Pure: Trigonometric Graphs
Trigonometric graphs applies the transformation rules from functions and graphs to y = sin(x), y = cos(x) and y = tan(x), and adds facts specific to trig graphs: their period, amplitude, symmetry, and, for tan and the reciprocal trig functions, their vertical asymptotes. A transformed graph such as y = a sin(b(x - c)) + d has amplitude |a|, period 360/b degrees, is shifted c to the right and d up, and every one of these numbers can be read straight off the equation.
Before you start
Make sure you're comfortable with these topics first:
Method
- Learn the key facts of each parent graph: y = sin(x) and y = cos(x) both have amplitude 1, period 360 degrees, and range -1 <= y <= 1; y = cos(x) is the graph of y = sin(x) translated 90 degrees to the left.
- y = tan(x) has period 180 degrees, an unbounded range (all real numbers), and a vertical asymptote wherever cos(x) = 0, i.e. at x = 90 + 180n degrees for integer n.
- For y = a sin(bx) (or the cos or tan equivalent), the amplitude becomes |a| and the period becomes 360/b degrees (or 180/b degrees for tan), since a larger b squeezes the same number of cycles into a smaller x-range.
- For y = sin(x - c) + d (or the cos or tan equivalent), the graph is translated c to the right (or |c| to the left, if c is negative) and d upward; the vertical translation shifts the whole wave, including its maximum and minimum values, by d, but never changes the amplitude or the period.
- To combine these into y = a sin(b(x-c)) + d, find the amplitude and period first from a and b, then shift the resulting wave c to the right and d up; locate a maximum, a minimum or an intercept by starting from the equivalent point on the standard sine wave and applying the same working.
- The reciprocal trig graphs are built from sin, cos and tan: cosec(x) = 1/sin(x), sec(x) = 1/cos(x), and cot(x) = 1/tan(x); each has a vertical asymptote wherever its parent function is zero, and cosec(x) and sec(x) both have range |y| >= 1, since one divided by a number no bigger than 1 in size is always at least 1 in size.
- A tan-based graph's asymptotes transform like any other vertical feature: for y = tan(b(x-c)), the asymptotes of y = tan(x) at x = 90 + 180n degrees map to x = c + (90+180n)/b degrees; a constant added outside the tan function does not move them, since an asymptote is about the INPUT being undefined, not the output's value.
- To count how many solutions an equation such as a sin(bx) + d = k has over a given range, compare k with the wave's maximum (d + |a|) and minimum (d - |a|) values first: no solution exists at all if k lies outside this interval, whatever the range of x, and otherwise the number of solutions can be found by picturing the horizontal line y = k crossing the wave.
- Check whether the parent function is odd (sin, tan, cosec, cot: f(-x) = -f(x)) or even (cos, sec: f(-x) = f(x)) before assuming a reflection in the y-axis changes anything; reflecting an even function in the y-axis leaves its graph completely unchanged.
Worked example
Find the amplitude, the period, and the coordinates of a maximum point and a minimum point of the graph of y = 3sin(2x) - 1, for 0 <= x <= 360 degrees.
- Compare with y = a sin(bx) + d: a = 3, b = 2, d = -1. Amplitude = |a| = 3. Period = 360/b = 360/2 = 180 degrees, so the wave completes two full cycles between 0 and 360 degrees.
- The graph oscillates about the midline y = d = -1 instead of y = 0, reaching a maximum value of d + |a| = -1 + 3 = 2 and a minimum value of d - |a| = -1 - 3 = -4.
- For plain y = sin(2x), the first maximum (sin = 1) occurs where 2x = 90 degrees, i.e. x = 45 degrees; the vertical stretch and translation only change the y-VALUE at that point, not the x-value where it occurs, so y = 3sin(2x) - 1 also has a maximum at x = 45.
- Similarly, the first minimum of sin(2x) (sin = -1) occurs where 2x = 270 degrees, i.e. x = 135 degrees, giving a minimum of y = 3sin(2x) - 1 at x = 135 also.
- Final answer: amplitude 3, period 180 degrees, maximum point (45, 2), minimum point (135, -4).
Practice questions
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Q1State the amplitude and the period of y = 5cos(x).Show answer
Answer: Amplitude 5, period 360 degrees.
Q2State the period of y = sin(4x).Show answer
Answer: 90 degrees (360/4).
Q3The graph of y = cos(x) is translated to give y = cos(x) - 3. State the maximum and minimum values of the new graph.Show answer
Answer: Maximum 1 - 3 = -2; minimum -1 - 3 = -4.
Q4State the two smallest positive values of x for which y = tan(x) has a vertical asymptote.Show answer
Answer: x = 90 degrees and x = 270 degrees.
Q5The graph of y = sin(x) has a minimum point at (270, -1). State the coordinates of the corresponding minimum point on the graph of y = sin(x) + 4.Show answer
Answer: (270, 3) (a vertical translation does not move where a minimum occurs, only its y-value: -1 + 4 = 3).
Q6State the two smallest positive values of x for which y = cosec(x) is undefined.Show answer
Answer: x = 180 degrees and x = 360 degrees (cosec(x) = 1/sin(x) is undefined wherever sin(x) = 0).
Exam-style questions
Written in the style of a A Level Maths exam paper, with a full mark scheme.
The graph of y = f(x), where f(x) = 2cos(3x) + 1, is drawn for 0 <= x <= 360 degrees. (a) State the amplitude, the period, and the equation of the midline of this graph. (3) (b) State the coordinates of the maximum point of y = f(x) with the smallest positive value of x. (2) (c) By comparing the value 3.5 with the maximum value of f(x), state the number of solutions of 2cos(3x) + 1 = 3.5 for 0 <= x <= 360 degrees. (1)
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(a) State the period of y = tan(x/2). (1) (b) Find the two smallest positive values of x for which the graph of y = tan(x/2) has a vertical asymptote. (2) (c) Solve tan(x/2) = 1 for 0 <= x < 720 degrees. (3)
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The graph of y = 4sin(x) is transformed to give the graph of y = 4sin(x - 60 degrees) + 2. (a) State the coordinates of the point where the ORIGINAL graph, y = 4sin(x), crosses the y-axis. (1) (b) State the amplitude and the equation of the midline of the new graph, y = 4sin(x - 60 degrees) + 2. (2) (c) Find the smallest positive value of x at which the new graph takes its maximum value, and state this maximum value. (3)
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Free printable worksheet
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