry

A tall building BC stands on horizontal ground, and a vertical flagpole CD stands on top of the building at C. From a point A on the ground, 40 m from the base B of the building, the angle of elevation to the top of the building, C, is 28 degrees, and the angle of elevation to the top of the flagpole, D, is 34 degrees.

Calculate the height BC of the building. Give your answer correct to 3 significant figures.

Calculate the height CD of the flagpole. Give your answer correct to 3 significant figures.

Calculate the distance AD, from A to the top of the flagpole. Give your answer correct to 3 significant figures.

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
(2, 4)B1cao
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
3.2 x 10^-3B1oe
Mark scheme for Question 3 [1 mark]
Question 3[1 mark]
Answer or workingMarks
5/12B1oe
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
B) 12 cm by 18 cmB1
Final answer: B
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
r stated as the hypotenuseB1cao
Final answer: C) r
Mark scheme for Question 6 [2 marks]
Question 6[2 marks]
Answer or workingMarks
identifies a pair of numbers with product 6 and sum -7 (-6 and -1), or one correct bracket seenM1
(2x - 1)(x - 3)A1cao
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
7/12B1cao
Mark scheme for Question 8 [2 marks]
Question 8[2 marks]
Answer or workingMarks
sqrt(27) = 3sqrt(3) identifiedM1
2sqrt(3) oeA1cao
Final answer: 2sqrt(3)
Mark scheme for Question 9 [2 marks]
Question 9[2 marks]
Answer or workingMarks
area ratio = 45/20 (=2.25)M1oe
1.5A1cao
Mark scheme for Question 10 [3 marks]
Question 10[3 marks]
Answer or workingMarks
3,460 / 7 = 494.2857... shown (or equivalent method)M1
494.29 (pounds) to the nearest pennyA1cao
notes that 7 x 494.29 = 3,460.03, which is 3p more than the £3,460 raised, so rounding to the nearest penny does not exactly reconcile with the totalB1oe
Final answer: GBP494.29 to the nearest penny; 7 x 494.29 = GBP3,460.03, which is 3p more than the GBP3,460 raised, so the shares do not exactly reconcile with the total once rounded.
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
use sin 30 = opposite/hypotenuse to form opposite = 10 * sin 30M1
5 cmA1cao
Mark scheme for Question 12 [3 marks]
Question 12[3 marks]
Answer or workingMarks
convert to improper fractions or use fraction key: 13/3 - 7/4M1oe
common denominator 12 used, or show calculator method to reach 31/12M1
2 7/12A1cao
Mark scheme for Question 13 [3 marks]
Question 13[3 marks]
Answer or workingMarks
convert £3.60 to 360pM1oe
form the ratio 360:90 and begin to simplifyM1
4:1A1cao
Mark scheme for Question 14 [4 marks]
Question 14[4 marks]
Answer or workingMarks
correct lowest power of each common prime identified, 2^2 and 5^1M1
20A1cao
correct highest power of each prime identified, 2^3 and 5^2M1
200A1cao
Final answer: 20 | 200
Mark scheme for Question 15 [5 marks]
Question 15[5 marks]
Answer or workingMarks
finds sugar per person = 240/8 = 30 (g)M1oe
180 gA1cao
finds butter per person = 200/8 = 25 (g)M1oe
620/25 (= 24.8) oe, dependent on the first M1dM1
24 cao, rounded down to a whole number of peopleA1
Final answer: 180 g | 24 people
Mark scheme for Question 16 [5 marks]
Question 16[5 marks]
Answer or workingMarks
factorise to (x + 5)(x - 6) or show factors giving product -30 and sum -1M1
set each factor to zero: x + 5 = 0 or x - 6 = 0M1
x = -5A1
x = 6A1
list both solutions as x = -5, 6 (exact)B1cao
Final answer: x = -5 or x = 6 (Exact values)
Mark scheme for Question 17 [8 marks]
Question 17[8 marks]
Answer or workingMarks
express original parts: parks = 5p, libraries = (t+3)p so total = (t+8)p = 1600M1
after change ratio becomes 3:2 so parks = 3q, libraries = 2q and total =5q =1600 so q = 320M1
parks amount is unchanged: 5p = 3q so p = 3q/5M1
substitute q=320 to get p = 3*320/5 = 192M1
use total (t+8)p =1600 so (t+8)*192 = 1600M1
solve (t+8) = 1600/192 = 25/3? show stepsM1
find t = 1600/192 - 8 = (25/3) - 8 = (25 - 24)/3 = 1/3M1
t = 1/3A1cao
Final answer: t = 1/3. Working check: total 1600 = 5p + (t+3)p = (t+8)p. New ratio 3:2 gives q = 320 and parks 3q = 960 so p = 960/5 = 192. Then t+8 = 1600/192 = 25/3 so t = 25/3 - 8 = 1/3.
Mark scheme for Question 18 [4 marks]
Question 18[4 marks]
Answer or workingMarks
b - aB1cao
-a cao, using that O is the midpoint of the diagonal AD in a regular hexagonB1
-b cao, using that O is the midpoint of the diagonal BEB1
2b oe, ft theirB1OE
Final answer: AB = b - a | OD = -a | OE = -b | EB = 2b
Mark scheme for Question 19 [4 marks]
Question 19[4 marks]
Answer or workingMarks
rearranges V = (4/3) x pi x r^3 to r^3 = 3V / (4 x pi)M1oe
r = awrt 4.92 cm (unrounded value should be carried forward if possible)M1
substitutes their r into SA = 4 x pi x r^2M1ft
awrt 305 cm^2 (cao; accept awrt 304-305 depending on rounding of r)A1
Final answer: 305 cm^2 (3 s.f.)
Mark scheme for Question 20 [7 marks]
Question 20[7 marks]
Answer or workingMarks
BC = 40 tan(28)M1oe
awrt 21.3 (m)A1
BD (total height) = 40 tan(34)M1oe
CD = their BD - their BCM1ft
awrt 5.71 (m)A1
AD = 40 / cos(34)M1oe
awrt 48.2 (m)A1
Final answer: BC = 21.3 m (3 s.f.) | CD = 5.71 m (3 s.f.) | AD = 48.2 m (3 s.f.)