A Level

A Level Maths Paper 3

Covers Proof and Algebraic Methods, Coordinate Geometry, Sequences, Series and the Binomial Expansion and 11 more.

14 questions - 60 marks - calculator allowed

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Questions

Question 1 [2 marks]

Sequences, Series and the Binomial Expansion

An arithmetic sequence has first term 5 and common difference 3.

Find the 20th term.

Question 2 [2 marks]

Coordinate Geometry

Find the equation of the straight line that passes through the points (1, 4) and (5, -8), giving your answer in the form y = mx + c.

Question 3 [3 marks]

Integration

Evaluate the definite integral of (3x^2 - 2x + 1) with respect to x between x = -1 and x = 2.

Question 4 [3 marks]

Vectors

Find the magnitude of the vector v = 5i - 12j, and find a unit vector in the same direction as v.

Question 5 [4 marks]

Differentiation

Using differentiation from first principles, show that the derivative of x^2 is 2x.

Question 6 [4 marks]

Exponentials and Logarithms

Solve the equation 5^(2x - 1) = 30, giving your answer to 3 significant figures.

Question 7 [4 marks]

Proof and Algebraic Methods

Without using a calculator, find the quotient and remainder when 2x^3 - 3x^2 + 4x - 1 is divided by (x - 1).

Question 8 [5 marks]

Forces and Newton's Laws

A block of mass 6 kg lies on a rough horizontal surface. The coefficient of friction between the block and the surface is 0.25. A horizontal force of 20 N is applied to the block.

Find the acceleration of the block. Use g = 9.8 m/s^2.

Question 9 [5 marks]

Moments

A non-uniform plank AB has length 5 m and weight 120 N, and rests horizontally on two supports at A and B. When a block of weight 60 N is placed at a point 2 m from A, the reaction at A is 100 N.

Find the reaction at B in this situation, and find the distance of the centre of mass of the plank from A.

Question 10 [5 marks]

Trigonometry

Express 3 sin(x) + 4 cos(x) in the form R sin(x + alpha), where R > 0 and 0 < alpha < 90 deg, giving the value of alpha to 1 decimal place.

Hence state the maximum value of 3 sin(x) + 4 cos(x), and the smallest positive value of x, in degrees, at which it occurs.

Question 11 [5 marks]

Probability and the Binomial Distribution

Two fair six-sided dice are thrown, and the sum of the two scores is recorded.

Find the probability that the sum is a prime number, given that at least one die shows a 5.

Question 12 [6 marks]

Sampling and Data Presentation

A college has 900 students: 340 study Sciences, 260 study Humanities and 300 study Arts. A stratified sample of 45 students is to be selected by subject, and within Sciences, systematic sampling is then used to choose the required number from a numbered list of all 340 Science students.

Find the number of Science students needed in the sample, and find the sampling interval that should be used for the systematic sampling.

Question 13 [6 marks]

Kinematics

A particle P moves in a straight line such that its displacement s metres from a fixed point O at time t seconds (t >= 0) is given by s = t^3 - 7t^2 + 10t.

Find the two values of t (other than t = 0) at which P is at O, and find the velocity of P at the larger of these two times.

Question 14 [6 marks]

The Normal Distribution and Hypothesis Testing

A seed supplier claims that 40% of a particular type of seed germinate within one week of planting. A gardener believes the true proportion is lower and plants a random sample of 25 of the seeds.

Using the binomial distribution X ~ B(25, 0.4), find the critical region for a test of H0: p = 0.4 against H1: p < 0.4 at the 5% significance level, stating the actual significance level. Given that 6 of the 25 seeds germinate within a week, state the conclusion of the test.

Model solutions

Mark scheme for Question 1 [2 marks]
Question 1[2 marks]
Answer or workingMarks
using term = a + (n - 1)dM1
62A1
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
gradient = (-8 - 4)/(5 - 1) = -3M1
y = -3x + 7A1
Mark scheme for Question 3 [3 marks]
Question 3[3 marks]
Answer or workingMarks
the antiderivative x^3 - x^2 + xM1
substituting the limits x = 2 and x = -1M1
the value 9A1
Final answer: 9
Mark scheme for Question 4 [3 marks]
Question 4[3 marks]
Answer or workingMarks
|v| = sqrt(5^2 + 12^2)M1
|v| = 13A1
the unit vector (5/13)i - (12/13)jA1
Final answer: |v| = 13; unit vector = (5/13)i - (12/13)j
Mark scheme for Question 5 [4 marks]
Question 5[4 marks]
Answer or workingMarks
writing f'(x) = lim as h tends to 0 of [(x + h)^2 - x^2]/hM1
expanding (x + h)^2 = x^2 + 2xh + h^2M1
simplifying the difference quotient to 2x + hA1
taking the limit as h tends to 0 to give f'(x) = 2x, completing the proofA1
Final answer: Proof: f'(x) = lim (h -> 0) of (2x + h) = 2x
Mark scheme for Question 6 [4 marks]
Question 6[4 marks]
Answer or workingMarks
taking logarithms of both sidesM1
using the power law to give (2x - 1) ln(5) = ln(30)M1
2x - 1 = 2.1133 (or equivalent unrounded value)A1
x = 1.56 (3 sf)A1
Mark scheme for Question 7 [4 marks]
Question 7[4 marks]
Answer or workingMarks
dividing to obtain the first term of the quotient, 2x^2M1
continuing the division to find the remaining terms of the quotientM1
the quotient 2x^2 - x + 3A1
the remainder 2A1
Final answer: Quotient = 2x^2 - x + 3, remainder = 2
Mark scheme for Question 8 [5 marks]
Question 8[5 marks]
Answer or workingMarks
finding the normal reaction R = mg = 58.8 NM1
finding the friction force = mu x R = 14.7 NM1
recognising the applied force exceeds the maximum friction, so the resultant force = 20 - 14.7M1
resultant force = 5.3 NA1
a = 0.883 m/s^2 (3 sf)A1
Mark scheme for Question 9 [5 marks]
Question 9[5 marks]
Answer or workingMarks
vertical equilibrium to find R_B = 180 - 100 = 80 NM1
taking moments about A: R_B x 5 = 120x + 60 x 2, using x for the distance of the centre of mass from AM1
forming the equation 400 = 120x + 120A1
solving for xM1
x = 2.33 m (3 sf)A1
Final answer: R_B = 80 N; centre of mass is 2.33 m from A (3 sf)
Mark scheme for Question 10 [5 marks]
Question 10[5 marks]
Answer or workingMarks
using R = sqrt(3^2 + 4^2)M1
R = 5A1
using tan(alpha) = 4/3M1
alpha = 53.1 deg (1 dp)A1
the maximum value 5, occurring at x = 90 - 53.1 = 36.9 deg (1 dp)A1
Final answer: R = 5, alpha = 53.1 deg; maximum value = 5 at x = 36.9 deg (1 dp)
Mark scheme for Question 11 [5 marks]
Question 11[5 marks]
Answer or workingMarks
identifying the 11 equally likely outcomes in which at least one die shows a 5M1
listing the corresponding sums (6, 7, 8, 9, 10 or 11)M1
identifying that the sums 7 and 11 are primeA1
counting 4 outcomes that give a prime sumA1
the probability = 4/11A1
Final answer: 4/11
Mark scheme for Question 12 [6 marks]
Question 12[6 marks]
Answer or workingMarks
the sampling fraction = 45/900 = 0.05M1
multiplying the Science total by the fractionM1
the Science sample size = 17A1
the systematic sampling interval = population size / sample sizeM1
the interval = 340/17 = 20A1
a correct statement of how the systematic sample would then be chosen, e.g. select a random start between 1 and 20 and then every 20th student thereafterB1
Final answer: 17 Science students needed; systematic sampling interval = 20
Mark scheme for Question 13 [6 marks]
Question 13[6 marks]
Answer or workingMarks
factorising s = t(t^2 - 7t + 10)M1
s = t(t - 2)(t - 5), giving t = 2 and t = 5A1
differentiating to find v = 3t^2 - 14t + 10M1
substituting t = 5 into vM1
v = 75 - 70 + 10A1
v = 15 m/sA1
Final answer: t = 2 s and t = 5 s; velocity at t = 5 is 15 m/s
Mark scheme for Question 14 [6 marks]
Question 14[6 marks]
Answer or workingMarks
identifying X ~ B(25, 0.4) and attempting cumulative probabilities under H0M1
P(X <= 5) = 0.0294 (acceptA1awrt
P(X <= 6) = 0.0736 (accept awrt), confirming this exceeds 0.05A1
the critical region X <= 5, with actual significance level 0.0294 (2.94%)A1
noting that 6 does not lie in the critical region, since 6 > 5A1
the conclusion: insufficient evidence at the 5% level that the true proportion germinating is lower than 40%A1
Final answer: Critical region X <= 5 (significance level 0.0294); since 6 is not in the critical region, there is insufficient evidence that the true proportion is lower than 40%