Higher Tier - Grades 4-6

Higher Core B

Higher mini test with proportion, functions, angles and data.

22 questions - 60 marks - calculator allowed

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Questions

Question 1 [1 marks]

Statistics and Probability

Here are the shoe sizes of 10 dancers in a class: 4, 5, 4, 6, 7, 4, 8, 5, 4, 6 Write down the mode of the shoe sizes.

Question 2 [1 marks]

Ratio and Proportion

y is inversely proportional to x.

Question 3 [2 marks]

Quadratics

Factorise 2x^2 + 5x + 3

Question 4 [3 marks]

Linear Algebra

Make x the subject of each formula.

y = 4x

y = x/7

w = kx

Question 5 [1 marks]

Graphs and Coordinates

A vehicle travels at a constant velocity of 5 m/s for 6 seconds. Work out the distance travelled in that time.

Question 6 [1 marks]

Indices and Standard Form

Simplify p^5 * p^3.

Question 7 [1 marks]

Linear Algebra

Evaluate the expression 3x^2 - 2x + 5 when x = -1.

Question 8 [1 marks]

Statistics and Probability

A frequency table shows how long, in minutes, each customer waited in a queue at a post office in Cardiff. Waiting time (minutes): 0-5, 5-10, 10-15, 15-20 Frequency: 6, 9, 7, 3 Write down the width of the class 10-15.

Question 9 [1 marks]

Indices and Standard Form

Work out the value of 16^(1/2).

Question 10 [2 marks]

Angles and Geometrical Reasoning

The diagram shows a flat solid made from three 1 cm cubes on a 2 by 2 grid (one grid position is empty).

Which of these is the correct plan of the solid?

Even though the plan is an L-shape, the front elevation of this solid is a plain 2 cm by 1 cm rectangle, with no gap visible. Give a reason why.

Question 11 [2 marks]

Graphs and Coordinates

A point (4, -2) lies on y = f(x). Find the image of this point on the graph y = f(x - 3) - 5.

Question 12 [2 marks]

Linear Algebra

Solve 5x - 4 > 21 Show your working.

Question 13 [2 marks]

Ratio and Proportion

A model yacht club has 18 wooden hulls and 30 plastic hulls. The wooden:plastic ratio is 3 : n. Work out n.

Question 14 [4 marks]

Number and Calculation

Priya is making identical party bags for her birthday. She has 60 chocolate coins and 84 jelly sweets. She wants to put the sweets and coins into the greatest possible number of bags so that every bag has the same number of chocolate coins and the same number of jelly sweets, with none left over.

Find the greatest number of party bags Priya can make.

Work out how many chocolate coins and how many jelly sweets will be in each bag.

Question 15 [4 marks]

Indices and Standard Form

A single red blood cell has a volume of 9.0 x 10^-11 cm^3. An adult has approximately 2.5 x 10^13 red blood cells in their body. Work out the total volume of all the red blood cells in the adult's body. Give your answer, in cm^3, in standard form, correct to 2 significant figures.

Question 16 [5 marks]

Area, Volume and Measures

A sector of a circle has area 154 cm^2 and angle 100 degrees. Calculate the radius of the circle, giving your answer correct to 3 significant figures.

Question 17 [6 marks]

Sequences

A theatre has rows of seats. Row 1 has 18 seats. Each row after Row 1 has 4 more seats than the row before it.

Find an expression, in terms of n, for the number of seats in Row n.

Work out the number of seats in Row 15.

Show that Row 19 has 90 seats.

Question 18 [6 marks]

Area, Volume and Measures

A model car is built using a scale of 1:24 compared with the real car (every linear dimension of the real car is 24 times the corresponding dimension of the model). The model car has a volume of 90 cm^3 and a surface area of 220 cm^2.

Work out the volume of the real car. Give your answer in cm^3, in standard form correct to 3 significant figures.

Work out the surface area of the real car in m^2, correct to 3 significant figures.

Question 19 [7 marks]

Ratio and Proportion

V is directly proportional to L^3. When L = 2, V = 40.

Find a formula for V in terms of L.

Work out V when L = 5.

Work out the value of L when V = 200, giving your answer to 3 significant figures.

Question 20 [1 marks]

Quadratics

The equations y = x^2 - 1 and y = 2x + 2 are solved simultaneously. Which one of these points is a solution to both equations?

Question 21 [6 marks]

Angles and Geometrical Reasoning

PAQ is a straight tangent line touching a circle at A. B and C are points on the circle, with chords AB and AC drawn, and BC also drawn to complete triangle ABC. Angle QAB = 47 degrees and angle PAC = 65 degrees (the angles between the tangent and each chord). Diagram: circle with straight tangent line PAQ touching at A, chords AB and AC drawn to points B and C on either side, chord BC also drawn, angle QAB = 47 degrees and angle PAC = 65 degrees marked between tangent and each chord.

State the size of angle ACB, giving a reason for your answer.

State the size of angle ABC, giving a reason for your answer.

Calculate the size of angle BAC.

Question 22 [1 marks]

Quadratics

x^2 - 14x + 51 can be written in the form (x - 7)^2 + k. What is the value of k?

Model solutions

Mark scheme for Question 1 [1 mark]
Question 1[1 mark]
Answer or workingMarks
4B1cao
Mark scheme for Question 2 [1 mark]
Question 2[1 mark]
Answer or workingMarks
y = k/xB1oe
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
identifies a pair of numbers with product 6 and sum 5 (2 and 3), or one correct bracket seenM1
(2x + 3)(x + 1)A1cao
Mark scheme for Question 4 [3 marks]
Question 4[3 marks]
Answer or workingMarks
x = y/4B1oe
x = 7yB1oe
x = w/kB1oe
Final answer: x = y/4 | x = 7y | x = w/k
Mark scheme for Question 5 [1 mark]
Question 5[1 mark]
Answer or workingMarks
30 mB1cao
Mark scheme for Question 6 [1 mark]
Question 6[1 mark]
Answer or workingMarks
p^8B1cao
Mark scheme for Question 7 [1 mark]
Question 7[1 mark]
Answer or workingMarks
3(-1)^2 - 2(-1) + 5 = 3 + 2 + 5 = 10B1cao
Final answer: 10
Mark scheme for Question 8 [1 mark]
Question 8[1 mark]
Answer or workingMarks
5B1cao
Mark scheme for Question 9 [1 mark]
Question 9[1 mark]
Answer or workingMarks
4B1cao
Mark scheme for Question 10 [2 marks]
Question 10[2 marks]
Answer or workingMarks
BB1cao
correct reason, e.g. Column 2 still has a cube in Row 1, so that column still shows height 1 from the front; the missing cube in Row 2 is hidden behind itB1oe
Final answer: B | The empty grid position is hidden behind a cube in the other row of the same column, so the front elevation still shows full height across both columns.
Mark scheme for Question 11 [2 marks]
Question 11[2 marks]
Answer or workingMarks
apply right shift by 3 and down 5: (a,b) -> (a + 3, b - 5)M1oe
(7, -7)A1cao
Mark scheme for Question 12 [2 marks]
Question 12[2 marks]
Answer or workingMarks
5x > 25 oe (correct rearrangement)M1
x > 5A1cao
Mark scheme for Question 13 [2 marks]
Question 13[2 marks]
Answer or workingMarks
identify common factor: divide both parts by 6 or scale 18:30 to 3:xM1
5A1cao
Mark scheme for Question 14 [4 marks]
Question 14[4 marks]
Answer or workingMarks
60 = 2^2 x 3 x 5 and 84 = 2^2 x 3 x 7 shown, or an equivalent factor comparisonM1
12A1cao
60 divided by their answer to part (a), or 84 divided by their answer to part (a)M1ft
5 chocolate coins and 7 jelly sweets, both statedA1
Final answer: 12 | 5 chocolate coins and 7 jelly sweets per bag
Mark scheme for Question 15 [4 marks]
Question 15[4 marks]
Answer or workingMarks
multiplies coefficients, 9.0 x 2.5 = 22.5M1
adds powers of 10, -11 + 13 = 2, giving 22.5 x 10^2M1
2.25 x 10^3 (unrounded standard form value)A1
ft, awrt 2.3 x 10^3 (cm^3)B1
Final answer: 2.3 x 10^3 cm^3 (awrt, 2 sig figs)
Mark scheme for Question 16 [5 marks]
Question 16[5 marks]
Answer or workingMarks
sets up 154 = (100/360) x pi x r^2M1oe
rearranges to r^2 = 154 x 360 / (pi x 100)M1oe
r^2 = 176 (awrt) seenA1
square roots their r^2 valueM1
13.3 cm awrtA1cao
Final answer: 13.3 cm (3 s.f.)
Mark scheme for Question 17 [6 marks]
Question 17[6 marks]
Answer or workingMarks
common difference of 4 identified, e.g. 4n + ...M1oe
4n + 14A1cao
substitutes n = 15 into their formula, ft from part (a)M1
74A1cao
substitutes n = 19 into their formula, ft from part (a)M1
cso, 4(19) + 14 = 90 shown, answer printedA1
Final answer: 4n + 14 | 74 | 4(19) + 14 = 90
Mark scheme for Question 18 [6 marks]
Question 18[6 marks]
Answer or workingMarks
volume scale factor = 24^3 (=13824)M1
90 x 13824M1
1.24 x 10^6 cm^3 awrt (1244160 cm^3)A1
area scale factor = 24^2 (=576)M1
220 x 576 (=126720 cm^2), converted by dividing by 10000 to give m^2M1
12.7 m^2 awrt (12.672 m^2)A1
Final answer: 1.24 x 10^6 cm^3 (1244160 cm^3) | 12.7 m^2 (12.672 m^2)
Mark scheme for Question 19 [7 marks]
Question 19[7 marks]
Answer or workingMarks
finds k = 40/2^3 = 40/8 = 5M1oe
V = 5L^3A1oe
substitutes L = 5 into their formulaM1
V = 625A1cao
sets up 200 = 5L^3 leading to L^3 = 40M1oe
takes the cube root of their 40, dependent on the first M1dM1
3.42 awrt 3sfA1
Final answer: V = 5L^3 | V = 625 | L = 3.42 (3sf)
Mark scheme for Question 20 [1 mark]
Question 20[1 mark]
Answer or workingMarks
B) (3, 8) selectedB1
Final answer: B) (3, 8)
Mark scheme for Question 21 [6 marks]
Question 21[6 marks]
Answer or workingMarks
47 degreesB1
reason: alternate segment theoremB1
65 degreesB1
reason: alternate segment theoremB1
180 - 47 - 65M1oe
68 degreesA1cao
Final answer: 47 degrees | 65 degrees | 68 degrees
Mark scheme for Question 22 [1 mark]
Question 22[1 mark]
Answer or workingMarks
AB1