Higher Tier - Grades 4-9

IGCSE Maths Higher Paper 3

Covers Number and Calculation, Fractions, Decimals and Percentages, Indices, Surds and Standard Form and 9 more.

13 questions - 60 marks - calculator allowed

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Questions

Question 1 [3 marks]

Sequences and Graphs

Find the midpoint of the line segment joining the points (2, -5) and (8, 3).

Question 2 [3 marks]

Functions and Rates of Change

The function g is defined by g(x) = 2x^2 - 3.

Find g(-4).

Question 3 [3 marks]

Indices, Surds and Standard Form

Simplify (x^7 y^3)/(x^3 y^-2).

Give your answer using positive indices.

Question 4 [5 marks]

Quadratics and Simultaneous Equations

Solve 3x^2 + 11x - 4 = 0 by factorising.

Question 5 [5 marks]

Pythagoras and Trigonometry

A triangular field has vertices A, B and C.

Angle BAC = 55 degrees, angle ABC = 72 degrees, and side BC = 84 m.

Find the length of side AC, to the nearest metre.

Question 6 [5 marks]

Angles, Polygons and Circle Theorems

A ship sails from port A on a bearing of 062 degrees to port B, then continues on a bearing of 130 degrees to port C.

Find the bearing of port A from port B, and find the angle ABC.

Question 7 [4 marks]

Indices, Surds and Standard Form

Expand and simplify (3 + sqrt(5))(2 - sqrt(5)).

Give your answer in the form a + b sqrt(5), where a and b are integers.

Question 8 [5 marks]

Fractions, Decimals and Percentages

A savings account pays compound interest at 2.75% per year.

1500 pounds is invested.

Find the value of the investment after 5 years, to the nearest penny.

Question 9 [5 marks]

Number and Calculation

P = 6.4 x 10^5 and Q = 3.7 x 10^4.

Work out P + Q, giving your answer in standard form.

Question 10 [5 marks]

Mensuration and Vectors

A cone has base radius 4.5 cm and height 10 cm.

Find its volume, to 3 significant figures, using volume = (1/3) pi r^2 h.

Question 11 [5 marks]

Ratio and Proportion

The pressure P of a gas is inversely proportional to its volume V.

When V = 8, P = 30.

Find P when V = 12.

Question 12 [6 marks]

Statistics and Probability

The table shows the masses, in kg, of 90 parcels.

0 <= m < 5: 18 parcels, 5 <= m < 10: 34 parcels, 10 <= m < 15: 26 parcels, 15 <= m < 20: 12 parcels.

Using linear interpolation, estimate the number of parcels with a mass greater than 12 kg.

Question 13 [6 marks]

Linear Equations and Inequalities

A cafe sells coffees and teas. On Monday, 12 coffees and 8 teas were sold for a total of 54.20 pounds.

On Tuesday, 15 coffees and 5 teas were sold for a total of 54.50 pounds.

Find the price of one coffee and the price of one tea.

Model solutions

Mark scheme for Question 1 [3 marks]
Question 1[3 marks]
Answer or workingMarks
adding the x-coordinates and dividing by 2M1
adding the y-coordinates and dividing by 2M1
(5, -1)A1
Mark scheme for Question 2 [3 marks]
Question 2[3 marks]
Answer or workingMarks
substituting x = -4M1
2 x (-4)^2M1
g(-4) = 29A1
Final answer: 29
Mark scheme for Question 3 [3 marks]
Question 3[3 marks]
Answer or workingMarks
subtracting powers of x to get x^4M1
subtracting powers of y to get y^5M1
x^4 y^5A1
Mark scheme for Question 4 [5 marks]
Question 4[5 marks]
Answer or workingMarks
finding two numbers with product -12 (3 x -4) and sum 11M1
identifying 12 and -1M1
factorising to (3x - 1)(x + 4) = 0M1
x = 1/3A1
x = -4A1
Final answer: x = 1/3 or x = -4
Mark scheme for Question 5 [5 marks]
Question 5[5 marks]
Answer or workingMarks
finding angle ACB = 180 - 55 - 72 = 53 degreesM1
using the sine rule AC/sin B = BC/sin AM1
AC = 84 x sin 72 / sin 55M1
97.5 m before roundingA1
98 m (nearest metre)A1
Final answer: 98 m
Mark scheme for Question 6 [5 marks]
Question 6[5 marks]
Answer or workingMarks
recognising the back bearing differs from the original bearing by 180 degreesM1
062 + 180 = 242, the bearing of A from BM1
242 degreesA1
finding angle ABC as the difference between the bearing of A from B and the bearing of C from BM1
angle ABC = 242 - 130 = 112 degreesA1
Final answer: bearing of A from B = 242 degrees, angle ABC = 112 degrees
Mark scheme for Question 7 [4 marks]
Question 7[4 marks]
Answer or workingMarks
multiplying out to get 6 - 3 sqrt(5) + 2 sqrt(5) - 5M1
simplifying the surd terms to -sqrt(5)M1
simplifying the integer terms to 1M1
1 - sqrt(5)A1
Mark scheme for Question 8 [5 marks]
Question 8[5 marks]
Answer or workingMarks
identifying the multiplier 1.0275M1
using value = 1500 x 1.0275^5M1
evaluating 1.0275^5 correctly to at least 4 decimal placesM1
evaluating 1500 x their power before roundingM1
1717.91 poundsA1
Mark scheme for Question 9 [5 marks]
Question 9[5 marks]
Answer or workingMarks
converting to the same power of 10, such as P = 64 x 10^4M1
identifying Q = 3.7 x 10^4M1
64 x 10^4 + 3.7 x 10^4 = 67.7 x 10^4M1
677000A1
6.77 x 10^5A1
Mark scheme for Question 10 [5 marks]
Question 10[5 marks]
Answer or workingMarks
using volume = 1/3 pi r^2 hM1
1/3 x pi x 4.5^2 x 10M1
67.5 piA1
212.058... before roundingM1
212 cm^3A1
Mark scheme for Question 11 [5 marks]
Question 11[5 marks]
Answer or workingMarks
P = k/VM1
30 = k/8M1
k = 240A1
P = 240/12M1
20A1
Mark scheme for Question 12 [6 marks]
Question 12[6 marks]
Answer or workingMarks
cumulative frequencies 18, 52, 78, 90M1
identifying 12 kg lies in the class 10 <= m < 15M1
using linear interpolation: cumulative frequency at 12 = 52 + (12 - 10)/5 x 26M1
evaluating 52 + 10.4 = 62.4M1
subtracting from the total: 90 - 62.4 = 27.6M1
28 parcels (nearest whole number)A1
Final answer: 28 parcels
Mark scheme for Question 13 [6 marks]
Question 13[6 marks]
Answer or workingMarks
forming the equations 12x + 8y = 54.20 and 15x + 5y = 54.50M1
multiplying the first equation by 5 and the second by 8 to align the y termsM1
subtracting to eliminate y, giving 60x = 165M1
x = 2.75 (one coffee costs 2.75 pounds)A1
substituting x = 2.75 into one of the original equationsM1
y = 2.65 (one tea costs 2.65 pounds)A1
Final answer: coffee = 2.75 pounds, tea = 2.65 pounds