13+ Common Entrance · Topic guide

Sequences, Patterns and Formulae

Sequences, Patterns and Formulae covers recognising and continuing number sequences, finding the nth term of a linear (arithmetic) sequence, describing the rule behind a growing diagram pattern such as a tiling or matchstick pattern, and substituting into and rearranging simple formulae.

Year 7-8 (13+)MathsISEB

Before you start

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Method

  1. For a sequence of numbers, find the term-to-term rule first by working out the difference between consecutive terms.
  2. If the difference between terms is always the same, the sequence is linear, and its nth term has the form (common difference x n) plus or minus an adjustment.
  3. To find the nth term of a linear sequence, multiply the common difference by n, then work out what must be added or subtracted so that n = 1 gives the first term.
  4. Recognise common special sequences by their pattern: square numbers (1, 4, 9, 16, ...), triangular numbers (1, 3, 6, 10, ...) and sequences where each term is the sum of the two before it.
  5. For a growing diagram pattern, count how many extra items are added each time the pattern grows by one step, and link this directly to the term-to-term rule and the nth term.
  6. To substitute into a formula, replace each letter with its given value carefully, keeping to the correct order of operations, especially with powers and brackets.
  7. To rearrange a formula to make a different letter the subject, apply the same operation to both sides of the equation until the required letter stands alone.
  8. Check an nth term rule by testing it against at least two terms of the original sequence, not just the first.

Worked example

A sequence begins 5, 9, 13, 17, ... Find an expression for the nth term, and use it to find the 20th term.

  1. Find the common difference between terms: 9 - 5 = 4 and 13 - 9 = 4, so the difference is always 4.
  2. Since the difference is constant, the nth term starts with 4n.
  3. Compare 4n with the sequence when n = 1: 4 x 1 = 4, but the first term is 5, so 1 must be added: nth term = 4n + 1.
  4. Check with the second term: 4 x 2 + 1 = 9, which matches. Substitute n = 20 to find the 20th term: 4 x 20 + 1 = 81. Final answer: nth term = 4n + 1, and the 20th term is 81.

Practice questions

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Q1Write the next two terms of the sequence: 3, 7, 11, 15, ...Show answer

Answer: 19, 23 (the term-to-term rule is add 4)

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Q2Find the nth term of the sequence 2, 5, 8, 11, ...Show answer

Answer: 3n - 1 (common difference 3, and 3 x 1 - 1 = 2, which matches the first term)

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Q3The nth term of a sequence is 5n - 2. Find the 12th term.Show answer

Answer: 58 (5 x 12 - 2 = 60 - 2 = 58)

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Q4Write the first four terms of the sequence with nth term 2n^2.Show answer

Answer: 2, 8, 18, 32 (substituting n = 1, 2, 3, 4: 2 x 1, 2 x 4, 2 x 9, 2 x 16)

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Q5A pattern of dots grows so that pattern 1 has 4 dots, pattern 2 has 7 dots, and pattern 3 has 10 dots. How many dots will pattern 6 have?Show answer

Answer: 19 dots (the rule is add 3 each time, giving nth term = 3n + 1, and 3 x 6 + 1 = 19)

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Q6Using the formula v = u + at, find v when u = 5, a = 3 and t = 4.Show answer

Answer: 17 (v = 5 + 3 x 4 = 5 + 12 = 17)

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Q7Rearrange the formula P = 2l + 2w to make w the subject.Show answer

Answer: w = (P - 2l) / 2

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Q8The first three terms of the triangular numbers are 1, 3, 6. If the pattern continues in the same way, what is the next term after 6?Show answer

Answer: 10 (the differences between terms are 2 then 3, so the next difference is 4: 6 + 4 = 10)

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Exam-style questions

Written in the style of a 13+ Common Entrance exam paper, with a full mark scheme.

Q1[4 marks]

A sequence has nth term 6n - 4. (a) Find the 15th term. (b) Determine whether 158 is a term in this sequence, showing your reasoning.

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Q2[5 marks]

A tiling pattern is built from hexagonal tiles. Pattern 1 uses 6 tiles, pattern 2 uses 11 tiles, and pattern 3 uses 16 tiles. (a) Find an expression for the number of tiles in pattern n. (b) A pattern in this sequence uses 91 tiles. Find which pattern number this is.

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Q3[3 marks]

The cost, C pounds, of hiring a bouncy castle for h hours is given by the formula C = 45 + 12h. (a) Calculate the cost of hiring the bouncy castle for 5 hours. (b) A school has a budget of 120 pounds. Find the maximum whole number of hours they can hire the bouncy castle for, showing your working.

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Free printable worksheet

Want more practice on paper? Download the sequences, patterns and formulae worksheet pack - 10 pages of exam-style questions with a full mark scheme. One email opens every download in this browser for 14 days - no account, no card. Print it for personal and classroom use.

This topic is chapter 15 of 13+ Maths Workbook, the whole course as one free printable PDF.

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