Higher Secure B
A second secure Higher paper for mixed revision and timed practice.
Questions
Question 1 [1 marks]
Indices and Standard Form
Work out the value of 3^4.
Question 2 [2 marks]
Angles and Geometrical Reasoning
Draw a straight line segment AB of length 7 cm. Using a ruler and compasses only, construct the perpendicular bisector of AB. You must show all your construction lines.
Question 3 [2 marks]
Ratio and Proportion
P is directly proportional to Q. When Q = 5, P = 30. Find the value of P when Q = 9.
Question 4 [4 marks]
Area, Volume and Measures
The exchange rate is £1 sterling (GBP) = 1.16 euros (EUR).
Nadia changes £250 into euros. Work out how many euros she receives.
On the way home Nadia changes 87 euros back into £, using the same exchange rate. Work out how many £ she receives.
Question 5 [1 marks]
Graphs and Coordinates
The graph of y = g(x) is obtained from y = f(x) by first reflecting in the y-axis and then translating up by 6. Write g(x) in terms of f.
Question 6 [1 marks]
Statistics and Probability
A bag contains 3 blue and 9 red counters. One counter is chosen at random. Write down the probability it is red.
Question 7 [2 marks]
Graphs and Coordinates
Let f(x) = x^2 and g(x) = x + 1. Find (g o f)(3).
Question 8 [2 marks]
Quadratics
Factorise x^2 - 13x + 40
Question 9 [2 marks]
Number and Calculation
A plumber charges a call-out fee of £45 plus £30 per hour worked. Show that the total cost of a job lasting 2.5 hours is £120.
Question 10 [2 marks]
Statistics and Probability
A scatter graph shows the number of gym sessions attended per month (x) and the kilograms of weight lost that month (y), for data collected between 1 and 12 sessions per month. Aisha uses the line of best fit to estimate the weight lost by someone who attends 40 sessions in a month. Explain why this estimate would not be reliable.
Question 11 [2 marks]
Linear Algebra
Solve 2x + 5 = -3
Question 12 [2 marks]
Quadratics
Solve x^2 + 9x = 0
Question 13 [2 marks]
Linear Algebra
Anjali has p pounds. She has more than £15 but no more than £40. Write down an inequality, in terms of p, to show this information.
Question 14 [2 marks]
Area, Volume and Measures
Convert 0.003 km^2 into square metres (m^2).
Question 15 [3 marks]
Sequences
Here are the first four terms of a sequence. 1, 1.5, 2, 2.5
Write down the next term of the sequence.
Find an expression, in terms of n, for the nth term of the sequence.
Question 16 [3 marks]
Pythagoras and Trigonometry
In triangle LMN, angle L = 115 degrees, MN = 18 cm (opposite angle L), and LN = 9 cm (opposite angle M). Calculate the size of angle N. Give your answer correct to 1 decimal place.
Question 17 [3 marks]
Angles and Geometrical Reasoning
Enlarge triangle T with vertices (2, 1), (4, 1) and (2, 3) by a scale factor of -2 centre (1, 1). Find the coordinates of the image vertices.
Question 18 [5 marks]
Statistics and Probability
In a class of 30 students, 14 study French, 16 study Spanish and 5 study both French and Spanish. Every student studies French, Spanish, both, or neither.
Work out the number of students who study only French.
Work out the number of students who study neither French nor Spanish.
A student is picked at random from the class. Find the probability that the student studies both French and Spanish. Give your answer as a fraction in its simplest form.
Question 19 [5 marks]
Ratio and Proportion
A metal rod is stretched so that its length increases in direct proportion to the temperature increase. At 20 degrees C the rod is 1.25 m long. At 80 degrees C the rod is 1.253 m long. Assuming linear proportional change, find an expression for the length L (in metres) as a function of temperature t in degrees C, of the form L = m t + c. Give m and c to 6 decimal places.
Question 20 [6 marks]
Linear Algebra
A rectangle has length (2x + 5) cm and width (x + 3) cm. The perimeter of the rectangle is 46 cm.
Show that 6x + 16 = 46
Solve the equation to find the value of x.
Work out the length and the width of the rectangle.
Question 21 [7 marks]
Fractions, Decimals and Percentages
Deepa and her brother each invest £2000 for 5 years, in different types of account.
Account A pays compound interest at a rate of 2.5% per year. Deepa invests £2000 in Account A. Calculate the total amount in Account A after 5 years. Give your answer to the nearest penny.
Account B pays simple interest at a rate of 3% per year. Deepa's brother invests £2000 in Account B. Calculate the total amount in Account B after 5 years.
State which account gives the greater return after 5 years, and work out by how much.
Question 22 [1 marks]
Graphs and Coordinates
The graph of y = f(x) is transformed to give the graph of y = f(x) + 4. Which of the following correctly describes this transformation?
Question 23 [1 marks]
Quadratics
The equations y = x^2 - 1 and y = 2x + 2 are solved simultaneously. Which one of these points is a solution to both equations?
Question 24 [5 marks]
Ratio and Proportion
A metal alloy is made by mixing 300 g of metal A, which has a density of 8.4 g/cm^3, with 500 g of metal B, which has a density of 7.2 g/cm^3. Assuming there is no change in total volume when the metals are mixed, calculate the density of the alloy. Give your answer to 3 significant figures.
Question 25 [5 marks]
Graphs and Coordinates
Consider the family of cubics y = x^3 + kx^2 where k is a real constant. (a) Show that x = 0 is always a root. (b) For k = -3 find the other two roots and classify the nature of the turning points of the cubic (local max, local min or point of inflection).
For k = -3 find the other two roots. Then, by working out y at x = -1, 0, 1, 2, 3 and 4 and comparing neighbouring values, say whether the graph has a local maximum or a local minimum at x = 0 and at x = 2.
Question 26 [5 marks]
Number and Calculation
A padlock code has 4 digits. Each digit can be any number from 0 to 9.
The digits may be repeated. Work out the number of different codes possible.
The first digit of the code cannot be 0, although the other three digits may still be any digit from 0 to 9 and may repeat. Work out the number of different codes now possible.
Question 27 [4 marks]
Graphs and Coordinates
A curve y = r(x) passes through the point (8, 3).
After the transformation y = r(x) + c, the image of this point is (8, -5). Find the value of c.
The curve y = r(kx) has an image point (2, 3) that corresponds to (8, 3) on y = r(x). Find the value of k.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| 81 | B1cao |
| Question 2[2 marks] | |
|---|---|
| Answer or working | Marks |
| two pairs of intersecting arcs of equal radius (radius greater than half of AB), one pair centred on A and one pair centred on B | C1 |
| correct straight line drawn through both points of intersection, extending beyond AB, within 2 mm and 2 degrees of the true perpendicular bisector | A1 |
| Final answer: A straight line perpendicular to AB, passing through its midpoint, 3.5 cm from both A and B. | |
| Question 3[2 marks] | |
|---|---|
| Answer or working | Marks |
| finds the constant of proportionality k = 30/5 (=6), or uses a valid scale factor method | M1 |
| P = 54 | A1cao |
| Question 4[4 marks] | |
|---|---|
| Answer or working | Marks |
| 250 x 1.16 | M1 |
| 290 (euros) | A1cao |
| 87 / 1.16 | M1 |
| 75 (pounds) | A1cao |
| Final answer: 290 euros; £75 | |
| Question 5[1 mark] | |
|---|---|
| Answer or working | Marks |
| g(x) = f(-x) + 6 | B1cao |
| Question 6[1 mark] | |
|---|---|
| Answer or working | Marks |
| 9/12 or 3/4 | B1cao |
| Final answer: 3/4 | |
| Question 7[2 marks] | |
|---|---|
| Answer or working | Marks |
| compute f(3)=9 then g(9)=9+1 or equivalent | M1 |
| 10 | A1cao |
| Question 8[2 marks] | |
|---|---|
| Answer or working | Marks |
| attempts a factor pair of 40 that sums to -13, e.g. -8 and -5 | M1 |
| (x - 8)(x - 5) | A1cao |
| Question 9[2 marks] | |
|---|---|
| Answer or working | Marks |
| 30 x 2.5 = 75 seen | M1oe |
| 45 + 75 = 120 shown correctly | A1cso |
| Final answer: £120 (shown). Working check: 30 x 2.5 = 75; 45 + 75 = 120. | |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| 40 sessions is outside the range of data collected (1 to 12), so this is extrapolation | B1 |
| the same trend/rate of weight loss may not continue that far beyond the data, e.g. there could be a natural limit to how much weight can be lost, or attending 40 sessions a month may not be realistic | B1oe |
| Final answer: The estimate is unreliable because 40 sessions is far outside the data collected (1 to 12 sessions), so it involves extrapolation and the same trend may not continue. | |
| Question 11[2 marks] | |
|---|---|
| Answer or working | Marks |
| 2x = -8 | M1oe |
| x = -4 | A1cao |
| Question 12[2 marks] | |
|---|---|
| Answer or working | Marks |
| x(x + 9) = 0 | M1oe |
| x = 0 and x = -9 | A1cao |
| Final answer: x = 0 or x = -9 | |
| Question 13[2 marks] | |
|---|---|
| Answer or working | Marks |
| 15 < p oe or p <= 40 oe, one boundary correctly represented | M1 |
| 15 < p <= 40 oe cao, both boundaries correct with correct strict/non-strict signs | A1 |
| Final answer: 15 < p <= 40 | |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| use 1 km^2 = 1 000 000 m^2, multiply 0.003 by 1 000 000 | M1oe |
| 3000 m^2 | A1cao |
| Question 15[3 marks] | |
|---|---|
| Answer or working | Marks |
| 3 | B1cao |
| common difference of 0.5 identified, e.g. 0.5n + ... | M1oe |
| 0.5n + 0.5 oe cao, e.g. (n + 1)/2 | A1 |
| Final answer: 3 | 0.5n + 0.5 (oe) | |
| Question 16[3 marks] | |
|---|---|
| Answer or working | Marks |
| sin(M)/9 = sin(115)/18 | M1oe |
| angle M = awrt 26.9 (degrees), dep on correct sine rule setup | M1 |
| angle N = 180 - 115 - their M = awrt 38.1 (degrees) | A1ft |
| Final answer: angle N = 38.1 degrees (1 d.p.) | |
| Question 17[3 marks] | |
|---|---|
| Answer or working | Marks |
| subtract centre (1,1) then multiply by -2 for each coordinate (method shown) | M1oe |
| image of (2,1) is (-1,1) | A1cao |
| images of other vertices: (4,1) -> (-5,1) and (2,3) -> (-1,-3) | A1cao |
| Final answer: Images: (2,1) -> (-1,1); (4,1) -> (-5,1); (2,3) -> (-1,-3). | |
| Question 18[5 marks] | |
|---|---|
| Answer or working | Marks |
| 9 | B1cao |
| 30 - (9 + 11 + 5) | M1oe |
| 5 | A1cao |
| 5/30 | M1oe |
| 1/6 | A1cao |
| Final answer: 9 | 5 | 1/6 | |
| Question 19[5 marks] | |
|---|---|
| Answer or working | Marks |
| use two points to find gradient m = (1.253 - 1.25) / (80 - 20) | M1 |
| m = 0.000050 cao to 6 dp | A1 |
| substitute one point to find c using L = m t + c | M1 |
| c = 1.249000 cao to 6 dp | A1 |
| final correct expression L = 0.000050 t + 1.249000 | A1cao |
| Final answer: L = 0.000050 t + 1.249000. Working: m = (1.253 - 1.25)/(80 - 20) = 0.003/60 = 0.00005 = 0.000050 to 6 dp. Then c = 1.25 - 0.00005*20 = 1.25 - 0.001 = 1.249000. Check: at t = 80, L = 0.00005*80 + 1.249 = 0.004 + 1.249 = 1.253. | |
| Question 20[6 marks] | |
|---|---|
| Answer or working | Marks |
| 2[(2x + 5) + (x + 3)] = 46 oe (correct perimeter expression set equal to 46) | M1 |
| correctly expands and simplifies to 6x + 16 = 46 | A1dep |
| 6x = 30 | M1oe |
| x = 5 | A1cao |
| substitutes x = 5 into both expressions (ft their x) | M1 |
| length = 15 cm and width = 8 cm (both required | A1cao |
| Final answer: 6x + 16 = 46 (shown) | x = 5 | length = 15 cm, width = 8 cm | |
| Question 21[7 marks] | |
|---|---|
| Answer or working | Marks |
| 1.025^5 (= 1.131408212890625) | M1 |
| 2000 x their 1.131408212890625 | M1 |
| 2262.82 (pounds) | A1cao |
| 2000 x 0.03 x 5 (= 300) | M1 |
| 2300 (pounds) | A1cao |
| Account B ft from (a) and (b) | B1 |
| 37.18 (pounds) ft, correct difference | B1 |
| Final answer: £2262.82 | £2300 | Account B, by £37.18 | |
| Question 22[1 mark] | |
|---|---|
| Answer or working | Marks |
| B | B1 |
| Question 23[1 mark] | |
|---|---|
| Answer or working | Marks |
| B) (3, 8) selected | B1 |
| Final answer: B) (3, 8) | |
| Question 24[5 marks] | |
|---|---|
| Answer or working | Marks |
| volume of A = 300 / 8.4 oe, awrt 35.7 | M1 |
| volume of B = 500 / 7.2 oe, awrt 69.4 | M1 |
| total volume = their vol A + their vol B (ft), awrt 105 | M1 |
| density of alloy = 800 / their total volume | M1ft |
| 7.61 (g/cm^3) | A1awrt |
| Final answer: 7.61 g/cm^3 (3 s.f.) | |
| Question 25[5 marks] | |
|---|---|
| Answer or working | Marks |
| substitute x = 0 to give y = 0 thereby showing x=0 is a root | B1 |
| factor y = x^3 - 3x^2 as x^2(x - 3) or equivalent to find roots | M1 |
| identify roots x = 0 (double), x = 3 or explicitly x = 0,0,3 | M1 |
| work out values e.g. y(-1) = -4, y(0) = 0, y(1) = -2, y(2) = -4, y(3) = 0 and compare neighbouring values around x = 0 and x = 2 | M1 |
| x = 0 is a local maximum (0 is higher than the neighbouring values -4 and -2) and x = 2 is a local minimum (-4 is lower than the neighbouring values -2 and 0) | A1cao |
| Final answer: Substitute x = 0 gives y = 0, so x = 0 is a root. | Other roots: x = 0 (double root) and x = 3. Using y(-1) = -4, y(0) = 0, y(1) = -2, y(2) = -4, y(3) = 0: x = 0 is a local maximum (0 is higher than the values on either side, -4 and -2) and x = 2 is a local minimum (-4 is lower than the values on either side, -2 and 0). | |
| Question 26[5 marks] | |
|---|---|
| Answer or working | Marks |
| 10 * 10 * 10 * 10 oe seen | M1 |
| 10000 | A1cao |
| identifies 9 choices for the first digit | M1 |
| (dep) 9 * 10 * 10 * 10 | M1oe |
| 9000 | A1cao |
| Final answer: 10000 | 9000 | |
| Question 27[4 marks] | |
|---|---|
| Answer or working | Marks |
| 3 + c = -5 | M1oe |
| c = -8 | A1cao |
| 8 / k = 2 | M1oe |
| k = 4 | A1cao |
| Final answer: c = -8; k = 4 | |