Higher Stretch B
A second demanding Higher paper for late-stage exam readiness.
Questions
Question 1 [1 marks]
Pythagoras and Trigonometry
The diagram shows a right-angled triangle with the right angle marked. The sides are labelled p, q and r, where r is the side opposite the right angle. Diagram: right-angled triangle, right angle shown at the bottom-left corner, side p along the base, side q up the vertical side, side r as the slanted side joining the two ends.
Question 2 [1 marks]
Linear Algebra
Solve 36 = 4x
Question 3 [1 marks]
Statistics and Probability
A market trader sells sun hats. State the type of correlation you would expect between the number of hours of sunshine in a day and the number of sun hats sold that day.
Question 4 [2 marks]
Number and Calculation
A value v = 3.80, correct to 3 significant figures. Write down the error interval for v.
Question 5 [3 marks]
Ratio and Proportion
Mrs Okafor is comparing two bags of flour. Bag A: 750 g for £1.05. Bag B: 1.2 kg for £1.56.
Question 6 [3 marks]
Quadratics
Solve x^2 + 3x - 5 = 0. Give your solutions correct to 2 decimal places.
Question 7 [1 marks]
Indices and Standard Form
720000 is to be written in standard form. Put a ring around the number that is correctly written in standard form.
Question 8 [1 marks]
Linear Algebra
Solve y - 5 = 9.
Question 9 [2 marks]
Sequences
The nth term of a sequence is 2n + 7. Work out which term of the sequence is equal to 35.
Question 10 [2 marks]
Fractions, Decimals and Percentages
Work out 2 2/5 + 1 4/5. Give your answer as a mixed number.
Question 11 [2 marks]
Area, Volume and Measures
A parallelogram has an area of 108 cm^2 and a base of 9 cm. Work out the perpendicular height of the parallelogram.
Question 12 [2 marks]
Ratio and Proportion
Work out 150 US dollars in pounds. Use the exchange rate 1 GBP = 1.35 USD. Give your answer to 2 decimal places.
Question 13 [2 marks]
Linear Algebra
Solve 12 - 2x >= 4 Show your working.
Question 14 [2 marks]
Ratio and Proportion
The ratio of the length of Path A to the length of Path B is 15:40.
Simplify the ratio 15:40 fully.
Using your simplified ratio, write the length of Path A as a fraction of the length of Path B.
Question 15 [3 marks]
Graphs and Coordinates
Given points A(-1, 2), B(3, 5) and C(6, 1) are three consecutive vertices of a parallelogram ABCD in that order. Find the coordinates of D.
Question 16 [3 marks]
Area, Volume and Measures
A large rectangle is 18 cm by 10 cm. A central rectangle of 8 cm by 6 cm is not shaded. Find the area of the shaded part of the large rectangle.
Question 17 [3 marks]
Pythagoras and Trigonometry
For each right-angled triangle described below, write down which trigonometric ratio (sine, cosine or tangent) should be used.
The hypotenuse and angle theta are known. The side opposite theta is unknown. Which ratio should be used to find it?
The hypotenuse and angle theta are known. The side adjacent to theta is unknown. Which ratio should be used to find it?
The side opposite theta and the side adjacent to theta are known. Angle theta is unknown. Which ratio should be used to find it?
Question 18 [3 marks]
Area, Volume and Measures
A cube has volume 343 cm^3. Work out the total surface area of the cube.
Question 19 [4 marks]
Angles and Geometrical Reasoning
ABCD is a cyclic quadrilateral. Side AB is extended to a point E, so that angle CBE is the exterior angle of the quadrilateral at B. Angle CBE = 115 degrees. Diagram: circle with cyclic quadrilateral ABCD drawn on the circumference in order A, B, C, D, side AB extended beyond B to point E, angle CBE = 115 degrees marked at B.
Work out the size of angle ADC. Give a reason for your answer.
Work out the size of angle ABC.
Question 20 [4 marks]
Pythagoras and Trigonometry
A right-angled triangle PQR has right angle at Q. Side PQ = 8.0 cm and PR = 13.0 cm. Find QR and then find angle R to the nearest degree.
Find QR to 3 significant figures.
Find angle R to the nearest degree.
Question 21 [4 marks]
Statistics and Probability
The box plot below shows the number of goals scored by a football team in each of its last 32 matches.
Write down the median number of goals scored.
Work out the interquartile range of the number of goals scored.
The team is said to have had an "attacking game" if it scored more goals than the upper quartile. Estimate the number of matches, out of the 32, in which the team had an attacking game.
Question 22 [4 marks]
Linear Algebra
The sum of three consecutive odd integers is 51. Let the integers be n, n + 2 and n + 4. Form an equation and solve for n. State the three integers.
Question 23 [5 marks]
Statistics and Probability
Tom plays a game twice. In each round, the probability that Tom wins is 0.4, independently of any other round.
Complete the probability tree diagram for the two rounds by writing the missing probability on each of the four second-stage branches.
Work out the probability that Tom wins exactly one of the two rounds.
Question 24 [5 marks]
Area, Volume and Measures
A company sells two mathematically similar spherical balloons. The small balloon has diameter 20 cm and costs £3.50. The large balloon has diameter 35 cm and costs £9.50. The company intends the cost of each balloon to be proportional to the amount of material used to make it (its surface area).
Work out the surface area scale factor from the small balloon to the large balloon.
Use your answer to part (a) to work out what the large balloon should cost if the cost is exactly proportional to surface area.
The large balloon actually costs £9.50. Comment on whether the large balloon is good value for money compared with the small balloon, giving a reason.
Question 25 [5 marks]
Fractions, Decimals and Percentages
Grace's salary was £28000. It increased by 4% in year 1, by 3% in year 2, and by 2.5% in year 3.
Work out Grace's salary after year 3. Give your answer to the nearest penny.
Work out the overall percentage increase in Grace's salary over the three years. Give your answer correct to 1 decimal place.
Question 26 [5 marks]
Ratio and Proportion
It takes 6 builders 15 days to build a wall. Assume all builders work at the same constant rate, and the time taken is inversely proportional to the number of builders.
Work out how many days it would take 9 builders to build the same wall.
The wall needs to be completed in 5 days. Work out the minimum number of builders needed.
Question 27 [2 marks]
Number and Calculation
Explain why rounding 148 to 1 significant figure gives 100, and not 150.
Question 28 [3 marks]
Quadratics
n is a positive integer. Two consecutive odd numbers can be written as (2n + 1) and (2n - 1). Prove that the difference of their squares is always a multiple of 8.
Question 29 [4 marks]
Linear Algebra
Simplify fully: [1/x + 1/y] divided by [1/x - 1/y]. Give your answer as a single fraction in terms of x and y.
Question 30 [5 marks]
Graphs and Coordinates
The table shows values of f(x) = x^3 - 3x + 1 for integer values of x from -2 to 2. x : -2 , -1 , 0 , 1 , 2 f(x) : -1 , 3 , 1 , -1 , 3
Show that f(-1) = 3.
Using the table, write down the three intervals (each of width 1) in which the equation x^3 - 3x + 1 = 0 has a solution.
State the total number of real solutions to the equation x^3 - 3x + 1 = 0.
Question 31 [6 marks]
Ratio and Proportion
A shop sells fabric by the metre. The price per metre is p pounds. There is a special offer: buy at least 2 metres and get 15% off the total price; buy 5 or more metres and get 25% off the total price. (a) For a customer buying 4 metres, show in terms of p the total cost after discount. (b) For what values of p (p > 0) will the cost for 4 metres after that discount be less than £40? Give your answer as an inequality and solve.
(a) Show the total cost after discount for 4 metres in terms of p.
(b) For what values of p will the cost for 4 metres after discount be less than £40? Solve the inequality.
Question 32 [7 marks]
Graphs and Coordinates
A circle with centre O, the origin, has equation x^2 + y^2 = 25 P is the point (-3, 4).
Find the equation of the tangent to the circle at P.
This tangent intersects the line with equation y = 2x + 1 at a single point. Find the coordinates of this point.
Model solutions
| Question 1[1 mark] | |
|---|---|
| Answer or working | Marks |
| r stated as the hypotenuse | B1cao |
| Final answer: C) r | |
| Question 2[1 mark] | |
|---|---|
| Answer or working | Marks |
| x = 9 | B1cao |
| Question 3[1 mark] | |
|---|---|
| Answer or working | Marks |
| positive correlation | B1oe |
| Question 4[2 marks] | |
|---|---|
| Answer or working | Marks |
| one correct bound identified, 3.795 or 3.805 | M1oe |
| 3.795 <= v < 3.805 | A1cao |
| Question 5[3 marks] | |
|---|---|
| Answer or working | Marks |
| 1.2 kg converted to 1200 g | M1oe |
| 105 / 7.5 oe and 156 / 12 oe (price per 100 g for each bag) | M1 |
| 14p and 13p both correct, with bag B stated as better value | A1cao |
| Final answer: Bag B is better value (13p per 100 g compared with 14p per 100 g) | |
| Question 6[3 marks] | |
|---|---|
| Answer or working | Marks |
| correct substitution into the formula with a = 1, b = 3, c = -5, e.g. x = (-3 +/- sqrt(3^2 - 4(1)(-5)))/(2(1)) | M1 |
| x = 1.19 (awrt 1.19) | A1 |
| x = -4.19 (awrt -4.19) | A1 |
| Final answer: x = 1.19 or x = -4.19 | |
| Question 7[1 mark] | |
|---|---|
| Answer or working | Marks |
| B | B1 |
| Final answer: B (7.2 x 10^5) | |
| Question 8[1 mark] | |
|---|---|
| Answer or working | Marks |
| y = 14 | B1cao |
| Final answer: 14 | |
| Question 9[2 marks] | |
|---|---|
| Answer or working | Marks |
| 2n + 7 = 35 | M1oe |
| 14 cao (the 14th term) | A1 |
| Final answer: n = 14 (the 14th term) | |
| Question 10[2 marks] | |
|---|---|
| Answer or working | Marks |
| convert or add whole and fractions correctly, e.g. 2 + 1 and 2/5 + 4/5 = 6/5 shown | M1 |
| 4 1/5 | A1cao |
| Question 11[2 marks] | |
|---|---|
| Answer or working | Marks |
| Use height = area / base = 108 / 9 | M1 |
| 12 cm | A1cao |
| Question 12[2 marks] | |
|---|---|
| Answer or working | Marks |
| Divide dollars by 1.35 to convert to pounds (150 ÷ 1.35) | M1 |
| 111.11 awrt (to 2 dp) | A1 |
| Final answer: £111.11 awrt | |
| Question 13[2 marks] | |
|---|---|
| Answer or working | Marks |
| 8 >= 2x oe (correct rearrangement) | M1 |
| x <= 4 | A1cao |
| Question 14[2 marks] | |
|---|---|
| Answer or working | Marks |
| 3:8 | B1cao |
| 3/8 ft from (a) | B1 |
| Final answer: 3:8 | 3/8 | |
| Question 15[3 marks] | |
|---|---|
| Answer or working | Marks |
| calculate vector BC = C - B = (3, -4) or show method | M1 |
| apply vector to A: D = A + BC shown | M1 |
| (2, -2) | A1cao |
| Question 16[3 marks] | |
|---|---|
| Answer or working | Marks |
| use 18×10 - 8×6 or equivalent subtraction method | M1 |
| compute 180 - 48 | M1 |
| 132 cm^2 | A1cao |
| Question 17[3 marks] | |
|---|---|
| Answer or working | Marks |
| Sine (SOH) | B1cao |
| Cosine (CAH) | B1cao |
| Tangent (TOA) | B1cao |
| Final answer: Sine | Cosine | Tangent | |
| Question 18[3 marks] | |
|---|---|
| Answer or working | Marks |
| cube root of 343 (= 7 cm), or 7^3 = 343 seen | M1 |
| 6 x 7^2 (= 6 x 49) | M1 |
| 294 cm^2 | A1cao |
| Question 19[4 marks] | |
|---|---|
| Answer or working | Marks |
| use the exterior angle of a cyclic quadrilateral equals the interior opposite angle | M1 |
| 115 degrees cao, with reason stated | A1 |
| 180 - 115 oe, using angles on a straight line ABE or opposite angles in a cyclic quadrilateral | M1 |
| 65 degrees | A1cao |
| Final answer: 115 degrees | 65 degrees | |
| Question 20[4 marks] | |
|---|---|
| Answer or working | Marks |
| use Pythagoras QR = sqrt(PR^2 - PQ^2) or equivalent | M1 |
| 10.2 cm awrt (3 s.f.) | A1 |
| use sin R = opposite/hypotenuse = PQ/PR = 8/13 (PQ is opposite angle R) and take arcsin | M1 |
| 38 degrees | A1cao |
| Final answer: 10.2 cm | 38 degrees | |
| Question 21[4 marks] | |
|---|---|
| Answer or working | Marks |
| 2 | B1cao |
| 3 | B1cao |
| recognising that exactly 25% of matches lie above the upper quartile, i.e. 1/4 x 32 | M1oe |
| 8 | A1cao |
| Final answer: 2 goals | 3 goals | 8 matches | |
| Question 22[4 marks] | |
|---|---|
| Answer or working | Marks |
| form equation n + (n + 2) + (n + 4) = 51 | M1 |
| collect terms to 3n + 6 = 51 and solve to n = 15 | M1 |
| state the three integers correctly | M1 |
| integers are 15, 17 and 19 | A1cao |
| Final answer: 15, 17, 19 | |
| Question 23[5 marks] | |
|---|---|
| Answer or working | Marks |
| 0.4 (Win) on both second-stage branch pairs | B1 |
| 0.6 (Lose) on both second-stage branch pairs | B1 |
| 0.4 x 0.6 (or 0.6 x 0.4) for one correct route | M1 |
| 0.4 x 0.6 + 0.6 x 0.4 (both routes identified and added) | M1 |
| 0.48 | A1cao |
| Final answer: Win = 0.4 and Lose = 0.6 on each set of second-stage branches | 0.48 | |
| Question 24[5 marks] | |
|---|---|
| Answer or working | Marks |
| linear scale factor = 35/20 (=1.75) | M1 |
| 3.0625 cao (1.75^2) | A1 |
| 3.50 x their (a) | M1 |
| 10.72 (pounds) awrt | A1cao |
| correct comment with supporting reason, e.g. the large balloon is better value because its actual cost (£9.50) is less than the cost predicted by the surface area scale factor (£10.72) | C1 |
| Final answer: 3.0625 | £10.72 (awrt) | The large balloon is better value for money, since £9.50 is less than the £10.72 that proportional pricing would suggest. | |
| Question 25[5 marks] | |
|---|---|
| Answer or working | Marks |
| 1.04 x 1.03 x 1.025 (oe) used as combined multiplier | M1 |
| 28000 x their combined multiplier | M1 |
| £30743.44 | A1cao |
| (their (a) - 28000) / 28000 x 100 (oe | M1ft |
| 9.8% (awrt) | A1cao |
| Final answer: £30743.44 | 9.8% | |
| Question 26[5 marks] | |
|---|---|
| Answer or working | Marks |
| 6 x 15 (= 90) | M1oe |
| 90 / 9 | M1dep |
| 10 (days) | A1cao |
| 90 / 5 | M1ft |
| 18 (builders) | A1cao |
| Final answer: 10 days | 18 builders | |
| Question 27[2 marks] | |
|---|---|
| Answer or working | Marks |
| identifying that the first significant figure is the hundreds digit, 1, and all following digits become 0 for 1 sf | B1 |
| correct reasoning that the next digit (4, the tens digit) is less than 5, so the 1 is not rounded up, giving 100; 150 is not a rounding to 1 significant figure | B1 |
| Final answer: 100, because the first significant figure (1) is followed by a 4, which is less than 5, so it rounds down; 150 has two significant figures, not one. | |
| Question 28[3 marks] | |
|---|---|
| Answer or working | Marks |
| writes the difference of two squares (2n+1)^2 - (2n-1)^2 and factorises as [(2n+1)-(2n-1)][(2n+1)+(2n-1)] | M1 |
| simplifies brackets correctly to (2)(4n) | M1 |
| cso: concludes = 8n, which is a multiple of 8 for all integer n, fully justified | A1 |
| Final answer: (2n+1)^2 - (2n-1)^2 = 8n, a multiple of 8 (proven) | |
| Question 29[4 marks] | |
|---|---|
| Answer or working | Marks |
| writes the numerator as (y + x)/(xy) | M1 |
| writes the denominator as (y - x)/(xy) | M1 |
| divides the two fractions, cancelling the common factor xy | M1 |
| (x + y)/(y - x) | A1oe |
| Question 30[5 marks] | |
|---|---|
| Answer or working | Marks |
| (-1)^3-3(-1)+1=-1+3+1=3 | B1cso |
| between x=-2 and x=-1 (sign changes from -1 to 3) | B1 |
| between x=0 and x=1 (sign changes from 1 to -1) | B1 |
| between x=1 and x=2 (sign changes from -1 to 3) | B1 |
| 3, ft from part (b) | B1 |
| Final answer: 3 (shown) | Between x=-2 and x=-1; between x=0 and x=1; between x=1 and x=2 | 3 real solutions | |
| Question 31[6 marks] | |
|---|---|
| Answer or working | Marks |
| form 4p * (1 - 0.15) or 4p * 0.85 | M1 |
| correct expression 3.4 p | A1cao |
| form inequality 3.4 p < 40 | M1 |
| solve p < 40 / 3.4 | M1 |
| compute 40 / 3.4 = 11.764705... and round appropriately | A1 |
| final inequality p < 11.76... so p < 11.76(47) or p < 11.76 to 2 dp and state p > 0 | A1 |
| Final answer: Total cost = 4p * 0.85 = 3.4 p. Working check: 15% off means pay 85% so 4p*0.85 = 3.4p. | Inequality: 3.4 p < 40 -> p < 40 / 3.4 = 11.764705... So for p > 0 the cost is less than £40 when p < 11.764705... (approximately p < £11.76). Working check: p = 11.76 gives 3.4*11.76 = 40.0 approx. | |
| Question 32[7 marks] | |
|---|---|
| Answer or working | Marks |
| gradient of OP = 4/(-3) = -4/3, so tangent gradient = 3/4 | M1 |
| correct method using point P, e.g. y - 4 = (3/4)(x + 3) | M1 |
| correct rearrangement towards integer form | M1 |
| -3x + 4y = 25 (oe, e.g. y = (3/4)x + 25/4) | A1cao |
| sets their tangent equation equal to 2x + 1, ft their part (a) | P1 |
| correct algebraic method to solve for x, e.g. (3/4)x + 25/4 = 2x + 1 leading to 3x + 25 = 8x + 4 | M1 |
| (21/5, 47/5) (oe (4.2, 9.4)), both coordinates correct | A1cao |
| Final answer: -3x + 4y = 25 (oe y = (3/4)x + 25/4) | (21/5, 47/5) = (4.2, 9.4) | |