Year 11 Paper 6: Full Year 11 Review
Covers fractions, decimals and percentages, ratio and proportion, linear algebra, quadratics, graphs and coordinates, sequences, Pythagoras' theorem and trigonometry, and statistics and probability.
Year 11 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 11, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.
Questions
Question 1 [2 marks]
Sequences
Here are the first four terms of a sequence. 2, 6, 10, 14
Write down the next two terms of the sequence.
Describe, in words, the term-to-term rule for the sequence.
Question 2 [3 marks]
Statistics and Probability
Fatima has a biased coin. She flips it 40 times and records 28 heads.
Calculate the relative frequency of heads.
Fatima is going to flip the coin 500 times. Estimate the number of times it will land on heads.
Question 3 [4 marks]
Ratio and Proportion
The cost, C pounds, of a length of ribbon is directly proportional to its length, L metres. 3 metres of ribbon costs £4.50.
Work out the cost of 8 metres of the same ribbon.
Sarah has £10.50 to spend on this ribbon. Work out the maximum length of ribbon she can buy.
Question 4 [1 marks]
Linear Algebra
Solve x/4 = 3.
Question 5 [1 marks]
Pythagoras and Trigonometry
Explain why tan 90 degrees is undefined.
Question 6 [1 marks]
Statistics and Probability
A vet in Derby recorded the weight, in kg, of 6 dogs brought in for a check-up. Stem | Leaf 1 | 2 8 2 | 0 4 4 9 Key: 2 | 4 means 24 kg Write down the weight represented by the leaf 9 in the stem 2 row.
Question 7 [1 marks]
Linear Algebra
Which of the following is the solution to 2x + 1 >= x - 4?
Question 8 [2 marks]
Graphs and Coordinates
Find the coordinates of the midpoint of the line segment joining the points A(-3, 5) and B(5, -1).
Question 9 [2 marks]
Pythagoras and Trigonometry
In triangle PQR, PQ = 6 cm, PR = 9 cm and angle QPR = 40 degrees. Calculate the length of QR. Give your answer correct to 3 significant figures.
Question 10 [2 marks]
Statistics and Probability
A ball is drawn at random from a bag containing only red, blue and green balls. Event R is that the ball is red. Event Bl is that the ball is blue.
Explain why events R and Bl are mutually exclusive.
On a Venn diagram, state how you would show that two events are mutually exclusive.
Question 11 [2 marks]
Graphs and Coordinates
Find the inverse function f^{-1}(x) for f(x) = (x + 6)/4.
Question 12 [2 marks]
Statistics and Probability
Graph A shows the relationship between arm span and height for a class of students; the points lie close to a straight line. Graph B shows the relationship between shoe size and exam score for the same class; the points are scattered with no clear pattern.
State which graph shows the stronger correlation.
Give a reason for your answer.
Question 13 [3 marks]
Quadratics
Solve x^2 + 6x + 2 = 0 using the quadratic formula. Give your answers correct to 3 significant figures.
Question 14 [3 marks]
Linear Algebra
Solve the simultaneous equations: 1.5x + y = 9 0.5x + y = 5
Question 15 [3 marks]
Fractions, Decimals and Percentages
Sam paints 3/5 of a fence in the morning. In the afternoon he paints 1/4 of the remaining part. What fraction of the whole fence has Sam painted by the end of the day?
Question 16 [3 marks]
Linear Algebra
Tom thinks of a number, x. He multiplies it by 3, then subtracts 7. The result is greater than 14.
Write an inequality, in terms of x, to show this information.
Solve your inequality to find the possible values of x.
Question 17 [3 marks]
Statistics and Probability
Six students recorded the number of hours they revised and their test score (%). Hours revised (x): 2, 4, 5, 7, 8, 10. Test score % (y): 45, 55, 60, 68, 75, 85.
Calculate the mean number of hours revised.
Calculate the mean test score.
Write down the coordinates of the point that must lie on the line of best fit.
Question 18 [3 marks]
Ratio and Proportion
A chocolate costs £1.20 each. You can buy a pack of 5 for £5.00 or take a "3 for 2" offer in the shop. Which way is cheapest if you need 9 bars? Show working.
Question 19 [4 marks]
Graphs and Coordinates
A distance-time graph for a runner is made from three connected straight segments. From t = 0 to t = 8 seconds the distance is given by d = 2t metres. From t = 8 to t = 20 seconds the runner slows with speed 1.5 m/s. From t = 20 to t = 28 seconds the runner rests and distance stays constant. Use these expressions to answer the questions.
Find the distance from the start at t = 8 seconds.
Work out the distance at t = 20 seconds.
State the runner's speed between 20 and 28 seconds and explain what the graph looks like on that interval.
Question 20 [3 marks]
Statistics and Probability
A jar contains red, blue and yellow sweets. The probability of drawing red is (2x)/(5x + 3) and this equals 1/3. Solve for x.
Question 21 [6 marks]
Quadratics
The curve y = 4x^2 - 24x + c has a minimum value of 11. Find the value of c, and state the coordinates of the minimum point.
Question 22 [4 marks]
Graphs and Coordinates
Show that the cubic y = x^3 - 6x^2 + 11x - 6 factorises as (x - 1)(x - 2)(x - 3). Hence, sketch the cubic and state the x-intercepts.
Show that the cubic factorises as stated.
Hence sketch the cubic and state the x-intercepts.
Question 23 [3 marks]
Quadratics
Show that x^2 + 6x + 11 > 0 for all real values of x.
Question 24 [4 marks]
Linear Algebra
The formula connecting a and b is a = (3b + 7)/(b - 2). Show that b = (7 + 2a)/(a - 3)
Question 25 [4 marks]
Graphs and Coordinates
Find the equation of the straight line that is perpendicular to y = (1/2)x + 4 and passes through the point (3, -1). Give your answer in the form y = mx + c.
Question 26 [5 marks]
Ratio and Proportion
A metal alloy is made by mixing 300 g of metal A, which has a density of 8.4 g/cm^3, with 500 g of metal B, which has a density of 7.2 g/cm^3. Assuming there is no change in total volume when the metals are mixed, calculate the density of the alloy. Give your answer to 3 significant figures.
Question 27 [6 marks]
Statistics and Probability
In a school of 48 students, A is the event 'studies Art' and M is the event 'studies Music'. On the Venn diagram, n(A and M) = x, the number studying only Art is 2x, the number studying only Music is 3x, and the number studying neither is 12.
Show that x = 6.
Find P(A), the probability that a student chosen at random studies Art.
Given that a student studies Art, find the probability that they also study Music.
Model solutions
| Question 1[2 marks] | |
|---|---|
| Answer or working | Marks |
| 18 and 22 both correct | B1oe |
| start at 2 and add 4 each time | B1oe |
| Final answer: 18, 22 | Start at 2 and add 4 each time (oe). | |
| Question 2[3 marks] | |
|---|---|
| Answer or working | Marks |
| 0.7 oe (accept 7/10, 70%) | B1 |
| 0.7 x 500 oe, ft their (a) | M1 |
| 350 | A1cao |
| Final answer: 0.7 | 350 | |
| Question 3[4 marks] | |
|---|---|
| Answer or working | Marks |
| finds cost per metre: 4.50/3 (=1.50), or a correct scale factor method | M1 |
| £12.00 | A1cao |
| L = 10.50/1.50 (ft cost per metre from part a) | M1 |
| 7 metres | A1cao |
| Final answer: £12 (GBP 12.00) | 7 metres | |
| Question 4[1 mark] | |
|---|---|
| Answer or working | Marks |
| x = 12 | B1cao |
| Final answer: 12 | |
| Question 5[1 mark] | |
|---|---|
| Answer or working | Marks |
| correct reference to tan theta = sin theta / cos theta and cos90 = 0, so the calculation would involve dividing by zero (oe: adjacent side has length 0) | B1 |
| Final answer: tan90 is undefined because tan theta = sin theta / cos theta, and cos90 = 0, so the calculation would require dividing by zero. | |
| Question 6[1 mark] | |
|---|---|
| Answer or working | Marks |
| 29 kg | B1cao |
| Question 7[1 mark] | |
|---|---|
| Answer or working | Marks |
| A | B1cao |
| Final answer: A) x >= -5 | |
| Question 8[2 marks] | |
|---|---|
| Answer or working | Marks |
| ((-3 + 5)/2, (5 + (-1))/2) | M1oe |
| (1, 2) | A1cao |
| Question 9[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct substitution, e.g. QR^2 = 6^2 + 9^2 - 2*6*9*cos(40) | M1oe |
| QR = 5.85 cm (awrt 5.85) | A1cao |
| Final answer: QR = 5.85 cm (3 s.f.) | |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| correct reason, e.g. a single ball cannot be both red and blue at the same time / R intersect Bl = empty set | B1oe |
| the two circles do not overlap / have no intersection | B1oe |
| Final answer: A ball has only one colour, so it cannot be both red and blue. | The circles representing the two events would not overlap. | |
| Question 11[2 marks] | |
|---|---|
| Answer or working | Marks |
| set y=(x+6)/4, swap x and y and solve for y or equivalent | M1 |
| f^{-1}(x) = 4x - 6 | A1cao |
| Question 12[2 marks] | |
|---|---|
| Answer or working | Marks |
| Graph A | B1 |
| the points in Graph A lie closer to a straight line / are less scattered than in Graph B | B1 |
| Final answer: Graph A | The points in Graph A lie closer to a straight line, showing a stronger correlation than the scattered points in Graph B. | |
| Question 13[3 marks] | |
|---|---|
| Answer or working | Marks |
| correct substitution with a = 1, b = 6, c = 2 | M1 |
| x = -0.354 (awrt -0.354) | A1 |
| x = -5.65 (awrt -5.65) | A1 |
| Final answer: x = -0.354 or x = -5.65 | |
| Question 14[3 marks] | |
|---|---|
| Answer or working | Marks |
| subtracts the equations to eliminate y | M1 |
| x = 4 | A1cao |
| y = 3 | A1cao |
| Final answer: x = 4, y = 3 | |
| Question 15[3 marks] | |
|---|---|
| Answer or working | Marks |
| calculate remaining after morning, 1 - 3/5 = 2/5 and find 1/4 of this, 1/4 × 2/5 | M1 |
| add morning and afternoon amounts, e.g. 3/5 + 1/10 shown | M1 |
| 7/10 | A1cao |
| Question 16[3 marks] | |
|---|---|
| Answer or working | Marks |
| 3x - 7 > 14 oe | B1cao |
| 3x > 21 oe, ft from their inequality in part (a) | M1 |
| x > 7 oe | A1cao |
| Final answer: 3x - 7 > 14 | x > 7 | |
| Question 17[3 marks] | |
|---|---|
| Answer or working | Marks |
| 6 | B1cao |
| 64.7 (or 64.67, or 64 2/3) awrt 64.7 | B1 |
| (6, 64.7) ft from parts (a) and (b) | B1 |
| Final answer: 6 hours | 64.7% (1 d.p.) | (6, 64.7) | |
| Question 18[3 marks] | |
|---|---|
| Answer or working | Marks |
| Compute cost as singles: 9 * £1.20 = £10.80 or as two 5-packs = £10.00 | M1 |
| Compute cost with 3 for 2: for 9 bars pay for 6 -> 6 * £1.20 = £7.20 | M1 |
| 3 for 2 is cheapest, £7.20 | A1cao |
| Final answer: 3 for 2 is cheapest: cost = £7.20 (pay for 6 bars). Singles cost £10.80, two 5-packs cost £10.00. | |
| Question 19[4 marks] | |
|---|---|
| Answer or working | Marks |
| 16 m | B1cao |
| distance at 8 s plus 12 s at 1.5 m/s -> 16 + 1.5*12 | M1 |
| 34 m | A1cao |
| speed 0 m/s and horizontal line (distance constant) | B1oe |
| Final answer: 16 m | 34 m | Speed 0 m/s; the graph is a horizontal line at distance 34 m between t = 20 and 28 s. | |
| Question 20[3 marks] | |
|---|---|
| Answer or working | Marks |
| form 2x/(5x + 3) = 1/3 or equivalent | M1 |
| cross-multiply and rearrange correctly | M1 |
| x = 3 | A1cao |
| Final answer: 3 | |
| Question 21[6 marks] | |
|---|---|
| Answer or working | Marks |
| 4(x^2 - 6x) + c seen, factor of 4 taken out correctly | M1 |
| (x - 3)^2 seen within the bracket | M1 |
| 4(x - 3)^2 - 36 + c correctly simplified expression for y | A1 |
| dep: set -36 + c = 11, using their simplified constant term | M1 |
| c = 47 | A1cao |
| ft minimum point = (3, 11) | B1 |
| Final answer: c = 47; minimum point (3, 11) | |
| Question 22[4 marks] | |
|---|---|
| Answer or working | Marks |
| either show synthetic division by x=1 then x=2 or factor by grouping leading to factors (x-1),(x-2),(x-3) | M1 |
| (x - 1)(x - 2)(x - 3) | A1cao |
| sketch shows cubic crossing x-axis at three points and general shape correct | M1 |
| x-intercepts (1, 0), (2, 0), (3, 0) | A1cao |
| Final answer: (x - 1)(x - 2)(x - 3) | (1, 0), (2, 0), (3, 0) | |
| Question 23[3 marks] | |
|---|---|
| Answer or working | Marks |
| attempts to complete the square on x^2 + 6x + 11 | M1 |
| (x+3)^2 + 2 | A1cao |
| cso: correct conclusion, e.g. (x+3)^2 >= 0 for all real x, so (x+3)^2 + 2 >= 2 > 0 for all real x | B1 |
| Final answer: x^2 + 6x + 11 = (x+3)^2 + 2, and since (x+3)^2 >= 0 for all real x, the expression is always >= 2, so it is always greater than 0. | |
| Question 24[4 marks] | |
|---|---|
| Answer or working | Marks |
| multiplies both sides by (b - 2), e.g. a(b - 2) = 3b + 7 | M1 |
| expands and collects all terms in b on one side, e.g. ab - 3b = 7 + 2a | M1 |
| factorises out b, e.g. b(a - 3) = 7 + 2a, dependent on the previous method mark | dM1 |
| correct rearrangement with all steps shown leading to b = (7 + 2a)/(a - 3) | A1cso |
| Final answer: b = (7 + 2a)/(a - 3) (printed answer, shown) | |
| Question 25[4 marks] | |
|---|---|
| Answer or working | Marks |
| uses m1 x m2 = -1 to find the perpendicular gradient | M1 |
| gradient = -2 | A1cao |
| substitutes (3, -1) and m = -2 into y = mx + c to find c | M1dep |
| y = -2x + 5 oe | A1cao |
| Final answer: y = -2x + 5 | |
| Question 26[5 marks] | |
|---|---|
| Answer or working | Marks |
| volume of A = 300 / 8.4 oe, awrt 35.7 | M1 |
| volume of B = 500 / 7.2 oe, awrt 69.4 | M1 |
| total volume = their vol A + their vol B (ft), awrt 105 | M1 |
| density of alloy = 800 / their total volume | M1ft |
| 7.61 (g/cm^3) | A1awrt |
| Final answer: 7.61 g/cm^3 (3 s.f.) | |
| Question 27[6 marks] | |
|---|---|
| Answer or working | Marks |
| 2x + 3x + x + 12 = 48 formed (oe 6x + 12 = 48) | M1 |
| x = 6 | A1cso |
| n(A) = 2x + x = 18 (using x = 6) | M1 |
| 3/8 oe | A1cao |
| 6/18 seen | M1 |
| 1/3 oe | A1cao |
| Final answer: x = 6 | 3/8 | 1/3 | |