Higher Tier - Year 11

Year 11 Paper 6: Full Year 11 Review

Covers fractions, decimals and percentages, ratio and proportion, linear algebra, quadratics, graphs and coordinates, sequences, Pythagoras' theorem and trigonometry, and statistics and probability.

27 questions - 80 marks - calculator allowed

Year 11 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 11, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [2 marks]

Sequences

Here are the first four terms of a sequence. 2, 6, 10, 14

Write down the next two terms of the sequence.

Describe, in words, the term-to-term rule for the sequence.

Question 2 [3 marks]

Statistics and Probability

Fatima has a biased coin. She flips it 40 times and records 28 heads.

Calculate the relative frequency of heads.

Fatima is going to flip the coin 500 times. Estimate the number of times it will land on heads.

Question 3 [4 marks]

Ratio and Proportion

The cost, C pounds, of a length of ribbon is directly proportional to its length, L metres. 3 metres of ribbon costs £4.50.

Work out the cost of 8 metres of the same ribbon.

Sarah has £10.50 to spend on this ribbon. Work out the maximum length of ribbon she can buy.

Question 4 [1 marks]

Linear Algebra

Solve x/4 = 3.

Question 5 [1 marks]

Pythagoras and Trigonometry

Explain why tan 90 degrees is undefined.

Question 6 [1 marks]

Statistics and Probability

A vet in Derby recorded the weight, in kg, of 6 dogs brought in for a check-up. Stem | Leaf 1 | 2 8 2 | 0 4 4 9 Key: 2 | 4 means 24 kg Write down the weight represented by the leaf 9 in the stem 2 row.

Question 7 [1 marks]

Linear Algebra

Which of the following is the solution to 2x + 1 >= x - 4?

Question 8 [2 marks]

Graphs and Coordinates

Find the coordinates of the midpoint of the line segment joining the points A(-3, 5) and B(5, -1).

Question 9 [2 marks]

Pythagoras and Trigonometry

In triangle PQR, PQ = 6 cm, PR = 9 cm and angle QPR = 40 degrees. Calculate the length of QR. Give your answer correct to 3 significant figures.

Question 10 [2 marks]

Statistics and Probability

A ball is drawn at random from a bag containing only red, blue and green balls. Event R is that the ball is red. Event Bl is that the ball is blue.

Explain why events R and Bl are mutually exclusive.

On a Venn diagram, state how you would show that two events are mutually exclusive.

Question 11 [2 marks]

Graphs and Coordinates

Find the inverse function f^{-1}(x) for f(x) = (x + 6)/4.

Question 12 [2 marks]

Statistics and Probability

Graph A shows the relationship between arm span and height for a class of students; the points lie close to a straight line. Graph B shows the relationship between shoe size and exam score for the same class; the points are scattered with no clear pattern.

State which graph shows the stronger correlation.

Give a reason for your answer.

Question 13 [3 marks]

Quadratics

Solve x^2 + 6x + 2 = 0 using the quadratic formula. Give your answers correct to 3 significant figures.

Question 14 [3 marks]

Linear Algebra

Solve the simultaneous equations: 1.5x + y = 9 0.5x + y = 5

Question 15 [3 marks]

Fractions, Decimals and Percentages

Sam paints 3/5 of a fence in the morning. In the afternoon he paints 1/4 of the remaining part. What fraction of the whole fence has Sam painted by the end of the day?

Question 16 [3 marks]

Linear Algebra

Tom thinks of a number, x. He multiplies it by 3, then subtracts 7. The result is greater than 14.

Write an inequality, in terms of x, to show this information.

Solve your inequality to find the possible values of x.

Question 17 [3 marks]

Statistics and Probability

Six students recorded the number of hours they revised and their test score (%). Hours revised (x): 2, 4, 5, 7, 8, 10. Test score % (y): 45, 55, 60, 68, 75, 85.

Calculate the mean number of hours revised.

Calculate the mean test score.

Write down the coordinates of the point that must lie on the line of best fit.

Question 18 [3 marks]

Ratio and Proportion

A chocolate costs £1.20 each. You can buy a pack of 5 for £5.00 or take a "3 for 2" offer in the shop. Which way is cheapest if you need 9 bars? Show working.

Question 19 [4 marks]

Graphs and Coordinates

A distance-time graph for a runner is made from three connected straight segments. From t = 0 to t = 8 seconds the distance is given by d = 2t metres. From t = 8 to t = 20 seconds the runner slows with speed 1.5 m/s. From t = 20 to t = 28 seconds the runner rests and distance stays constant. Use these expressions to answer the questions.

Find the distance from the start at t = 8 seconds.

Work out the distance at t = 20 seconds.

State the runner's speed between 20 and 28 seconds and explain what the graph looks like on that interval.

Question 20 [3 marks]

Statistics and Probability

A jar contains red, blue and yellow sweets. The probability of drawing red is (2x)/(5x + 3) and this equals 1/3. Solve for x.

Question 21 [6 marks]

Quadratics

The curve y = 4x^2 - 24x + c has a minimum value of 11. Find the value of c, and state the coordinates of the minimum point.

Question 22 [4 marks]

Graphs and Coordinates

Show that the cubic y = x^3 - 6x^2 + 11x - 6 factorises as (x - 1)(x - 2)(x - 3). Hence, sketch the cubic and state the x-intercepts.

Show that the cubic factorises as stated.

Hence sketch the cubic and state the x-intercepts.

Question 23 [3 marks]

Quadratics

Show that x^2 + 6x + 11 > 0 for all real values of x.

Question 24 [4 marks]

Linear Algebra

The formula connecting a and b is a = (3b + 7)/(b - 2). Show that b = (7 + 2a)/(a - 3)

Question 25 [4 marks]

Graphs and Coordinates

Find the equation of the straight line that is perpendicular to y = (1/2)x + 4 and passes through the point (3, -1). Give your answer in the form y = mx + c.

Question 26 [5 marks]

Ratio and Proportion

A metal alloy is made by mixing 300 g of metal A, which has a density of 8.4 g/cm^3, with 500 g of metal B, which has a density of 7.2 g/cm^3. Assuming there is no change in total volume when the metals are mixed, calculate the density of the alloy. Give your answer to 3 significant figures.

Question 27 [6 marks]

Statistics and Probability

In a school of 48 students, A is the event 'studies Art' and M is the event 'studies Music'. On the Venn diagram, n(A and M) = x, the number studying only Art is 2x, the number studying only Music is 3x, and the number studying neither is 12.

Show that x = 6.

Find P(A), the probability that a student chosen at random studies Art.

Given that a student studies Art, find the probability that they also study Music.

Model solutions

Mark scheme for Question 1 [2 marks]
Question 1[2 marks]
Answer or workingMarks
18 and 22 both correctB1oe
start at 2 and add 4 each timeB1oe
Final answer: 18, 22 | Start at 2 and add 4 each time (oe).
Mark scheme for Question 2 [3 marks]
Question 2[3 marks]
Answer or workingMarks
0.7 oe (accept 7/10, 70%)B1
0.7 x 500 oe, ft their (a)M1
350A1cao
Final answer: 0.7 | 350
Mark scheme for Question 3 [4 marks]
Question 3[4 marks]
Answer or workingMarks
finds cost per metre: 4.50/3 (=1.50), or a correct scale factor methodM1
£12.00A1cao
L = 10.50/1.50 (ft cost per metre from part a)M1
7 metresA1cao
Final answer: £12 (GBP 12.00) | 7 metres
Mark scheme for Question 4 [1 mark]
Question 4[1 mark]
Answer or workingMarks
x = 12B1cao
Final answer: 12
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
correct reference to tan theta = sin theta / cos theta and cos90 = 0, so the calculation would involve dividing by zero (oe: adjacent side has length 0)B1
Final answer: tan90 is undefined because tan theta = sin theta / cos theta, and cos90 = 0, so the calculation would require dividing by zero.
Mark scheme for Question 6 [1 mark]
Question 6[1 mark]
Answer or workingMarks
29 kgB1cao
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
AB1cao
Final answer: A) x >= -5
Mark scheme for Question 8 [2 marks]
Question 8[2 marks]
Answer or workingMarks
((-3 + 5)/2, (5 + (-1))/2)M1oe
(1, 2)A1cao
Mark scheme for Question 9 [2 marks]
Question 9[2 marks]
Answer or workingMarks
correct substitution, e.g. QR^2 = 6^2 + 9^2 - 2*6*9*cos(40)M1oe
QR = 5.85 cm (awrt 5.85)A1cao
Final answer: QR = 5.85 cm (3 s.f.)
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
correct reason, e.g. a single ball cannot be both red and blue at the same time / R intersect Bl = empty setB1oe
the two circles do not overlap / have no intersectionB1oe
Final answer: A ball has only one colour, so it cannot be both red and blue. | The circles representing the two events would not overlap.
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
set y=(x+6)/4, swap x and y and solve for y or equivalentM1
f^{-1}(x) = 4x - 6A1cao
Mark scheme for Question 12 [2 marks]
Question 12[2 marks]
Answer or workingMarks
Graph AB1
the points in Graph A lie closer to a straight line / are less scattered than in Graph BB1
Final answer: Graph A | The points in Graph A lie closer to a straight line, showing a stronger correlation than the scattered points in Graph B.
Mark scheme for Question 13 [3 marks]
Question 13[3 marks]
Answer or workingMarks
correct substitution with a = 1, b = 6, c = 2M1
x = -0.354 (awrt -0.354)A1
x = -5.65 (awrt -5.65)A1
Final answer: x = -0.354 or x = -5.65
Mark scheme for Question 14 [3 marks]
Question 14[3 marks]
Answer or workingMarks
subtracts the equations to eliminate yM1
x = 4A1cao
y = 3A1cao
Final answer: x = 4, y = 3
Mark scheme for Question 15 [3 marks]
Question 15[3 marks]
Answer or workingMarks
calculate remaining after morning, 1 - 3/5 = 2/5 and find 1/4 of this, 1/4 × 2/5M1
add morning and afternoon amounts, e.g. 3/5 + 1/10 shownM1
7/10A1cao
Mark scheme for Question 16 [3 marks]
Question 16[3 marks]
Answer or workingMarks
3x - 7 > 14 oeB1cao
3x > 21 oe, ft from their inequality in part (a)M1
x > 7 oeA1cao
Final answer: 3x - 7 > 14 | x > 7
Mark scheme for Question 17 [3 marks]
Question 17[3 marks]
Answer or workingMarks
6B1cao
64.7 (or 64.67, or 64 2/3) awrt 64.7B1
(6, 64.7) ft from parts (a) and (b)B1
Final answer: 6 hours | 64.7% (1 d.p.) | (6, 64.7)
Mark scheme for Question 18 [3 marks]
Question 18[3 marks]
Answer or workingMarks
Compute cost as singles: 9 * £1.20 = £10.80 or as two 5-packs = £10.00M1
Compute cost with 3 for 2: for 9 bars pay for 6 -> 6 * £1.20 = £7.20M1
3 for 2 is cheapest, £7.20A1cao
Final answer: 3 for 2 is cheapest: cost = £7.20 (pay for 6 bars). Singles cost £10.80, two 5-packs cost £10.00.
Mark scheme for Question 19 [4 marks]
Question 19[4 marks]
Answer or workingMarks
16 mB1cao
distance at 8 s plus 12 s at 1.5 m/s -> 16 + 1.5*12M1
34 mA1cao
speed 0 m/s and horizontal line (distance constant)B1oe
Final answer: 16 m | 34 m | Speed 0 m/s; the graph is a horizontal line at distance 34 m between t = 20 and 28 s.
Mark scheme for Question 20 [3 marks]
Question 20[3 marks]
Answer or workingMarks
form 2x/(5x + 3) = 1/3 or equivalentM1
cross-multiply and rearrange correctlyM1
x = 3A1cao
Final answer: 3
Mark scheme for Question 21 [6 marks]
Question 21[6 marks]
Answer or workingMarks
4(x^2 - 6x) + c seen, factor of 4 taken out correctlyM1
(x - 3)^2 seen within the bracketM1
4(x - 3)^2 - 36 + c correctly simplified expression for yA1
dep: set -36 + c = 11, using their simplified constant termM1
c = 47A1cao
ft minimum point = (3, 11)B1
Final answer: c = 47; minimum point (3, 11)
Mark scheme for Question 22 [4 marks]
Question 22[4 marks]
Answer or workingMarks
either show synthetic division by x=1 then x=2 or factor by grouping leading to factors (x-1),(x-2),(x-3)M1
(x - 1)(x - 2)(x - 3)A1cao
sketch shows cubic crossing x-axis at three points and general shape correctM1
x-intercepts (1, 0), (2, 0), (3, 0)A1cao
Final answer: (x - 1)(x - 2)(x - 3) | (1, 0), (2, 0), (3, 0)
Mark scheme for Question 23 [3 marks]
Question 23[3 marks]
Answer or workingMarks
attempts to complete the square on x^2 + 6x + 11M1
(x+3)^2 + 2A1cao
cso: correct conclusion, e.g. (x+3)^2 >= 0 for all real x, so (x+3)^2 + 2 >= 2 > 0 for all real xB1
Final answer: x^2 + 6x + 11 = (x+3)^2 + 2, and since (x+3)^2 >= 0 for all real x, the expression is always >= 2, so it is always greater than 0.
Mark scheme for Question 24 [4 marks]
Question 24[4 marks]
Answer or workingMarks
multiplies both sides by (b - 2), e.g. a(b - 2) = 3b + 7M1
expands and collects all terms in b on one side, e.g. ab - 3b = 7 + 2aM1
factorises out b, e.g. b(a - 3) = 7 + 2a, dependent on the previous method markdM1
correct rearrangement with all steps shown leading to b = (7 + 2a)/(a - 3)A1cso
Final answer: b = (7 + 2a)/(a - 3) (printed answer, shown)
Mark scheme for Question 25 [4 marks]
Question 25[4 marks]
Answer or workingMarks
uses m1 x m2 = -1 to find the perpendicular gradientM1
gradient = -2A1cao
substitutes (3, -1) and m = -2 into y = mx + c to find cM1dep
y = -2x + 5 oeA1cao
Final answer: y = -2x + 5
Mark scheme for Question 26 [5 marks]
Question 26[5 marks]
Answer or workingMarks
volume of A = 300 / 8.4 oe, awrt 35.7M1
volume of B = 500 / 7.2 oe, awrt 69.4M1
total volume = their vol A + their vol B (ft), awrt 105M1
density of alloy = 800 / their total volumeM1ft
7.61 (g/cm^3)A1awrt
Final answer: 7.61 g/cm^3 (3 s.f.)
Mark scheme for Question 27 [6 marks]
Question 27[6 marks]
Answer or workingMarks
2x + 3x + x + 12 = 48 formed (oe 6x + 12 = 48)M1
x = 6A1cso
n(A) = 2x + x = 18 (using x = 6)M1
3/8 oeA1cao
6/18 seenM1
1/3 oeA1cao
Final answer: x = 6 | 3/8 | 1/3