Foundation Tier - Year 11

Year 11 Paper 3: Foundation Full Course Review

Covers number, proportion, linear and quadratic algebra, functions, geometry, trigonometry, mensuration, and statistics and probability.

22 questions - 80 marks - calculator allowed

Year 11 here means a typical teaching order, not a syllabus rule. No exam board defines what belongs to Year 11, and schools sequence the course differently. Check it against your own scheme of work before using it to decide what a class has covered.

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Questions

Question 1 [2 marks]

Number and Calculation

A stationery shop orders 34 boxes of pens. Each box contains 48 pens.

The shop already has 156 pens in stock. Work out the total number of pens now in the shop.

Question 2 [2 marks]

Functions and Rates of Change

The function f is defined by f(x) = x^2 - 3x.

Find f(-2).

Question 3 [2 marks]

Mensuration and Vectors

A triangle has base 16 cm and perpendicular height 7 cm. Find its area.

Question 4 [2 marks]

Number and Calculation

A youth club needs to transport 138 students to a trip.

Each coach seats 24 students. Find the minimum number of coaches needed.

Question 5 [3 marks]

Quadratics and Simultaneous Equations

Factorise completely 3x^2 + 9x - 84.

Question 6 [3 marks]

Linear Equations and Inequalities

Expand and simplify 3(2x - 5) + 4(x + 6).

Question 7 [3 marks]

Functions and Rates of Change

The function g is defined by g(x) = 2x^2 - 3.

Find g(-4).

Question 8 [4 marks]

Pythagoras and Trigonometry

In a right-angled triangle, the side opposite angle y is 9 cm and the side adjacent to angle y is 6.5 cm.

Find y to 1 decimal place.

Question 9 [4 marks]

Angles, Polygons and Circle Theorems

Three angles meet at a point. One angle is 130 degrees, another is 3x degrees and the third is 2x degrees.

Find the value of x, then state the size of the smallest of the three angles at the point.

Question 10 [4 marks]

Statistics and Probability

The prices, in pounds, of 6 items in a shop are 12, 15, 9, 18, 14 and 16.

Find the mean price. A seventh item priced at 30 pounds is then added to the list.

Find the new mean price of all 7 items.

Question 11 [4 marks]

Ratio and Proportion

A bag of 360 sweets is shared between Priya, Sam and Tom in the ratio 4:5:9.

Find the difference between Tom's share and Priya's share.

Question 12 [3 marks]

Linear Equations and Inequalities

Solve the inequality 4x + 7 < 2x + 19.

Question 13 [4 marks]

Functions and Rates of Change

The function g is defined by g(x) = x^2 - 2x.

Find the value of g(5) - g(-2).

Question 14 [4 marks]

Angles, Polygons and Circle Theorems

A, B and C are points on the circumference of a circle, where AC is a diameter.

Angle BAC = 34 degrees. Find angle ABC and angle BCA.

Question 15 [4 marks]

Statistics and Probability

A spinner has sections labelled A, B, C and D.

P(A) = 0.3, P(B) = 0.25 and P(C) = 0.2.

Find P(D).

Question 16 [4 marks]

Ratio and Proportion

In a school, the ratio of Year 10 students to Year 11 students is 5:4.

The ratio of Year 11 students to Year 12 students is 2:3.

Find the ratio of Year 10 to Year 11 to Year 12 students, in its simplest form.

Question 17 [4 marks]

Number and Calculation

Determine whether 259 is a prime number. Show your working.

Question 18 [4 marks]

Mensuration and Vectors

A circular pond has radius 6.5 m.

Find its circumference to 1 decimal place.

Question 19 [5 marks]

Angles, Polygons and Circle Theorems

A, B and C are points on the circumference of a circle with centre O.

B is on the major arc AC and angle AOC (the non-reflex angle at the centre) = 136 degrees.

Find angle ABC and angle OAC.

Question 20 [5 marks]

Quadratics and Simultaneous Equations

Solve 2x^2 - 5x - 12 = 0 by factorising.

Question 21 [5 marks]

Linear Equations and Inequalities

Tickets to a fair cost 6 pounds each, and there is a fixed 8 pound parking charge.

A family has a budget of 50 pounds.

Form an inequality and find the greatest number of tickets the family can buy without exceeding their budget.

Question 22 [5 marks]

Functions and Rates of Change

The function h is defined by h(x) = 3/(x - 2) for x is not equal to 2.

Find h^-1(x), and hence find h^-1(1).

Model solutions

Mark scheme for Question 1 [2 marks]
Question 1[2 marks]
Answer or workingMarks
34 x 48 = 1632M1
1788 pensA1
Mark scheme for Question 2 [2 marks]
Question 2[2 marks]
Answer or workingMarks
substituting x = -2 into f(x) = x^2 - 3xM1
f(-2) = 10A1
Final answer: 10
Mark scheme for Question 3 [2 marks]
Question 3[2 marks]
Answer or workingMarks
area = 1/2 x 16 x 7M1
56 cm^2A1
Mark scheme for Question 4 [2 marks]
Question 4[2 marks]
Answer or workingMarks
dividing 138 by 24 to get 5.75M1
6 coaches (rounding up)A1
Final answer: 6 coaches
Mark scheme for Question 5 [3 marks]
Question 5[3 marks]
Answer or workingMarks
taking out the common factor 3: 3(x^2 + 3x - 28)M1
finding factors of -28 that sum to 3, which are 7 and -4M1
3(x + 7)(x - 4)A1
Mark scheme for Question 6 [3 marks]
Question 6[3 marks]
Answer or workingMarks
expanding to 6x - 15 + 4x + 24M1
collecting like x terms and constantsM1
10x + 9A1
Mark scheme for Question 7 [3 marks]
Question 7[3 marks]
Answer or workingMarks
substituting x = -4M1
2 x (-4)^2M1
g(-4) = 29A1
Final answer: 29
Mark scheme for Question 8 [4 marks]
Question 8[4 marks]
Answer or workingMarks
using tan y = opposite/adjacentM1
tan y = 9/6.5M1
y = tan^-1(9/6.5)M1
54.2 degreesA1
Mark scheme for Question 9 [4 marks]
Question 9[4 marks]
Answer or workingMarks
using angles around a point sum to 360 degreesM1
130 + 3x + 2x = 360M1
solving to x = 46M1
the smallest angle = 2 x 46 = 92 degreesA1
Final answer: x = 46; smallest angle = 92 degrees
Mark scheme for Question 10 [4 marks]
Question 10[4 marks]
Answer or workingMarks
summing the six prices to get 84M1
mean = 14 poundsA1
adding the seventh price: 84 + 30 = 114M1
new mean = 114/7 = 16.29 pounds (2 d.p.)A1
Final answer: mean = 14 pounds, new mean = 16.29 pounds
Mark scheme for Question 11 [4 marks]
Question 11[4 marks]
Answer or workingMarks
total parts = 4 + 5 + 9 = 18M1
one part = 360 / 18 = 20M1
Tom's share = 9 x 20 = 180 and Priya's share = 4 x 20 = 80M1
100 sweetsA1
Mark scheme for Question 12 [3 marks]
Question 12[3 marks]
Answer or workingMarks
collecting terms in x on one side, such as 2x + 7 < 19M1
2x < 12M1
x < 6A1
Mark scheme for Question 13 [4 marks]
Question 13[4 marks]
Answer or workingMarks
g(5) = 25 - 10 = 15M1
g(-2) = 4 + 4 = 8M1
subtracting g(-2) from g(5)M1
7A1
Mark scheme for Question 14 [4 marks]
Question 14[4 marks]
Answer or workingMarks
recognising angle ABC = 90 degrees, the angle in a semicircleM1
using angle sum in triangle ABC = 180 degreesM1
180 - 90 - 34M1
angle BCA = 56 degreesA1
Final answer: angle ABC = 90 degrees, angle BCA = 56 degrees
Mark scheme for Question 15 [4 marks]
Question 15[4 marks]
Answer or workingMarks
probabilities summing to 1M1
0.3 + 0.25 + 0.2 = 0.75M1
1 - 0.75M1
0.25A1
Mark scheme for Question 16 [4 marks]
Question 16[4 marks]
Answer or workingMarks
scaling the second ratio so the Year 11 parts match: 2:3 becomes 4:6M1
combining to get Year 10 : Year 11 : Year 12 = 5 : 4 : 6M1
checking the ratio cannot be simplified furtherM1
5:4:6A1
Mark scheme for Question 17 [4 marks]
Question 17[4 marks]
Answer or workingMarks
testing division by small primes such as 2, 3 and 5M1
testing division by 7M1
259 = 7 x 37A1
stating 259 is not a prime number, since it has factors other than 1 and itselfA1
Final answer: Not prime, since 259 = 7 x 37
Mark scheme for Question 18 [4 marks]
Question 18[4 marks]
Answer or workingMarks
using circumference = 2 pi rM1
2 x pi x 6.5M1
40.840... before roundingM1
40.8 mA1
Mark scheme for Question 19 [5 marks]
Question 19[5 marks]
Answer or workingMarks
recognising the angle at the centre is twice the angle at the circumference on the same arcM1
angle ABC = 136 / 2M1
angle ABC = 68 degreesA1
using triangle OAC is isosceles since OA = OC, so base angles = (180 - 136)/2M1
angle OAC = 22 degreesA1
Final answer: angle ABC = 68 degrees, angle OAC = 22 degrees
Mark scheme for Question 20 [5 marks]
Question 20[5 marks]
Answer or workingMarks
finding two numbers with product -24 and sum -5M1
identifying -8 and 3M1
factorising to (2x + 3)(x - 4) = 0M1
x = -3/2A1
x = 4A1
Final answer: x = -3/2 or x = 4
Mark scheme for Question 21 [5 marks]
Question 21[5 marks]
Answer or workingMarks
forming the inequality 6n + 8 <= 50M1
subtracting 8 from both sides to get 6n <= 42M1
dividing both sides by 6M1
n <= 7A1
the greatest number of tickets is 7A1
Final answer: 7 tickets
Mark scheme for Question 22 [5 marks]
Question 22[5 marks]
Answer or workingMarks
writing x = 3/(y - 2), swapping x and yM1
multiplying both sides by (y - 2) to get x(y - 2) = 3M1
expanding and rearranging to make y the subjectM1
h^-1(x) = (3 + 2x)/xA1
h^-1(1) = 5A1
Final answer: h^-1(x) = (3 + 2x)/x; h^-1(1) = 5