Monohybrid Inheritance and Genetic Diagrams
Monohybrid inheritance is the IGCSE requirement to construct and interpret genetic diagrams (Punnett squares and genetic crosses) for a single gene with two alleles, using the correct terminology (allele, genotype, phenotype, homozygous, heterozygous, dominant, recessive) and to predict offspring ratios, including for sex-linked and codominant inheritance patterns beyond the plain dominant/recessive crosses covered at GCSE. Students must set out a full genetic diagram (parental phenotypes, genotypes, gametes, a Punnett square, and offspring genotype/phenotype ratios) rather than just stating a final ratio.
Method
- Define the key terms precisely, since they are marked individually: allele (a different version of a gene); genotype (the combination of alleles an organism has for a gene, written with letters, for example Bb); phenotype (the observable characteristic resulting from the genotype, for example brown eyes); homozygous (having two identical alleles for a gene, for example BB or bb); heterozygous (having two different alleles for a gene, for example Bb); dominant allele (an allele whose characteristic appears in the phenotype even when only one copy is present, conventionally shown with a capital letter); recessive allele (an allele whose characteristic only appears in the phenotype when two copies are present, conventionally shown with a lower-case letter).
- Set out a full genetic diagram in this exact order every time: state the parents' phenotypes and genotypes; state the gametes each parent can produce (each gamete carries one allele, since gametes are haploid); draw a Punnett square with one parent's gametes along the top and the other's down the side, and fill in every offspring genotype in the grid; read off the genotype ratio from the grid, then convert to a phenotype ratio using which genotypes give which phenotype; state the final ratio in simplest form (for example, 3:1) and, if asked, as a percentage or fraction.
- For a monohybrid cross between two heterozygotes (Bb x Bb), show that the offspring genotype ratio is 1 BB : 2 Bb : 1 bb, giving a phenotype ratio of 3 dominant : 1 recessive.
- For a test cross (an individual of unknown genotype, showing the dominant phenotype, crossed with a known homozygous recessive), explain the logic: if any recessive-phenotype offspring appear, the unknown parent must be heterozygous (since it must carry a recessive allele to pass on); if all offspring show the dominant phenotype, the unknown parent is more likely to be homozygous dominant.
- For codominance, define it precisely (both alleles are expressed in the phenotype of a heterozygote, with neither masking the other, giving a distinct third phenotype rather than a blend) and apply it to a named example such as human ABO blood groups, where allele I_A and allele I_B are codominant and both are dominant to i, so genotype I_A I_B gives phenotype AB.
- For sex linkage, explain that a sex-linked gene is carried on a sex chromosome (usually the X chromosome), so its inheritance pattern differs between males (XY, only one X, so a single recessive allele is always expressed) and females (XX, need two recessive alleles to show the recessive phenotype), which is why sex-linked recessive conditions such as red-green colour blindness or haemophilia are much more common in males.
- Always show every step of the diagram in an exam answer, even when the final ratio seems obvious, since IGCSE mark schemes award marks for stating gametes and completing the Punnett square correctly, not only for the final ratio.
Worked example
In pea plants, the allele for tall stems (T) is dominant to the allele for short stems (t). A heterozygous tall plant (Tt) is crossed with a short plant (tt). Use a genetic diagram to predict the phenotype ratio of the offspring.
- State the parents' genotypes and phenotypes: Tt (tall) x tt (short).
- State the gametes each parent can produce: the Tt parent produces gametes T and t; the tt parent produces only gametes t and t.
- Draw a Punnett square with the Tt parent's gametes (T, t) along the top and the tt parent's gametes (t, t) down the side.
- Fill in the four boxes: Tt, tt, Tt, tt.
- Read off the genotype ratio: 2 Tt : 2 tt, which simplifies to 1 Tt : 1 tt.
- Convert to phenotypes: Tt is tall (T is dominant), tt is short, so the final answer is a phenotype ratio of 1 tall : 1 short (50% tall, 50% short).
Practice questions
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Q1Define the term 'heterozygous'.Show answer
Answer: Having two different alleles for a particular gene (for example, Bb).
Q2State the difference between genotype and phenotype.Show answer
Answer: Genotype is the combination of alleles an organism has for a gene; phenotype is the observable characteristic that results from the genotype.
Q3In guinea pigs, black fur (B) is dominant to white fur (b). Two heterozygous black guinea pigs (Bb) are crossed. State the expected phenotype ratio of their offspring.Show answer
Answer: 3 black : 1 white.
Q4State what is meant by a 'test cross'.Show answer
Answer: A cross between an individual showing the dominant phenotype but of unknown genotype, and an individual that is homozygous recessive, used to determine whether the unknown individual is homozygous or heterozygous dominant.
Q5In humans, red-green colour blindness is caused by a recessive allele carried on the X chromosome. Explain why colour blindness is much more common in males than in females.Show answer
Answer: Males are XY, so they have only one X chromosome; a single recessive colour-blindness allele on that X chromosome will always be expressed, since there is no second X chromosome that could carry a dominant allele to mask it. Females are XX, so they need the recessive allele on both X chromosomes to be colour blind, which is much less likely.
Q6In human ABO blood groups, alleles I_A and I_B are codominant, and both are dominant to allele i. State the genotype of a person with blood group AB.Show answer
Answer: I_A I_B.
Exam-style questions
Written in the style of a IGCSE Science exam paper, with a full mark scheme.
In pea plants, round seed shape (R) is dominant to wrinkled seed shape (r). State the genotype(s) possible for a pea plant with round seeds.
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A plant breeder crosses two pea plants, both heterozygous for seed shape (Rr x Rr, where R = round is dominant, r = wrinkled is recessive). The cross produces 184 offspring seeds in total. Using the expected ratio from a genetic diagram, calculate the expected number of wrinkled seeds among the offspring.
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Haemophilia is a genetic disorder caused by a recessive allele (h) carried on the X chromosome; the dominant allele (H) allows normal blood clotting. A woman who is a carrier for haemophilia (heterozygous, unaffected) has children with a man who does not have haemophilia. Using a full genetic diagram, predict the genotype and phenotype ratios of their children, and explain why sons and daughters are affected differently.
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Free printable worksheet
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