Foundation Tier - Grades 1-5

IGCSE Maths Foundation Paper 1

Covers Number and Calculation, Fractions, Decimals and Percentages, Indices, Surds and Standard Form and 9 more.

17 questions - 60 marks - calculator allowed

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Questions

Question 1 [2 marks]

Linear Equations and Inequalities

Solve x/4 - 3 = 9.

Question 2 [2 marks]

Mensuration and Vectors

A triangle has base 16 cm and perpendicular height 7 cm. Find its area.

Question 3 [3 marks]

Quadratics and Simultaneous Equations

Expand and simplify (x + 7)(x - 3).

Question 4 [3 marks]

Ratio and Proportion

A fruit squash is made from concentrate and water in the ratio 1:6.

Yuki uses 150 ml of concentrate. Find the total volume of squash she makes, in millilitres.

Question 5 [3 marks]

Statistics and Probability

The numbers of goals scored by a football team in six matches are 2, 0, 3, 1, 4 and 2.

Find the mean and the range of the number of goals.

Question 6 [3 marks]

Functions and Rates of Change

The function g is defined by g(x) = 2x^2 - 3.

Find g(-4).

Question 7 [3 marks]

Number and Calculation

Work out 6 + 4 x (9 - 5)^2 / 8.

Question 8 [4 marks]

Pythagoras and Trigonometry

In a right-angled triangle, the side opposite angle y is 9 cm and the side adjacent to angle y is 6.5 cm.

Find y to 1 decimal place.

Question 9 [4 marks]

Angles, Polygons and Circle Theorems

Three angles meet at a point. One angle is 130 degrees, another is 3x degrees and the third is 2x degrees.

Find the value of x, then state the size of the smallest of the three angles at the point.

Question 10 [3 marks]

Indices, Surds and Standard Form

Simplify sqrt(8) x sqrt(18), giving your answer as an integer.

Question 11 [4 marks]

Sequences and Graphs

The straight line L has equation y = 2x - 7.

Find the equation of the line parallel to L that passes through (3, 4).

Question 12 [4 marks]

Indices, Surds and Standard Form

Work out the value of 3^-2 + 2^0, giving your answer as a single fraction.

Question 13 [4 marks]

Functions and Rates of Change

The functions f and g are defined by f(x) = x^2 - 4 and g(x) = 3x.

Find the values of x for which f(x) = g(x).

Question 14 [4 marks]

Sequences and Graphs

Find the equation of the straight line that passes through the points (1, 4) and (4, 13),

giving your answer in the form y = mx + c.

Question 15 [4 marks]

Mensuration and Vectors

A prism has cross-sectional area 22 cm^2 and length 16 cm.

Find the volume of the prism.

Question 16 [5 marks]

Fractions, Decimals and Percentages

A roll of ribbon is 5.4 m long.

Priya cuts off 1/3 of the ribbon for a project, then cuts 2/5 of what remains for a second project.

How many centimetres of ribbon are left?

Question 17 [5 marks]

Mensuration and Vectors

A window is made from a rectangle measuring 120 cm by 80 cm, topped with a semicircle whose diameter equals the 80 cm width of the rectangle.

Find the total area of the window, to the nearest cm^2.

Model solutions

Mark scheme for Question 1 [2 marks]
Question 1[2 marks]
Answer or workingMarks
adding 3 to both sides to get x/4 = 12M1
x = 48A1
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
area = 1/2 x 16 x 7M1
56 cm^2A1
Mark scheme for Question 3 [3 marks]
Question 3[3 marks]
Answer or workingMarks
at least two correct product termsM1
x^2 - 3x + 7x - 21M1
x^2 + 4x - 21A1
Mark scheme for Question 4 [3 marks]
Question 4[3 marks]
Answer or workingMarks
recognising 150 ml represents 1 part of the ratioM1
total parts = 1 + 6 = 7M1
1050 mlA1
Mark scheme for Question 5 [3 marks]
Question 5[3 marks]
Answer or workingMarks
summing the six values to get 12M1
mean = 2A1
range = 4A1
Final answer: mean 2, range 4
Mark scheme for Question 6 [3 marks]
Question 6[3 marks]
Answer or workingMarks
substituting x = -4M1
2 x (-4)^2M1
g(-4) = 29A1
Final answer: 29
Mark scheme for Question 7 [3 marks]
Question 7[3 marks]
Answer or workingMarks
evaluating the bracket (9 - 5) = 4 and squaring to get 16M1
multiplying by 4 and dividing by 8 to get 8M1
14A1
Mark scheme for Question 8 [4 marks]
Question 8[4 marks]
Answer or workingMarks
using tan y = opposite/adjacentM1
tan y = 9/6.5M1
y = tan^-1(9/6.5)M1
54.2 degreesA1
Mark scheme for Question 9 [4 marks]
Question 9[4 marks]
Answer or workingMarks
using angles around a point sum to 360 degreesM1
130 + 3x + 2x = 360M1
solving to x = 46M1
the smallest angle = 2 x 46 = 92 degreesA1
Final answer: x = 46; smallest angle = 92 degrees
Mark scheme for Question 10 [3 marks]
Question 10[3 marks]
Answer or workingMarks
multiplying to get sqrt(8 x 18) = sqrt(144)M1
evaluating 8 x 18 = 144M1
12A1
Mark scheme for Question 11 [4 marks]
Question 11[4 marks]
Answer or workingMarks
identifying gradient 2 from a parallel lineM1
using y = 2x + cM1
substituting (3, 4) to get 4 = 6 + cM1
y = 2x - 2A1
Mark scheme for Question 12 [4 marks]
Question 12[4 marks]
Answer or workingMarks
3^-2 = 1/9M1
2^0 = 1M1
writing 1 as 9/9M1
10/9A1
Mark scheme for Question 13 [4 marks]
Question 13[4 marks]
Answer or workingMarks
forming the equation x^2 - 4 = 3xM1
rearranging to x^2 - 3x - 4 = 0M1
factorising to (x - 4)(x + 1) = 0M1
x = 4 or x = -1A1
Mark scheme for Question 14 [4 marks]
Question 14[4 marks]
Answer or workingMarks
finding the gradient (13 - 4)/(4 - 1) = 3M1
substituting (1, 4) into y = 3x + cM1
solving to find c = 1M1
y = 3x + 1A1
Mark scheme for Question 15 [4 marks]
Question 15[4 marks]
Answer or workingMarks
volume = cross-sectional area x lengthM1
22 x 16M1
352A1
cm^3B1
Final answer: 352 cm^3
Mark scheme for Question 16 [5 marks]
Question 16[5 marks]
Answer or workingMarks
finding 2/3 of 5.4 = 3.6 m remaining after the first cutM1
finding 2/5 of 3.6 = 1.44 mM1
subtracting to leave 3.6 - 1.44 = 2.16 mM1
converting 2.16 m to centimetresM1
216 cmA1
Mark scheme for Question 17 [5 marks]
Question 17[5 marks]
Answer or workingMarks
the rectangle area = 120 x 80 = 9600 cm^2M1
the semicircle radius = 40 cmM1
the semicircle area = 1/2 x pi x 40^2M1
the semicircle area = 2513.27... cm^2A1
the total area = 12113 cm^2A1
Final answer: 12113 cm^2