Higher Core A
Higher tier fundamentals, including crossover algebra and geometry.
Questions
Question 1 [1 marks]
Indices and Standard Form
Write 9.1 x 10^4 as an ordinary number.
Question 2 [1 marks]
Fractions, Decimals and Percentages
Work out 3/8 + 2/8. Give your answer in its simplest form.
Question 3 [5 marks]
Statistics and Probability
Freya Sinclair organised a charity bake sale where 90 cakes were sold, either Sponge or Chocolate, in the morning or the afternoon. Some of the results are shown in the two-way table below.
Question 4 [2 marks]
Linear Algebra
Solve 2(x + 3) = 16 Show your working.
Question 5 [2 marks]
Graphs and Coordinates
The graphs of x = 3 and y = 2x - 4 are drawn on the grid. Write down the solution of the simultaneous equations x = 3 and y = 2x - 4.
Question 6 [2 marks]
Ratio and Proportion
A cyclist travels at a constant speed of 20 m/s. Work out this speed in km/h.
Question 7 [2 marks]
Area, Volume and Measures
Shape 1 has sides of length 4.5 cm and 6 cm. Shape 2 is mathematically similar to shape 1. The side on shape 2 corresponding to the 4.5 cm side has length 3 cm.
Question 8 [2 marks]
Linear Algebra
Show that the equation 4(2x - 3) = 2(x + 9) simplifies to x = 5
Question 9 [4 marks]
Quadratics
A student attempts to solve 3x^2 + 4x - 2 = 0 using the quadratic formula. Their working is shown below: x = (-4 +/- sqrt(4^2 - 4x3x(-2))) / (2x3) x = (-4 +/- sqrt(16 - 24)) / 6 Identify the error made by the student, and find the correct solutions to the equation, giving your answers correct to 2 decimal places.
Question 10 [5 marks]
Sequences
Here are the first four terms of a sequence. 50, 44, 38, 32
Write down the next term of the sequence.
Find an expression, in terms of n, for the nth term of the sequence.
Explain whether 0 is a term of the sequence.
Question 11 [6 marks]
Pythagoras and Trigonometry
A surveyor stands at point A and measures the angle of elevation to the top of a tower as 31 degrees. She then walks 48 m closer to the tower along the level ground to point B and measures the angle of elevation as 46 degrees. Work out the height of the tower to the nearest metre.
Find the height of the tower to the nearest metre.
Question 12 [6 marks]
Angles and Geometrical Reasoning
Two points A(-5, 0) and B(5, 0) are 10 cm apart on a coordinate grid (1 unit = 1 cm). (a) Describe the locus of points that are equidistant from A and B, and give its equation. (b) A circle has centre A and radius 13 cm. Find the coordinates of the points where this circle meets the locus from part (a). Show your working.
Describe the geometric locus in words and give its equation.
Find the coordinates of the points where the circle centre A radius 13 cm meets the locus x = 0. Show your working.
Question 13 [7 marks]
Graphs and Coordinates
Tom walks 3 km from home to the park in 40 minutes. He then jogs 5 km from the park to the leisure centre in 25 minutes.
Calculate Tom's average speed while walking, in km/h.
Calculate Tom's average speed while jogging, in km/h.
Calculate Tom's average speed for the whole journey from home to the leisure centre, in km/h. Give your answer correct to 1 decimal place.
Question 14 [3 marks]
Angles and Geometrical Reasoning
A search and rescue team searches a triangular area defined by three points X, Y and Z. XY = 12 km, XZ = 9 km, and the angle YXZ (the angle between the bearings from X to Y and from X to Z) is 105 degrees. Diagram: Point X is shown with a North arrow and two rays to Y (12 km) and Z (9 km), with angle YXZ marked 105 degrees.
Question 15 [4 marks]
Graphs and Coordinates
Each equation below is a transformation of y = sin x. Match each equation to the letter of the description that correctly describes its transformation. A) Translation by vector (-90, 0) B) Stretch, scale factor 4, parallel to the y-axis C) Translation by vector (0, -3) D) Stretch, scale factor 2, parallel to the x-axis
y = sin x - 3
y = sin(x + 90)
y = 4 sin x
y = sin(x/2)
Question 16 [8 marks]
Statistics and Probability
A bag contains 3 red counters and n blue counters only, where n > 0. Two counters are taken from the bag at random, one after another, without replacement.
Show that the probability that both counters are red is 6 / ((n+3)(n+2)).
Given that the probability that both counters are red is 1/5, show that n^2 + 5n - 24 = 0.
Hence find the number of blue counters in the bag.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 91000 | B1cao |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| 5/8 | B1cao |
| Question 3[5 marks] | |
|---|---|
| Answer or working | Marks |
| Morning Total = 42 | B1cao |
| Morning Chocolate = 20 | B1cao |
| Afternoon Sponge = 30 | B1cao |
| Afternoon Chocolate = 18 | B1cao |
| Chocolate column Total = 38 | B1cao |
| Final answer: Morning Total = 42, Morning Chocolate = 20, Afternoon Sponge = 30, Afternoon Chocolate = 18, Chocolate Total = 38 | |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| 2x + 6 = 16 oe (expand correctly) | M1 |
| x = 5 | A1cao |
| Question 5[2 marks] | |
|---|---|
| Answer or working | Marks |
| x = 3 | B1 |
| y = 2 (oe as a coordinate pair) | B1 |
| Final answer: x = 3, y = 2 | |
| Question 6[2 marks] | |
|---|---|
| Answer or working | Marks |
| 20 x 3.6 oe, e.g. 20 x 3600 / 1000 | M1 |
| 72 (km/h) | A1cao |
| Final answer: 72 km/h | |
| Question 7[2 marks] | |
|---|---|
| Answer or working | Marks |
| scale factor = 3/4.5 oe (= 2/3) | M1 |
| 4 (cm) | A1cao |
| Final answer: 4 cm | |
| Question 8[2 marks] | |
|---|---|
| Answer or working | Marks |
| expand both sides correctly, 8x - 12 = 2x + 18 | M1oe |
| cso, correct rearrangement shown to give x = 5 with no errors | A1 |
| Final answer: x = 5 (shown) | |
| Question 9[4 marks] | |
|---|---|
| Answer or working | Marks |
| identifies the sign error, e.g. 4 x 3 x (-2) = -24 so 4^2 - 4ac = 16 - (-24) = 16 + 24, not 16 - 24 | B1 |
| correct discriminant of 40 used in the formula with a = 3, b = 4, c = -2 | M1 |
| x = 0.39 (awrt 0.39) | A1 |
| x = -1.72 (awrt -1.72) | A1 |
| Final answer: x = 0.39 or x = -1.72 | |
| Question 10[5 marks] | |
|---|---|
| Answer or working | Marks |
| 26 | B1cao |
| common difference of -6 used correctly, e.g. -6n + c | M1oe |
| 56 - 6n oe | A1cao |
| 56 - 6n = 0 oe, or 56 / 6 evaluated | M1 |
| correct conclusion: no, since n = 9.33... (28/3) is not a positive integer | A1oe |
| Final answer: 26 | 56 - 6n | No, 0 is not a term (n would be 9.33..., not a whole number) | |
| Question 11[6 marks] | |
|---|---|
| Answer or working | Marks |
| use tan 31 = h / x and tan 46 = h / (x - 48) to form two equations | M1 |
| eliminate x: h = x * tan31 and h = (x - 48) * tan46 then set x * tan31 = (x - 48) * tan46 | M1 |
| rearrange to x (tan31 - tan46) = -48 * tan46 and solve for x | M1 |
| find h using h = x * tan31 | M1 |
| height = 69 m awrt (1 m) | A1 |
| method and final value consistent with working | A1 |
| Final answer: 69 m | |
| Question 12[6 marks] | |
|---|---|
| Answer or working | Marks |
| identify locus as the perpendicular bisector of AB (the set of points equidistant from A and B) | M1 |
| state equation x = 0 (since AB is horizontal with midpoint (0,0)) | A1cao |
| set up equation of circle centre A(-5,0) radius 13: (x+5)^2 + y^2 = 169 | M1 |
| substitute x = 0: 25 + y^2 = 169, so y^2 = 144 | M1 |
| y = 12 or y = -12 | A1 |
| final coordinates (0, 12) and (0, -12) | A1cao |
| Final answer: The locus is the perpendicular bisector of AB: the straight line through the midpoint (0,0) at right angles to AB. Since AB lies along the x-axis, the perpendicular bisector is the y-axis, equation x = 0. | (0, 12) and (0, -12). | |
| Question 13[7 marks] | |
|---|---|
| Answer or working | Marks |
| 3 divided by (40/60) | M1oe |
| 4.5 (km/h) | A1cao |
| 5 divided by (25/60) | M1oe |
| 12 (km/h) | A1cao |
| total distance = 8 (km) | M1 |
| total time = 65 minutes oe (13/12 hours, or 1.0833 hours) | M1 |
| awrt 7.4 (km/h) | A1 |
| Final answer: 4.5 km/h | 12 km/h | 7.4 km/h | |
| Question 14[3 marks] | |
|---|---|
| Answer or working | Marks |
| area = 0.5 x 12 x 9 x sin(105) | M1oe |
| correct process | M1 |
| awrt 52.2 (km^2) | A1 |
| Final answer: 52.2 km^2 | |
| Question 15[4 marks] | |
|---|---|
| Answer or working | Marks |
| C | B1 |
| A | B1 |
| B | B1 |
| D | B1 |
| Final answer: C | A | B | D | |
| Question 16[8 marks] | |
|---|---|
| Answer or working | Marks |
| P(first red) = 3/(n+3) | M1 |
| P(second red | first red) = 2/(n+2) | M1 |
| cso: 3/(n+3) x 2/(n+2) = 6/((n+3)(n+2)) | A1 |
| 5 x 6 = (n+3)(n+2), i.e. (n+3)(n+2) = 30 | M1 |
| cso: expands to n^2 + 5n + 6 = 30, giving n^2 + 5n - 24 = 0 | A1 |
| factorises: (n+8)(n-3) = 0 | M1 |
| n = 3 selected, rejecting n = -8 since n > 0 | M1 |
| n = 3 | A1cao |
| Final answer: 6 / ((n+3)(n+2)) shown | n^2 + 5n - 24 = 0 shown | 3 blue counters | |